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Trigonometric Functions

Practice exam-style IB Math AI questions for Trigonometric Functions, aligned with the syllabus and grouped by topic.

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Question 1
HL • Paper 1
Easy
Calculator Permitted
HL • Paper 1
Easy
Calculator Permitted

A bicycle wheel has radius 0.340 m0.340\ \text{m}. The wheel turns through an angle of 125∘125^\circ.

A

Express 125∘125^\circ in radians, giving your answer as an exact multiple of π\pi.

[1]
B

the distance travelled by a point on the circumference during this turn.

[2]
C

The wheel completes this turn 1818 times. the total distance travelled by the bicycle, assuming there is no slipping.

[2]
Question 2
HL • Paper 1
Easy
Calculator Permitted
HL • Paper 1
Easy
Calculator Permitted

A sector of a circle has central angle 1.201.20 radians and area 48.0 cm248.0\ \text{cm}^2.

A

the radius of the circle.

[2]
B

the length of the arc of the sector.

[2]
Question 3
HL • Paper 1
Easy
Calculator Permitted
HL • Paper 1
Easy
Calculator Permitted

A belt passes around a pulley of radius 0.120 m0.120\ \text{m}. The belt moves without slipping. During one stage of a machine cycle, 3.80 m3.80\ \text{m} of belt passes the pulley.

A

the angle, in radians, through which the pulley turns.

[2]
B

the corresponding number of complete revolutions and partial revolutions.

[1]
C

The pulley rotates at a constant angular speed of 7.50 rad s−17.50\ \text{rad s}^{-1}. the time taken for this stage of the cycle.

[2]
Question 4
HL • Paper 1
Easy
Calculator Permitted
HL • Paper 1
Easy
Calculator Permitted

A windscreen wiper sweeps through an angle of 105∘105^\circ. The rubber blade covers distances from 0.180 m0.180\ \text{m} to 0.620 m0.620\ \text{m} from the pivot.

A

the area swept by the rubber blade.

[3]
B

the distance travelled by the outer tip of the blade during one sweep.

[1]

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Question 5
HL • Paper 1
Easy
Calculator Permitted
HL • Paper 1
Easy
Calculator Permitted

A rotating beacon illuminates a fixed point while turning through an angle of 0.8500.850 radians. The beacon rotates uniformly at 1212 revolutions per minute.

A

Express 0.8500.850 radians in degrees.

[1]
B

the fraction of one complete revolution represented by this angle.

[1]
C

the time for which the fixed point is illuminated during each revolution.

[2]
Question 6
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

A garden bed is in the shape of an annular sector. Its inner radius is 4.00 m4.00\ \text{m}, its outer radius is 11.0 m11.0\ \text{m} and its central angle is 1.351.35 radians.

A

the area of the garden bed.

[3]
B

the total length of the boundary of the garden bed.

[2]
Question 7
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

The terminal side of an angle θ\theta meets the unit circle at the point PP. The point PP lies in the third quadrant and cos⁡θ=−0.360\cos\theta=-0.360, where 0≤θ<2π0\leq\theta<2\pi.

A

sin⁡θ\sin\theta.

[2]
B

tan⁡θ\tan\theta.

[1]
C

the value of θ\theta.

[2]
Question 8
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

An angle α\alpha satisfies tan⁡α=−1.70\tan\alpha=-1.70 and cos⁡α>0\cos\alpha>0, where 0≤α<2π0\leq\alpha<2\pi.

A

the quadrant in which the terminal side of α\alpha lies.

[1]
B

Using trigonometric identities, cos⁡α\cos\alpha and sin⁡α\sin\alpha.

[3]
C

α\alpha.

[1]

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Question 9
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

A point moves anticlockwise around the unit circle. At time t=0t=0, its angular position is 0.4000.400 radians. Its angular speed is 1.80 rad s−11.80\ \text{rad s}^{-1}. The vertical coordinate of the point is denoted by yy. Consider 0≤t≤40\leq t\leq4.

A

a model for yy in terms of tt.

[1]
B

the first time at which yy reaches its maximum and the first time at which it reaches its minimum.

[2]
C

all times in the interval when the point lies on the horizontal axis.

[2]
Question 10
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

Consider the equation

sin⁡x=0.6cos⁡(2x)\sin x=0.6\cos(2x)

where 0≤x≤2π0\leq x\leq2\pi.

A

Using a graphical method, the equation.

[3]
B

the common value of the two expressions at either solution.

[1]
Question 11
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

A circular sector has perimeter 26 cm26\ \text{cm} and area 40 cm240\ \text{cm}^2. Its radius is r cmr\ \text{cm} and its central angle is θ\theta radians.

A

rr satisfies the equation r2−13r+40=0r^2-13r+40=0.

[3]
B

all possible pairs (r,θ)(r,\theta).

[3]
Question 12
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

Consider the equation

2sin⁡x=0.6x+0.42\sin x=0.6x+0.4

where 0≤x≤2π0\leq x\leq2\pi.

A

Using a graphical method, the equation.

[3]
B

the number of solutions and how the graph confirms that no solutions have been omitted.

[2]

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Question 13
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

In triangle ABCABC, side a=15.0 ma=15.0\ \text{m}, side b=12.0 mb=12.0\ \text{m} and angle A=1.20A=1.20 radians.

A

Use the sine rule to the principal possible value of angle BB.

[2]
B

why the supplementary value of BB does not form a triangle.

[1]
C

the length of side cc for the valid triangle.

[2]
Question 14
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

An alternating voltage is modelled by

V(t)=240sin⁡(100πt−0.400)V(t)=240\sin(100\pi t-0.400)

where VV is measured in volts and tt is measured in seconds. Consider 0≤t≤0.0400\leq t\leq0.040.

A

Using a graphical method, all times at which V(t)=150V(t)=150.

[4]
B

the total duration during which V(t)>150V(t)>150 over this interval.

[2]
Question 15
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

In triangle ABCABC, side a=12.0 cma=12.0\ \text{cm}, side b=15.0 cmb=15.0\ \text{cm} and angle A=0.650A=0.650 radians.

A

the two possible values of angle BB.

[3]
B

For each possible triangle, the length of side cc.

[2]
C

why both solutions correspond to valid triangles.

[1]
Question 16
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

The temperatures recorded by two sensors during a 1212-hour test are modelled by

A(t)=12+3sin⁡(πt6)A(t)=12+3\sin\left(\frac{\pi t}{6}\right)

and

B(t)=13+3cos⁡(πt6)B(t)=13+3\cos\left(\frac{\pi t}{6}\right)

where temperature is measured in ∘C^\circ\text{C} and 0≤t≤120\leq t\leq12.

A

Using a graphical method, the times at which the two sensors record the same temperature.

[3]
B

the common temperature at each of these times.

[1]
C

the total length of time during which sensor AA records a higher temperature than sensor BB.

[2]

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Question 17
HL • Paper 2
Medium
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HL • Paper 2
Medium
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A theatre follow-spot illuminates an annular sector of the stage. The inner radius is 4.50 m4.50\ \text{m}, the outer radius is 16.0 m16.0\ \text{m} and the angle of the sector is 72∘72^\circ.

A
I.

Express the angle of the sector in radians, giving your answer as an exact multiple of π\pi.

[2]
II.

the area illuminated by the follow-spot.

[2]
B

A translucent floor covering is required for the illuminated region. An additional 8%8\% of its area is allowed for cutting waste. The covering is sold in rolls containing 12.0 m212.0\ \text{m}^2. the minimum number of rolls required.

[4]
Question 18
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

A decorative mosaic has the shape of an annular sector. Its outer radius is r mr\ \text{m}, its inner radius is (r−2) m(r-2)\ \text{m}, its central angle is 2.202.20 radians and its area is 52.8 m252.8\ \text{m}^2.

A
I.

Form an equation in rr using the area of the mosaic.

[2]
II.

the outer and inner radii.

[2]
B

the total length of the boundary of the mosaic.

[3]
C

Tiles of width 0.300 m0.300\ \text{m} are placed side by side along the outer curved edge. the minimum number of tiles required.

[1]
Question 19
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A curved stained-glass panel is a sector of a circle. Its curved edge has length 9.60 m9.60\ \text{m} and the area of the sector is 28.8 m228.8\ \text{m}^2. The two endpoints of the curved edge are joined by a straight support.

A
I.

the radius of the sector.

[2]
II.

the central angle of the sector.

[2]
B

the area enclosed between the curved edge and the straight support.

[4]
Question 20
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The curved edge of a bridge arch is modelled by the minor arc of a circle of radius 30.0 m30.0\ \text{m}. The length of this arc is 28.0 m28.0\ \text{m}. The region between the arc and its chord is filled with decorative material.

A
I.

the angle subtended by the arc at the centre of the circle.

[2]
II.

the area of the corresponding sector.

[2]
B
I.

the area of the decorative region.

[2]
II.

the maximum perpendicular distance between the chord and the arc.

[2]

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Question 21
HL • Paper 2
Hard
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HL • Paper 2
Hard
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A lampshade panel is cut in the shape of an annular sector. Its inner radius is 18.0 cm18.0\ \text{cm}, its outer radius is 30.0 cm30.0\ \text{cm} and its outer curved edge has length 40.0 cm40.0\ \text{cm}.

A
I.

the central angle of the panel.

[2]
II.

the length of the inner curved edge.

[2]
B

A radial strip with angular width 0.08000.0800 radians is used as an overlapping seam and is not visible. the visible area of one completed panel.

[2]
C

A sheet contains 2.00 m22.00\ \text{m}^2 of material, of which 12%12\% is lost during cutting. the maximum number of completed panels that can be made from one sheet.

[2]
Question 22
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A circular particle detector has outer radius 2.40 m2.40\ \text{m}. It contains 150150 identical radial sensors. Each sensor detects a centre-based sector extending from the centre to the detector's outer boundary; its outer arc has length 0.0750 m0.0750\ \text{m}. Adjacent sensor sectors are separated by equal angular gaps of 0.01000.0100 radians. There are 150150 such equal gaps, in addition to one remaining angular gap.

A
I.

the angle subtended by one sensor sector.

[2]
II.

the total area detected by the 150150 sensors.

[2]
B
I.

the sensors and their separating gaps do not fill a complete revolution, and the remaining angular gap.

[2]
II.

the length of the outer arc corresponding to the remaining angular gap.

[2]
Question 23
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The cross-section of water in a horizontal cylindrical tank is modelled by a minor circular segment. The tank has radius 5.50 m5.50\ \text{m} and the curved boundary of the water has length 8.40 m8.40\ \text{m}.

A
I.

the angle subtended by the curved water boundary at the centre of the tank.

[2]
II.

the length of the straight water surface joining the endpoints of the curved boundary.

[2]
B
I.

the cross-sectional area of the water.

[2]
II.

the maximum depth of the water segment, measured perpendicular to the straight water surface.

[2]
Question 24
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The height, HH, in metres, of a passenger on an observation wheel is modelled by

H(t)=24+19cos⁡(π18(t−4)),0≤t≤36H(t)=24+19\cos\left(\frac{\pi}{18}(t-4)\right),\qquad 0\leq t\leq36

where tt is measured in minutes.

A
I.

the maximum and minimum heights of the passenger.

[2]
II.

the period of the wheel and the first time at which the passenger reaches maximum height.

[2]
B

the total time during the ride for which the passenger is more than 35 m35\ \text{m} above the ground.

[4]

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Question 25
HL • Paper 3
Hard
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HL • Paper 3
Hard
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A coastal radar scans a sector of radius 40 km40\ \text{km} and central angle 1.101.10 radians. After each scan, the sector is rotated anticlockwise through 0.8200.820 radians. Consecutive scanned sectors therefore overlap.

A
I.

the length of the outer arc scanned during one scan.

[2]
II.

the area covered during one scan.

[2]
B

the minimum number of consecutive scans required for every direction from the radar station to have been scanned. your answer.

[4]
Question 26
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A tracking marker moves anticlockwise around the unit circle. Initially it is at the point PP in the second quadrant, where the horizontal coordinate is −0.650-0.650. It then moves with constant angular speed 0.720 rad s−10.720\ \text{rad s}^{-1}.

A
I.

the vertical coordinate of PP.

[2]
II.

the initial angular position of PP.

[2]
B

For 0≤t≤100\leq t\leq10, all times when the marker has vertical coordinate 0.5000.500.

[4]
Question 27
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
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During an eight-hour wildlife survey, sound levels at two monitoring stations are modelled by

S1(t)=60+8sin⁡(πt4)S_1(t)=60+8\sin\left(\frac{\pi t}{4}\right)

and

S2(t)=62+6cos⁡(πt4)S_2(t)=62+6\cos\left(\frac{\pi t}{4}\right)

where sound level is measured in decibels and 0≤t≤80\leq t\leq8.

A
I.

Using a graphical method, the times when the stations record the same sound level.

[2]
II.

the common sound level at each of these times.

[2]
B

the total duration for which station 1 records a higher sound level than station 2.

[4]
Question 28
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A motorized stage light projects a narrow beam to a wall 25.0 m25.0\ \text{m} from its pivot. Its angular position is modelled by

θ(t)=1.20+0.900sin⁡(0.400t),0≤t≤20\theta(t)=1.20+0.900\sin(0.400t),\qquad 0\leq t\leq20

where θ\theta is measured in radians and tt is measured in seconds.

A
I.

the minimum and maximum angular positions of the beam.

[2]
II.

the area swept out by the beam between its extreme positions.

[2]
B

A warning signal operates whenever θ(t)>1.80\theta(t)>1.80. the total time for which the warning signal operates during the given interval.

[4]

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Question 29
HL • Paper 2
Hard
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HL • Paper 2
Hard
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During a 2424-hour laboratory test, the outputs of two light sensors are modelled by

A(t)=50+30sin⁡(πt12)A(t)=50+30\sin\left(\frac{\pi t}{12}\right)

and

B(t)=55+25sin⁡(π(t−2)12)B(t)=55+25\sin\left(\frac{\pi(t-2)}{12}\right)

where 0≤t≤240\leq t\leq24 and output is measured in lux.

A
I.

Using a graphical method, the times when the two sensors have equal output.

[2]
II.

the common output at each of these times.

[2]
B

the total time during which sensor AA has a greater output than sensor BB.

[4]
Question 30
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Three emergency shelters form triangle ABCABC. The distances opposite angles AA and BB are a=27.0 kma=27.0\ \text{km} and b=34.0 kmb=34.0\ \text{km} respectively. The measured angle is A=0.720A=0.720 radians.

A
I.

Use the sine rule to the two possible values of angle BB.

[3]
II.

why both values of BB produce valid triangles.

[1]
B

the length of side cc for each possible triangle.

[4]
Question 31
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A point PP moves anticlockwise around the unit circle. Its angular position is θ\theta, where 0≤θ≤4π0\leq\theta\leq4\pi. A sensor is activated whenever PP lies on the line

y=0.600x+0.200y=0.600x+0.200
A
I.

Using the unit-circle definitions of sine and cosine, write an equation in θ\theta for activation of the sensor.

[2]
II.

Using a graphical method, all values of θ\theta for which the sensor is activated.

[2]
B
I.

the relationship between the first two activation angles and the final two activation angles.

[2]
II.

the distance travelled by PP along the unit circle from the first activation to the final activation.

[2]
Question 32
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
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Consider the equation

sin⁡x=0.300+0.400cos⁡x\sin x=0.300+0.400\cos x

where 0≤x≤4π0\leq x\leq4\pi.

A
I.

the two functions that should be graphed to the equation.

[1]
II.

Using a graphical method, the equation in the given interval.

[3]
B

Use the Pythagorean identity to the possible values of cos⁡x\cos x and confirm the solutions from part (a).

[4]

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Question 33
HL • Paper 2
Hard
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HL • Paper 2
Hard
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Consider the equation

tan⁡x=3sin⁡x\tan x=3\sin x

where 0≤x≤2π0\leq x\leq2\pi.

A
I.

the definition of tan⁡x\tan x in terms of sine and cosine.

[1]
II.

every solution must satisfy

sin⁡x(1−3cos⁡x)=0\sin x(1-3\cos x)=0
[2]
B
III.

the original equation in the given interval.

[3]
IV.

why x=π2x=\frac{\pi}{2} and x=3π2x=\frac{3\pi}{2} are not solutions, even though multiplication by cos⁡x\cos x was used.

[2]
Question 34
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
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A marker moves anticlockwise around the unit circle with angular position

θ(t)=1.40t−0.500\theta(t)=1.40t-0.500

where tt is measured in seconds and 0≤t≤80\leq t\leq8. Its vertical coordinate is denoted by y(t)y(t).

A
I.

a model for y(t)y(t).

[1]
II.

all times when y(t)=−0.250y(t)=-0.250.

[3]
B

the total time for which the marker lies in the second quadrant.

[4]
Question 35
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
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An illuminated display is an annular sector with inner radius 1.80 m1.80\ \text{m} and outer radius 5.20 m5.20\ \text{m}. Its boundary has total length 13.6 m13.6\ \text{m}. Identical displays are placed around a circular tower. The angular displacement between successive displays is one third of the angle of each display.

A
I.

the central angle of the display is approximately 0.9710.971 radians.

[2]
II.

the area of one display.

[2]
B

the minimum number of displays required to illuminate every direction around the tower. If you did not obtain θ=0.971\theta=0.971 in part (a), use this value.

[4]
Question 36
HL • Paper 3
Hard
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HL • Paper 3
Hard
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Two points AA and BB lie on a unit circle. The length of the minor chord ABAB is 1.301.30. The angle subtended by this chord at the centre is θ\theta radians.

A
I.

Using the Pythagorean identity or the cosine rule, cos⁡θ=0.155\cos\theta=0.155.

[2]
II.

θ\theta.

[2]
B

the area of the minor circular segment bounded by chord ABAB and the minor arc ABAB.

[4]

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Question 37
HL • Paper 3
Hard
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HL • Paper 3
Hard
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Three marine observation stations form triangle ABCABC. The measured values are a=18.0 kma=18.0\ \text{km}, b=24.0 kmb=24.0\ \text{km} and A=0.550A=0.550 radians, where side aa is opposite angle AA.

A
I.

the two possible values of angle BB.

[2]
II.

why both values produce a valid triangle.

[2]
B

the area of each possible triangle.

[4]
Question 38
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
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An electrical signal is modelled by

V(t)=120sin⁡(40πt)+30cos⁡(40πt)V(t)=120\sin(40\pi t)+30\cos(40\pi t)

where VV is measured in volts, tt is measured in seconds and 0≤t≤0.1000\leq t\leq0.100.

A
I.

Write V(t)V(t) in the form Rsin⁡(40πt+ϕ)R\sin(40\pi t+\phi), where R>0R>0 and 0<ϕ<π20<\phi<\frac{\pi}{2}.

[3]
II.

the period of the signal.

[1]
B

Using a graphical method, the total duration for which V(t)>100V(t)>100 over the given interval.

[4]
Question 39
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
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The vertical coordinates of two markers on a rotating stage are modelled by

yA(t)=sin⁡(0.8t+0.2)y_A(t)=\sin(0.8t+0.2)

and

yB(t)=cos⁡(0.8t−0.4)y_B(t)=\cos(0.8t-0.4)

where 0≤t≤120\leq t\leq12. Define D(t)=yA(t)−yB(t)D(t)=y_A(t)-y_B(t).

A
I.

all times when the markers have the same vertical coordinate.

[3]
II.

how the graph confirms that no equality times have been omitted.

[1]
B

Express D(t)D(t) as a single sine function and its maximum value.

[4]
Question 40
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
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A robotic arm of length 2.40 m2.40\ \text{m} rotates about a fixed pivot. Its angle from the positive horizontal direction is

θ(t)=1.10+0.700sin⁡(0.500t)\theta(t)=1.10+0.700\sin(0.500t)

where 0≤t≤4π0\leq t\leq4\pi, tt is measured in seconds, and the coefficient 0.5000.500 has units of s−1\text{s}^{-1}.

A
I.

the maximum angular range swept by the arm.

[2]
II.

the area of the sector swept by the arm.

[2]
B

A safety alarm operates whenever the tip of the arm is to the left of the vertical line through the pivot. the total time for which the alarm operates.

[4]

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Question 41
HL • Paper 3
Hard
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HL • Paper 3
Hard
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A camera moves anticlockwise on a circular rail of radius 15.0 m15.0\ \text{m}. Its angular displacement from its starting point is

θ(t)=0.400t+0.250sin⁡(0.400t)\theta(t)=0.400t+0.250\sin(0.400t)

where tt is measured in seconds and 0≤t≤150\leq t\leq15.

A
I.

the distance travelled along the rail during the first 1010 seconds.

[2]
II.

the area of the sector swept out by the radius joining the centre to the camera during this time.

[2]
B

the times at which the camera crosses the vertical diameter of the rail.

[4]
Question 42
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

An acoustic panel has the shape of a circular sector. Its curved edge has fixed length 12.0 m12.0\ \text{m}. The radius is rr metres and the central angle is θ\theta radians. Design restrictions require the panel area to be at most 45.0 m245.0\ \text{m}^2 and its total perimeter to be at most 26.0 m26.0\ \text{m}.

A
I.

θ=12r\theta=\frac{12}{r}.

[1]
II.

Express the area KK in terms of rr and the restriction on rr imposed by the area limit.

[3]
B

Taking into account the perimeter restriction and the requirement 0<θ≤2π0<\theta\leq2\pi, the feasible interval for rr. the maximum possible area of the panel.

[4]
Question 43
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Two ground stations AA and BB and a drone at CC form a triangle. The angle AA is 0.9000.900 radians and the opposite distance is a=20.0 kma=20.0\ \text{km}. An initial gives b=18.0 kmb=18.0\ \text{km}.

A
I.

the principal possible value of BB.

[2]
II.

why the supplementary value of BB is invalid.

[2]
B

The actual value of bb may be anywhere in the interval 14.0≤b≤22.014.0\leq b\leq22.0. the subintervals for which the information produces one triangle and two triangles.

[4]
Question 44
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A point rotates around the unit circle with angular position θ=0.600t\theta=0.600t. A sensor calculates the signal

S(t)=3cos⁡2θ+2sin⁡2θS(t)=3\cos^2\theta+2\sin^2\theta

where tt is measured in seconds.

tt / s

θ\theta / rad

x=cos⁡(θ)x=\cos(\theta)

y=sin⁡(θ)y=\sin(\theta)

x2x^2

y2y^2

S(t)S(t)

0.000

0.000

1.000

0.000

1.000

0.000

3.000

0.773

0.464

0.894

0.447

0.800

0.200

2.800

2.618

1.571

0.000

1.000

0.000

1.000

2.000

4.463

2.678

-0.894

0.447

0.800

0.200

2.800

4.800

2.880

-0.966

0.259

0.933

0.067

2.933

A
I.

S(t)=2.5+0.5cos⁡(1.20t)S(t)=2.5+0.5\cos(1.20t)

[2]
II.

the period of SS.

[2]
B

During one period, the total time for which S(t)>2.80S(t)>2.80. why the signal completes a full cycle while the point completes only half a revolution.

[4]

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Question 45
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

In triangle ABCABC, angle A=1.05A=1.05 radians and side a=25.0 ma=25.0\ \text{m}. The possible measured value of side bb is denoted by p mp\ \text{m}, where p>0p>0.

A
I.

For p=27.0p=27.0, the two possible values of angle BB.

[3]
II.

that both values produce valid triangles.

[1]
B

Classify all positive values of pp according to whether the information produces one triangle, two triangles or no triangle.

[4]
Question 46
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

In triangle ABCABC, A=0.800A=0.800 radians, a=10.0 cma=10.0\ \text{cm} and the length bb may vary.

A
I.

For b=12.0 cmb=12.0\ \text{cm}, the two possible values of BB.

[2]
II.

that both values produce a valid triangle.

[2]
B

Classify all positive values of bb according to whether zero, one or two triangles are possible.

[4]
Question 47
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

For a real parameter kk, consider

sin⁡x=k(x−π),0≤x≤2π\sin x=k(x-\pi),\qquad 0\leq x\leq2\pi

The value x=πx=\pi is a solution for every value of kk.

A
I.

Using a graphical method, the equation when k=−0.300k=-0.300.

[3]
II.

why the two non-central solutions are equally spaced from π\pi.

[1]
B

By considering how the line changes as kk varies, classify the number of distinct solutions for k<−1k<-1, k=−1k=-1, −1<k<0-1<k<0 and k≥0k\geq0.

[4]
Question 48
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Consider the equation

tan⁡x=2cos⁡x\tan x=2\cos x

where 0≤x≤2π0\leq x\leq2\pi.

A
I.

Using tan⁡x=sin⁡xcos⁡x\tan x=\frac{\sin x}{\cos x} and the Pythagorean identity, any solution satisfies

2sin⁡2x+sin⁡x−2=02\sin^2x+\sin x-2=0

[2]
II.

the valid value of sin⁡x\sin x.

[2]
B

the original equation, and why no solutions have been introduced at values where tangent is undefined.

[4]

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Graph Theory

Trigonometry