Clastify logo
Clastify logo
Exam prep
Exemplars
Review
HOT

Trigonometric Functions

Master IB Math AA Trigonometric Functions with notes created by examiners and strictly aligned with the syllabus.

IB Syllabus Requirements for Trigonometric Functions

3.5

Unit circle definitions, exact trigonometric values and the ambiguous sine rule

3.6

Pythagorean identity, double angle identities and relationships between trigonometric ratios

3.7

Circular functions, transformations and modelling

3.8

Trigonometric equations in finite intervals

3.5

UNIT CIRCLE DEFINITIONS, EXACT TRIGONOMETRIC VALUES AND THE AMBIGUOUS SINE RULE

Sine and cosine on the unit circle

A unit circle is a circle with centre at the origin and radius 11. Suppose the terminal arm of an angle θ\theta meets the circle at PP. The coordinates of PP are (cosθ,sinθ)(\cos \theta,\sin \theta), where θ\theta is measured anticlockwise from the positive xx-axis, usually in radians unless degrees are explicitly given.

Here, cosθ\cos \theta gives the xx-coordinate of PP, while sinθ\sin \theta gives its yy-coordinate. Unlike right-triangle SOHCAHTOA, this definition works for any angle, including angles larger than π2\frac{\pi}{2} and negative angles.

Image

The quadrant determines each sign. Both coordinates are positive in quadrant I. In quadrant II, xx is negative and yy is positive, so cosine is negative and sine is positive. Both are negative in quadrant III. In quadrant IV, cosine is positive and sine is negative. This explains the usual quadrant sign diagram.

Related positions on the unit circle produce related trig values. For example,

cosx=cos(x)\cos x=\cos(-x)

Reflecting a point in the xx-axis doesn’t change its xx-coordinate. Also,

sin(π+x)=sinx\sin(\pi+x)=-\sin x

since a rotation by π\pi moves a point to the opposite side of the circle. And

tan(3πx)=tanx\tan(3\pi-x)=-\tan x

because 3πx3\pi-x has the same tangent behaviour as πx\pi-x. Tangent is negative in quadrant II when the reference angle is xx.

Tangent and the gradient of a line

The tangent function is defined by

tanθ=sinθcosθ\tan \theta=\frac{\sin \theta}{\cos \theta}

where θ\theta is the angle and cosθ0\cos \theta \ne 0. Since sinθ\sin \theta is the vertical coordinate and cosθ\cos \theta is the horizontal coordinate, tangent compares vertical change with horizontal change.

For a straight line through the origin that makes an angle θ\theta with the positive xx-axis, the equation is

y=xtanθy=x\tan \theta

where xx is the horizontal coordinate and yy is the vertical coordinate. So tanθ\tan \theta is the gradient of the line. This connects trigonometry with coordinate geometry: angle and gradient are two ways to represent the same steepness.

Image

Exact values

You need to know the exact values of sine, cosine and tangent for 00, π6\frac{\pi}{6}, π4\frac{\pi}{4}, π3\frac{\pi}{3}, π2\frac{\pi}{2}, and their multiples. The first-quadrant values come from two special triangles: the 3030^\circ-6060^\circ-9090^\circ triangle and the 4545^\circ-4545^\circ-9090^\circ triangle.

For the first quadrant:

  • sin0=0\sin 0=0, sinπ6=12\sin \frac{\pi}{6}=\frac{1}{2}, sinπ4=12\sin \frac{\pi}{4}=\frac{1}{\sqrt{2}}, sinπ3=32\sin \frac{\pi}{3}=\frac{\sqrt{3}}{2}, sinπ2=1\sin \frac{\pi}{2}=1.
  • Cosine uses the same list in reverse order.
  • Tangent is sine divided by cosine, giving tanπ6=13\tan \frac{\pi}{6}=\frac{1}{\sqrt{3}}, tanπ4=1\tan \frac{\pi}{4}=1, and tanπ3=3\tan \frac{\pi}{3}=\sqrt{3}.

For multiples, don’t memorise a huge table. Find the reference angle first, then use the quadrant to decide the sign. For example, cos3π4=12\cos \frac{3\pi}{4}=-\frac{1}{\sqrt{2}} because 3π4\frac{3\pi}{4} lies in quadrant II and has reference angle π4\frac{\pi}{4}. Similarly, 210210^\circ lies in quadrant III with reference angle 3030^\circ, so tan210=33\tan 210^\circ=\frac{\sqrt{3}}{3}. Exact trig values with reference-angle examples

θ\theta / radθ\theta / °sinθ\sin\thetacosθ\cos\thetatanθ\tan\thetaReference angle / quadrant
00010x-axis
π/6\pi/63012\frac{1}{2}32\frac{\sqrt{3}}{2}13\frac{1}{\sqrt{3}}QI
π/4\pi/44512\frac{1}{\sqrt{2}}12\frac{1}{\sqrt{2}}1QI
π/3\pi/36032\frac{\sqrt{3}}{2}12\frac{1}{2}3\sqrt{3}QI
π/2\pi/29010undefinedy-axis
3π/43\pi/413512\frac{1}{\sqrt{2}}12-\frac{1}{\sqrt{2}}1-1Ref. π/4\pi/4, QII
7π/67\pi/621012-\frac{1}{2}32-\frac{\sqrt{3}}{2}33\frac{\sqrt{3}}{3}Ref. π/6\pi/6, QIII

The ambiguous case of the sine rule

The ambiguous case occurs in a non-right triangle when the sine rule gives two possible triangles, since two supplementary angles have the same sine. In symbols,

sinθ=sin(πθ)\sin \theta=\sin(\pi-\theta)

for angles inside a triangle.

The sine rule is

asinA=bsinB=csinC\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}

where AA, BB and CC are the angles of a triangle, and aa, bb and cc are their opposite side lengths, all measured in the same length unit. The ambiguous case can arise when two sides and a non-included acute angle are given, especially if the side opposite the given angle is the shorter of the two given sides.

Use this routine: calculate the angle with the sine rule, check its supplement, then see whether the triangle angle sum allows that second value. The largest angle must also be opposite the longest side. This check rules out many impossible second answers.

Image

Historically, sine as a function of an angle appears explicitly in Indian mathematics, including work associated with Aryabhata. Trigonometry did not arrive fully formed from one place; different cultures shaped the representation and language now treated as standard mathematics.

3.6

PYTHAGOREAN IDENTITY, DOUBLE ANGLE IDENTITIES AND RELATIONSHIPS BETWEEN TRIGONOMETRIC RATIOS

The Pythagorean identity

A trigonometric identity is an equation involving trigonometric functions that holds for every angle where both sides are defined. The most important identity in this part of the course is

cos2θ+sin2θ=1\cos^2 \theta+\sin^2 \theta=1

It comes directly from Pythagoras on the unit circle. Since the point (cosθ,sinθ)(\cos \theta,\sin \theta) is one unit from the origin, its coordinates must satisfy x2+y2=1x^2+y^2=1.

Image

This identity lets you move between sine and cosine without calculating the angle. For example, if sinθ=35\sin \theta=\frac{3}{5}, then

cos2θ=1(35)2=1625\cos^2 \theta=1-\left(\frac{3}{5}\right)^2=\frac{16}{25}

so cosθ=±45\cos \theta=\pm\frac{4}{5}. The sign matters and depends on the quadrant. Cosine is negative when the angle lies in quadrant II, while it is positive in quadrant I.

Double angle identities for sine and cosine

The double angle identities express a trigonometric function of twice an angle using functions of the original angle. You should know

sin2θ=2sinθcosθ\sin 2\theta=2\sin \theta\cos \theta

and

cos2θ=cos2θsin2θ\cos 2\theta=\cos^2 \theta-\sin^2 \theta

By using cos2θ+sin2θ=1\cos^2 \theta+\sin^2 \theta=1, you can also write the cosine double angle identity as

cos2θ=2cos2θ1\cos 2\theta=2\cos^2 \theta-1

or

cos2θ=12sin2θ\cos 2\theta=1-2\sin^2 \theta

All three versions of cos2θ\cos 2\theta are equivalent. Usually, though, one form fits the question better than the others. For an equation containing only sine, choose 12sin2θ1-2\sin^2 \theta. For one containing only cosine, use 2cos2θ12\cos^2 \theta-1.

Dynamic graphing packages help you check these identities visually. Compare sin2x\sin 2x with 2sinxcosx2\sin x\cos x, or plot the three forms of cos2x\cos 2x. Their graphs lie exactly on top of each other. This gives visual evidence of the identity rather than a proof by itself, but it’s a useful way to build confidence in the algebra.

Image

Relationships between trigonometric ratios

The basic relationship

tanθ=sinθcosθ\tan \theta=\frac{\sin \theta}{\cos \theta}

where cosθ0\cos \theta \ne 0, allows you to find possible tangent values from information about sine and cosine. Use it alongside the Pythagorean identity and the signs for each quadrant.

If sinθ\sin \theta is known but θ\theta is not, begin by finding the possible values of cosθ\cos \theta from cos2θ=1sin2θ\cos^2 \theta=1-\sin^2 \theta. Then divide. When no quadrant is given, tangent may have more than one possible value. If the angle is stated to be acute, sine and cosine are both positive, so the ambiguity disappears.

A common neat application is finding sin2x\sin 2x without finding xx. If cosx=34\cos x=\frac{3}{4} and xx is acute, then

sinx=1(34)2=74\sin x=\sqrt{1-\left(\frac{3}{4}\right)^2}=\frac{\sqrt{7}}{4}

and therefore

sin2x=2sinxcosx=2(74)(34)=378\sin 2x=2\sin x\cos x=2\left(\frac{\sqrt{7}}{4}\right)\left(\frac{3}{4}\right)=\frac{3\sqrt{7}}{8}

Pay attention to the phrase without finding xx. It isn’t a trick; it is the purpose of using identities. They change the representation without bringing in unnecessary rounded angle values.

3.7

CIRCULAR FUNCTIONS, TRANSFORMATIONS AND MODELLING

Circular functions and their graphs

A circular function is a trigonometric function with an input interpreted as an angle on the unit circle. This section covers sinx\sin x, cosx\cos x and tanx\tan x. Here, xx is the input angle and is measured in radians unless the question specifies degrees.

A periodic function repeats its output values after a fixed horizontal interval. Both sine and cosine have period 2π2\pi, so

sin(x+2π)=sinx\sin(x+2\pi)=\sin x

and

cos(x+2π)=cosx\cos(x+2\pi)=\cos x

The period of tangent is π\pi. Therefore,

tan(x+π)=tanx\tan(x+\pi)=\tan x

Over one full period, the sine graph starts at 00, rises to 11, returns to 00, falls to 1-1, and comes back to 00. Cosine starts at 11 and has the same wave shape, shifted left by π2\frac{\pi}{2}. Tangent looks different. It increases through the origin, with vertical asymptotes at values such as x=π2x=-\frac{\pi}{2}, x=π2x=\frac{\pi}{2} and x=3π2x=\frac{3\pi}{2}.

Image

Amplitude, period and composite sine functions

A transformed sine function is usually written as

f(x)=asin(b(x+c))+df(x)=a\sin(b(x+c))+d

Here, xx is the input angle or time-like variable, while f(x)f(x) is the output value. The value aa sets the vertical scale, bb is the horizontal frequency factor, cc controls horizontal translation, and dd gives the vertical translation. These quantities are unitless in pure trigonometry. In a modelling context, xx and f(x)f(x) use the units stated in the problem.

The amplitude measures the distance from the midline to either a maximum or a minimum. For f(x)=asin(b(x+c))+df(x)=a\sin(b(x+c))+d, it is a|a|. When the maximum and minimum values are known, use

amplitude=maximum valueminimum value2\text{amplitude}=\frac{\text{maximum value}-\text{minimum value}}{2}

The period is the horizontal length of one complete cycle. For this function,

period=2πb\text{period}=\frac{2\pi}{|b|}

Its midline is y=dy=d. The maximum and minimum values give

d=maximum value+minimum value2d=\frac{\text{maximum value}+\text{minimum value}}{2}

Watch the sign of cc. In sin(b(x+c))\sin(b(x+c)), a positive cc shifts the graph left by cc. Many textbooks instead use asin(b(xc))+da\sin(b(x-c))+d; in that form, positive cc shifts the graph right. Read the brackets rather than relying on memory.

Transformations

Trigonometric graphs follow the same transformation rules as other functions. Moving from y=sinxy=\sin x to y=3sin2xy=3\sin 2x, the outside factor 33 produces a stretch by scale factor 33 in the yy direction. The factor 22 inside the angle produces a stretch by scale factor 12\frac{1}{2} in the xx direction. The transformed graph has amplitude 33 and period π\pi.

Image

Consider the function

g(x)=1sin(x+π2)g(x)=1-\sin\left(x+\frac{\pi}{2}\right)

The negative sign reflects the sine curve in the xx-axis. Inside the brackets, +π2+\frac{\pi}{2} shifts it left by π2\frac{\pi}{2}, while the outside +1+1 shifts it up by 11. These are the same graph transformations used for functions.

Real-life contexts

Repeated motion can often be modelled with trigonometric functions. Examples include tide height, a point on a Ferris wheel, simple harmonic motion, and periodic sound waves in music. Each parameter has a clear meaning: amplitude is half the total variation, period is the length of one full cycle, and vertical shift gives the central value.

Suppose a tide ranges from 77 metres to 1515 metres. Its amplitude is 44 metres and its midline is 1111 metres. If one cycle takes 1212 hours, then 2πb=12\frac{2\pi}{|b|}=12, giving b=π6b=\frac{\pi}{6} when time is measured in hours. One possible cosine model is

h(t)=4cos(π6t)+11h(t)=4\cos\left(\frac{\pi}{6}t\right)+11

where tt is the time in hours after a chosen starting time, and h(t)h(t) is the water depth in metres. Units matter here: π6\frac{\pi}{6} means radians per hour.

Image

Regression technology may produce a sinusoidal model in an algebraic form different from asin(b(x+c))+da\sin(b(x+c))+d. The model isn’t wrong, but its parameters may need to be rewritten or interpreted carefully before you compare it with the syllabus form.

3.8

TRIGONOMETRIC EQUATIONS IN FINITE INTERVALS

Why the interval matters

A trigonometric equation is an equation in which the unknown appears inside a trigonometric function. Trigonometric functions are periodic, so most trig equations have infinitely many solutions when no interval is given. In this syllabus, you solve them over a finite interval, such as 0x2π0\le x\le 2\pi or 0x1800^\circ\le x\le 180^\circ. General solutions are not required here.

Assume radians on examination papers unless the question clearly uses degrees. An interval in radians needs an answer in radians; an interval in degrees needs an answer in degrees. Don’t switch between them halfway through your solution.

Solving analytically

A clean analytic method is:

  1. Isolate the trigonometric expression if possible.
  2. Find the reference angle or principal value.
  3. Use the unit circle or graph to find all solutions in the stated finite interval.
  4. Check endpoints if the interval includes them.

For example, start with

2sinx=12\sin x=1

which gives sinx=12\sin x=\frac{1}{2}. On 0x2π0\le x\le 2\pi, sine is positive in quadrants I and II. Therefore,

x=π6,5π6x=\frac{\pi}{6},\frac{5\pi}{6}

If the equation contains a multiple or shifted angle, solve for the complete inside expression first. For

2tan(3(x4))=12\tan(3(x-4))=1

set

u=3(x4)u=3(x-4)

Convert the given interval for xx to the corresponding interval for uu, then solve tanu=12\tan u=\frac{1}{2} within that interval. Finally, convert back using x=u3+4x=\frac{u}{3}+4. Doing this helps you avoid missing repeated solutions.

Solving graphically

For a graphical solution, plot both sides and locate their intersections within the given interval. With

2sinx=12\sin x=1

graph y=2sinxy=2\sin x and y=1y=1. The solutions are the xx-coordinates of the intersection points. This method is useful when rearranging the equation is awkward, but the interval and angle mode still need to be correct.

Image

Equations that become quadratics

Some trig equations can be rewritten as quadratic equations in sinx\sin x, cosx\cos x or tanx\tan x. Temporarily treat the trigonometric function as one variable.

For example,

2sin2x+sinx=02\sin^2 x+\sin x=0

is easier to read as a quadratic in sinx\sin x:

sinx(2sinx+1)=0\sin x(2\sin x+1)=0

So sinx=0\sin x=0 or sinx=12\sin x=-\frac{1}{2}. From there, find every value of xx in the finite interval.

A less obvious example is

2sinx=cos2x2\sin x=\cos 2x

Use cos2x=12sin2x\cos 2x=1-2\sin^2 x to obtain

2sinx=12sin2x2\sin x=1-2\sin^2 x

then rearrange it into a quadratic in sinx\sin x. Reject impossible values such as sinx=32\sin x=\frac{3}{2}, since sine and cosine values must lie between 1-1 and 11.

When an equation contains both sine and cosine, look for an identity that rewrites everything using one trig function. This is where the double angle identities from section 3.6 earn their keep.

3.9

RECIPROCAL TRIGONOMETRIC RATIOS AND INVERSE TRIGONOMETRIC FUNCTIONS

HL

Reciprocal trigonometric ratios

A reciprocal trigonometric ratio is a trigonometric function formed by taking the reciprocal of sine, cosine or tangent. There are three such ratios:

secθ=1cosθ\sec \theta=\frac{1}{\cos \theta}
cscθ=1sinθ\csc \theta=\frac{1}{\sin \theta}

and

cotθ=1tanθ\cot \theta=\frac{1}{\tan \theta}

Some resources use cosec instead of csc\csc; both mean the reciprocal of sine.

Their graphs have vertical asymptotes wherever the original function equals zero. For instance, secx\sec x has vertical asymptotes where cosx=0\cos x=0, while cscx\csc x has them where sinx=0\sin x=0. Reciprocal trig ratios and asymptotes

ReciprocalDefinitionWhere original is 0Vertical asymptotes
secθ\sec\theta1cosθ\dfrac{1}{\cos\theta}cosθ=0\cos\theta=0θ=π2+kπ\theta=\dfrac{\pi}{2}+k\pi
cscθ\csc\theta1sinθ\dfrac{1}{\sin\theta}sinθ=0\sin\theta=0θ=kπ\theta=k\pi
cotθ\cot\theta1tanθ\dfrac{1}{\tan\theta}tanθ=0\tan\theta=0θ=kπ\theta=k\pi

Pythagorean identities with reciprocal ratios

Begin with

sin2θ+cos2θ=1\sin^2 \theta+\cos^2 \theta=1

and divide each term by cos2θ\cos^2 \theta. This gives

tan2θ+1=sec2θ\tan^2 \theta+1=\sec^2 \theta

It is usually written as

1+tan2θ=sec2θ1+\tan^2 \theta=\sec^2 \theta

Dividing the original identity by sin2θ\sin^2 \theta instead gives

1+cot2θ=csc2θ1+\cot^2 \theta=\csc^2 \theta

These identities come from the same unit-circle relationship, expressed using reciprocal ratios. In proofs, they often provide the quickest way to replace 1+tan2θ1+\tan^2 \theta or 1+cot2θ1+\cot^2 \theta with one squared reciprocal function.

Inverse trigonometric functions

An inverse trigonometric function returns an angle from a trigonometric ratio after the original trigonometric function has been restricted to a one-to-one domain. The restriction is necessary because sinx\sin x, cosx\cos x and tanx\tan x repeat, so without it they fail the horizontal line test.

The inverse sine function is

f(x)=arcsinxf(x)=\arcsin x

Its domain is [1,1][-1,1], and its range is [π2,π2]\left[-\frac{\pi}{2},\frac{\pi}{2}\right].

The inverse cosine function is

f(x)=arccosxf(x)=\arccos x

Its domain is [1,1][-1,1], and its range is [0,π][0,\pi].

The inverse tangent function is

f(x)=arctanxf(x)=\arctan x

Its domain is R\mathbb{R}, and its range is (π2,π2)\left(-\frac{\pi}{2},\frac{\pi}{2}\right). The endpoints aren’t included because the graph has horizontal asymptotes there. Inverse trig branches, domains and ranges.

FunctionDomainRange [rad]Branch / graph note
y=arcsinxy=\arcsin x[1,1][-1,1][π2,π2]\left[-\frac{\pi}{2},\frac{\pi}{2}\right]Chosen one-to-one branch
y=arccosxy=\arccos x[1,1][-1,1][0,π][0,\pi]Chosen one-to-one branch
y=arctanxy=\arctan xR\mathbb{R}(π2,π2)\left(-\frac{\pi}{2},\frac{\pi}{2}\right)Horizontal asymptotes at y=±π2y=\pm\frac{\pi}{2}

These ranges are conventional, but they aren’t arbitrary. Each one selects a branch on which the original trigonometric function is one-to-one. The chosen range also determines the value we state. For example, arcsin(12)\arcsin\left(\frac{1}{2}\right) is π6\frac{\pi}{6} rather than 5π6\frac{5\pi}{6} because π6\frac{\pi}{6} lies in the selected range for arcsine.

3.10

COMPOUND ANGLE IDENTITIES AND THE DOUBLE ANGLE IDENTITY FOR TANGENT

HL

Compound angle identities

A compound angle identity rewrites a trigonometric function of a sum or difference of angles using the trigonometric functions of the separate angles. For angles AA and BB, the sine identities are

sin(A+B)=sinAcosB+cosAsinB\sin(A+B)=\sin A\cos B+\cos A\sin B

and

sin(AB)=sinAcosBcosAsinB\sin(A-B)=\sin A\cos B-\cos A\sin B

For cosine, the identities are

cos(A+B)=cosAcosBsinAsinB\cos(A+B)=\cos A\cos B-\sin A\sin B

and

cos(AB)=cosAcosB+sinAsinB\cos(A-B)=\cos A\cos B+\sin A\sin B

The tangent identities are

tan(A+B)=tanA+tanB1tanAtanB\tan(A+B)=\frac{\tan A+\tan B}{1-\tan A\tan B}

and

tan(AB)=tanAtanB1+tanAtanB\tan(A-B)=\frac{\tan A-\tan B}{1+\tan A\tan B}

provided the denominators are not zero and the tangent values involved are defined.

You can use these identities to find exact values for angles formed from standard angles. For instance, 165165^\circ can be written as 120+45120^\circ+45^\circ. Its tangent can therefore be found exactly with the compound tangent identity instead of using a calculator decimal.

Deriving double angle identities

A double angle identity is a compound angle identity in which both angles are the same.

sin(θ+θ)=sinθcosθ+cosθsinθ\sin(\theta+\theta)=\sin \theta\cos \theta+\cos \theta\sin \theta

This gives

sin2θ=2sinθcosθ\sin 2\theta=2\sin \theta\cos \theta

Next

cos(θ+θ)=cosθcosθsinθsinθ\cos(\theta+\theta)=\cos \theta\cos \theta-\sin \theta\sin \theta

which gives

cos2θ=cos2θsin2θ\cos 2\theta=\cos^2 \theta-\sin^2 \theta

The other two forms of cos2θ\cos 2\theta follow from sin2θ+cos2θ=1\sin^2 \theta+\cos^2 \theta=1.

Double angle identity for tangent

Set A=B=θA=B=\theta in the compound tangent identity to get

where tanθ\tan \theta is defined and 1tan2θ01-\tan^2 \theta\ne 0. This denominator condition matters. If it is zero, the angle 2θ2\theta corresponds to a tangent asymptote.

Compound angle identities also provide some of the algebraic background for De Moivre's theorem, which appears later in complex numbers. The same ideas underlie phase shifts in sinusoidal voltage and the angle relationships used in triangulation, including GPS-style positioning.

3.11

SYMMETRY PROPERTIES OF TRIGONOMETRIC FUNCTIONS

HL

Symmetry from the unit circle and the graphs

Trigonometric symmetry isn't a collection of unrelated rules. It follows from reflections on the unit circle and the repeating shapes of trigonometric graphs. For an angle θ\theta,

sin(πθ)=sinθ\sin(\pi-\theta)=\sin \theta

The two angles are mirror images in the yy-axis, so their yy-coordinates are equal.

Also,

cos(πθ)=cosθ\cos(\pi-\theta)=-\cos \theta

Here, reflection gives the point the opposite xx-coordinate.

Dividing sine by cosine gives

tan(πθ)=tanθ\tan(\pi-\theta)=-\tan \theta

Quadrant II reference-angle identities on the unit circle.

AngleUnit-circle pointSineCosineTangent
θ\theta(cosθ,sinθ)(\cos\theta,\sin\theta)sinθ\sin\thetacosθ\cos\thetatanθ\tan\theta
πθ\pi-\theta(cosθ,sinθ)(-\cos\theta,\sin\theta)sinθ\sin\thetacosθ-\cos\thetatanθ-\tan\theta

These are the quadrant-II forms of the reference-angle relationships. They link back to the unit circle definitions in section 3.5 and the compound angle identities in section 3.10. For example, the compound identity for sin(AB)\sin(A-B) can also be used to prove sin(πθ)\sin(\pi-\theta).

Odd and even symmetry

An even function satisfies f(x)=f(x)f(-x)=f(x) for every xx in its domain. Cosine is even:

cos(x)=cosx\cos(-x)=\cos x

An odd function satisfies f(x)=f(x)f(-x)=-f(x) for every xx in its domain. Sine and tangent are odd:

sin(x)=sinx\sin(-x)=-\sin x

and

tan(x)=tanx\tan(-x)=-\tan x

On a graph, even symmetry appears as reflection in the yy-axis. Odd symmetry gives rotational symmetry of 180180^\circ about the origin. So the cosine graph is balanced on either side of the yy-axis, while sine and tangent pass through the origin and show matching opposite behaviour on each side.

Image

Periodicity and repeated solutions

Symmetry makes equations easier to solve because one known solution, together with periodicity, often produces others. For example, if sinx=k\sin x=k has one solution in quadrant I, the identity sin(πθ)=sinθ\sin(\pi-\theta)=\sin \theta may give another in quadrant II. Further solutions then repeat every 2π2\pi.

A trigonometric equation can therefore have infinitely many discrete solutions on the real line but only finitely many within a finite interval. There’s no contradiction: periodicity produces endless repeats, yet each repeat is a separate point rather than a continuous block of solutions. Simple harmonic motion graphs in physics use exactly this repeated structure.

Were those notes helpful?

geometry-and-shapes Geometry & Shapes

vectors Vectors