The gradient of a curve is given by
The curve passes through the point .
Find in terms of .
0
A function satisfies , for , and .
Find .
0
The curves and enclose a finite region.
Find the -coordinates of the points of intersection of the two curves.
Find the area of the enclosed region.
0
Evaluate .
0
A function satisfies , and .
Find .
Hence find .
0
Evaluate .
0
The function satisfies
It is given that .
Find an expression for .
Find .
0
For , the shaded region is bounded by the curve
and the -axis.

Explain why the area of the shaded region is equal to .
Find the area of the shaded region.
0
The function is defined by .
Write down the -intercepts of the graph of .
Find the total area enclosed by the graph of , the -axis and the lines and .
0
Let , for .
Find the value of .
Find the total area between the graph of and the -axis for .
0
Consider the integral .
Using the substitution , show that .
Hence find the exact value of .
0
Find the exact value of .
0
The region is bounded by the curve and the -axis, for .
Find the area of .
The region is rotated through radians about the -axis. Find the volume of the solid formed.
0
The curves and enclose a region in the first quadrant.
Find the -coordinates of the points of intersection of the two curves.
The region is rotated through radians about the -axis. Find the volume of the solid formed.
0
Let
The graph of crosses the -axis at , and .

Write down an integral expression for the total area enclosed by the graph of and the -axis between and .
Find this total area.
0
The functions and are defined by
The graphs of and enclose two finite regions.

Find the -coordinates of all points of intersection of the two graphs.
Find the total area of the two finite regions enclosed by the graphs.
0
Consider the integral
Use the substitution .
Show that
Hence find the exact value of .
0
Let
Use integration by parts to find an exact expression for .
Give the value of to three significant figures.
0
A curve is given by
The region is enclosed by the curve and the -axis.

Write down an integral expression for the area of .
Find the area of .
The region is rotated through about the -axis. Find the volume of the solid formed.
0
A differentiable function is defined for . It is given that
and .
Find in terms of and an arbitrary constant .
Hence determine .
Find the exact value of .
Hence find . If you did not obtain a value in part (b)(i), use .
0
For , define
Find in terms of .
Find .
Show that is an increasing function for .
Hence determine the value of , where , such that . If you did not obtain in part (a)(ii), use .
0
A function satisfies
and .
Part (a)
Find in terms of and an arbitrary constant .
Hence determine .
Find .
Part (c)
Find the exact value of . If you did not obtain in part (b), use .
Determine the exact value of such that .
0
Let .
By using integration by parts twice, show that .
Hence find .
0
A small wind turbine produces power at a rate
kilowatts, where is the time in hours after 06:00 and . The total energy produced, in kilowatt-hours, is found by integrating with respect to .

Write down an integral expression for the total energy produced during the 12-hour period.
Calculate this total energy.
Find the average power produced during the 12-hour period.
Explain why the energy produced from 06:00 to 18:00 is not equal to .
Determine the time after 06:00 at which half of the total energy has been produced.
0
A curve has gradient function
The curve passes through the point .
Find in terms of .
Verify that your expression satisfies the given gradient function.
Find the value of when .
The point on with -coordinate has -coordinate , where . Find . If you did not obtain an expression for in part (a), use .
0
The height, in metres, of an arch above a horizontal walkway is modelled by
where is the horizontal distance in metres from one end of the arch.

Find the area under the arch between and .
Find the average height of the arch on this interval.
Show that the area under the arch from to is given by
Find the value of for which the area under the arch from to is .
State why there is only one such value of in the interval .
0
A curve has gradient function
The curve passes through .
Find in terms of .
Find the value of for which .
0
Consider the integral
Use repeated integration by parts to find the exact value of .
Write down the value of to three significant figures.
0
Let
Use integration by parts twice to show that
Hence find to three significant figures.
0
The region bounded by the curve
the -axis and the line is rotated through about the -axis.

Find the -intercept of the curve.
Write down an integral expression for the volume of the solid formed.
Find this volume.
0
A decorative lamp shade is modelled by rotating the curve through radians about the -axis, where and .

Show that
Hence show that the volume of the lamp shade is .
lamp shade has volume and . Find .
The value of from part (b) is kept fixed. Find the value of required to double the volume.
Find the area enclosed by the generating curve and the -axis in terms of and .
0
The function is defined by
Part (a)
Write down the zeros of .
Determine the sign of on each of the intervals and .
Part (b)
Show that an antiderivative of is .
Find the value of . If you did not show the antiderivative in part (b)(i), use .
Find the total area enclosed by the graph of and the -axis for .
0
The functions and are defined by
The graphs of and enclose a finite region.
Find the -coordinates of the points of intersection of the graphs.
State which graph is above the other between the points of intersection.
Find the area of the finite region enclosed by the two graphs.
horizontal line , where , intersects the graph of at two points. The area enclosed by and is . Find the value of .
0
The function is defined by
Find the -intercept of the graph of on this interval.
State the sign of on each side of this intercept in the interval .
Find an antiderivative of .
Find the exact value of .
Find the total area between the graph of and the -axis on the interval .
0
Consider the definite integral
Use the substitution to show that
Hence find the exact value of .
The region under the curve , above the -axis, between and , is rotated through radians about the -axis. Find the exact volume of the solid formed. If you did not obtain a value for , use .
0
The curve is considered for .
Use integration by parts to show that
Hence find the area between the curve, the -axis, and the lines and .
Use integration by parts and the result from part (a)(i) to show that
The region between , the -axis, and the lines and is rotated through radians about the -axis. Find the exact volume of the solid formed. If you did not show the result in part (b)(i), use it here.
0
A curve is given by
The region is bounded by the curve, the -axis, and the lines and .
Find the coordinates of the endpoints of the curve on the boundary of .
Find the area of .
The region is rotated through radians about the -axis. Write down an integral expression for the volume of the solid formed.
Hence find the exact volume of the solid formed.
0
Consider the integral
Use the substitution to show that
Hence evaluate exactly.
The region under the curve , above the -axis, between and , is rotated through radians about the -axis. Find the exact volume of the solid formed. If you did not obtain a value for , use .
0
The functions and are defined by
The region is bounded by the -axis and the graphs of and .

Find the -coordinate of the point of intersection of the two graphs.
State which curve is above the other for the region .
Find the area of .
vertical line divides into two regions of equal area. Write down an equation that satisfies.
Hence find . If you did not obtain the area in part (b), use .
0
Let
The graph of crosses the -axis twice on this interval.

Find the two -intercepts of the graph of .
Find the signed area .
Find the total area between the graph of and the -axis for .
Let be the value such that the total area between the graph and the -axis from to is half of the total area found in part (b). Write down an equation for .
Hence find . If you did not obtain the total area in part (b), use .
0
The curve has equation
The region is bounded by , the -axis, and the lines and .

Use integration by parts to find the area of .
Find the maximum height of the region .
The region is rotated through radians about the -axis. Show that the volume of the solid formed is
Use repeated integration by parts to find exactly.
Hence find the volume of the solid formed.
0
A plane region lies between the curve
and the -axis.

Write down an integral expression for the area of .
Use the substitution to find the area of .
The region is rotated through radians about the -axis. Find the volume of the solid formed.
Let divide the solid into two parts of equal volume. Write down an equation for .
Hence find . If you did not obtain the volume in part (b), use .
0
The region is bounded by the curve
the -axis, the -axis, and the line .

Use integration by parts to find the exact area of .
Write this area correct to three significant figures.
The region is rotated through radians about the -axis. Write down an integral expression for the volume of the solid formed, and calculate .
Let divide the solid into two parts of equal volume. Write down an equation for .
Hence find . If you did not obtain the volume in part (b), use .
0
For , define This question investigates how varies with the parameter .

Use the substitution to express as an integral with respect to .
Hence show that .
Find the value of for which .
Prove that is a decreasing function of for .
Deduce the number of positive solutions of when .
0
For , let
This question investigates a recurrence relation for .
4 | |
5 | |
6 | |
7 | |
8 | |
9 | |
10 | |
11 |
Write down the exact value of .
Use integration by parts to show that for .
Hence find the exact values of , and .
Show that for .
Use the result in part (c) to find an integer such that for all .
0
For , the curve and the line enclose a finite region with the -axis. The region is denoted by .

Find the -coordinate of the point where meets .
Show that the area of is .
Find and interpret its sign for .
Find the value of for which the area of is .
For this value of , find the volume generated when is rotated through radians about the -axis. If you did not obtain a value for , use .
0
A region is bounded by the curve and the -axis. The curve lies to the right of the -axis on this interval.

Find the area of .
Find the volume generated when is rotated through radians about the -axis.
horizontal line divides into two regions of equal area. Write an equation satisfied by .
Find .
Explain why integration with respect to is the natural method for this region.
0
The region is bounded by the curve , the -axis, and the vertical lines and .

Find the exact area of .
Use integration by parts to show that
Find the exact volume generated when is rotated through radians about the -axis.
vertical line divides the volume in part (c) into two equal volumes. Find .
0
The curve
forms a single arch above the -axis. The region under the arch is denoted by .

Use the substitution to find the exact area of .
State why the definite integral gives the geometric area without splitting the interval.
Find the volume generated when is rotated through radians about the -axis.
vertical plane perpendicular to the -axis cuts the solid into two parts of equal volume at . Find .
0
A region is bounded by the curve
the -axis, and the horizontal lines and , where .

Write down an integral expression for the area of .
Use the substitution and integration by parts to show that
Write down an integral expression for the volume formed when is rotated through radians about the -axis.
Show that
Find the value of for which .
0
A density profile along a beam is modelled by For , define

Use the reverse chain rule to show that .
Find .
Find such that .
The region under the curve from to the value of found in part (b) is rotated through radians about the -axis. Write down an integral expression for the volume and find its value. If you did not obtain , use .
0
Let
By using integration by parts, show that
Hence evaluate exactly.
Find the exact value of . If you did not obtain in part (a)(ii), use .
Determine the exact value of such that
0
Let
Show that .
Show that .
Hence find the exact values of and .
Find the total area between the graph of and the -axis for .
0
Water enters a tank at a rate
litres per minute, where is the time in minutes after the tap is opened. At the same time, water leaves the tank at a constant rate of litres per minute. Initially the tank contains litres of water.

Write down an integral expression for the net change in the volume of water in the tank during the first 8 minutes.
Calculate this net change.
Find the time at which the accumulated volume predicted by the inflow and outflow rates is greatest during the first 8 minutes, ignoring any capacity limit.
Find this greatest accumulated volume, ignoring any capacity limit.
The capacity of the tank is litres. Determine the time at which the tank first overflows.
Explain why the tank is not still overflowing at .
0
Let
The function is positive on and negative on .

Use integration by parts twice to show that
Hence find the signed area .
Find the total area between the graph of and the -axis for .
The value , where , is such that the area between the graph and the -axis from to is half of the positive lobe area. Write down an equation for .
Hence find . If you did not obtain the positive lobe area, use .
0
The region is bounded by the curve
the -axis, and the lines and .

Use the substitution to show that the area of is
Find the area of to three significant figures.
The region is rotated through radians about the -axis. Find the volume of the solid formed.
Let divide the solid into two parts of equal volume. Write down an equation for .
Hence find , taking the root in the interval . If you did not obtain the volume in part (b), use .
0
For real , define This question first considers the case and then generalizes.

Using integration by parts twice, show that
Hence find exactly.
By considering , show that
Find the positive value of for which .
Explain why no value can satisfy .
0
The tangent half-angle substitution is . This question investigates .
For , show that the integral becomes .
Hence find exactly.
Show that, for ,
Find directly from the original integral.
State what this suggests about the formula in part (b) as .
0
For , define
n | A_n | nA_n |
|---|---|---|
1 | 0.250000 | 0.250000 |
2 | 0.184320 | 0.368641 |
5 | 0.102778 | 0.513889 |
10 | 0.059068 | 0.590682 |
20 | 0.031900 | 0.638004 |
50 | 0.013401 | 0.670039 |
Find the exact value of .
Use integration by parts to show that
Show that for .
Find the exact values of and .
Using the table or technology, estimate and explain why this value is reasonable.
0
For , a family of profile curves is given by
The region is bounded by the curve, the -axis, and the lines and .

For this part, take .
Write down an integral expression for the area of .
Use integration by parts to find this area.
The region is rotated through radians about the -axis. Write down an integral expression for the volume of the solid formed.
Calculate .
Let divide the solid in part (b) into two parts of equal volume. Write down an equation for .
Hence find . If you did not obtain the volume in part (b), use .
For general , let
Justify that decreases as increases, and determine the value of for which .
0