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Matrices

Practice exam-style IB Math AI questions for Matrices, aligned with the syllabus and grouped by topic.

Verified by Karim
Verified by Karim
Paper
Difficulty
Status
Level
Question 1
HL • Paper 1
Easy
Calculator Permitted
HL • Paper 1
Easy
Calculator Permitted

Let

A=(213041),B=(123021)A=\begin{pmatrix}2&-1&3\\0&4&1\end{pmatrix},\qquad B=\begin{pmatrix}1&2\\3&0\\-2&1\end{pmatrix}
A

State the orders of ABAB and BABA.

[1]
B

Calculate ABAB.

[2]
C

Calculate BABA and hence explain why AA and BB do not commute.

[2]
Question 2
HL • Paper 1
Easy
Calculator Permitted
HL • Paper 1
Easy
Calculator Permitted

A shop sells three models of headphones. The numbers sold during two weeks are represented by

Q=(402530353228)Q=\begin{pmatrix}40&25&30\\35&32&28\end{pmatrix}

The selling prices and unit costs, in dollars, are

p=(12189),c=(7115)p=\begin{pmatrix}12\\18\\9\end{pmatrix},\qquad c=\begin{pmatrix}7\\11\\5\end{pmatrix}
A

Calculate the revenue in each week.

[2]
B

Calculate the profit in each week.

[2]
C

State which week had the greater profit and by how much.

[1]
Question 3
HL • Paper 2
Easy
Calculator Permitted
HL • Paper 2
Easy
Calculator Permitted

A pair of numbers is encoded using y=Aq\mathbf{y}=A\mathbf{q}, where

A=(2113)A=\begin{pmatrix}2&1\\-1&3\end{pmatrix}
A

Find A1A^{-1}.

[2]
B

An encoded column is y=(1716)\mathbf{y}=\begin{pmatrix}17\\16\end{pmatrix}. Decode this column.

[2]
C

Encode the column (84)\begin{pmatrix}8\\4\end{pmatrix}.

[1]
Question 4
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

The matrices AA, BB, CC and XX satisfy AX+B=CAX+B=C, where

A=(3121),B=(1204),C=(9561)A=\begin{pmatrix}3&1\\2&1\end{pmatrix},\quad B=\begin{pmatrix}1&-2\\0&4\end{pmatrix},\quad C=\begin{pmatrix}9&5\\6&1\end{pmatrix}
A

Find A1A^{-1}.

[2]
B

Solve for XX.

[3]
Question 5
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

A manufacturer combines xx kg of material A, yy kg of material B and zz kg of material C. The mixture has a total mass of 100100 kg. The materials provide 22, 33 and 55 nutrient units per kg respectively, and the mixture must provide 380380 nutrient units. Their costs are $4, $6 and $3 per kg respectively, and the total cost is $410.

A

Write the information as a matrix equation of the form Ax=bA\mathbf{x}=\mathbf{b}.

[2]
B

Use an inverse matrix to determine xx, yy and zz.

[3]
C

Find the percentage by mass of material C in the mixture.

[1]
Question 6
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

Consider the matrix

A=(k23k1)A=\begin{pmatrix}k&2\\3&k-1\end{pmatrix}

where kRk\in\mathbb{R}.

A

Find the values of kk for which AA is singular.

[2]
B

Find A1A^{-1} when k=4k=4.

[2]
Question 7
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

Matrices AA, BB and XX satisfy XA=BXA=B, where

A=(1235),B=(4123)A=\begin{pmatrix}1&2\\3&5\end{pmatrix},\qquad B=\begin{pmatrix}4&1\\-2&3\end{pmatrix}
A

Find A1A^{-1}.

[1]
B

Solve for XX.

[2]
C

Explain why using X=A1BX=A^{-1}B is not valid.

[1]
Question 8
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

At a theatre, adult tickets cost $18, student tickets cost $12 and child tickets cost $7. A total of 250250 tickets were sold for $3470. The number of adult tickets sold was 4040 more than the number of student tickets sold.

A

Represent the information as a matrix equation, using aa, ss and cc for the numbers of adult, student and child tickets.

[2]
B

Use an inverse matrix to determine the number of each type of ticket sold.

[2]
C

Find the percentage of the tickets sold that were child tickets.

[1]
Question 9
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

Let

M=(4213)M=\begin{pmatrix}4&2\\1&3\end{pmatrix}
A

Find the characteristic polynomial of MM.

[2]
B

Hence find the eigenvalues of MM.

[1]
C

Find an eigenvector corresponding to each eigenvalue.

[2]
Question 10
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

A two-region model is represented by

sn+1=Msn,M=(0.720.180.280.82)\mathbf{s}_{n+1}=M\mathbf{s}_n,\qquad M=\begin{pmatrix}0.72&0.18\\0.28&0.82\end{pmatrix}

The total population of the two regions is 50005000.

A

Given that s0=(30002000)\mathbf{s}_0=\begin{pmatrix}3000\\2000\end{pmatrix}, find s1\mathbf{s}_1.

[2]
B

Find the invariant state with total population 50005000.

[2]
C

State the eigenvalue associated with the invariant state and justify your answer.

[1]
Question 11
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

The matrix

M=(k213)M=\begin{pmatrix}k&2\\1&3\end{pmatrix}

has eigenvalue 55.

A

Determine the value of kk.

[2]
B

Find an eigenvector corresponding to the eigenvalue 55.

[1]
C

Find the other eigenvalue of MM.

[1]
Question 12
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

The matrix

M=(3122)M=\begin{pmatrix}3&1\\2&2\end{pmatrix}

has eigenvalues 44 and 11. Corresponding eigenvectors are (11)\begin{pmatrix}1\\1\end{pmatrix} and (12)\begin{pmatrix}1\\-2\end{pmatrix} respectively.

A

Write down matrices PP and DD such that M=PDP1M=PDP^{-1}.

[2]
B

Find P1P^{-1}.

[1]
C

Hence calculate M5M^5.

[3]
Question 13
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Each year, 85%85\% of the residents of town A remain in A and 15%15\% move to town B. Of the residents of town B, 80%80\% remain in B and 20%20\% move to town A. Initially, town A has 60006000 residents and town B has 40004000 residents. Assume the total population remains constant. Let sn=(AnBn)\mathbf{s}_n=\begin{pmatrix}A_n\\B_n\end{pmatrix}, where AnA_n and BnB_n are the populations of towns A and B, respectively, after nn years.

A

Write down the transition matrix MM such that sn+1=Msn\mathbf{s}_{n+1}=M\mathbf{s}_n.

[1]
B

Calculate the population of each town after 88 years.

[2]
C

Determine the long-term population of each town.

[3]
Question 14
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

The populations, in hundreds, of two interacting species are modelled by

sn+1=Msn,M=(1.10.20.10.8)\mathbf{s}_{n+1}=M\mathbf{s}_n,\qquad M=\begin{pmatrix}1.1&0.2\\0.1&0.8\end{pmatrix}

Initially, s0=(400100)\mathbf{s}_0=\begin{pmatrix}400\\100\end{pmatrix}.

A

Calculate s1\mathbf{s}_1.

[1]
B

Calculate s6\mathbf{s}_6.

[2]
C

Find the dominant eigenvalue of MM.

[1]
D

Determine the long-term ratio of the first species population to the second species population, and interpret the dominant eigenvalue.

[2]
Question 15
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

Let

M=(2112)M=\begin{pmatrix}2&1\\1&2\end{pmatrix}

The eigenvalues of MM are 33 and 11.

A

Find corresponding eigenvectors and hence write M=PDP1M=PDP^{-1}.

[2]
B

Hence find an expression for MnM^n, where nn is a positive integer.

[2]
C

Find the least positive integer nn for which the element in row 11, column 22 of MnM^n is greater than 10001000.

[2]
Question 16
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

A simplified population model is defined by

sn+1=Msn,M=(1110),s0=(10)\mathbf{s}_{n+1}=M\mathbf{s}_n,\qquad M=\begin{pmatrix}1&1\\1&0\end{pmatrix},\qquad \mathbf{s}_0=\begin{pmatrix}1\\0\end{pmatrix}
A

Find the eigenvalues of MM in exact form.

[2]
B

Find an eigenvector corresponding to each eigenvalue.

[2]
C

Using diagonalization, calculate s10\mathbf{s}_{10}.

[2]
Question 17
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

A bakery produces rolls, cakes and pies. The numbers produced on Monday and Tuesday are represented by

Q=(12080601507090)Q=\begin{pmatrix}120&80&60\\150&70&90\end{pmatrix}

The flour and sugar required per item, in kilograms, are represented by

R=(0.200.050.350.080.150.03)R=\begin{pmatrix}0.20&0.05\\0.35&0.08\\0.15&0.03\end{pmatrix}

where the first column represents flour and the second column represents sugar.

A
I.

State the order of the matrix QRQR.

[1]
II.

Calculate QRQR and interpret its elements.

[2]
B

Flour costs 1.40 dollars per kilogram and sugar costs 2.20 dollars per kilogram. Calculate the ingredient cost for each day.

[2]
C

On Wednesday, 400400 items are produced, using 105105 kg of flour and 2424 kg of sugar. Let xx, yy and zz be the numbers of rolls, cakes and pies produced. Use an inverse matrix to determine xx, yy and zz.

[3]
Question 18
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

A coding system encodes a block q\mathbf q of three numbers using y=Aq\mathbf y=A\mathbf q, where

A=(120011201)A=\begin{pmatrix}1&2&0\\0&1&1\\2&0&1\end{pmatrix}
A
I.

Calculate det(A)\det(A).

[1]
II.

Hence explain why every encoded block can be decoded uniquely.

[2]
B
I.

Find A1A^{-1}.

[2]
II.

Decode y=(131314)\mathbf y=\begin{pmatrix}13\\13\\14\end{pmatrix}.

[1]
C

A second coding matrix is

B=(120011131)B=\begin{pmatrix}1&2&0\\0&1&1\\1&3&1\end{pmatrix}

Show that this matrix is unsuitable for unique decoding.

[2]
Question 19
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

A two-component production column q\mathbf q is processed first by a packaging matrix PP and then by a transport matrix TT, where

P=(211302),T=(10.520.210.5),q=(4030)P=\begin{pmatrix}2&1\\1&3\\0&2\end{pmatrix}, \qquad T=\begin{pmatrix}1&0.5&2\\0.2&1&0.5\end{pmatrix}, \qquad \mathbf q=\begin{pmatrix}40\\30\end{pmatrix}
A process diagram showing the production column $\mathbf q$ passing first through operation $P$ and then through operation $T$, with arrows indicating the order of multiplication. The output is shown only as an unlabeled placeholder; no numerical output vector is displayed.
A
I.

Calculate PqP\mathbf q.

[2]
II.

Hence calculate T(Pq)T(P\mathbf q).

[2]
B

Calculate TPTP and verify that (TP)q=T(Pq)(TP)\mathbf q=T(P\mathbf q).

[2]
C

The final output is (295182)\begin{pmatrix}295\\182\end{pmatrix}. Use an inverse matrix to recover the original production column.

[2]
Question 20
HL • Paper 3
Medium
Calculator Permitted
HL • Paper 3
Medium
Calculator Permitted

Two digital filters act on a signal vector. Their matrices are

S=(1201),T=(2011)S=\begin{pmatrix}1&2\\0&1\end{pmatrix},\qquad T=\begin{pmatrix}2&0\\1&1\end{pmatrix}

and the initial signal is v=(34)\mathbf{v}=\begin{pmatrix}3\\4\end{pmatrix}.

A
I.

Find the output when filter SS is applied first and filter TT second.

[2]
II.

Find the output when the order of the filters is reversed.

[2]
B

Calculate STST and TSTS. Hence explain why the order in which the filters are applied is significant, despite matrix multiplication being associative.

[4]
Question 21
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Three sensors measure environmental quantities xx, yy and zz. Their readings satisfy

2x+yz=7,x+3y+2z=11,3xy+z=3.\begin{aligned} 2x+y-z&=7,\\ x+3y+2z&=11,\\ 3x-y+z&=3. \end{aligned}
A

(a)

I.

Write the system as a matrix equation Ax=bA\mathbf x=\mathbf b.

[2]
II.

Use an inverse matrix to solve the system.

[3]
B

A recalibration changes the right-hand-side vector by Δb=(011)\Delta\mathbf b=\begin{pmatrix}0\\1\\-1\end{pmatrix}.

I.

Find the corresponding change Δx\Delta\mathbf x in the solution.

[2]
II.

Hence state the recalibrated values of xx, yy and zz. If you did not obtain Δx\Delta\mathbf x, use (0.20.40)\begin{pmatrix}-0.2\\0.4\\0\end{pmatrix}.

[2]
Question 22
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The matrices AA, BB, CC and XX satisfy AXB=CAXB=C, where

A=(1201),B=(2011),C=(15573)A=\begin{pmatrix}1&2\\0&1\end{pmatrix},\quad B=\begin{pmatrix}2&0\\1&1\end{pmatrix},\quad C=\begin{pmatrix}15&5\\7&3\end{pmatrix}
A
I.

Find A1A^{-1} and B1B^{-1}.

[2]
II.

Show that X=A1CB1X=A^{-1}CB^{-1}.

[2]
B

Hence determine XX.

[2]
C

A student claims that X=B1CA1X=B^{-1}CA^{-1}. Explain why this rearrangement is invalid.

[2]
Question 23
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Customers subscribe to either a basic service or a premium service. Each month, 80%80\% of basic subscribers remain on basic and 75%75\% of premium subscribers remain on premium. Initially there are 540540 basic and 360360 premium subscribers. The total number of subscribers remains constant.

A two-state transition diagram labelled Basic and Premium, showing monthly movement between and within the two subscription categories without displaying the transition matrix.
A
I.

Write down the transition matrix MM and initial state s0\mathbf s_0 such that sn+1=Msn\mathbf s_{n+1}=M\mathbf s_n.

[2]
II.

Calculate the state after one month.

[1]
B
I.

Find the eigenvalues of MM and an eigenvector corresponding to each.

[3]
II.

Hence find an expression for the number BnB_n of basic subscribers after nn months.

[2]
C

Hence determine the long-term numbers of basic and premium subscribers.

[2]
Question 24
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A directed network has adjacency matrix

A=(0110001110010100)A=\begin{pmatrix} 0&1&1&0\\ 0&0&1&1\\ 1&0&0&1\\ 0&1&0&0 \end{pmatrix}

The element in row ii, column jj is 11 when there is a direct route from location ii to location jj, and is 00 otherwise.

1

2

3

4

1

0

1

1

0

2

0

0

1

1

3

1

0

0

1

4

0

1

0

0

A
I.

Calculate A2A^2.

[2]
II.

Interpret the element in row 11, column 44 of A2A^2.

[2]
B
I.

Calculate the total number of routes of exactly three stages starting at location 22.

[2]
II.

State why A3A^3 and A2AA^2A must be equal.

[1]
C

Explain why an entry of 22 in a power of AA does not mean that there are two direct routes between the corresponding locations.

[2]
Question 25
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Four unknown calibration constants are represented by

x=(wxyz)\mathbf x=\begin{pmatrix}w\\x\\y\\z\end{pmatrix}

They satisfy Ax=bA\mathbf x=\mathbf b, where

A=(1111210304123021),eqquadb=(17283123)A=\begin{pmatrix} 1&1&1&1\\ 2&1&0&3\\ 0&4&1&2\\ 3&0&2&1 \end{pmatrix}, eqquad \mathbf b=\begin{pmatrix}17\\28\\31\\23\end{pmatrix}
A
I.

Calculate det(A)\det(A) and explain why the system has a unique solution.

[2]
II.

Use an inverse matrix to find the calibration constants.

[2]
B

After a change in conditions, the constant column becomes

b=(19353128)\mathbf b'=\begin{pmatrix}19\\35\\31\\28\end{pmatrix}
I.

Find the new calibration column x\mathbf x'.

[2]
II.

Find Δx=xx\Delta\mathbf x=\mathbf x'-\mathbf x.

[1]
C

Verify that AΔx=bbA\Delta\mathbf x=\mathbf b'-\mathbf b and explain what this demonstrates.

[2]
Question 26
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A workshop produces standard, touring and cargo bicycles. Let xx, yy and zz denote the daily numbers produced. The production constraints are represented by

x+y+z=60,2x+3y+5z=180,4x+2y+6z=200.\begin{aligned} x+y+z&=60,\\ 2x+3y+5z&=180,\\ 4x+2y+6z&=200. \end{aligned}
A
I.

Write the constraints in the form Ax=bA\mathbf{x}=\mathbf{b}.

[2]
II.

Use an inverse matrix to determine the daily production of each type of bicycle.

[2]
B

A revised plan leaves the total number of bicycles unchanged but increases the right-hand sides of the second and third constraints by 66 and 44 respectively. Determine the revised production plan and interpret the change.

[4]
Question 27
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Three-number message blocks are encoded using y=Aq\mathbf{y}=A\mathbf{q}, where

A=(110011101)A=\begin{pmatrix}1&1&0\\0&1&1\\1&0&1\end{pmatrix}
A
I.

Find det(A)\det(A) and hence state whether the coding can be reversed uniquely.

[2]
II.

Decode the received block y=(151922)\mathbf{y}=\begin{pmatrix}15\\19\\22\end{pmatrix}.

[2]
B

A second coding system uses

B=(110011121)B=\begin{pmatrix}1&1&0\\0&1&1\\1&2&1\end{pmatrix}

Show that this coding system can lose information by finding two distinct plaintext blocks that produce the same encoded block.

[4]
Question 28
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A two-sensor calibration model is A(k)x=bA(k)\mathbf{x}=\mathbf{b}, where

A(k)=(k14k2)A(k)=\begin{pmatrix}k&1\\4&k-2\end{pmatrix}
A
I.

Find the values of kk for which the calibration matrix is singular.

[2]
II.

For k=3k=3 and b=(1115)\mathbf{b}=\begin{pmatrix}11\\15\end{pmatrix}, determine x\mathbf{x}.

[2]
B

Explain why calibration becomes unreliable when kk is very close to either value found in part (a)(i), even if A(k)1A(k)^{-1} technically exists.

[4]
Question 29
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

An economy has agricultural and manufacturing sectors. The internal consumption matrix is

C=(0.20.10.30.2)C=\begin{pmatrix}0.2&0.1\\0.3&0.2\end{pmatrix}

and external demand is d=(430360)\mathbf{d}=\begin{pmatrix}430\\360\end{pmatrix}. Total output x\mathbf{x} satisfies x=Cx+d\mathbf{x}=C\mathbf{x}+\mathbf{d}.

A
I.

Rearrange the model into the form Ax=dA\mathbf{x}=\mathbf{d} and write down AA.

[2]
II.

Use an inverse matrix to determine the total output required from each sector.

[2]
B

Determine the internal demand CxC\mathbf{x} and explain why total output must exceed external demand in both sectors.

[4]
Question 30
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A directed transport network has three stations. Its adjacency matrix is

A=(011101010)A=\begin{pmatrix}0&1&1\\1&0&1\\0&1&0\end{pmatrix}

where the element in row ii, column jj is the number of direct routes from station ii to station jj.

A directed network with three labelled stations whose arrows correspond to the adjacency matrix in the stem.
A
I.

Calculate A2A^2.

[2]
II.

Interpret the element in row 22, column 22 of A2A^2.

[2]
B

A traveller may use at most two stages, and a journey of zero stages is allowed only when the starting and finishing stations are the same. Construct a matrix whose entries count all such journeys. Hence determine the number of permitted journeys from station 11 to station 33.

[4]
Question 31
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A design point is transformed using

R=(0110),S=(2001)R=\begin{pmatrix}0&-1\\1&0\end{pmatrix},\qquad S=\begin{pmatrix}2&0\\0&1\end{pmatrix}

Here RR is a rotation and SS is a horizontal stretch.

A coordinate-plane design showing Region A and point P(1,3), with the origin and x-axis aligned to the y=0 gridline forming the bottom edge of Region A. Tick labels must be aligned to this axis. The design indicates that a rotation and a horizontal stretch will be applied, without showing the final images.
A
I.

Find the image of (13)\begin{pmatrix}1\\3\end{pmatrix} when RR is applied first and SS second.

[2]
II.

Find the image when the stretch is applied first and the rotation second.

[2]
B

A region has area 1212 square units. Determine its area after either composite transformation and explain why the two composites have the same area scale factor but different effects on points.

[4]
Question 32
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

The amplitudes of two coupled vibration modes after nn cycles are represented by sn=Mns0\mathbf{s}_n=M^n\mathbf{s}_0, where

M=(5222),s0=(50)M=\begin{pmatrix}5&2\\2&2\end{pmatrix},\qquad \mathbf{s}_0=\begin{pmatrix}5\\0\end{pmatrix}
A
I.

Find the eigenvalues of MM.

[2]
II.

Find a corresponding eigenvector for each eigenvalue.

[2]
B

Express sn\mathbf{s}_n in terms of nn. Hence determine the limiting ratio of its first component to its second component.

[4]
Question 33
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Consider the parameter-dependent system

A(k)(xy)=(34),A(k)=(k12k1)A(k)\begin{pmatrix}x\\y\end{pmatrix}=\begin{pmatrix}3\\4\end{pmatrix}, \qquad A(k)=\begin{pmatrix}k&1\\2&k-1\end{pmatrix}

where kRk\in\mathbb R.

A
I.

Find the values of kk for which A(k)A(k) is singular.

[2]
II.

Find A(k)1A(k)^{-1} for all other values of kk.

[2]
B
I.

Explain why the system has no solution when k=2k=2.

[1]
II.

Solve the system when k=2.01k=2.01, giving the coordinates to three significant figures.

[2]
C

Discuss why solutions close to k=2k=2 may be highly sensitive to small measurement errors.

[2]
Question 34
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Let

M=(5222)M=\begin{pmatrix}5&2\\2&2\end{pmatrix}
A
I.

Find the eigenvalues of MM.

[2]
II.

Find an eigenvector corresponding to each eigenvalue.

[2]
B
I.

Write matrices PP and DD such that M=PDP1M=PDP^{-1}.

[2]
II.

Hence find an expression for MnM^n, where nZ+n\in\mathbb Z^+.

[2]
C

Find the least positive integer nn for which the element in row 11, column 22 of MnM^n exceeds 10510^5.

[2]
Question 35
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The populations of two interacting organisms are modelled by

sn+1=Msn,M=(1.20.30.20.7),s0=(500200)\mathbf s_{n+1}=M\mathbf s_n, \qquad M=\begin{pmatrix}1.2&0.3\\0.2&0.7\end{pmatrix}, \qquad \mathbf s_0=\begin{pmatrix}500\\200\end{pmatrix}

Population values are measured in thousands.

A
I.

Find the eigenvalues of MM.

[2]
II.

Find a corresponding eigenvector for each eigenvalue.

[2]
B
I.

Express s0\mathbf s_0 as a linear combination of the eigenvectors.

[2]
II.

Hence find an expression for sn\mathbf s_n. If you did not obtain the coefficients, use a=12007a=\frac{1200}{7} and b=1007b=-\frac{100}{7}.

[3]
C

Determine the long-term ratio of the first population to the second population and interpret the dominant eigenvalue.

[2]
Question 36
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

For kRk\in\mathbb R, let

Mk=(k21k+1)M_k=\begin{pmatrix}k&2\\1&k+1\end{pmatrix}
A
I.

Show that the eigenvalues of MkM_k are k+2k+2 and k1k-1.

[2]
II.

Find an eigenvector corresponding to each eigenvalue.

[2]
B
I.

Write matrices PP and DkD_k such that Mk=PDkP1M_k=PD_kP^{-1}.

[1]
II.

Hence find an expression for MknM_k^n.

[2]
C

For k=0.4k=0.4, determine the long-term ratio of the two components of Mkn(41)M_k^n\begin{pmatrix}4\\1\end{pmatrix}.

[2]
Question 37
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A simplified ranking algorithm updates the scores of two webpages using

rn+1=Mrn,M=(0.60.90.40.1),r0=(0.50.5)\mathbf r_{n+1}=M\mathbf r_n, \qquad M=\begin{pmatrix}0.6&0.9\\0.4&0.1\end{pmatrix}, \qquad \mathbf r_0=\begin{pmatrix}0.5\\0.5\end{pmatrix}
A
AI.

Find the eigenvalues of MM.

[2]
AII.

Find an eigenvector corresponding to each eigenvalue.

[2]
B
BI.

Show that

r0=113(94)526(11)\mathbf r_0=\frac1{13}\begin{pmatrix}9\\4\end{pmatrix}-\frac5{26}\begin{pmatrix}1\\-1\end{pmatrix}
[2]
BII.

Hence find an expression for rn\mathbf r_n.

[2]
C

Find the least value of nn for which each score differs from its limiting value by less than 0.0010.001.

[2]
Question 38
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A damped displacement model is given by

sn+1=Msn,eqquadM=(010.180.9),eqquads0=(107)\mathbf s_{n+1}=M\mathbf s_n, eqquad M=\begin{pmatrix}0&1\\-0.18&0.9\end{pmatrix}, eqquad \mathbf s_0=\begin{pmatrix}10\\7\end{pmatrix}

The first component of sn\mathbf s_n is the displacement, in millimetres, at step nn.

A
I.

Find the eigenvalues of MM.

[2]
II.

Find an eigenvector corresponding to each eigenvalue.

[2]
B
I.

Express s0\mathbf s_0 as a linear combination of the eigenvectors.

[2]
II.

Hence find an expression for the displacement dnd_n.

[2]
C

Determine the first step at which the magnitude of the displacement is less than 0.10.1 mm, and explain why the displacement approaches zero.

[2]
Question 39
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A reversible numerical filter is represented by

F=(1201)F=\begin{pmatrix}1&2\\0&-1\end{pmatrix}

A column v\mathbf v is updated repeatedly according to vn+1=Fvn\mathbf v_{n+1}=F\mathbf v_n.

A
I.

Show that F2=IF^2=I.

[2]
II.

Hence state F1F^{-1}.

[1]
B
I.

Find the eigenvalues of FF and a corresponding eigenvector for each.

[2]
II.

Diagonalize FF and hence obtain a formula for FnF^n.

[2]
C

Given v0=(43)\mathbf v_0=\begin{pmatrix}4\\3\end{pmatrix}, determine v2025\mathbf v_{2025} and explain the periodic behaviour of the sequence.

[2]
Question 40
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Matrices AA, BB and XX satisfy AXB=CAXB=C, where

A=(1102),B=(2011),C=(113142)A=\begin{pmatrix}1&1\\0&2\end{pmatrix},\quad B=\begin{pmatrix}2&0\\1&1\end{pmatrix},\quad C=\begin{pmatrix}11&3\\14&2\end{pmatrix}
A
I.

Find A1A^{-1} and B1B^{-1}.

[2]
II.

Hence solve for XX.

[2]
B

A student claims that X=B1A1CX=B^{-1}A^{-1}C. Explain the error and verify the correct solution by substitution.

[4]
Question 41
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

The numbers of books borrowed from two sections of a library are modelled by

sn+1=Msn,M=(0.80.30.20.7),s0=(800200)\mathbf{s}_{n+1}=M\mathbf{s}_n,\qquad M=\begin{pmatrix}0.8&0.3\\0.2&0.7\end{pmatrix},\qquad \mathbf{s}_0=\begin{pmatrix}800\\200\end{pmatrix}
A
I.

Show that 11 and 0.50.5 are eigenvalues of MM, and find a corresponding eigenvector for each.

[2]
II.

Hence show that

sn=(600400)+200(0.5)n(11)\mathbf{s}_n=\begin{pmatrix}600\\400\end{pmatrix}+200(0.5)^n\begin{pmatrix}1\\-1\end{pmatrix}
[2]
B

Determine the least value of nn for which each component is within one book of its long-term value. Interpret the long-term state.

[4]
Question 42
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

The numbers of active users of two competing online platforms are modelled by

sn+1=Msn,M=(1.20.40.10.9),s0=(9010)\mathbf{s}_{n+1}=M\mathbf{s}_n,\qquad M=\begin{pmatrix}1.2&0.4\\0.1&0.9\end{pmatrix},\qquad \mathbf{s}_0=\begin{pmatrix}90\\10\end{pmatrix}

The components are measured in thousands.

A
I.

Find the eigenvalues of MM.

[2]
II.

Find an expression for sn\mathbf{s}_n.

[2]
B

Determine the first value of nn for which the model predicts more than one million active users in total. State one reason why predictions far beyond this point should be treated cautiously.

[4]
Question 43
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A conic is represented by

(xy)M(xy)=12,M=(5222)\begin{pmatrix}x&y\end{pmatrix} M \begin{pmatrix}x\\y\end{pmatrix}=12, \qquad M=\begin{pmatrix}5&-2\\-2&2\end{pmatrix}
Rotated ellipse in the original x-y axes.
A
I.

Find the eigenvalues of MM.

[2]
II.

Find unit eigenvectors and construct an orthogonal matrix PP that diagonalizes MM.

[2]
B

Using coordinates (uv)=PT(xy)\begin{pmatrix}u\\v\end{pmatrix}=P^T\begin{pmatrix}x\\y\end{pmatrix}, find the equation of the conic in uu and vv. Hence state its shape, semi-axis lengths and area.

[4]
Question 44
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A parameter-dependent update matrix is

M(a)=(a0.20.2a)M(a)=\begin{pmatrix}a&0.2\\0.2&a\end{pmatrix}

A state is updated by sn+1=M(a)sn\mathbf{s}_{n+1}=M(a)\mathbf{s}_n.

A
I.

Find the eigenvalues and corresponding eigenvector directions of M(a)M(a).

[2]
II.

Write a diagonalization of M(a)M(a).

[2]
B

Determine the set of values of aa for which every initial state approaches the zero vector as nn\to\infty. Justify your answer using the eigenvalues.

[4]
Question 45
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Let

M(p)=(p11p)M(p)=\begin{pmatrix}p&1\\1&p\end{pmatrix}

where pRp\in\mathbb{R}.

A
I.

Find the eigenvalues and corresponding eigenvectors of M(p)M(p).

[2]
II.

Hence find a formula for M(p)nM(p)^n, where nn is a positive integer.

[2]
B

For p=0.6p=0.6, an initial state is s0=(73)\mathbf{s}_0=\begin{pmatrix}7\\3\end{pmatrix}. The state evolves according to sn+1=M(0.6)sn\mathbf{s}_{n+1}=M(0.6)\mathbf{s}_n. Define dn=(sn)1(sn)2d_n=(\mathbf{s}_n)_1-(\mathbf{s}_n)_2. Find an expression for sn\mathbf{s}_n and explain the alternating behaviour of dnd_n.

[4]
Question 46
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

The values, in thousands of dollars, of two linked investment funds are modelled by

sn+1=Msn,M=(1.050.020.011.04),s0=(320140)\mathbf{s}_{n+1}=M\mathbf{s}_n,\qquad M=\begin{pmatrix}1.05&0.02\\0.01&1.04\end{pmatrix},\qquad \mathbf{s}_0=\begin{pmatrix}320\\140\end{pmatrix}
A
I.

Find the eigenvalues and a corresponding eigenvector for each.

[2]
II.

Find an expression for sn\mathbf{s}_n.

[2]
B

Determine the first value of nn for which the combined modelled value exceeds one million dollars. Hence state the long-term ratio of the value of the first fund to the second.

[4]
Question 47
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Let

M=(3212)M=\begin{pmatrix}3&2\\1&2\end{pmatrix}
A
I.

Find the characteristic polynomial and eigenvalues of MM.

[2]
II.

Show directly that M25M+4I=0M^2-5M+4I=0.

[2]
B
I.

Deduce a recurrence relating MnM^n, Mn1M^{n-1} and Mn2M^{n-2} for n2n\ge2.

[1]
II.

Using diagonalization, find an explicit expression for MnM^n.

[3]
C

Verify that the expression from part (b)(ii) satisfies the recurrence from part (b)(i).

[2]
Question 48
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A two-page ranking model uses the transition matrix

M(d)=(0.50.5+0.5d0.50.50.5d)M(d)=\begin{pmatrix}0.5&0.5+0.5d\\0.5&0.5-0.5d\end{pmatrix}

where 0<d<10<d<1. A ranking vector has components summing to 11 and is updated by rn+1=M(d)rn\mathbf{r}_{n+1}=M(d)\mathbf{r}_n.

A two-page directed-link diagram illustrating a ranking process with a damping parameter, without displaying the invariant ranking.
A
I.

Show that 11 is an eigenvalue and determine the invariant ranking vector r\mathbf{r}_* in terms of dd.

[2]
II.

Find the second eigenvalue and a corresponding eigenvector.

[2]
B

For d=0.8d=0.8 and r0=(10)\mathbf{r}_0=\begin{pmatrix}1\\0\end{pmatrix}, determine the least value of nn for which both components of rn\mathbf{r}_n are within 0.0010.001 of their invariant values. Explain why the rankings alternate around equilibrium.

[4]

Financial Mathematics

Number Skills