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Vectors

Practice exam-style IB Math AA questions for Vectors, aligned with the syllabus and grouped by topic.

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Question 1
HL • Paper 1
Easy
Non Calculator
HL • Paper 1
Easy
Non Calculator

The points AA and BB have position vectors

OA⃗=(−123),OB⃗=(3−15)\vec{OA}=\begin{pmatrix}-1\\2\\3\end{pmatrix},\qquad \vec{OB}=\begin{pmatrix}3\\-1\\5\end{pmatrix}
A

AB⃗\vec{AB} and ∣AB⃗∣|\vec{AB}|.

[2]
B

a unit vector in the direction from BB to AA.

[2]
C

The point PP lies on ABAB such that AP:PB=3:1AP:PB=3:1. the coordinates of PP.

[1]
Question 2
HL • Paper 1
Easy
Non Calculator
HL • Paper 1
Easy
Non Calculator

The line LL passes through the points A(2,−1,3)A(2,-1,3) and B(5,−1,−1)B(5,-1,-1).

A

a vector equation of LL.

[2]
B

Write LL in Cartesian form.

[2]
C

whether the point C(11,−1,−9)C(11,-1,-9) lies on LL.

[1]
Question 3
HL • Paper 2
Easy
Calculator Permitted
HL • Paper 2
Easy
Calculator Permitted

The points AA and BB have coordinates A(−2,1,4)A(-2,1,4) and B(4,−3,7)B(4,-3,7). A point CC lies on the ray from AA through BB, and AC=10AC=10.

A

AB→\overrightarrow{AB} and ∣AB→∣|\overrightarrow{AB}|.

[2]
B

the unit vector in the direction of AB→\overrightarrow{AB}.

[1]
C

the coordinates of CC.

[2]
Question 4
HL • Paper 2
Easy
Calculator Permitted
HL • Paper 2
Easy
Calculator Permitted

Consider the lines

L1:r=(3−14)+s(2−21),L2:r=(a51)+t(6−63)L_1:\mathbf{r}=\begin{pmatrix}3\\-1\\4\end{pmatrix}+s\begin{pmatrix}2\\-2\\1\end{pmatrix},\quad L_2:\mathbf{r}=\begin{pmatrix}a\\5\\1\end{pmatrix}+t\begin{pmatrix}6\\-6\\3\end{pmatrix}
A

why L1L_1 and L2L_2 are parallel or coincident.

[1]
B

the value of aa for which L1L_1 and L2L_2 are coincident.

[3]
C

the relationship between L1L_1 and L2L_2 when a=9a=9.

[1]

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Question 5
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Let

u=(2p−1),v=(p13)\mathbf{u}=\begin{pmatrix}2\\p\\-1\end{pmatrix},\qquad \mathbf{v}=\begin{pmatrix}p\\1\\3\end{pmatrix}
A

Given that u\mathbf{u} is perpendicular to v\mathbf{v}, pp.

[2]
B

For this value of pp, let θ\theta be the angle between u\mathbf{u} and a=(1−22)\mathbf{a}=\begin{pmatrix}1\\-2\\2\end{pmatrix}. the exact value of cos⁡θ\cos\theta.

[3]
Question 6
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Two particles PP and QQ move in three dimensions. At time tt seconds, their position vectors are

rP=(102)+t(2−11),rQ=(7−68)+t(−12−2)\mathbf{r}_P=\begin{pmatrix}1\\0\\2\end{pmatrix}+t\begin{pmatrix}2\\-1\\1\end{pmatrix},\qquad \mathbf{r}_Q=\begin{pmatrix}7\\-6\\8\end{pmatrix}+t\begin{pmatrix}-1\\2\\-2\end{pmatrix}

where t≥0t\geq 0.

A

the speed of each particle.

[2]
B

whether the particles collide. If they do, the time of collision.

[3]
Question 7
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Let

u=(12−1),v=(3−12)\mathbf{u}=\begin{pmatrix}1\\2\\-1\end{pmatrix},\qquad \mathbf{v}=\begin{pmatrix}3\\-1\\2\end{pmatrix}
A

u×v\mathbf{u}\times\mathbf{v}.

[2]
B

the area of the parallelogram with adjacent sides represented by u\mathbf{u} and v\mathbf{v}.

[1]
C

The points A(1,0,2)A(1,0,2), B(2,2,1)B(2,2,1) and C(4,−1,4)C(4,-1,4) are such that AB⃗=u\vec{AB}=\mathbf{u} and AC⃗=v\vec{AC}=\mathbf{v}. the area of triangle ABCABC.

[2]
Question 8
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The line LL and plane Π\Pi are given by

L:r=(12−1)+λ(112),Π:2x−y+2z=3L:\mathbf{r}=\begin{pmatrix}1\\2\\-1\end{pmatrix}+\lambda\begin{pmatrix}1\\1\\2\end{pmatrix},\qquad \Pi:2x-y+2z=3
A

the point of intersection of LL and Π\Pi.

[3]
B

Let ϕ\phi be the acute angle between LL and Π\Pi. the exact value of sin⁡ϕ\sin\phi.

[2]

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Question 9
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The plane Π\Pi and line LL are given by

Π:x+ay+2z=4\Pi:x+ay+2z=4 L:r=(201)+λ(1−1a),λ,a∈RL:\mathbf{r}=\begin{pmatrix}2\\0\\1\end{pmatrix}+\lambda\begin{pmatrix}1\\-1\\a\end{pmatrix},\qquad \lambda,a\in\mathbb{R}
A

the value of aa for which the direction of LL is parallel to Π\Pi.

[2]
B

For this value of aa, whether LL lies in Π\Pi or is parallel and distinct from Π\Pi.

[2]
Question 10
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Let

u=(2−13),v=(k41)\mathbf{u}=\begin{pmatrix}2\\-1\\3\end{pmatrix},\quad \mathbf{v}=\begin{pmatrix}k\\4\\1\end{pmatrix}

where k>0k>0. The angle between u\mathbf{u} and v\mathbf{v} is 1.101.10 radians.

A

u⋅v\mathbf{u}\cdot \mathbf{v} in terms of kk.

[1]
B

the value of kk.

[4]
Question 11
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The line L1L_1 passes through the points A(1,2,−1)A(1,2,-1) and B(4,−2,5)B(4,-2,5). The line L2L_2 has equation

r=(210)+t(12−2)\mathbf{r}=\begin{pmatrix}2\\1\\0\end{pmatrix}+t\begin{pmatrix}1\\2\\-2\end{pmatrix}
A

a vector equation for L1L_1.

[2]
B

Write L1L_1 in Cartesian form.

[2]
C

the acute angle between L1L_1 and L2L_2.

[2]
Question 12
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The lines L1L_1 and L2L_2 are given by

L1:r=(102)+λ(2−13),L2:r=(5m8)+μ(112)L_1:\mathbf{r}=\begin{pmatrix}1\\0\\2\end{pmatrix}+\lambda\begin{pmatrix}2\\-1\\3\end{pmatrix},\quad L_2:\mathbf{r}=\begin{pmatrix}5\\m\\8\end{pmatrix}+\mu\begin{pmatrix}1\\1\\2\end{pmatrix}
A

, if the lines intersect, then λ=2\lambda=2.

[2]
B

the value of mm for which the lines intersect.

[2]
C

the point of intersection when m=−2m=-2.

[1]

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Question 13
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The points AA, BB and CC have coordinates A(2,−1,0)A(2,-1,0), B(5,1,4)B(5,1,4) and C(0,3,2)C(0,3,2).

A

→AB×→AC\rightarrow{AB}\times \rightarrow{AC}.

[2]
B

the area of triangle ABCABC.

[2]
C

a unit vector perpendicular to the plane containing AA, BB and CC.

[2]
Question 14
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

A plane \i\i has vector equation

r=(12−3)+λ(210)+μ(−132)\mathbf{r}=\begin{pmatrix}1\\2\\-3\end{pmatrix}+\lambda\begin{pmatrix}2\\1\\0\end{pmatrix}+\mu\begin{pmatrix}-1\\3\\2\end{pmatrix}

The point P(k,1,0)P(k,1,0) lies on \i\i.

A

a normal vector to \i\i.

[2]
B

the Cartesian equation of \i\i.

[2]
C

kk.

[1]
Question 15
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The line LL and plane π\pi are given by

L:r=(2−14)+t(13−2),π:2x−y+z=7L:\mathbf{r}=\begin{pmatrix}2\\-1\\4\end{pmatrix}+t\begin{pmatrix}1\\3\\-2\end{pmatrix},\quad \pi:2x-y+z=7
A

the point where LL intersects π\pi.

[3]
B

the acute angle between LL and π\pi.

[2]
Question 16
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Consider the lines

L1:r=(12−1)+λ(2−13),L2:r=(31k)+μ(11−1)L_1:\mathbf{r}=\begin{pmatrix}1\\2\\-1\end{pmatrix}+\lambda\begin{pmatrix}2\\-1\\3\end{pmatrix},\qquad L_2:\mathbf{r}=\begin{pmatrix}3\\1\\k\end{pmatrix}+\mu\begin{pmatrix}1\\1\\-1\end{pmatrix}

where λ,μ,k∈R\lambda,\mu,k\in\mathbb{R}.

A

the two direction vectors are not parallel.

[1]
B

the value of kk for which L1L_1 and L2L_2 intersect.

[4]
C

the relationship between L1L_1 and L2L_2 when k≠2k\ne 2.

[1]

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Question 17
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The plane Π\Pi passes through the points A(1,0,−1)A(1,0,-1), B(2,3,0)B(2,3,0) and C(−1,1,2)C(-1,1,2).

A

two non-parallel direction vectors in Π\Pi.

[2]
B

a normal vector to Π\Pi.

[2]
C

a Cartesian equation of Π\Pi.

[2]
Question 18
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The planes Π1\Pi_1 and Π2\Pi_2 are given by

Π1:x+z=2\Pi_1:x+z=2 Π2:px+y+z=1\Pi_2:px+y+z=1

where p∈Rp\in\mathbb{R}. The acute angle between the planes is π4\dfrac{\pi}{4}.

A

the value of pp.

[4]
Question 19
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The line LL has equation

L:r=(1−12)+λ(21−1),λ∈RL:\mathbf{r}=\begin{pmatrix}1\\-1\\2\end{pmatrix}+\lambda\begin{pmatrix}2\\1\\-1\end{pmatrix},\qquad \lambda\in\mathbb{R}

The point PP has coordinates (0,3,1)(0,3,1). A plane Π\Pi contains LL and the point PP.

A

a vector in Π\Pi which is not parallel to LL.

[1]
B

a normal vector to Π\Pi.

[2]
C

a Cartesian equation of Π\Pi.

[2]
Question 20
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The planes Π1\Pi_1 and Π2\Pi_2 are given by

Π1:x+y+z=3\Pi_1:x+y+z=3 Π2:2x−y+z=1\Pi_2:2x-y+z=1

The planes intersect in the line LL.

A

a direction vector for LL.

[2]
B

one point on LL.

[2]
C

write a vector equation of LL.

[2]

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Question 21
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Two drones, AA and BB, move in straight lines. Their position vectors, in kilometres, tt hours after 09:00 are

rA=(140)+t(2−11),rB=(7−23)+t(−120)\mathbf{r}_A=\begin{pmatrix}1\\4\\0\end{pmatrix}+t\begin{pmatrix}2\\-1\\1\end{pmatrix},\quad \mathbf{r}_B=\begin{pmatrix}7\\-2\\3\end{pmatrix}+t\begin{pmatrix}-1\\2\\0\end{pmatrix}

where 0≤t≤40\leq t\leq 4.

Drone

Initial position vector / km

Velocity vector / km h−1\text{km h}^{-1}

A

(1,4,0)(1,4,0)

(2,−1,1)(2,-1,1)

B

(7,−2,3)(7,-2,3)

(−1,2,0)(-1,2,0)

A

rB−rA\mathbf{r}_B-\mathbf{r}_A in terms of tt.

[2]
B

the minimum distance between the drones during this time interval.

[3]
Question 22
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The planes \i1\i_1 and \i2\i_2 are given by

\i1:x+2y−kz=5,\i2:3x−y+2z=7\i_1:x+2y-kz=5,\quad \i_2:3x-y+2z=7

where k>1k>1. The acute angle between the planes is 1.101.10 radians.

A

normal vectors to \i1\i_1 and \i2\i_2.

[1]
B

kk.

[4]
Question 23
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The planes \i1\i_1 and \i2\i_2 are given by

\i1:x+2y−z=4,\i2:3x−y+2z=1\i_1:x+2y-z=4,\quad \i_2:3x-y+2z=1

The planes intersect in the line LL.

A

a direction vector for LL.

[2]
B

a vector equation for LL.

[3]
Question 24
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The points A(1,2,0)A(1,2,0), B(3,0,1)B(3,0,1) and C(0,1,4)C(0,1,4) lie in the plane Π\Pi. A point DD lies on the line through AA perpendicular to Π\Pi.

A
I.

AB⃗\vec{AB} and AC⃗\vec{AC}.

[2]
II.

a normal vector to Π\Pi.

[3]
B

a Cartesian equation of Π\Pi.

[3]
C

Given that AD=3146AD=3\sqrt{146} and that the zz-coordinate of DD is positive, the coordinates of DD.

[3]

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Question 25
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The line LL has equation r=(2−13)+λ(12−2)\mathbf r=\begin{pmatrix}2\\-1\\3\end{pmatrix}+\lambda\begin{pmatrix}1\\2\\-2\end{pmatrix}, λ∈R\lambda\in\mathbb R. The point PP has coordinates (5,0,1)(5,0,1).

A
I.

Let AA be a general point on LL. PA⃗\vec{PA} in terms of λ\lambda.

[2]
II.

the value of λ\lambda for which PAPA is perpendicular to LL.

[2]
B

the shortest distance from PP to LL.

[2]
C

The point RR lies on LL and PR=14PR=\sqrt{14}. the possible coordinates of RR.

[3]
Question 26
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The lines L1L_1 and L2L_2 are defined by L1:r=(102)+λ(21−1)L_1:\mathbf r=\begin{pmatrix}1\\0\\2\end{pmatrix}+\lambda\begin{pmatrix}2\\1\\-1\end{pmatrix} and L2:r=(3k1)+μ(1−12)L_2:\mathbf r=\begin{pmatrix}3\\k\\1\end{pmatrix}+\mu\begin{pmatrix}1\\-1\\2\end{pmatrix}, where k∈Rk\in\mathbb R.

A
I.

L1L_1 and L2L_2 are not parallel.

[1]
II.

the exact value of the cosine of the acute angle between L1L_1 and L2L_2.

[2]
B

the value of kk for which L1L_1 and L2L_2 intersect, and the point of intersection.

[4]
C

the relationship between L1L_1 and L2L_2 when k≠1k\ne1.

[1]
Question 27
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Two lines are given by L1:r=(012)+λ(12−1)L_1:\mathbf r=\begin{pmatrix}0\\1\\2\end{pmatrix}+\lambda\begin{pmatrix}1\\2\\-1\end{pmatrix} and L2:r=(103)+μ(12−1)L_2:\mathbf r=\begin{pmatrix}1\\0\\3\end{pmatrix}+\mu\begin{pmatrix}1\\2\\-1\end{pmatrix}, where λ,μ∈R\lambda,\mu\in\mathbb R.

A
I.

why the lines are parallel.

[1]
II.

the lines are distinct.

[2]
B

a Cartesian equation of the plane containing both L1L_1 and L2L_2.

[3]
C

the exact distance between L1L_1 and L2L_2.

[3]
Question 28
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Two inspection robots, AA and BB, move along straight paths inside a storage facility. Their position vectors, in metres, tt minutes after 10:00, are

rA=(210)+t(3−12),rB=(12−54)+t(−121)\mathbf{r}_A=\begin{pmatrix}2\\1\\0\end{pmatrix}+t\begin{pmatrix}3\\-1\\2\end{pmatrix},\qquad \mathbf{r}_B=\begin{pmatrix}12\\-5\\4\end{pmatrix}+t\begin{pmatrix}-1\\2\\1\end{pmatrix}

where 0≤t≤40\leq t\leq 4.

A
I.

the speed of each robot.

[2]
II.

the acute angle between the two paths.

[2]
B

Let D(t)D(t) be the distance between the robots at time tt. D(t)2=26t2−124t+152D(t)^2=26t^2-124t+152.

[3]
C

the minimum distance between the robots during the four-minute interval. whether they come within 22 metres of each other.

[3]

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Question 29
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

A triangular metal plate has vertices A(1,2,−1)A(1,2,-1), B(5,0,2)B(5,0,2) and C(2,6,1)C(2,6,1). A laser path is modelled by the infinite line

L:r=(875)+λ(−2−1−3)L:\mathbf{r}=\begin{pmatrix}8\\7\\5\end{pmatrix}+\lambda\begin{pmatrix}-2\\-1\\-3\end{pmatrix}
A
I.

AB⃗×AC⃗\vec{AB}\times\vec{AC}.

[2]
II.

the area of triangle ABCABC.

[2]
III.

a Cartesian equation of the plane containing the plate.

[1]
B

the point where the line LL meets the plane of the plate.

[3]
C

the acute angle between the line LL and the plate.

[2]
Question 30
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The line LL is given by

L:r=(1−23)+λ(21−1)L:\mathbf{r}=\begin{pmatrix}1\\-2\\3\end{pmatrix}+\lambda\begin{pmatrix}2\\1\\-1\end{pmatrix}

A plane π\pi contains LL and the point P(4,0,5)P(4,0,5).

A

two non-parallel direction vectors in π\pi.

[2]
B

the Cartesian equation of π\pi.

[3]
C

the acute angle between π\pi and the plane x+y−2z=0x+y-2z=0.

[2]
Question 31
HL • Paper 3
Medium
Calculator Permitted
HL • Paper 3
Medium
Calculator Permitted

A navigation system records three points in space, A(−6,2,−1)A(-6,2,-1), B(0,1,1)B(0,1,1) and C(−4,6,−2)C(-4,6,-2). A fourth point DD is to be chosen so that ABDCABDC is a parallelogram, with ABAB and ACAC as adjacent sides.

A
AI.

AB⃗\vec{AB} and AC⃗\vec{AC}.

[2]
AII.

the coordinates of DD.

[2]
B
B.

the diagonals of ABDCABDC bisect each other.

[2]
C

A point PP moves along the diagonal ADAD.

CI.

the value of the parameter tt for which P=A+tAD⃗P=A+t\vec{AD} is closest to the origin is 4374\frac{43}{74}.

[3]
CII.

the minimum distance from the origin to the diagonal ADAD. If you did not obtain t=4374t=\frac{43}{74}, use this value.

[1]
Question 32
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Two particles AA and BB move in straight lines. At time tt seconds, their position vectors are rA=(120)+t(2−11)\mathbf r_A=\begin{pmatrix}1\\2\\0\end{pmatrix}+t\begin{pmatrix}2\\-1\\1\end{pmatrix} and rB=(510)+t(−110)\mathbf r_B=\begin{pmatrix}5\\1\\0\end{pmatrix}+t\begin{pmatrix}-1\\1\\0\end{pmatrix}, where t≥0t\geq0.

A
I.

AB⃗\vec{AB} in terms of tt.

[2]
II.

AB2=14t2−28t+17AB^2=14t^2-28t+17.

[2]
B

the minimum distance between the particles and the time at which it occurs.

[3]
C

the values of tt for which AB=7AB=\sqrt7.

[3]

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Question 33
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

The planes Π1\Pi_1 and Π2\Pi_2 have equations Π1:x+2y−z=4\Pi_1:x+2y-z=4 and Π2:2x−y+z=0\Pi_2:2x-y+z=0. Their line of intersection is LL.

A
I.

a direction vector for LL.

[3]
II.

(1,1,−1)(1,1,-1) lies on LL.

[2]
B

a vector equation of LL.

[2]
C

the exact value of the cosine of the acute angle between Π1\Pi_1 and Π2\Pi_2.

[2]
D

the Cartesian equation of the plane which contains LL and the point Q(1,0,0)Q(1,0,0).

[3]
Question 34
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

The plane Π\Pi has vector equation r=(102)+s(11−1)+t(2−11)\mathbf r=\begin{pmatrix}1\\0\\2\end{pmatrix}+s\begin{pmatrix}1\\1\\-1\end{pmatrix}+t\begin{pmatrix}2\\-1\\1\end{pmatrix}, where s,t∈Rs,t\in\mathbb R. The line LL is given by r=(3−25)+λ(−12−1)\mathbf r=\begin{pmatrix}3\\-2\\5\end{pmatrix}+\lambda\begin{pmatrix}-1\\2\\-1\end{pmatrix}.

A
I.

a normal vector to Π\Pi.

[3]
II.

a Cartesian equation of Π\Pi.

[2]
B

the point of intersection of LL and Π\Pi.

[2]
C

the exact value of sin⁡ϕ\sin\phi, where ϕ\phi is the acute angle between LL and Π\Pi.

[2]
D

the Cartesian equation of the plane which contains LL and is perpendicular to Π\Pi.

[2]
Question 35
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

The points A(1,0,0)A(1,0,0), B(3,1,−1)B(3,1,-1), D(p,1,3)D(p,1,3) and CC form a parallelogram ABCDABCD, where C=B+D−AC=B+D-A.

A
I.

AB⃗\vec{AB} and AD⃗\vec{AD} in terms of pp.

[2]
II.

the value of pp for which ABCDABCD is a rectangle.

[2]
B

For p=2p=2, the area of ABCDABCD.

[3]
C

For p=2p=2, a Cartesian equation of the plane containing the rectangle.

[3]
Question 36
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

The plane Π\Pi has equation 2x−y+2z=52x-y+2z=5. The point PP has coordinates (4,1,2)(4,1,2).

A
I.

a vector equation of the line through PP perpendicular to Π\Pi.

[2]
II.

the coordinates of the foot HH of the perpendicular from PP to Π\Pi.

[2]
B

the distance from PP to Π\Pi.

[2]
C

The point P′P' is the reflection of PP in Π\Pi. the coordinates of P′P'.

[3]

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Question 37
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Two intersecting lines L1L_1 and L2L_2 pass through A(1,2,−1)A(1,2,-1). Their direction vectors are d1=(1−12)\mathbf d_1=\begin{pmatrix}1\\-1\\2\end{pmatrix} and d2=(21−1)\mathbf d_2=\begin{pmatrix}2\\1\\-1\end{pmatrix} respectively. The plane containing both lines is Π\Pi. The plane Σ\Sigma has equation x+y−z=0x+y-z=0.

A
I.

a normal vector to Π\Pi.

[2]
II.

a Cartesian equation of Π\Pi.

[2]
B

the exact value of the cosine of the acute angle between Π\Pi and Σ\Sigma.

[2]
C

a vector equation of the line of intersection of Π\Pi and Σ\Sigma.

[4]
Question 38
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Two straight service cables are modelled by the lines

L1:r=(102)+λ(21−1),L2:r=(45−1)+μ(1−22)L_1:\mathbf{r}=\begin{pmatrix}1\\0\\2\end{pmatrix}+\lambda\begin{pmatrix}2\\1\\-1\end{pmatrix},\qquad L_2:\mathbf{r}=\begin{pmatrix}4\\5\\-1\end{pmatrix}+\mu\begin{pmatrix}1\\-2\\2\end{pmatrix}
A
I.

the two lines do not intersect.

[3]
II.

the geometrical relationship between the two lines.

[1]
B

Let PP be the point on L1L_1 and QQ the point on L2L_2 such that PQPQ is perpendicular to both lines. the coordinates of PP and QQ.

[5]
C

the shortest distance between the two cables and the acute angle between them.

[2]
Question 39
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The planes Π1\Pi_1 and Π2\Pi_2 are given by

Π1:x−2y+z=3,Π2:2x+y−z=4\Pi_1:x-2y+z=3,\qquad \Pi_2:2x+y-z=4

They intersect in the line LL. The point AA has coordinates (4,1,7)(4,1,7).

A
I.

a direction vector for LL.

[2]
II.

a vector equation of LL.

[3]
B

the point on LL closest to AA. If you did not obtain a vector equation for LL, use r=(11/5−2/50)+t(135)\mathbf{r}=\begin{pmatrix}11/5\\-2/5\\0\end{pmatrix}+t\begin{pmatrix}1\\3\\5\end{pmatrix}.

[3]
C

the acute angle between Π1\Pi_1 and Π2\Pi_2.

[2]
Question 40
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A parallelogram-shaped sensor screen lies in the plane

Π:r=(2−13)+λ(120)+μ(012)\Pi:\mathbf{r}=\begin{pmatrix}2\\-1\\3\end{pmatrix}+\lambda\begin{pmatrix}1\\2\\0\end{pmatrix}+\mu\begin{pmatrix}0\\1\\2\end{pmatrix}

where 0≤λ≤30\leq \lambda\leq 3 and 0≤μ≤20\leq \mu\leq 2. A signal travels along

L:r=(1058)+t(−3−2−1)L:\mathbf{r}=\begin{pmatrix}10\\5\\8\end{pmatrix}+t\begin{pmatrix}-3\\-2\\-1\end{pmatrix}
A
I.

a normal vector to Π\Pi.

[2]
II.

a Cartesian equation of Π\Pi is 4x−2y+z=134x-2y+z=13.

[2]
B

the point where the signal line meets the plane of the screen.

[3]
C

whether the signal hits the parallelogram-shaped screen. your answer.

[3]

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Question 41
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The points A(1,2,0)A(1,2,0), B(7,5,2)B(7,5,2), C(5,11,5)C(5,11,5) and D(−1,8,3)D(-1,8,3) are vertices of a quadrilateral. The point EE has coordinates (2,4,9)(2,4,9).

A
I.

ABCDABCD is a parallelogram.

[2]
II.

the area of ABCDABCD.

[2]
B

a Cartesian equation of the plane containing ABCDABCD.

[3]
C

the shortest distance from EE to the plane containing ABCDABCD. If you did not obtain the plane equation, use −3x−22y+42z+47=0-3x-22y+42z+47=0.

[4]
Question 42
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Two underwater probes move with constant velocities. Probe AA starts from (0,1,−2)(0,1,-2) and has actual velocity (4−11)\begin{pmatrix}4\\-1\\1\end{pmatrix} metres per second. Probe BB starts from (18,−2,5)(18,-2,5) and has actual velocity (−21−1)\begin{pmatrix}-2\\1\\-1\end{pmatrix} metres per second. Let tt be the time in seconds after both probes start moving.

A
I.

vector equations for the positions of the two probes.

[2]
II.

the acute angle between the paths of the two probes.

[2]
B

whether the probes collide.

[2]
C

the time at which the probes are closest together, and this minimum distance.

[4]
Question 43
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Two straight tunnels are modelled by

L1:r=(2−10)+s(121)L_1:\mathbf{r}=\begin{pmatrix}2\\-1\\0\end{pmatrix}+s\begin{pmatrix}1\\2\\1\end{pmatrix} L2:r=(553)+u(−210)L_2:\mathbf{r}=\begin{pmatrix}5\\5\\3\end{pmatrix}+u\begin{pmatrix}-2\\1\\0\end{pmatrix}
A
I.

the tunnels intersect, and their point of intersection.

[3]
II.

the angle between the two tunnels.

[1]
B

a Cartesian equation of the plane containing both tunnels.

[3]
C

A ventilation shaft is drilled from A(1,1,8)A(1,1,8) perpendicular to this plane. the point where the shaft meets the plane, and the length of the shaft.

[3]
Question 44
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Two underwater vehicles move in straight lines. Their position vectors, in kilometres, tt hours after noon are

rP=(2−31)+t(12−1),rQ=(85−2)+t(−201)\mathbf{r}_P=\begin{pmatrix}2\\-3\\1\end{pmatrix}+t\begin{pmatrix}1\\2\\-1\end{pmatrix},\qquad \mathbf{r}_Q=\begin{pmatrix}8\\5\\-2\end{pmatrix}+t\begin{pmatrix}-2\\0\\1\end{pmatrix}

where 0≤t≤50\leq t\leq 5.

Vehicle

x(t)x(t) / km

y(t)y(t) / km

z(t)z(t) / km

Time interval / h

P

2+t2+t

−3+2t-3+2t

1−t1-t

0≤t≤50\le t\le 5

Q

8−2t8-2t

55

−2+t-2+t

0≤t≤50\le t\le 5

A
I.

the speed of each vehicle.

[2]
B
I.

the square of the distance between the vehicles is 17t2−80t+10917t^2-80t+109.

[3]
II.

the minimum distance between the vehicles during the time interval.

[3]
C

For safety, the vehicles must remain at least 44 km apart.

I.

the interval of time during which the safety condition (the vehicles' separation is at least 4 km4\ \text{km}) is not satisfied.

[3]
II.

the duration of this unsafe interval.

[1]

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Question 45
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Consider the two lines

L1:r=(1−23)+λ(21−1),L2:r=(a01)+μ(13−2)L_1:\mathbf{r}=\begin{pmatrix}1\\-2\\3\end{pmatrix}+\lambda\begin{pmatrix}2\\1\\-1\end{pmatrix},\qquad L_2:\mathbf{r}=\begin{pmatrix}a\\0\\1\end{pmatrix}+\mu\begin{pmatrix}1\\3\\-2\end{pmatrix}

where a,λ,μ∈Ra,\lambda,\mu\in\mathbb{R}.

A
I.

L1L_1 and L2L_2 are not parallel.

[1]
II.

the value of aa for which the two lines intersect, and the point of intersection.

[5]
B
I.

the relationship between the lines when a≠5a\ne 5.

[1]
C

Assume a≠5a\ne5.

I.

the shortest distance between L1L_1 and L2L_2 in terms of aa.

[4]
Question 46
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

The point Cs=(2,s,3)C_s=(2,s,3) moves along a straight vertical track. The fixed points are A(1,0,2)A(1,0,2) and B(4,1,−1)B(4,1,-1). The area of triangle ABCsABC_s changes as ss varies.

I.

AB⃗×ACs⃗\vec{AB}\times\vec{AC_s} in terms of ss.

[3]
I.

the area of triangle ABCsABC_s is 1218s2+38\frac{1}{2}\sqrt{18s^2+38}.

[2]
II.

the minimum possible area of triangle ABCsABC_s.

[2]
I.

the values of ss for which the area of triangle ABCsABC_s is 55 square units.

[3]
II.

geometrically why two different values of ss give the same area in part (c)(i).

[2]
Question 47
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A family of planes Πk\Pi_k passes through the point A(1,−1,2)A(1,-1,2) and contains the two direction vectors

u=(210),v=(0k3)\mathbf{u}=\begin{pmatrix}2\\1\\0\end{pmatrix},\qquad \mathbf{v}=\begin{pmatrix}0\\k\\3\end{pmatrix}
A
AI.

a normal vector to Πk\Pi_k in terms of kk.

[2]
AII.

a Cartesian equation of Πk\Pi_k is 3x−6y+2kz=9+4k3x-6y+2kz=9+4k.

[2]
B
B.

the value of kk for which P(5,0,1)P(5,0,1) lies on Πk\Pi_k.

[2]
C

For the remainder of this question, take k=3k=3.

CI.

the acute angle between Π3\Pi_3 and the plane 2x+y−z=42x+y-z=4.

[3]
CII.

the point on Π3\Pi_3 closest to the origin, and the shortest distance from the origin to Π3\Pi_3.

[3]
Question 48
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Two planes are given by

Π1:x−y+2z=4\Pi_1:x-y+2z=4 Π2:2x+y−z=1\Pi_2:2x+y-z=1

They intersect in a line LL.

A
I.

a direction vector for LL.

[2]
II.

a vector equation of LL.

[3]
B

For each real value of kk, define the plane

Πk:(1+2k)x+(−1+k)y+(2−k)z=4+k\Pi_k:(1+2k)x+(-1+k)y+(2-k)z=4+k
I.

every plane Πk\Pi_k contains the line LL.

[2]
II.

kk such that Πk\Pi_k is perpendicular to the plane x+z=0x+z=0.

[2]
C
I.

the acute angle between Π1\Pi_1 and Π2\Pi_2.

[3]

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Question 49
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

The lines L1L_1 and L2L_2 are given by L1:r=(000)+λ(100)L_1:\mathbf r=\begin{pmatrix}0\\0\\0\end{pmatrix}+\lambda\begin{pmatrix}1\\0\\0\end{pmatrix} and L2:r=(102)+μ(011)L_2:\mathbf r=\begin{pmatrix}1\\0\\2\end{pmatrix}+\mu\begin{pmatrix}0\\1\\1\end{pmatrix}.

A
I.

the two lines do not intersect.

[2]
II.

the relationship between the two lines.

[1]
B

Let AA be a point on L1L_1 and BB be a point on L2L_2 such that ABAB is perpendicular to both lines. the coordinates of AA and BB.

[4]
C

the shortest distance between L1L_1 and L2L_2.

[1]
D

the Cartesian equation of the plane containing L1L_1 and parallel to L2L_2.

[2]
Question 50
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Three planes are given by Π1:x+y+z=3\Pi_1:x+y+z=3, Π2:x−y+2z=4\Pi_2:x-y+2z=4 and Π3:2x+ay+5z=b\Pi_3:2x+ay+5z=b, where a,b∈Ra,b\in\mathbb R. The line of intersection of Π1\Pi_1 and Π2\Pi_2 is denoted by LL.

A
I.

a direction vector for LL.

[2]
II.

a vector equation of LL.

[3]
B

the values of aa and bb for which Π3\Pi_3 contains LL.

[4]
C

For a=0a=0 and b=10b=10, the common point of intersection of the three planes.

[3]
Question 51
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The line LL and the plane Πk\Pi_k are defined by

L:r=(12−1)+t(2−13),Πk:kx+y−2z=5L:\mathbf{r}=\begin{pmatrix}1\\2\\-1\end{pmatrix}+t\begin{pmatrix}2\\-1\\3\end{pmatrix},\qquad \Pi_k:kx+y-2z=5

where k∈Rk\in\mathbb{R}.

A
I.

the value of kk for which LL is parallel to Πk\Pi_k.

[2]
II.

For this value of kk, whether LL lies in Πk\Pi_k or is parallel and distinct from Πk\Pi_k.

[2]
B

For k=1k=1, the point of intersection of LL and Πk\Pi_k, and the acute angle between LL and Πk\Pi_k.

[4]
C

all values of kk for which the acute angle between LL and Πk\Pi_k is 0.4000.400 radians.

[4]
Question 52
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Three planes are defined by

Π1:x+y+z=6\Pi_1:x+y+z=6 Π2:2x−y+3z=10\Pi_2:2x-y+3z=10 Π3:x+ay+2z=7\Pi_3:x+ay+2z=7

where a∈Ra\in\mathbb{R}.

A
I.

a vector equation of the line of intersection of Π1\Pi_1 and Π2\Pi_2.

[3]
II.

the coordinates of the common point of the three planes when a=1a=1.

[1]
B

the value of aa for which the three planes have no common point. your answer.

[4]
C

For a=1a=1, the acute angle between Π2\Pi_2 and Π3\Pi_3.

[2]

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Question 53
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A triangular solar panel has vertices A(0,0,2)A(0,0,2), B(4,1,3)B(4,1,3) and C(1,5,6)C(1,5,6). A vertical support cable passes through the point D(2,2,0)D(2,2,0) and is parallel to the zz-axis.

A
I.

a normal vector to the plane of the panel.

[2]
II.

the area of the triangular panel.

[2]
III.

a Cartesian equation of the plane of the panel.

[1]
B

the height at which the vertical cable meets the plane of the panel.

[2]
C

whether the cable meets the triangular panel itself, rather than only the plane containing it.

[2]
D

the acute angle between the panel and the horizontal plane z=0z=0.

[2]
Question 54
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A tunnel is modelled by the line

Lm:r=(m10)+t(1m2)L_m:\mathbf{r}=\begin{pmatrix}m\\1\\0\end{pmatrix}+t\begin{pmatrix}1\\m\\2\end{pmatrix}

where m∈Rm\in\mathbb{R}. A fault plane is modelled by

Π:2x−y+z=4\Pi:2x-y+z=4
A
I.

the value of mm for which LmL_m is parallel to Π\Pi.

[2]
II.

For this value of mm, whether LmL_m lies in Π\Pi or is parallel and distinct from Π\Pi.

[2]
B

the value of mm for which LmL_m intersects Π\Pi when t=1t=1. the point of intersection for this value of mm.

[3]
C

For m=1m=1, the acute angle between LmL_m and Π\Pi.

[2]
D

all values of mm for which the acute angle between LmL_m and Π\Pi is 20∘20^\circ.

[3]
Question 55
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Two signal directions in a three-dimensional tracking device are represented by

u=(3−12),v=(14−2)\mathbf{u}=\begin{pmatrix}3\\-1\\2\end{pmatrix},\qquad \mathbf{v}=\begin{pmatrix}1\\4\\-2\end{pmatrix}

A third adjustable direction is given by d=(1k2)\mathbf{d}=\begin{pmatrix}1\\k\\2\end{pmatrix}, where k∈Rk\in\mathbb{R}.

A
I.

the angle between u\mathbf{u} and v\mathbf{v}.

[3]
II.

the vector projection of v\mathbf{v} onto u\mathbf{u}.

[2]
B
I.

kk if d\mathbf{d} is perpendicular to u+v\mathbf{u}+\mathbf{v}.

[2]
C

The value of kk is now allowed to vary.

I.

the value of kk for which the acute angle between d\mathbf{d} and u\mathbf{u} is a minimum.

[4]
II.

this minimum acute angle. If you did not obtain k=−57k=-\frac{5}{7}, use this value.

[1]
Question 56
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A light ray travels along the line

L:r=(501)+t(−212),t∈RL:\mathbf{r}=\begin{pmatrix}5\\0\\1\end{pmatrix}+t\begin{pmatrix}-2\\1\\2\end{pmatrix},\qquad t\in\mathbb{R}

and reflects from the plane mirror

Π:x+2y−2z=6\Pi:x+2y-2z=6
A
I.

the point at which the ray meets the plane.

[3]
II.

the acute angle between the incoming ray and the plane.

[3]
B

The reflected direction is obtained by reversing the component of the incoming direction parallel to the normal vector of the mirror.

I.

a direction vector for the reflected ray.

[4]
II.

a vector equation of the reflected ray.

[2]

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Question 57
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Two straight support cables are modelled by the following two lines

L1:r=(012)+λ(121)L_1:\mathbf{r}=\begin{pmatrix}0\\1\\2\end{pmatrix}+\lambda\begin{pmatrix}1\\2\\1\end{pmatrix} L2:r=(3−10)+μ(21−1)L_2:\mathbf{r}=\begin{pmatrix}3\\-1\\0\end{pmatrix}+\mu\begin{pmatrix}2\\1\\-1\end{pmatrix}
A
I.

the two lines are skew.

[3]
II.

a unit vector perpendicular to both lines.

[2]
B
I.

the shortest distance between the two lines.

[3]
C

Let PP be the point on L1L_1 and QQ the point on L2L_2 such that PQPQ is the shortest connecting segment.

I.

the coordinates of PP and QQ.

[5]
Question 58
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A tetrahedral frame has vertices A(1,0,0)A(1,0,0), B(3,2,1)B(3,2,1), C(0,4,2)C(0,4,2) and D(2,−1,h)D(2,-1,h), where h∈Rh\in\mathbb{R} and h≠−12h\ne-\frac{1}{2}.

A
A.

AC⃗×AD⃗\vec{AC}\times\vec{AD} in terms of hh.

[3]
B.

the volume VV of the tetrahedron is ∣10h+5∣6\frac{|10h+5|}{6}.

[2]
B
C.

the values of hh for which the volume is 55 cubic units.

[3]
C
D.

the value of hh for which the faces ABCABC and ABDABD are perpendicular.

[4]
Question 59
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A triangular landing panel has vertices A(0,0,0)A(0,0,0), B(6,0,2)B(6,0,2) and C(2,5,1)C(2,5,1). A probe travels along the line

r=(128)+t(1−1−3),t≥0\mathbf{r}=\begin{pmatrix}1\\2\\8\end{pmatrix}+t\begin{pmatrix}1\\-1\\-3\end{pmatrix},\qquad t\geq 0
A
I.

a Cartesian equation of the plane containing the triangular panel.

[3]
B
I.

the point where the probe path meets the plane.

[3]
II.

whether this point lies inside the triangular panel.

[3]
C

A second probe travels in the same direction as the first probe, starting from (1,q,8)(1,q,8), where qq is a real constant. Its path is

r=(1q8)+t(1−1−3),t≥0\mathbf{r}=\begin{pmatrix}1\\q\\8\end{pmatrix}+t\begin{pmatrix}1\\-1\\-3\end{pmatrix},\qquad t\geq 0
I.

qq so that the second probe hits the side ABAB of the triangular panel.

[4]
Question 60
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Two planes are given by

Π1:2x−y+2z=3\Pi_1:2x-y+2z=3 Π2:x+2y−2z=−1\Pi_2:x+2y-2z=-1

A moving point lies on the line

L:r=(102)+s(2−11),s∈RL:\mathbf{r}=\begin{pmatrix}1\\0\\2\end{pmatrix}+s\begin{pmatrix}2\\-1\\1\end{pmatrix},\qquad s\in\mathbb{R}
A
A.

the distances from a point on LL to Π1\Pi_1 and Π2\Pi_2 are ∣3+7s∣3\frac{|3+7s|}{3} and ∣2+2s∣3\frac{|2+2s|}{3} respectively.

[3]
B
B.

the points on LL which are equidistant from Π1\Pi_1 and Π2\Pi_2.

[3]
C
CI.

Cartesian equations of the two planes whose points are equidistant from Π1\Pi_1 and Π2\Pi_2.

[3]
CII.

the acute angle between Π1\Pi_1 and Π2\Pi_2.

[3]

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Trigonometric Functions