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Distributions

Practice exam-style IB Math AA questions for Distributions, aligned with the syllabus and grouped by topic.

Verified by Karim
Verified by Karim
Paper
Difficulty
Status
Level
Question 1
SL • Paper 1
Easy
Non Calculator
SL • Paper 1
Easy
Non Calculator

A discrete random variable XX has probability distribution

P(X=x)=k(x+1),x{0,1,2,3}P(X=x)=k(x+1), \quad x\in\{0,1,2,3\}
A

Find the value of kk.

[2]
B

Find E(X)E(X).

[2]
C

A player receives 2X2X counters and pays an entry fee of cc counters to play. Find cc if the game is fair.

[2]
Question 2
SL • Paper 1
Easy
Non Calculator
SL • Paper 1
Easy
Non Calculator

The random variable XX is normally distributed with mean 5050. It is known that approximately 68%68\% of the values of XX lie between 4444 and 5656.

A normal curve centred at its mean, with a symmetric central region shaded between two vertical boundary lines. The centre and the two boundary values are labelled as given in the question, and the shaded area is labelled as approximately 68 percent.
A

Find the standard deviation of XX.

[2]
B

Find the approximate value of P(X>56)P(X>56).

[2]
C

Using the empirical rule, write down the approximate value of P(38<X<62)P(38<X<62).

[1]
Question 3
SL • Paper 2
Easy
Calculator Permitted
SL • Paper 2
Easy
Calculator Permitted

A discrete random variable XX has probability distribution

P(X=x)=k(x+1),x{0,1,2,3,4}P(X=x)=k(x+1), \quad x\in\{0,1,2,3,4\}

In a game, a player receives a prize of $1.50 for each point scored by XX.

A

Find the value of kk.

[2]
B

Find E(X)E(X).

[2]
C

Find the entry fee that would make the game fair.

[1]
Question 4
SL • Paper 2
Easy
Calculator Permitted
SL • Paper 2
Easy
Calculator Permitted

A discrete random variable XX has probability distribution

P(X=x)=k(6x),x{1,2,3,4,5}P(X=x)=k(6-x), \quad x\in\{1,2,3,4,5\}
A

Find kk.

[2]
B

Find P(X3)P(X\geq 3).

[1]
C

A score of XX gives a prize of $2X2X. Find the fair entry fee for this game.

[2]
Question 5
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

Let XB(4,13)X\sim B\left(4,\frac{1}{3}\right).

A

Find P(X=2)P(X=2).

[2]
B

Find P(X1)P(X\geq 1).

[2]
C

Find Var(X)\operatorname{Var}(X).

[1]
Question 6
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

A box contains a large number of identical components. The probability that a randomly selected component is defective is 15\frac{1}{5}. A quality inspector selects 55 components independently. Let XX be the number of defective components selected.

A

State two assumptions needed for XX to be modelled by a binomial distribution.

[2]
B

Find P(X=1)P(X=1).

[2]
C

Find the expected number of defective components selected.

[1]
Question 7
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

The random variable XX is normally distributed with mean 3030. It is given that P(X<24)=0.18P(X<24)=0.18.

A

Write down P(X>36)P(X>36).

[1]
B

Find P(24<X<36)P(24<X<36).

[2]
C

Find P(X<36X>24)P(X<36\mid X>24).

[2]
Question 8
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The random variable XX is normally distributed with mean μ\mu and standard deviation σ\sigma. The value 6868 has standardized value 1-1, and the value 9292 has standardized value 22.

A

Find μ\mu and σ\sigma.

[3]
B

Find the value of xx whose standardized value is 12\frac{1}{2}.

[1]
C

Let ZN(0,1)Z\sim N(0,1) and suppose P(Z<12)=qP\left(Z<\frac{1}{2}\right)=q. Write down P(X>80)P(X>80) in terms of qq.

[1]
Question 9
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The discrete random variable XX has probability distribution

x102P(X=x)141214\begin{array}{c|ccc} x & -1 & 0 & 2\\ \hline P(X=x) & \frac{1}{4} & \frac{1}{2} & \frac{1}{4} \end{array}
A

Find E(X)E(X).

[2]
B

Find Var(X)\operatorname{Var}(X).

[3]
C

Let Y=42XY=4-2X. Find Var(Y)\operatorname{Var}(Y).

[1]
Question 10
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The continuous random variable XX has probability density function

f(x)={kx,0x2,0,otherwise.f(x)= \begin{cases} kx, & 0\leq x\leq 2,\\ 0, & \text{otherwise.} \end{cases}
A

Find the value of kk.

[2]
B

Find P(X>1)P(X>1).

[2]
C

Find E(X)E(X).

[2]
Question 11
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

A packet contains 1212 seeds. Each seed germinates independently with probability 0.820.82. Let XX be the number of seeds in the packet that germinate.

A

Write down the distribution of XX.

[1]
B

Find P(X=10)P(X=10).

[2]
C

Find the probability that at least 99 seeds germinate.

[2]
D

Find the standard deviation of XX.

[1]
Question 12
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

The lifetime, TT hours, of a type of rechargeable battery is modelled by TN(μ,7.52)T\sim N(\mu,7.5^2). It is known that 18%18\% of these batteries last less than 4242 hours.

A

Determine the value of μ\mu.

[3]
B

Using your value of μ\mu, find P(45<T<55)P(45<T<55).

[2]
Question 13
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

A discrete random variable XX has probability distribution

P(X=x)=cx2,x{1,2,3,4}P(X=x)=cx^2, \quad x\in\{1,2,3,4\}

A new random variable is defined by Y=52XY=5-2X.

A

Find cc.

[1]
B

Find E(X)E(X).

[2]
C

Find Var(X)\operatorname{Var}(X).

[2]
D

Find E(Y)E(Y) and Var(Y)\operatorname{Var}(Y).

[1]
Question 14
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The continuous random variable XX has probability density function

f(x)={ax,0x<2,a(4x),2x4,0,otherwise.f(x)=\begin{cases} ax, & 0\leq x<2,\\ a(4-x), & 2\leq x\leq 4,\\ 0, & \text{otherwise}. \end{cases}
A

Find aa.

[2]
B

Find E(X)E(X).

[2]
C

Find Var(X)\operatorname{Var}(X).

[2]
Question 15
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

A discrete random variable XX can take the values 11, 22 and 44. Its probability distribution is

P(X=1)=p,P(X=2)=2p,P(X=4)=13pP(X=1)=p,\quad P(X=2)=2p,\quad P(X=4)=1-3p

It is given that E(X)=3E(X)=3.

A

Find pp.

[3]
B

Find P(X2)P(X\geq 2).

[1]
C

In a game, a player receives XX counters. Find the entry fee, in counters, that makes the game fair.

[1]
Question 16
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The continuous random variable XX has probability density function

f(x)={ax,0x1,a(2x),1<x2,0,otherwise.f(x)= \begin{cases} ax, & 0\leq x\leq 1,\\ a(2-x), & 1<x\leq 2,\\ 0, & \text{otherwise.} \end{cases}
A

Find aa.

[2]
B

Write down the mode of XX.

[1]
C

Show that the median of XX is 11.

[2]
Question 17
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The continuous random variable XX has probability density function

f(x)={3x2,0x1,0,otherwise.f(x)= \begin{cases} 3x^2, & 0\leq x\leq 1,\\ 0, & \text{otherwise.} \end{cases}
A

Find E(X)E(X).

[2]
B

Find Var(X)\operatorname{Var}(X).

[2]
C

Let Y=6X1Y=6X-1. Find E(Y)E(Y) and Var(Y)\operatorname{Var}(Y).

[2]
Question 18
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Let XN(40,16)X\sim N(40,16) and YN(50,25)Y\sim N(50,25). Let ZN(0,1)Z\sim N(0,1), and suppose P(Z<32)=qP\left(Z<\frac{3}{2}\right)=q.

A

Find the standardized value corresponding to X=46X=46.

[1]
B

Express P(X>46)P(X>46) in terms of qq.

[1]
C

Find the value of yy such that P(Y<y)=P(X>46)P(Y<y)=P(X>46).

[3]
Question 19
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

The mass, MM grams, of apples from a farm is modelled by a normal distribution with mean 165165 and standard deviation 1212.

A

Find P(150<M<180)P(150<M<180).

[2]
B

Find the 9090th percentile of the apple masses.

[2]
C

A box contains 2020 independently selected apples from the farm. Find the probability that at least 1818 of them have mass greater than 150150 grams.

[2]
Question 20
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

A factory produces electronic components. The probability that a component is defective is 0.040.04, independently of other components. A box contains nn components.

A

Write down an expression, in terms of nn, for the probability that a box contains at least one defective component.

[2]
B

Find the smallest value of nn such that the probability that a box contains at least one defective component is greater than 0.50.5.

[2]
C

For this value of nn, find the expected number of defective components in a box.

[1]
Question 21
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

A random variable XX is normally distributed with mean μ\mu and standard deviation σ\sigma. It is known that

P(X<72)=0.12andP(X>95)=0.08P(X<72)=0.12 \quad \text{and} \quad P(X>95)=0.08
A

Write down two equations involving μ\mu and σ\sigma.

[3]
B

Determine μ\mu and σ\sigma.

[2]
C

Find the standardized value corresponding to X=90X=90.

[1]
Question 22
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The continuous random variable XX has probability density function

f(x)={kx(4x),0x4,0,otherwise.f(x)=\begin{cases} kx(4-x), & 0\leq x\leq 4,\\ 0, & \text{otherwise}. \end{cases}
A

Find kk.

[2]
B

Find P(X>3)P(X>3).

[2]
C

Find the lower quartile of XX.

[2]
Question 23
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The continuous random variable XX has probability density function

f(x)={ke0.2x,x0,0,x<0.f(x)=\begin{cases} ke^{-0.2x}, & x\geq 0,\\ 0, & x<0. \end{cases}
A

Show that k=0.2k=0.2.

[2]
B

Find P(X>8)P(X>8).

[2]
C

Find the value of mm such that P(X<m)=0.90P(X<m)=0.90.

[2]
Question 24
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The marks on a standardized test are modelled by XN(68,92)X\sim N(68,9^2). Students with a standardized value greater than 1.21.2 receive an award. A school has 5050 students taking the test, and their marks may be assumed independent.

A

Assuming that marks are whole numbers, find the minimum mark required to receive an award.

[2]
B

Find the probability that a randomly selected student receives an award.

[1]
C

Find the probability that at least 88 of the 5050 students receive an award.

[2]
D

Find the expected number of students in the school who receive an award.

[1]
Question 25
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

A discrete random variable XX has probability distribution

x0124P(X=x)p2p3p16p\begin{array}{c|cccc} x&0&1&2&4\\ \hline P(X=x)&p&2p&3p&1-6p \end{array}

where pp is a constant.

A

Find the range of possible values of pp.

[2]
B
I.

Given that E(X)=2E(X)=2, find the value of pp.

[2]
II.

Hence find P(X2)P(X\geq 2).

[1]
III.

Two independent observations of XX are made. Find the probability that their sum is at least 44. If you did not obtain a value of pp in part (b)(i), use p=18p=\frac{1}{8}.

[2]
C

In a game, a player receives 3X3X counters. Find the entry fee, in counters, that would make the game fair.

[3]
Question 26
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

A player takes five independent shots at a target. The probability of hitting the target on each shot is pp. Let XX be the number of hits. It is given that

P(X=0)=32P(X=5)P(X=0)=32P(X=5)
A

State the distribution of XX.

[1]
B
I.

Find pp.

[3]
II.

Hence find P(X=2)P(X=2).

[2]
C

Find the expected number of hits and the variance of XX. If you did not obtain a value of pp, use p=13p=\frac{1}{3}.

[2]
D

The player receives 1212 points if at least one shot hits the target, and receives 00 points otherwise. Find the fair entry fee, in points, for this game.

[2]
Question 27
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

The random variable XX is normally distributed with mean 8080. It is known that approximately 95%95\% of the values of XX lie between 6868 and 9292.

A

Find the standard deviation of XX.

[2]
B
I.

Using the empirical rule, write down the approximate value of P(74<X<86)P(74<X<86).

[1]
II.

Using the empirical rule, find the approximate value of P(X>92)P(X>92).

[2]
III.

Using the empirical rule, find the approximate value of P(68<X<86)P(68<X<86).

[1]
C

Two independent values of XX are selected. Find the approximate probability that both values are greater than 9292.

[3]
Question 28
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

The length, LL cm, of a manufactured rod is modelled by a normal distribution with mean 2020. Using the empirical rule, approximately 95%95\% of rods have lengths between 1818 cm and 2222 cm. A rod is called short if its length is less than 1919 cm.

A

Find the standard deviation of LL.

[2]
B
I.

Using the empirical rule, find the approximate probability that a rod is short.

[2]
II.

Find the approximate probability that a rod has length greater than 2222 cm.

[1]
C

Three rods are selected independently. Find the approximate probability that exactly one of them is short. If you did not obtain an answer in part (b)(i), use P(short)=0.16P(\text{short})=0.16.

[2]
D

Give two reasons why the probability found in part (c) may not be a reliable prediction for a real production line.

[2]
Question 29
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

At a school fair a game gives a score XX. The probability distribution of XX is shown in the table.

x0258P(X=x)0.18p0.22q\begin{array}{c|cccc} x&0&2&5&8\\ \hline P(X=x)&0.18&p&0.22&q \end{array}

It is known that E(X)=3.70E(X)=3.70.

A
I.

Write down an equation involving pp and qq.

[1]
II.

Find the values of pp and qq.

[3]
B
I.

Find P(X5)P(X\ge 5).

[1]
II.

The game is played twice independently. Find the probability that the total score is at least 1010. If you did not obtain values for pp and qq, use p=1130p=\frac{11}{30} and q=730q=\frac{7}{30}.

[3]
C

In a different game using the same score XX, a player receives $3 if X=5X=5, receives $10 if X=8X=8, and receives nothing otherwise. Find the entry fee that would make this game fair.

[3]
Question 30
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

An airline finds that each passenger who buys a ticket for a particular short flight independently has probability 0.080.08 of not arriving for the flight.

A

For a flight with 1818 tickets sold, let XX be the number of passengers who do not arrive.

I.

State the distribution of XX.

[1]
II.

Find P(X=2)P(X=2).

[2]
III.

Find the expected number of passengers who do not arrive.

[2]
B

For a separate flight scenario, the aircraft has 1818 seats. The airline decides to sell 2020 tickets. Let YY be the number of passengers who arrive for the flight.

I.

State the distribution of YY.

[1]
II.

Find the probability that more passengers arrive than there are seats.

[2]
III.

The airline pays $60 compensation for each passenger who arrives but cannot be seated. Find the expected compensation paid on one such flight.

[2]
C

State one reason why the binomial model for the number of passengers who arrive may not be appropriate in this context.

[2]
Question 31
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

The time TT minutes taken by a courier to complete a delivery route is modelled by TN(32,4.52)T\sim N(32,4.5^2). A route taking more than 3838 minutes is called late.

A
I.

Find the probability that a route is late.

[2]
II.

Twenty-five routes are completed independently. Find the probability that at most one of them is late. If you did not obtain an answer to part (a)(i), use 0.09120.0912.

[3]
B
I.

Find the 9595th percentile of the delivery route times.

[2]
II.

The company pays a $5 refund for a late route and an additional $10 refund if the route takes more than 4242 minutes. Find the expected refund for 100100 independent routes.

[2]
C

Give one reason why the normal model may not be suitable for delivery times on all days.

[2]
Question 32
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

A new website advertises a subscription service. Each visitor independently has probability 0.0350.035 of buying a subscription. In a campaign with 120120 independent visitors, let XX be the number of visitors who buy a subscription.

A

In one advertising campaign there are 120120 visitors. Let XX be the number of visitors who buy a subscription.

I.

State the distribution of XX.

[1]
II.

Find P(X3)P(X\le 3).

[2]
III.

Find E(X)E(X) and Var(X)\operatorname{Var}(X).

[2]
B
I.

Each subscription gives the website revenue of $18. Find the expected revenue from the 120120 visitors.

[1]
II.

The campaign has a fixed cost of $c. Find cc if the expected profit is zero.

[2]
C

Find the smallest number of independent visitors required so that the probability of at least one subscription is greater than 0.950.95.

[2]
Question 33
SL • Paper 1
Hard
Non Calculator
SL • Paper 1
Hard
Non Calculator

Two spinners, AA and BB, are spun independently. Let AA be the score on the first spinner, with probability distribution

a1234P(A=a)12141818\begin{array}{c|cccc} a&1&2&3&4\\ \hline P(A=a)&\frac{1}{2}&\frac{1}{4}&\frac{1}{8}&\frac{1}{8} \end{array}

Let BB be the score on the second spinner, where

P(B=1)=q,P(B=2)=2q,P(B=5)=13qP(B=1)=q,\quad P(B=2)=2q,\quad P(B=5)=1-3q
A

Find E(A)E(A).

[2]
B
I.

Find the range of possible values of qq.

[2]
II.

Find E(B)E(B) in terms of qq.

[2]
C

It is given that P(B>A)=12P(B>A)=\frac12. Find qq.

[3]
D

A game is played by spinning both spinners once. The player's gain is BAcB-A-c, where cc is an entry fee. Find cc so that the game is fair. If you did not obtain qq, use q=14q=\frac14.

[3]
Question 34
SL • Paper 1
Hard
Non Calculator
SL • Paper 1
Hard
Non Calculator

A student answers nn independent multiple-choice questions. The probability that the student answers any one question correctly is pp. Let XX be the number of correct answers. It is given that

E(X)=3andVar(X)=2E(X)=3\quad\text{and}\quad \operatorname{Var}(X)=2
A
I.

Write down two equations involving nn and pp.

[2]
II.

Hence find nn and pp.

[2]
B

Find the probability that the student answers no questions correctly. If you did not obtain values for nn and pp, use n=9n=9 and p=13p=\frac13.

[2]
C

A prize of 55 points is awarded for each correct answer, but a fixed penalty of dd points is deducted. Find dd so that the expected score is 88 points.

[2]
D

State two assumptions, other than independence, needed for this binomial model to be appropriate.

[2]
Question 35
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

A random variable XX is normally distributed with mean μ\mu and standard deviation σ\sigma. The value 3535 has standardized value 2-2, and the value 5050 has standardized value 11. Let ZN(0,1)Z\sim N(0,1) and let P(Z<1)=qP(Z<1)=q.

A
I.

Write down two equations involving μ\mu and σ\sigma.

[2]
II.

Hence find μ\mu and σ\sigma.

[2]
B

Express P(40<X<50)P(40<X<50) in terms of qq.

[3]
C

Find the value of xx such that P(X>x)=P(X<35)P(X>x)=P(X<35).

[2]
Question 36
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

A discrete random variable XX has probability distribution

x1124P(X=x)p2pp14p\begin{array}{c|cccc} x&-1&1&2&4\\ \hline P(X=x)&p&2p&p&1-4p \end{array}

It is given that E(X)=2E(X)=2.

A
I.

Find pp.

[2]
II.

Find E(X2)E(X^2). If you did not obtain pp, use p=213p=\frac{2}{13}.

[3]
B

Find Var(X)\operatorname{Var}(X).

[2]
C

Let Y=32XY=3-2X. Find E(Y)E(Y) and Var(Y)\operatorname{Var}(Y).

[2]
D

Find the possible values of aa such that Var(aX+5)=42\operatorname{Var}(aX+5)=42.

[2]
Question 37
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

A continuous random variable XX has probability density function

f(x)={asinx,0xπ,0,otherwise.f(x)=\begin{cases} a\sin x,&0\leq x\leq \pi,\\ 0,&\text{otherwise.} \end{cases}
A
I.

Show that a=12a=\frac12.

[2]
II.

State the mode of XX.

[1]
III.

Find P(X<π6)P\left(X<\frac{\pi}{6}\right).

[1]
B

Show that the median of XX is π2\frac{\pi}{2}.

[2]
C

Find E(X)E(X).

[2]
D

Give a reason why the answers to parts (b) and (c) are equal.

[2]
Question 38
SL • Paper 2
Hard
Calculator Permitted
SL • Paper 2
Hard
Calculator Permitted

A cafe uses two machines to fill cups of coffee. The volume AA ml from machine A is normally distributed with mean 250250 and standard deviation 66. The volume BB ml from machine B is normally distributed with mean 255255 and standard deviation 55. On a particular day, 70%70\% of cups are filled by machine A and the rest by machine B. A cup is selected at random.

A
I.

Find the probability that a cup filled by machine A contains less than 245245 ml.

[2]
II.

Find the probability that the selected cup contains less than 245245 ml.

[2]
B
I.

Given that the selected cup contains less than 245245 ml, find the probability that it was filled by machine A.

[3]
II.

Twelve cups are selected independently from all cups filled that day. Find the probability that at least three contain less than 245245 ml. If you did not obtain an answer to part (a)(ii), use 0.1480.148.

[2]
C

The cafe wants to label the largest 10%10\% of cups filled by machine A as extra-full. Find the minimum volume for this label.

[3]
Question 39
SL • Paper 2
Hard
Calculator Permitted
SL • Paper 2
Hard
Calculator Permitted

The length LL cm of a fish in a lake is modelled by LN(34,3.22)L\sim N(34,3.2^2). A fish is classified as undersized if L<30L<30, and large if L>38L>38.

A

(a)

I.

Find the probability that a randomly selected fish is undersized.

[2]
II.

Find the probability that a fish has length between 3030 cm and 3838 cm.

[2]
B

(b)

I.

In a sample of 4040 independently selected fish, find the probability that fewer than three are undersized. If you did not obtain an answer to part (a)(i), use 0.1060.106.

[3]
II.

Find the expected number of large fish in 200200 independently selected fish.

[1]
C

Find the value of kk such that P(34k<L<34+k)=0.90P(34-k<L<34+k)=0.90.

[3]
Question 40
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The time TT minutes taken by runners in a long race is modelled by a normal distribution with mean μ\mu and standard deviation σ\sigma. It is known that P(T<210)=0.18P(T<210)=0.18 and P(T<260)=0.92P(T<260)=0.92.

A
I.

Write down two equations involving μ\mu and σ\sigma using standardized values.

[2]
II.

Hence find μ\mu and σ\sigma.

[3]
B
I.

Find P(220<T<250)P(220<T<250). If you did not obtain values for μ\mu and σ\sigma, use μ=229.72\mu=229.72 and σ=21.55\sigma=21.55 for subsequent calculations; otherwise use your unrounded values.

[2]
II.

A runner is in the fastest 5%5\% if their time is less than rr minutes. Find rr to 3 significant figures. If you did not obtain values for μ\mu and σ\sigma, use μ=229.72\mu=229.72 and σ=21.55\sigma=21.55 for this calculation; otherwise use your unrounded values.

[2]
C

Sixteen runners are selected independently. Find the probability that at least four of them finish in less than 210210 minutes.

[3]
Question 41
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The number of claims NN made by a customer in one year has probability distribution

n0125P(N=n)a3a0.250.15\begin{array}{c|cccc} n&0&1&2&5\\ \hline P(N=n)&a&3a&0.25&0.15 \end{array}

The annual cost to an insurer, in dollars, is C=200N+80C=200N+80.

A
I.

Find aa.

[2]
II.

Find E(N)E(N).

[1]
III.

Find Var(N)\operatorname{Var}(N).

[2]
B
I.

Find E(C)E(C).

[2]
II.

Find Var(C)\operatorname{Var}(C). If you did not obtain Var(N)\operatorname{Var}(N), use 2.312.31.

[2]
C

A premium PP dollars is charged. A loss is made by the insurer if C>PC>P.

I.

Find the premium that makes the expected profit zero.

[1]
II.

Determine the smallest whole-number premium such that the probability of a loss is at most 0.200.20.

[2]
Question 42
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Readings RR from an environmental sensor are modelled by a normal distribution with mean μ\mu and standard deviation σ\sigma. It is known that

P(R<18)=0.10,P(R>30)=0.05P(R<18)=0.10,\qquad P(R>30)=0.05
A
I.

Write down two equations involving μ\mu and σ\sigma using standardized values.

[2]
II.

Determine μ\mu and σ\sigma.

[3]
B
I.

Find the standardized value corresponding to R=27R=27.

[2]
II.

An alert is triggered when R>27R>27. Find the probability that an alert is triggered.

[2]
C
I.

Over 3030 independent days, find the probability that alerts are triggered on at least 88 days. If you did not obtain an answer to part (b)(ii), use 0.1800.180.

[2]
II.

Determine the alert threshold hh such that the expected number of alerts in 3030 independent days is 33.

[1]
Question 43
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A game uses a spinner which gives a score X{0,1,2,3}X\in\{0,1,2,3\}. The probability of score xx is modelled by

P(X=x)=k(x+θ),x=0,1,2,3P(X=x)=k(x+\theta), \quad x=0,1,2,3

where θ>0\theta>0. A player pays an entry fee and then receives two tokens for each point scored.

Score, xx

Probability, P(X=x)P(X=x)

0

kθk\theta

1

k(1+θ)k(1+\theta)

2

k(2+θ)k(2+\theta)

3

k(3+θ)k(3+\theta)

A
I.

Show that k=16+4θk=\dfrac{1}{6+4\theta}.

[2]
II.

Find E(X)E(X) in terms of θ\theta.

[2]
B

It is found from many trials that the mean score is approximately 1.901.90. Determine the value of θ\theta predicted by the model.

[2]
C
I.

Find the entry fee, in tokens, which makes the original game fair.

[1]
II.

For this value of θ\theta, find the variance of the player's net gain when the fair entry fee is used.

[3]
D

A modified game charges 3.503.50 tokens but limits the number of tokens received to a maximum of 33. Determine whether this modified game is favourable to the player in the long run.

[3]
Question 44
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A security system consists of independent sensors. In one installation there are 88 sensors, each of which detects movement with probability pp. The probability that at least one sensor detects movement is 0.7600.760.

A schematic diagram of a room with several identical sensors positioned around it. Each sensor has the same detection probability and sensors are labelled as acting independently.
A
I.

Show that p0.163p\approx 0.163.

[2]
II.

State the distribution of YY, the number of detections in 2020 independent sensors of the same type.

[1]
III.

Find E(Y)E(Y).

[1]
B

Find the probability that at least 44 of the 2020 sensors detect movement.

[2]
C

Determine the smallest number of independent sensors required so that the probability of at least one detection is greater than 0.990.99.

[3]
D

Comment on one modelling assumption that may be invalid if the sensors are placed very close together.

[2]
Question 45
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

The volume XX ml in bottles filled by a machine is modelled by a normal distribution N(μ,σ2)N(\mu,\sigma^2). It is known that P(X<490)=0.04P(X<490)=0.04 and P(X>515)=0.10P(X>515)=0.10.

Normal density of bottle volumes with cut lines at 490 ml and 515 ml.
A
I.

Write down two equations involving μ\mu and σ\sigma.

[2]
II.

Determine μ\mu and σ\sigma.

[3]
B

Find P(500<X<510)P(500<X<510).

[2]
C

Twelve bottles are selected independently. Find the probability that at least 77 have volumes between 500500 ml and 510510 ml. If you did not obtain an answer to part (b), use 0.4550.455.

[3]
D

Find the value of aa such that P(μa<X<μ+a)=0.98P(\mu-a<X<\mu+a)=0.98.

[3]
Question 46
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A continuous random variable XX has probability density function

f(x)={kx(6x),0x6,0,otherwise.f(x)=\begin{cases} kx(6-x), & 0\le x\le 6,\\ 0, & \text{otherwise.} \end{cases}
Unscaled qualitative sketch of the parabolic shape of f(x) on its support.
A
I.

Show that k=136k=\dfrac{1}{36}.

[2]
II.

Find P(X>4)P(X>4).

[2]
B

Find E(X)E(X) and Var(X)\operatorname{Var}(X).

[4]
C

Explain why the median of XX is 33.

[2]
D

A new random variable is defined by Y=102XY=10-2X. Find E(Y)E(Y) and Var(Y)\operatorname{Var}(Y).

[2]
Question 47
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A website records whether it has at least one service interruption on each day. The events on different days are modelled as independent. From historical data, the probability of no service interruptions in a period of 3030 days is 0.2140.214.

Context

Length / days

Relevant data

Historical 30-day period

30

P(no interruption in all 30 days)=0.214P(\text{no interruption in all 30 days})=0.214

Future 90-day period

90

X=X= number of days with at least one interruption

Model assumption

Days are independent; daily interruption probability (p) is constant

A
I.

Show that the model gives a daily interruption probability of approximately 0.05010.0501.

[2]
II.

For a future period of 9090 days, state the distribution of XX, the number of days with at least one interruption.

[1]
III.

Find the mean number of days with interruptions in this 9090-day period.

[1]
B

Find the probability that there are fewer than 33 days with interruptions in a future 9090-day period. Give your answer to 3 significant figures.

[2]
C

Determine the smallest integer kk such that P(Xk)0.95P(X\le k)\ge 0.95.

[3]
D

The website manager suspects that after one interruption, another interruption is more likely on the following day. Explain how this would affect the suitability of the binomial model.

[2]
Question 48
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

An insurance policy covers the number of claims NN made by one customer in a year. The distribution is shown in the table.

n01234P(N=n)a2a3a2aa\begin{array}{c|ccccc} n&0&1&2&3&4\\ \hline P(N=n)&a&2a&3a&2a&a \end{array}

The annual cost to the insurer, in units, is C=120N+50C=120N+50.

n

P(N=n)

C [units]

0

a

50

1

2a

170

2

3a

290

3

2a

410

4

a

530

A
I.

Find aa.

[1]
II.

Find E(N)E(N) and Var(N)\operatorname{Var}(N).

[4]
B

Find E(C)E(C) and Var(C)\operatorname{Var}(C).

[3]
C

A premium PP is charged. Find the premium which makes the expected annual profit zero.

[1]
D

The insurer wants the probability of making a loss on this customer to be at most 0.200.20. Determine the smallest premium, in whole units, which achieves this.

[2]
Question 49
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Scores in two aptitude tests are modelled by normal distributions. Test A scores are modelled by AN(82,62)A\sim N(82,6^2). Test B scores are modelled by BN(μ,σ2)B\sim N(\mu,\sigma^2). For Test B, P(B<74)=0.08P(B<74)=0.08 and P(B>94)=0.15P(B>94)=0.15.

Normal score distributions for Tests A and B.
A
I.

Find the standardized value corresponding to a Test A score of 9090.

[1]
II.

Find P(A>90)P(A>90).

[2]
B

Determine μ\mu and σ\sigma for Test B.

[4]
C

A certificate is awarded to the top 10%10\% of Test B candidates. Find the minimum Test B score required for a certificate.

[2]
D

A student scores 9292 on Test A and 9292 on Test B. Determine on which test the student performed better relative to the test population. Justify your answer.

[3]
Question 50
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

The length LL mm of a manufactured part is modelled by LN(100,2.52)L\sim N(100,2.5^2). A part is classified as acceptable if 96<L<10496<L<104. A batch contains independently produced parts.

Normal density of part lengths with limits at 96 and 104 mm.
A
I.

Find the probability that a randomly selected part is acceptable.

[2]
II.

State the distribution of XX, the number of acceptable parts in a batch of 1515 parts.

[1]
III.

Find E(X)E(X).

[1]
B

Find the probability that at least 1414 parts in a batch of 1515 are acceptable.

[2]
C

Determine the smallest batch size nn for which the expected number of unacceptable parts is greater than 55.

[2]
D

Find the greatest batch size nn for which the probability that all parts are acceptable is greater than 0.50.5.

[2]
Question 51
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A training app gives a user 2020 independent questions. For this user, the probability of answering any one question correctly is 0.720.72. Let XX be the number of correct answers.

A simple interface-style diagram showing a sequence of identical quiz questions, each with two possible outcomes, correct or incorrect. The diagram emphasizes independent trials with the same success probability.
A
I.

State the distribution of XX.

[1]
II.

Find E(X)E(X) and Var(X)\operatorname{Var}(X).

[2]
B

Find P(X16)P(X\ge 16).

[2]
C

A badge is awarded if the user answers at least rr questions correctly. Determine the smallest value of rr such that the probability of receiving the badge is less than 0.100.10.

[3]
D

The app charges an entry fee of ee tokens and gives a prize of 5050 tokens if the badge is awarded. For r=18r=18, find the fair entry fee.

[2]
Question 52
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

A continuous random variable XX has probability density function

f(x)={k(1+x),0x2,0,otherwise.f(x)=\begin{cases} k(1+x),&0\leq x\leq 2,\\ 0,&\text{otherwise.} \end{cases}
A
I.

Find kk.

[2]
II.

Find the cumulative distribution function F(x)F(x) for 0x20\leq x\leq 2.

[3]
B

Find the median of XX.

[3]
C

Find E(X)E(X) and Var(X)\operatorname{Var}(X).

[3]
Question 53
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

A continuous random variable TT has probability density function

f(t)={ket,t0,0,t<0.f(t)=\begin{cases} ke^{-t},&t\geq 0,\\ 0,&t<0. \end{cases}
A
I.

Show that k=1k=1.

[2]
II.

Find P(T>a)P(T>a), where a0a\geq 0.

[2]
III.

Find the median of TT.

[1]
B

Find E(T)E(T).

[2]
C

Given that E(T2)=2E(T^2)=2, find Var(T)\operatorname{Var}(T).

[2]
D

A machine is replaced at time cc. Find cc such that the probability that the machine lasts longer than cc is equal to the median of TT divided by 44.

[3]
Question 54
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

A random variable XX is normally distributed with mean μ\mu and standard deviation σ\sigma. The value 7272 has standardized value 1-1, and the value 8484 has standardized value 12\frac12. Let ZN(0,1)Z\sim N(0,1), with P(Z<1)=aP(Z<1)=a and P(Z<2)=bP(Z<2)=b.

A
I.

Write down two equations involving μ\mu and σ\sigma.

[2]
II.

Hence find μ\mu and σ\sigma.

[2]
B

Express P(64<X<88)P(64<X<88) in terms of aa and bb.

[3]
C

Four independent observations of XX are made. Find, in terms of aa, the probability that exactly three of the observations are greater than 8888.

[3]
Question 55
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The continuous random variable XX has probability density function

f(x)={c(x+1),0x2,c(5x),2<x5,0,otherwise.f(x)=\begin{cases} c(x+1),&0\le x\le 2,\\ c(5-x),&2<x\le 5,\\ 0,&\text{otherwise.} \end{cases}
Probability density function of X on its support.
A
I.

Show that c=217c=\dfrac{2}{17}.

[3]
II.

State the mode of XX.

[1]
III.

Find P(1<X<3)P(1<X<3).

[1]
B

Find the median of XX.

[4]
C
I.

Find E(X)E(X).

[2]
II.

Find Var(X)\operatorname{Var}(X). If you did not obtain an answer to part (c)(i), use E(X)=2.14E(X)=2.14.

[3]
Question 56
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

For a>1a>-1, the continuous random variable XX has probability density function

f(x)={k(1+ax2),0x1,0,otherwise.f(x)=\begin{cases} k(1+ax^2),&0\le x\le 1,\\ 0,&\text{otherwise.} \end{cases}

It is given that E(X)=0.580E(X)=0.580.

A
I.

Show that k=11+a3k=\dfrac{1}{1+\frac{a}{3}}.

[2]
II.

Find the value of aa.

[3]
B

Use a=2417a=\dfrac{24}{17} for this part.

I.

Find P(X<0.4)P(X<0.4).

[2]
II.

State the mode of XX, giving a reason.

[2]
C
I.

Find the median of XX.

[2]
II.

Find Var(X)\operatorname{Var}(X). If you did not obtain a value for aa, use a=1.41a=1.41.

[2]
Question 57
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The continuous random variable XX has probability density function

f(x)={k(4(x1)2),1x3,0,otherwise.f(x)=\begin{cases} k\left(4-(x-1)^2\right),&-1\le x\le 3,\\ 0,&\text{otherwise.} \end{cases}

A new random variable is defined by Y=50+10XY=50+10X.

Probability density function of X on [-1, 3], a symmetric downward-opening parabola.
A
I.

Show that k=332k=\dfrac{3}{32}.

[3]
II.

Find P(X>2)P(X>2).

[2]
B
I.

Find E(X)E(X), giving a reason.

[2]
II.

Find Var(X)\operatorname{Var}(X).

[2]
C
I.

Find E(Y)E(Y) and Var(Y)\operatorname{Var}(Y).

[2]
II.

Find the value of cc such that P(Y>c)=0.100P(Y>c)=0.100.

[2]
Question 58
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

For t>1t>-1, a continuous random variable XX has density

ft(x)={c(1+tx),0x1,0,otherwise.f_t(x)=\begin{cases} c(1+tx), & 0\le x\le 1,\\ 0, & \text{otherwise.} \end{cases}

This family is used to model a measurement that may be biased towards larger or smaller values.

Three linear densities from the same family.
A
I.

Find cc in terms of tt.

[2]
II.

Find E(X)E(X) in terms of tt.

[2]
B

It is known that the median is 0.6000.600. Determine tt.

[3]
C

For this value of tt, find the mode and the mean.

[2]
D

Prove that, for this family, E(X)>12E(X)>\dfrac12 if and only if t>0t>0.

[2]
Question 59
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

The waiting time XX minutes for a response from an automated system has probability density function

f(x)={k(x+1)ex,x0,0,x<0.f(x)=\begin{cases} k(x+1)e^{-x}, & x\ge 0,\\ 0, & x<0. \end{cases}
Probability density curve for waiting time X, shown without the exact intercept.
A
I.

Show that k=12k=\dfrac12.

[2]
II.

Find the cumulative distribution function F(x)F(x) for x0x\ge 0.

[2]
B

Find E(X)E(X) and Var(X)\operatorname{Var}(X).

[4]
C

Determine the median waiting time.

[2]
D

A response taking more than 33 minutes is described as delayed. Find the probability that, in 1010 independent responses, at least one is delayed.

[2]
Question 60
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

For a>1a>1, a continuous random variable XX has probability density function

f(x)={kx,0x<1,k,1x<a,k(a+1x),axa+1,0,otherwise.f(x)=\begin{cases} kx, & 0\le x<1,\\ k, & 1\le x<a,\\ k(a+1-x), & a\le x\le a+1,\\ 0, & \text{otherwise.} \end{cases}

This density has a flat central section and two sloping sides.

x interval

f(x)

0 ≤ x < 1

kx

1 ≤ x < a

k

a ≤ x ≤ a+1

k(a+1-x)

otherwise

0

A
I.

Show that k=1ak=\dfrac1a.

[2]
II.

Explain why the distribution is symmetric about x=a+12x=\dfrac{a+1}{2}.

[2]
B

It is known that E(X)=2.5E(X)=2.5. Determine aa.

[2]
C

For a=4a=4, find P(X<1.5)P(X<1.5).

[2]
D

For a=4a=4, find Var(X)\operatorname{Var}(X).

[3]
E

State the median when a=4a=4, giving a reason.

[2]

Bivariate Statistics

Probability