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Trigonometric Functions

Practice exam-style IB Math AA questions for Trigonometric Functions, aligned with the syllabus and grouped by topic.

Paper
Difficulty
Status
Level
Question 1
SL • Paper 1
Easy
Non Calculator

The point PP lies on the unit circle and corresponds to the angle θ\theta, where π<θ<3π2\pi<\theta<\dfrac{3\pi}{2}. Given that tanθ=3\tan\theta=\sqrt{3}:

A

Find the value of θ\theta.

[2]
Write your answer here...
B

Write down the coordinates of PP.

[2]
Write your answer here...
C

line through the origin makes an angle 2πθ2\pi-\theta with the positive xx-axis. Find the gradient of the line.

[1]
Write your answer here...

0

Question 2
SL • Paper 1
Easy
Non Calculator

Let xx be an angle such that π2<x<π\dfrac{\pi}{2}<x<\pi and cosx=35\cos x=-\dfrac{3}{5}.

A

Find sinx\sin x.

[2]
Write your answer here...
B

Find cos2x\cos 2x.

[1]
Write your answer here...
C

Find sin2x\sin 2x.

[2]
Write your answer here...

0

Question 3
SL • Paper 1
Easy
Non Calculator
A

Solve 2sin(xπ4)=12\sin\left(x-\dfrac{\pi}{4}\right)=1 for 0x2π0\le x\le 2\pi.

[4]
Write your answer here...

0

Question 4
SL • Paper 2
Easy
Calculator Permitted

A line ll passes through the origin and makes an angle θ\theta with the positive xx-axis, where π<θ<3π2\pi<\theta<\dfrac{3\pi}{2}. A point P(4,k)P(-4,k) lies on ll. Given that sinθ=513\sin\theta=-\dfrac{5}{13}, answer the following.

A

Find cosθ\cos\theta.

[1]
Write your answer here...
B

Find the exact value of kk.

[2]
Write your answer here...
C

Find the exact value of cos2θ\cos 2\theta.

[2]
Write your answer here...

0

Question 5
SL • Paper 2
Easy
Calculator Permitted

Let xx be an angle such that π2<x<π\dfrac{\pi}{2}<x<\pi and cosx=0.28\cos x=-0.28.

A

Find sinx\sin x.

[2]
Write your answer here...
B

Find sin2x\sin 2x and cos2x\cos 2x.

[3]
Write your answer here...

0

Question 6
SL • Paper 1
Medium
Non Calculator

In triangle ABCABC, A=30A=30^\circ, a=5a=5 and b=52b=5\sqrt{2}, where aa and bb are opposite AA and BB respectively.

A

Find the possible values of angle CC.

[5]
Write your answer here...

0

Question 7
SL • Paper 1
Medium
Non Calculator

A periodic quantity is modelled by f(t)=asin(bt)+df(t)=a\sin(bt)+d, where b>0b>0. The maximum value of ff is 1010, the minimum value is 22, and the period is π\pi. Also, for small positive values of tt, f(t)>f(0)f(t)>f(0).

A

Find the amplitude and the value of dd.

[2]
Write your answer here...
B

Find the value of bb.

[2]
Write your answer here...
C

Determine the values of aa, bb and dd.

[2]
Write your answer here...

0

Question 8
SL • Paper 1
Medium
Non Calculator
A

Solve 2cos2xcosx1=02\cos^2 x-\cos x-1=0 for 0x2π0\le x\le 2\pi.

[5]
Write your answer here...

0

Question 9
HL • Paper 1
Medium
Non Calculator

Let π<θ<3π2\pi<\theta<\dfrac{3\pi}{2} and tanθ=2\tan\theta=2.

A

Find secθ\sec\theta.

[3]
Write your answer here...
B

Find cscθ\csc\theta.

[2]
Write your answer here...

0

Question 10
HL • Paper 1
Medium
Non Calculator

The function ff is defined by f(x)=arccos(2x1)f(x)=\arccos(2x-1).

A

Find the domain of ff.

[2]
Write your answer here...
B

Solve f(x)=2π3f(x)=\dfrac{2\pi}{3}.

[3]
Write your answer here...

0

Question 11
HL • Paper 1
Medium
Non Calculator

Let 0<θ<π40<\theta<\dfrac{\pi}{4} and tanθ=13\tan\theta=\dfrac{1}{3}.

A

Find tan2θ\tan 2\theta.

[3]
Write your answer here...
B

Hence find tan(2θ+π4)\tan\left(2\theta+\dfrac{\pi}{4}\right).

[2]
Write your answer here...

0

Question 12
HL • Paper 1
Medium
Non Calculator

Consider the equation sin(πx)=cos(x)\sin(\pi-x)=\cos(-x) for πxπ-\pi\le x\le \pi.

A

Use symmetry properties to rewrite the equation in the form sinx=cosx\sin x=\cos x.

[2]
Write your answer here...
B

Hence solve the equation for πxπ-\pi\le x\le \pi.

[2]
Write your answer here...

0

Question 13
SL • Paper 2
Medium
Calculator Permitted

Consider the equation

2sin2x3cosx=02\sin^2x-3\cos x=0

for 0x2π0\le x\le 2\pi.

A

Show that the equation can be written as 2cos2x+3cosx2=02\cos^2x+3\cos x-2=0.

[1]
Write your answer here...
B

Hence solve the equation.

[3]
Write your answer here...

0

Question 14
HL • Paper 2
Medium
Calculator Permitted

Let θ\theta be an angle such that π2<θ<π\dfrac{\pi}{2}<\theta<\pi and tanθ=125\tan\theta=-\dfrac{12}{5}.

A

Find the exact values of secθ\sec\theta and cscθ\csc\theta.

[3]
Write your answer here...
B

Solve sec2x3tanx=5\sec^2x-3\tan x=5 for 0x<2π0\le x<2\pi.

[3]
Write your answer here...

0

Question 15
HL • Paper 2
Medium
Calculator Permitted

The function ff is defined by

f(x)=arccos(2x1)f(x)=\arccos(2x-1)
A

State the domain and range of ff.

[2]
Write your answer here...
B

Solve exactly f(x)=2arctan(34)f(x)=2\arctan\left(\dfrac{3}{4}\right).

[3]
Write your answer here...

0

Question 16
HL • Paper 2
Medium
Calculator Permitted

The graph of y=2csc(x0.4)+1y=2\csc(x-0.4)+1 is considered for 0x2π0\le x\le 2\pi.

Graph of y = 2 csc(x - 0.4) + 1 for 0 ≤ x ≤ 2π.
A

Find the equations of the vertical asymptotes in this interval.

[2]
Write your answer here...
B

Solve 2csc(x0.4)+1=52\csc(x-0.4)+1=5 in this interval.

[2]
Write your answer here...
C

State the range of y=2csc(x0.4)+1y=2\csc(x-0.4)+1.

[1]
Write your answer here...

0

Question 17
HL • Paper 1
Medium
Non Calculator

This question uses the compound angle identities.

A

Show that sinπ12=624\sin\dfrac{\pi}{12}=\dfrac{\sqrt{6}-\sqrt{2}}{4}.

[3]
Write your answer here...
B

Hence solve sin(x+π12)=624\sin\left(x+\dfrac{\pi}{12}\right)=\dfrac{\sqrt{6}-\sqrt{2}}{4} for 0x2π0\le x\le 2\pi.

[3]
Write your answer here...

0

Question 18
HL • Paper 1
Medium
Non Calculator
A

Solve secxtanx=13\sec x-\tan x=\dfrac{1}{3} for 0x<π20\le x<\dfrac{\pi}{2}.

[6]
Write your answer here...

0

Question 19
SL • Paper 2
Medium
Calculator Permitted

In triangle ABCABC, AB=9 cmAB=9\ \text{cm}, AC=7 cmAC=7\ \text{cm} and ABC=0.620\angle ABC=0.620 radians. This information gives two possible triangles.

Redraw a geometrically accurate non-right triangle showing one valid configuration only. Place $B$ and $A$ so that $AB=9\ \text{cm}$; from $B$, draw the ray $BC$ so that $\angle ABC=0.620$ radians, and choose the nearer intersection of this ray with the circle centered at $A$ of radius $7\ \text{cm}$, giving $AC=7\ \text{cm}$. Label $A$, $B$, $C$, $AB=9\ \text{cm}$, $AC=7\ \text{cm}$, and the angle at $B$. The angle at $B$ should appear approximately $35.5^\circ$, not $61^\circ$. Do not show the second possible position explicitly, and draw the figure to scale as far as practical.
A

Find the two possible values of ACB\angle ACB.

[3]
Write your answer here...
B

Hence find the two possible areas of triangle ABCABC.

[3]
Write your answer here...

0

Question 20
SL • Paper 2
Medium
Calculator Permitted

The height hh metres of a floating marker above the sea bed is modelled by

h(t)=asin(b(tc))+dh(t)=a\sin(b(t-c))+d

where tt is the time in hours after midnight and a>0a>0. The maximum height is 5.85.8 metres at t=2t=2, the minimum height is 1.41.4 metres at t=8t=8, and the motion has period 1212 hours, with b>0b>0 and 6<c6-6<c\le 6.

Sinusoidal marker height over one 12-hour cycle.
A

Find the values of aa, bb and dd.

[3]
Write your answer here...
B

Find the value of cc.

[2]
Write your answer here...
C

Find the first time after midnight when the height is 4.54.5 metres.

[2]
Write your answer here...

0

Question 21
SL • Paper 2
Medium
Calculator Permitted

The equation

2tan(3(x1))=12\tan(3(x-1))=1

is to be solved for 0x30\le x\le 3.

A

Let u=3(x1)u=3(x-1). Find the corresponding interval for uu.

[1]
Write your answer here...
B

Hence solve the equation for xx.

[4]
Write your answer here...

0

Question 22
HL • Paper 2
Medium
Calculator Permitted

Let AA and BB be acute angles such that tanA=2\tan A=2 and tanB=13\tan B=\dfrac{1}{3}.

A

Find the exact value of tan(A+B)\tan(A+B).

[2]
Write your answer here...
B

Find A+BA+B, giving your answer to 33 significant figures.

[1]
Write your answer here...
C

Hence solve tan(2x)=7\tan(2x)=7 for 0xπ0\le x\le \pi.

[3]
Write your answer here...

0

Question 23
HL • Paper 2
Medium
Calculator Permitted

For 0x2π0\le x\le 2\pi, define

f(x)=sinx+sin(πx)+cos(π+x)f(x)=\sin x+\sin(\pi-x)+\cos(\pi+x)
A

Use symmetry properties of trigonometric functions to simplify f(x)f(x).

[2]
Write your answer here...
B

Write f(x)f(x) in the form Rsin(xα)R\sin(x-\alpha), where R>0R>0 and 0<α<π20<\alpha<\dfrac{\pi}{2}.

[2]
Write your answer here...
C

Solve f(x)=1f(x)=1.

[2]
Write your answer here...

0

Question 24
SL • Paper 1
Medium
Non Calculator

Let θ\theta be an angle such that π2<θ<π\dfrac{\pi}{2}<\theta<\pi and cosθ=513\cos\theta=-\dfrac{5}{13}. A point PP on the unit circle corresponds to the angle θ\theta.

A
I.

Find sinθ\sin\theta.

[2]
Write your answer here...
II.

Hence find tanθ\tan\theta.

[2]
Write your answer here...
B
I.

line ll passes through the origin and is perpendicular to OPOP. Find the gradient of ll.

[2]
Write your answer here...
II.

Write down an equation of ll.

[1]
Write your answer here...
C

The point PP is reflected in the line y=xy=x. The image is QQ. Determine the angle α\alpha, 0α<2π0\leq \alpha<2\pi, corresponding to QQ on the unit circle, in terms of θ\theta. Hence find tanα\tan\alpha.

[3]
Write your answer here...

0

Question 25
SL • Paper 1
Medium
Non Calculator

In triangle ABCABC, side lengths aa, bb and cc are opposite angles AA, BB and CC respectively. It is given that A=45A=45^\circ, a=4a=4 and b=26b=2\sqrt{6}.

A
I.

Use the sine rule to show that sinB=32\sin B=\dfrac{\sqrt{3}}{2}.

[2]
Write your answer here...
II.

Find the two possible values of BB.

[2]
Write your answer here...
B
I.

Find the corresponding two possible values of CC.

[2]
Write your answer here...
II.

Find the two possible exact values of cc.

[2]
Write your answer here...
C

Find the two possible exact areas of triangle ABCABC.

[3]
Write your answer here...

0

Question 26
SL • Paper 1
Medium
Non Calculator

The function ff is defined by

f(x)=32sin(2x+π3),0xπf(x)=3-2\sin\left(2x+\frac{\pi}{3}\right),\quad 0\leq x\leq \pi
A
I.

State the amplitude and period of ff.

[2]
Write your answer here...
II.

Describe the horizontal and vertical translations from y=2sin(2x)y=-2\sin(2x) to y=f(x)y=f(x).

[2]
Write your answer here...
B
I.

Find the maximum and minimum values of ff.

[2]
Write your answer here...
II.

Find the values of xx in the given interval for which f(x)=5f(x)=5.

[2]
Write your answer here...
C

Solve f(x)=4f(x)=4 for 0xπ0\leq x\leq \pi.

[3]
Write your answer here...

0

Question 27
SL • Paper 2
Medium
Calculator Permitted

The brightness BB of a rotating warning light, in arbitrary units, is modelled by

B(t)=asin(b(tc))+d,0t16B(t)=a\sin(b(t-c))+d,\quad 0\leq t\leq 16

where tt is the time in seconds after the light is switched on and a>0a>0. The brightness has a maximum value of 7272 at t=1.5t=1.5 and a minimum value of 1818 at t=5.5t=5.5. The motion is periodic.

Brightness of a warning light over two cycles.
A
I.

Find the values of aa and dd.

[2]
Write your answer here...
II.

Find the value of bb, taking b>0b>0.

[2]
Write your answer here...
III.

Determine one possible value of cc for this choice of bb.

[2]
Write your answer here...
B

Using your model, find all times in the interval 0t160\leq t\leq 16 when B(t)=60B(t)=60. If you did not obtain a model in part (a), use B(t)=27sin(π4(t+0.5))+45B(t)=27\sin\left(\dfrac{\pi}{4}(t+0.5)\right)+45.

[3]
Write your answer here...
C

Determine the total length of time, in seconds, during 0t160\leq t\leq 16 for which the brightness is greater than 6060.

[3]
Write your answer here...

0

Question 28
SL • Paper 2
Medium
Calculator Permitted

In triangle ABCABC, the side lengths opposite AA, BB and CC are aa, bb and cc respectively. It is given that A=0.650A=0.650 radians, a=10.0 cma=10.0\ \text{cm} and b=13.0 cmb=13.0\ \text{cm}.

A non-right triangle labelled $A$, $B$, $C$, with side $a$ opposite angle $A$ and side $b$ opposite angle $B$. The diagram should indicate that two different positions of vertex $B$ may be possible for the same given data.
A
I.

Use the sine rule to find the two possible values of angle BB.

[4]
Write your answer here...
B
I.

For each possible triangle, find the corresponding value of CC.

[2]
Write your answer here...
II.

For each possible triangle, find the corresponding length of cc.

[2]
Write your answer here...
C

design condition states that the area of triangle ABCABC must exceed 20 cm220\ \text{cm}^2. Determine which of the possible triangles satisfies this condition.

[2]
Write your answer here...

0

Question 29
SL • Paper 2
Medium
Calculator Permitted

A machine component moves vertically. Its height hh cm above a fixed level is modelled by

h(x)=acos(b(xc))+dh(x)=a\cos(b(x-c))+d

where xx is measured in seconds and b>0b>0. The graph of hh has consecutive maximum points at (2,9)(2,9) and (12,9)(12,9), and a minimum point at (7,1)(7,1).

Sinusoidal graph of h against time x.
A
I.

Find the amplitude and the value of dd.

[2]
Write your answer here...
II.

Find the value of bb.

[2]
Write your answer here...
III.

Find a possible model for h(x)h(x).

[3]
Write your answer here...
B

second component has height g(x)=h(x3)+2g(x)=h(x-3)+2. Describe the transformation from the graph of hh to the graph of gg.

[2]
Write your answer here...
C

Find the first time after x=0x=0 when the height of the second component is 88 cm. If you did not obtain a model in part (a), use h(x)=4cos(π5(x2))+5h(x)=4\cos\left(\dfrac{\pi}{5}(x-2)\right)+5.

[3]
Write your answer here...

0

Question 30
HL • Paper 2
Medium
Calculator Permitted

Consider the equation

arctanx+arctan(2x)=π4\arctan x+\arctan(2x)=\frac{\pi}{4}
A

Show that any solution must satisfy 2x2+3x1=02x^2+3x-1=0.

[2]
Write your answer here...
B

Hence find the exact solution of the original equation.

[3]
Write your answer here...

0

Question 31
SL • Paper 1
Hard
Non Calculator

The height hh metres of a point on a rotating wheel above the ground is modelled by

h(t)=acos(b(tc))+dh(t)=a\cos(b(t-c))+d

where tt is the time in seconds, a>0a>0 and b>0b>0. The maximum height is 1414 metres at t=1t=1, and the minimum height is 22 metres at t=5t=5. The maximum at t=1t=1 and the minimum at t=5t=5 are consecutive extrema.

A
I.

Find aa and dd.

[2]
Write your answer here...
II.

Find bb.

[2]
Write your answer here...
III.

Find a possible value of cc.

[1]
Write your answer here...
B

Hence write down a model for h(t)h(t).

[2]
Write your answer here...
C
I.

Find the first time after t=1t=1 when h(t)=8+32h(t)=8+3\sqrt2.

[3]
Write your answer here...
II.

Determine the values of tt in 1t91\leq t\leq 9 for which h(t)=5h(t)=5.

[2]
Write your answer here...

0

Question 32
SL • Paper 1
Hard
Non Calculator

Consider the equation

2sinx=cos2x2\sin x=\cos 2x

for πxπ-\pi\leq x\leq \pi.

A
I.

Show that the equation can be written as 2sin2x+2sinx1=02\sin^2x+2\sin x-1=0.

[3]
Write your answer here...
II.

Hence find the possible values of sinx\sin x.

[2]
Write your answer here...
B

Let α=arcsin(312)\alpha=\arcsin\left(\dfrac{\sqrt3-1}{2}\right), where 0<α<π20<\alpha<\dfrac{\pi}{2}. Solve the equation for πxπ-\pi\leq x\leq \pi.

[3]
Write your answer here...
C
I.

Find the exact value of cos2x\cos 2x for each solution.

[2]
Write your answer here...
II.

Determine whether the equation has any solution in πx<0-\pi\leq x<0. Give a reason.

[2]
Write your answer here...

0

Question 33
SL • Paper 1
Hard
Non Calculator

Consider the equation

2tan(2xπ4)=22\tan\left(2x-\frac{\pi}{4}\right)=2

where 0x2π0\leq x\leq 2\pi.

A
I.

Let u=2xπ4u=2x-\dfrac{\pi}{4}. Find the corresponding interval for uu.

[2]
Write your answer here...
II.

Solve the equation for uu in this interval.

[2]
Write your answer here...
B

Hence solve the original equation for xx.

[3]
Write your answer here...
C
I.

Find the values of xx in 0x2π0\leq x\leq 2\pi for which tan(2xπ4)\tan\left(2x-\dfrac{\pi}{4}\right) is undefined.

[3]
Write your answer here...
II.

State the number of branches of the graph of y=tan(2xπ4)y=\tan\left(2x-\dfrac{\pi}{4}\right) in 0x2π0\leq x\leq 2\pi.

[2]
Write your answer here...

0

Question 34
HL • Paper 1
Hard
Non Calculator

Let 0x<2π0\leq x<2\pi. Consider the equation

secx+tanx=3\sec x+\tan x=3
A
AI.

Show that (secx+tanx)(secxtanx)=1(\sec x+\tan x)(\sec x-\tan x)=1.

[2]
Write your answer here...
AII.

Hence find secxtanx\sec x-\tan x.

[2]
Write your answer here...
B
BI.

Find secx\sec x and tanx\tan x.

[2]
Write your answer here...
BII.

Hence find sinx\sin x and cosx\cos x.

[2]
Write your answer here...
C

Solve secx+tanx=3\sec x+\tan x=3 for 0x<2π0\leq x<2\pi.

[4]
Write your answer here...

0

Question 35
HL • Paper 1
Hard
Non Calculator

The function ff is defined by

f(x)=arcsin(2x1)f(x)=\arcsin(2x-1)
A
AI.

Find the domain of ff.

[2]
Write your answer here...
AII.

State the range of ff.

[2]
Write your answer here...
B
BI.

Find f(14)f\left(\dfrac{1}{4}\right).

[2]
Write your answer here...
BII.

Solve f(x)=π3f(x)=\dfrac{\pi}{3}.

[2]
Write your answer here...
C

Let g(x)=arccos(2x1)g(x)=\arccos(2x-1) on the same domain as ff. Show that f(x)+g(x)=π2f(x)+g(x)=\dfrac{\pi}{2} for 0x10\leq x\leq1.

[4]
Write your answer here...

0

Question 36
SL • Paper 2
Hard
Calculator Permitted

Consider the function

f(x)=2sinxcos2x,0x2πf(x)=2\sin x-\cos 2x,\quad 0\leq x\leq 2\pi
Curve of $f(x)=2\sin x-\cos 2x$ with a horizontal line at $y=1.5$.
A
I.

Show that f(x)=2sin2x+2sinx1f(x)=2\sin^2x+2\sin x-1.

[2]
Write your answer here...
B
I.

Hence solve f(x)=0f(x)=0 for 0x2π0\leq x\leq 2\pi.

[4]
Write your answer here...
C

Use a GDC to find the maximum and minimum values of ff on 0x2π0\leq x\leq 2\pi.

[3]
Write your answer here...
D

Find the set of values of xx for which f(x)>1.5f(x)>1.5.

[2]
Write your answer here...

0

Question 37
SL • Paper 2
Hard
Calculator Permitted

A narrow laser beam is emitted from the origin in the coordinate plane. At time tt seconds, the beam makes an angle

θ=0.25t+0.300\theta=0.25t+0.300

with the positive xx-axis. A vertical screen is placed along the line x=4x=4. For times before the first parallel position, the point where the beam meets the screen has coordinates (4,y)(4,y).

A coordinate diagram with the origin, a ray making angle $\theta$ with the positive $x$-axis, and a vertical screen at $x=4$. The intersection point $(4,y)$ should be labelled.
A
I.

Show that y=4tan(0.25t+0.300)y=4\tan(0.25t+0.300).

[2]
Write your answer here...
II.

Find the first time at which the beam is parallel to the screen. Give your answer to three significant figures.

[2]
Write your answer here...
B

Find the time in the interval 0t<π20.3000.250\leq t<\dfrac{\dfrac{\pi}{2}-0.300}{0.25} when y=6y=6.

[3]
Write your answer here...
C

At the time found in part (b), find the distance from the origin to the point where the beam meets the screen.

[2]
Write your answer here...
D

State why the model cannot give a finite value of yy at the first parallel time, t=π20.3000.25t=\dfrac{\dfrac{\pi}{2}-0.300}{0.25} (which is 5.085.08 s to three significant figures).

[1]
Write your answer here...

0

Question 38
SL • Paper 2
Hard
Calculator Permitted

The function

f(x)=atan(b(xc))+df(x)=a\tan(b(x-c))+d

has vertical asymptotes at x=1x=1 and x=5x=5. The centre of one branch is the point (3,2)(3,2), and the point (4,5)(4,5) lies on the graph. Use the convention that b>0b>0 and that cc is the xx-coordinate of the centre of the branch between the two given asymptotes.

Tangent graph with asymptotes at x=1 and x=5.
A
I.

Find the values of bb, cc and dd.

[3]
Write your answer here...
II.

Find the value of aa.

[3]
Write your answer here...
B

Solve f(x)=0f(x)=0 for 1x9-1\leq x\leq 9. Give your answers to 3 significant figures. If you did not obtain ff, use f(x)=3tan(π4(x3))+2f(x)=3\tan\left(\dfrac{\pi}{4}(x-3)\right)+2.

[3]
Write your answer here...
C

State the equations of all vertical asymptotes of ff in the interval 1x9-1\leq x\leq 9.

[1]
Write your answer here...

0

Question 39
HL • Paper 2
Hard
Calculator Permitted

Consider the function

f(x)=3sec(2x)2,0x2πf(x)=3\sec(2x)-2,\quad 0\leq x\leq 2\pi
Separate continuous branches of y=3sec(2x)-2 on 0≤x≤2π, with gaps at the vertical asymptotes.
A
I.

Find the equations of the vertical asymptotes of the graph of ff.

[2]
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II.

State the range of ff.

[3]
Write your answer here...
B

Solve f(x)=4f(x)=4 for 0x2π0\leq x\leq 2\pi.

[3]
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C

Find the area enclosed by the curve y=f(x)y=f(x), the xx-axis, the yy-axis and the line x=π6x=\dfrac{\pi}{6}.

[2]
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0

Question 40
HL • Paper 2
Hard
Calculator Permitted

Consider the function

f(x)=5sinx+12cosxf(x)=5\sin x+12\cos x

where 0x2π0\leq x\leq 2\pi.

A
I.

Write f(x)f(x) in the form Rsin(x+α)R\sin(x+\alpha), where R>0R>0 and 0<α<π20<\alpha<\dfrac{\pi}{2}.

[4]
Write your answer here...
II.

State the maximum value of f(x)f(x).

[1]
Write your answer here...
B

Solve f(x)=6f(x)=6 for 0x2π0\leq x\leq 2\pi. If you did not obtain part (a), use f(x)=13sin(x+1.18)f(x)=13\sin(x+1.18).

[3]
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C

Let AA be the area between the graph of y=f(x)y=f(x) and the xx-axis over the interval from the smaller solution in part (b) to the larger solution in part (b). Determine AA.

[4]
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0

Question 41
HL • Paper 2
Hard
Calculator Permitted

Define

f(x)=sin(πx)+cos(x),πx3πf(x)=\sin(\pi-x)+\cos(-x),\quad -\pi\leq x\leq 3\pi
A
I.

Use symmetry properties of trigonometric functions to simplify f(x)f(x).

[2]
Write your answer here...
II.

Show that, for any xx such that both xx and π2x\dfrac{\pi}{2}-x lie in the stated domain, f(π2x)=f(x)f\left(\dfrac{\pi}{2}-x\right)=f(x). Hence the formula has reflection symmetry about the line x=π4x=\dfrac{\pi}{4} on the portions of the graph for which reflected points are in the domain.

[2]
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B

Write f(x)f(x) in the form Rsin(x+α)R\sin(x+\alpha), where R>0R>0 and 0<α<π20<\alpha<\dfrac{\pi}{2}.

[2]
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C

Solve f(x)=0.500f(x)=0.500 for πx3π-\pi\leq x\leq 3\pi.

[4]
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0

Question 42
HL • Paper 3
Hard
Calculator Permitted

This question investigates the graph of the reciprocal trigonometric function fa,d(x)=asec(xπ6)+df_{a,d}(x)=a\sec\left(x-\frac{\pi}{6}\right)+d, where a>0a>0, for 0x2π0\le x\le 2\pi.

Transformed secant graph on $0\le x\le 2\pi$.
A

Consider first the function f(x)=2sec(xπ6)1f(x)=2\sec\left(x-\frac{\pi}{6}\right)-1.

I.

Find the equations of the vertical asymptotes of the graph of ff in the interval 0x2π0\le x\le 2\pi.

[2]
Write your answer here...
II.

Write down the range of ff.

[2]
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B

Solve 2sec(xπ6)1=32\sec\left(x-\frac{\pi}{6}\right)-1=3 for 0x2π0\le x\le 2\pi.

[3]
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C

For the general function fa,df_{a,d}, show that its range is yday\le d-a or yd+ay\ge d+a.

[2]
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D

member of the family has range y4y\le -4 or y2y\ge 2. Determine aa and dd.

[2]
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0

Question 43
HL • Paper 3
Hard
Calculator Permitted

For 0<a<π20<a<\frac{\pi}{2}, define ga(x)=sin(x+a)+sin(xa)g_a(x)=\sin(x+a)+\sin(x-a) for 0x2π0\le x\le 2\pi.

Three sample curves of g_a(x)=2cos(a)sin x.
A

Use compound angle identities to rewrite ga(x)g_a(x).

I.

Show that ga(x)=2cosasinxg_a(x)=2\cos a\sin x.

[3]
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II.

State the amplitude and period of gag_a.

[2]
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B

For a=π6a=\frac{\pi}{6}, solve ga(x)=1g_a(x)=1 for 0x2π0\le x\le 2\pi.

[3]
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C

Determine the value of aa for which the equation ga(x)=1g_a(x)=1 has exactly one solution in the interval 0x2π0\le x\le 2\pi.

[3]
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0

Question 44
HL • Paper 3
Hard
Calculator Permitted

In triangle ABCABC, side lengths aa, bb and cc are opposite angles AA, BB and CC respectively. Let A=40A=40^\circ and a=8 cma=8\ \text{cm}. The side bb may vary.

A labelled ambiguous-case triangle diagram with the point $A$, point $C$, and ray $AC$ fixed so that the angle at $A$ is $40^\circ$. Show the two possible points $B$ and $B'$ on the ray from $A$ for the same $b=AC$, with $BC=B'C=a=8\ \text{cm}$, and label the different lengths $c=AB$ and $c'=AB'$.
A

When b=10 cmb=10\ \text{cm}, find the two possible values of angle BB.

[3]
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B

For b=10 cmb=10\ \text{cm}, find the two possible values of cc.

[3]
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C

Determine the values of bb for which two different triangles are possible.

[3]
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D

Describe what happens geometrically when b=8sin40b=\frac{8}{\sin40^\circ}.

[2]
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0

Question 45
HL • Paper 3
Hard
Calculator Permitted

The temperature TT degrees Celsius in a greenhouse during one day is modelled by T(t)=d+acos(b(tc))T(t)=d+a\cos(b(t-c)), where 0t240\le t\le 24 is the time in hours after midnight and a>0a>0, b>0b>0, and 0c<240\le c<24. The maximum temperature is 28C28^\circ\text{C} at t=15t=15, and the minimum temperature is 16C16^\circ\text{C} at t=3t=3. The model has period 2424 hours.

Greenhouse temperature over one day.
A

Determine three parameters in the model.

I.

Find aa and dd.

[3]
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II.

Find bb.

[2]
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B

Find cc for this model.

[3]
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C

Find the first time after midnight when the model predicts 25C25^\circ\text{C}.

[2]
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D

Find the rate of change of temperature at the time found in part (c), and interpret its sign.

[2]
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0

Question 46
HL • Paper 1
Hard
Non Calculator

This question uses compound angle identities. Let

F(x)=3cosxsinxF(x)=\sqrt3\cos x-\sin x
A
I.

Show that F(x)=2cos(x+π6)F(x)=2\cos\left(x+\dfrac{\pi}{6}\right).

[3]
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II.

Find the maximum value of F(x)F(x).

[2]
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B

Solve F(x)=1F(x)=1 for 0x2π0\leq x\leq2\pi.

[4]
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C
I.

Find the exact value of F(7π12)F\left(\dfrac{7\pi}{12}\right).

[2]
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II.

Determine the values of kk for which F(x)=kF(x)=k has no solution. Give your answer in interval notation.

[2]
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0

Question 47
HL • Paper 1
Hard
Non Calculator

Let 0<x<π20<x<\dfrac{\pi}{2} and let t=tanxt=\tan x.

A
I.

Use the compound angle formula for tangent to derive tan2x=2t1t2\tan2x=\dfrac{2t}{1-t^2}, where t1t\ne1.

[3]
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II.

Explain why t>0t>0.

[2]
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B

Solve tan2x=3tanx\tan2x=3\tan x for 0<x<π20<x<\dfrac{\pi}{2}, excluding values for which tan2x\tan2x is undefined.

[4]
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C
I.

For x=π6x=\dfrac{\pi}{6}, find the exact value of tan(2x+π4)\tan\left(2x+\dfrac{\pi}{4}\right).

[2]
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II.

Justify why x=π4x=\dfrac{\pi}{4} is not a solution to the equation in part (b).

[2]
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0

Question 48
HL • Paper 1
Hard
Non Calculator

For 0x2π0\leq x\leq2\pi, define

f(x)=sin(π+x)+sin(πx)2cos(x)f(x)=\sin(\pi+x)+\sin(\pi-x)-2\cos(-x)
A
I.

Use symmetry properties to simplify f(x)f(x).

[3]
Write your answer here...
II.

State the range of ff.

[1]
Write your answer here...
B

Solve f(x)=1f(x)=1 for 0x2π0\leq x\leq2\pi.

[3]
Write your answer here...
C
I.

Prove that f(2πx)=f(x)f(2\pi-x)=f(x) for all xx in the domain.

[3]
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II.

Interpret this result as a symmetry of the graph of y=f(x)y=f(x) on 0x2π0\leq x\leq2\pi.

[2]
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0

Question 49
HL • Paper 1
Hard
Non Calculator

Consider the function

g(x)=2sec(xπ3)1g(x)=2\sec\left(x-\frac{\pi}{3}\right)-1

for 0x2π0\leq x\leq2\pi.

A
I.

Find the equations of the vertical asymptotes of the graph of y=g(x)y=g(x) in the given interval.

[3]
Write your answer here...
II.

State the range of gg on its domain.

[2]
Write your answer here...
B

Solve g(x)=3g(x)=3 for 0x2π0\leq x\leq2\pi.

[4]
Write your answer here...
C
I.

Find the exact value of g(π3)g\left(\dfrac{\pi}{3}\right).

[1]
Write your answer here...
II.

On the interval π3x<5π6\dfrac{\pi}{3}\leq x<\dfrac{5\pi}{6}, define the inverse branch g1g^{-1}. Find g1(5)g^{-1}(5).

[3]
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0

Question 50
HL • Paper 2
Hard
Calculator Permitted

Let

g(x)=arctanx+arctan(1x),xRg(x)=\arctan x+\arctan(1-x),\quad x\in\mathbb{R}
Graph of g(x)=arctan x+arctan(1-x) on a wide interval.
A
I.

Show that

tan(g(x))=1x2x+1\tan(g(x))=\frac{1}{x^2-x+1}
[3]
Write your answer here...
II.

Explain why g(x)>0g(x)>0 for all real xx.

[1]
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B

Solve g(x)=π4g(x)=\dfrac{\pi}{4}.

[3]
Write your answer here...
C

Use a GDC to determine the maximum value of g(x)g(x) and the value of xx at which it occurs.

[2]
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D

Find the two solutions of g(x)=0.800g(x)=0.800.

[2]
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0

Question 51
HL • Paper 2
Hard
Calculator Permitted

Let

F(x)=tan(2x)3tanxF(x)=\tan(2x)-3\tan x

where 0x<2π0\leq x<2\pi and both terms are defined.

Graph of y = tan(2x) - 3 tan x on 0≤x<2π.
A
I.

Show that, for u=tanxu=\tan x,

F(x)=u(3u21)1u2F(x)=\frac{u(3u^2-1)}{1-u^2}
[4]
Write your answer here...
B

Hence solve F(x)=0F(x)=0 for 0x<2π0\leq x<2\pi.

[4]
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C

Find all values of xx in 0x<2π0\leq x<2\pi for which F(x)=4F(x)=4.

[3]
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0

Question 52
HL • Paper 2
Hard
Calculator Permitted

An alternating voltage is modelled by

V(t)=8sin(50t)6cos(50t),0t0.200V(t)=8\sin(50t)-6\cos(50t),\quad 0\leq t\leq0.200

where tt is measured in seconds and VV is measured in volts.

Sinusoidal voltage graph over 0 to 0.200 s with V=7 line.
A
I.

Show that V(t)V(t) can be written in the form

V(t)=10sin(50tα)V(t)=10\sin(50t-\alpha)

where 0<α<π20<\alpha<\dfrac{\pi}{2}.

[4]
Write your answer here...
II.

Find the period of the voltage. Give your answer in seconds.

[1]
Write your answer here...
B

Find all times in 0t0.2000\leq t\leq0.200 for which V(t)=7V(t)=7. If you did not obtain the form in part (a), use V(t)=10sin(50t0.644)V(t)=10\sin(50t-0.644).

[4]
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C

Determine the total length of time during 0t0.2000\leq t\leq0.200 for which V(t)>7V(t)>7.

[3]
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D

Find the first time after t=0t=0 at which the voltage is increasing at its greatest possible rate.

[1]
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0

Question 53
HL • Paper 3
Hard
Calculator Permitted

For k>0k>0, define Fk(x)=arctanx+arctan(kx)F_k(x)=\arctan x+\arctan(kx) for x0x\ge 0. This question investigates equations of the form Fk(x)=αF_k(x)=\alpha.

Family of curves F_k(x)=arctan x + arctan(kx) for selected positive k, with asymptote y=π.
A

Consider FkF_k for a fixed positive value of kk.

I.

State the range of FkF_k.

[2]
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II.

Show that FkF_k is increasing on x0x\ge 0.

[2]
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B

Solve F3(x)=π3F_3(x)=\frac{\pi}{3}, giving your answer exactly.

[4]
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C

Justify that for every α\alpha such that 0<α<π0<\alpha<\pi, the equation Fk(x)=αF_k(x)=\alpha has exactly one solution for x0x\ge 0.

[2]
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D

For 0<α<π20<\alpha<\frac{\pi}{2}, let t=tanαt=\tan\alpha. Find the solution of Fk(x)=αF_k(x)=\alpha in terms of kk and tt.

[2]
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0

Question 54
HL • Paper 3
Hard
Calculator Permitted

A line through the origin makes an angle θ\theta with the positive xx-axis, where tanθ=14\tan\theta=\frac{1}{4}. A sequence of gradients is defined by m0=tanθm_0=\tan\theta and mn+1=2mn1mn2m_{n+1}=\frac{2m_n}{1-m_n^2} when mn21m_n^2\ne 1.

A coordinate diagram showing several lines through the origin whose angles are successive doublings of an initial acute angle, with the corresponding gradients labelled m_0, m_1 and m_2.
A

Find the first two gradients in the sequence.

I.

Find m1m_1 exactly.

[2]
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II.

Find m2m_2 exactly.

[2]
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B

Show by induction that mn=tan(2nθ)m_n=\tan(2^n\theta) whenever all the terms involved are defined.

[3]
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C

Using technology, determine the least positive integer nn for which mn>10m_n>10.

[2]
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D

Interpret the result in part (c) geometrically.

[2]
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0

Question 55
HL • Paper 3
Hard
Calculator Permitted

For real kk, consider the equation 2sinx=k+cos2x2\sin x=k+\cos 2x on the interval 0x2π0\le x\le 2\pi.

Four sample curves comparing 2sin x with k + cos 2x.
A

Show that the equation can be written as 2sin2x+2sinx+k1=02\sin^2x+2\sin x+k-1=0.

[2]
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B

Solve the equation for k=0k=0.

[3]
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C

Determine the set of values of kk for which the equation has at least one solution.

[3]
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D

Determine the value of kk for which the equation has exactly three solutions in the interval 0x2π0\le x\le 2\pi.

[3]
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0

Question 56
HL • Paper 3
Hard
Calculator Permitted

For 0<r10<r\le 1, define fr(x)=arcsinx+arccos(rx)f_r(x)=\arcsin x+\arccos(rx). This question investigates how the chosen ranges of inverse trigonometric functions affect equations involving frf_r.

Selected curves of f_r(x)=arcsin x+arccos(rx) on [-1,1].
A

State the ranges of the two inverse functions used in frf_r.

[2]
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B

Show that f1(x)=π2f_1(x)=\frac{\pi}{2} for 1x1-1\le x\le 1.

[2]
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C

Solve f12(x)=2π3f_{\frac{1}{2}}(x)=\frac{2\pi}{3} exactly.

[4]
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D

Find the value of rr for which fr(1)=2π3f_r(1)=\frac{2\pi}{3}.

[2]
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0

Question 57
HL • Paper 3
Hard
Calculator Permitted

This question investigates the equation 4cos3x3cosx=124\cos^3x-3\cos x=\frac{1}{2} using compound angle identities.

Graphs of $y=\cos(3x)$ and $y=\frac{1}{2}$ on $0\le x\le 2\pi$, with the six intersection points marked. The horizontal line is at the positive level $y=0.5$; its y-axis tick label is $0.5$, not $-0.5$.
A

Derive a cubic expression for cos3x\cos 3x in terms of cosx\cos x.

[4]
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B

Hence solve 4cos3x3cosx=124\cos^3x-3\cos x=\frac{1}{2} for 0x2π0\le x\le 2\pi.

[4]
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C

Deduce the number of distinct real roots of 8t36t1=08t^3-6t-1=0.

[2]
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D

Find the three roots of 8t36t1=08t^3-6t-1=0 to 33 significant figures.

[2]
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0

Question 58
HL • Paper 3
Hard
Calculator Permitted

Let f(x)=tanx+tan(π3x)f(x)=\tan x+\tan\left(\frac{\pi}{3}-x\right) on the interval π6<x<π2-\frac{\pi}{6}<x<\frac{\pi}{2}, excluding any value where the function is undefined.

Curve of f(x)=tan x+tan(pi/3-x) on its domain.
A

Show that the graph of ff is symmetric about the vertical line x=π6x=\frac{\pi}{6}.

[1]
Write your answer here...
B

Let t=tanxt=\tan x. Show that f(x)=3(1+t2)1+3tf(x)=\frac{\sqrt{3}(1+t^2)}{1+\sqrt{3}t}.

[3]
Write your answer here...
C

Find the value of xx in 0xπ30\le x\le \frac{\pi}{3} for which f(x)f(x) is a minimum, and find this minimum value.

[3]
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D

Explain why f(x)f(x) is undefined at x=π6x=-\frac{\pi}{6}.

[2]
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E

Solve f(x)=4f(x)=4 on π6<x<π2-\frac{\pi}{6}<x<\frac{\pi}{2}.

[3]
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0

Question 59
HL • Paper 3
Hard
Calculator Permitted

A simplified sound wave is modelled by S(t)=sin(5t)+sin(7t)S(t)=\sin(5t)+\sin(7t) for 0tπ0\le t\le \pi. This question investigates the zeros of this type of combined wave.

Sound wave S(t) with envelope curves.
A

Use compound angle identities to show that S(t)=2sin(6t)costS(t)=2\sin(6t)\cos t.

[3]
Write your answer here...
B

Find all zeros of S(t)S(t) in the interval 0tπ0\le t\le \pi.

[3]
Write your answer here...
C

For an integer n2n\ge 2, define Sn(t)=sin((n1)t)+sin((n+1)t)S_n(t)=\sin((n-1)t)+\sin((n+1)t). Show that Sn(t)=2sin(nt)costS_n(t)=2\sin(nt)\cos t.

[3]
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D

Deduce the number of distinct zeros of Sn(t)S_n(t) in 0tπ0\le t\le \pi.

[3]
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0

Question 60
HL • Paper 3
Hard
Calculator Permitted

Consider f(x)=secx+cscxf(x)=\sec x+\csc x on the interval 0<x<π20<x<\frac{\pi}{2}.

Graph of y = sec x + csc x on 0 < x < π/2, showing a single minimum and steep growth near both ends.
A

Rewrite f(x)f(x) in terms of u=sinx+cosxu=\sin x+\cos x.

I.

Show that f(x)=sinx+cosxsinxcosxf(x)=\frac{\sin x+\cos x}{\sin x\cos x}.

[1]
Write your answer here...
II.

Let u=sinx+cosxu=\sin x+\cos x. Hence show that f(x)=2uu21f(x)=\frac{2u}{u^2-1}.

[3]
Write your answer here...
B

Find the range of possible values of uu on 0<x<π20<x<\frac{\pi}{2}.

[2]
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C

Determine the minimum value of f(x)f(x) and the value of xx where it occurs.

[4]
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D

Solve secx+cscx=4\sec x+\csc x=4 for 0<x<π20<x<\frac{\pi}{2}.

[3]
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0


Geometry & Shapes

Vectors