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Transformations

Practice exam-style IB Math AI questions for Transformations, aligned with the syllabus and grouped by topic.

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Question 1
HL • Paper 1
Easy
Calculator Permitted
HL • Paper 1
Easy
Calculator Permitted

Starting with the graph of f(x)=x2f(x)=x^2, two sequences of transformations are considered.

Sequence A translates the graph 22 units upwards and then applies a vertical stretch with scale factor 33.

Sequence B applies the vertical stretch first and then translates the graph 22 units upwards.

A

the function obtained from sequence A.

[2]
B

the function obtained from sequence B.

[2]
C

the vertical distance between the two resulting graphs.

[1]
Question 2
HL • Paper 1
Easy
Calculator Permitted
HL • Paper 1
Easy
Calculator Permitted

For a product, Q=f(P)Q=f(P) models weekly demand QQ, in units, at a price PP dollars. Following an advertising campaign, demand is modelled by

g(P)=1.2f(P−5)+30g(P)=1.2f(P-5)+30

Before the campaign, the point (20,200)(20,200) lies on the demand curve.

A

each of the three transformations in the context of the model.

[3]
B

the point on the new demand curve corresponding to (20,200)(20,200), and its coordinates.

[2]
Question 3
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

The graph of y=f(x)y=f(x) contains the points A(−2,5)A(-2,5) and B(4,−1)B(4,-1). The graph is transformed to the graph of

g(x)=−2f(3(x−1))+4g(x)=-2f(3(x-1))+4
A

the coordinates of the image of AA on the graph of gg.

[2]
B

the coordinates of the image of BB on the graph of gg.

[2]
Question 4
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

The graph of y=f(x)y=f(x) has xx-intercepts at x=−3x=-3 and x=1x=1, and a local maximum at (0,4)(0,4). A new function is defined by

h(x)=−12f(−2x)h(x)=-\frac12f(-2x)
A

fully the transformations that map the graph of ff onto the graph of hh.

[4]
B

the xx-intercepts of the graph of hh.

[1]
C

the coordinates and nature of the turning point on the graph of hh.

[1]

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Question 5
HL • Paper 1
Medium
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HL • Paper 1
Medium
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The height of an animated fountain jet is modelled by

h(t)=−12(t−4)2+8h(t)=-\frac12(t-4)^2+8

where tt is the time in seconds and hh is the height in metres. A second animation starts 33 seconds later, runs at twice the speed and displays the jet at 1.51.5 times its original height.

A

a function H(t)H(t) that models the second animation.

[2]
B

the time and height of the maximum point in the second animation.

[2]
C

the two times at which the second animation shows the jet at ground level.

[1]
Question 6
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

The function gg is defined by

g(x)=−3cos⁡(2(x−π4))+1g(x)=-3\cos\left(2\left(x-\frac{\pi}{4}\right)\right)+1
A

a sequence of transformations that maps the graph of y=cos⁡xy=\cos x onto the graph of gg.

[5]
B

The point (0,1)(0,1) is a maximum point on y=cos⁡xy=\cos x. its image and its nature on the graph of gg.

[2]
Question 7
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

Let f(x)=ln⁡xf(x)=\ln x. A transformed function is defined by

g(x)=2f(−(x−3))+4g(x)=2f(-(x-3))+4
A

a sequence of transformations that maps the graph of ff onto the graph of gg.

[4]
B

the domain of gg and the equation of its vertical asymptote.

[2]
Question 8
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

A voltage signal is modelled by V=f(t)V=f(t), where tt is measured in seconds and VV in volts. A second sensor delays the signal by 0.40.4 seconds, reverses its polarity, amplifies its magnitude by a factor of 2.52.5, and adds an offset of 0.10.1 volts. The original signal has a local maximum at (1.2,0.8)(1.2,0.8).

A

a function G(t)G(t) for the output of the second sensor.

[3]
B

the image of the local maximum and its nature on the graph of GG.

[3]

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Question 9
HL • Paper 1
Medium
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HL • Paper 1
Medium
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The graph of a non-symmetric function ff is shown. It has endpoints (−4,1)(-4,1) and (2,5)(2,5), a local minimum at (−1,−2)(-1,-2) and an xx-intercept at (12,0)\left(\dfrac12,0\right). A new function is defined by

g(x)=f(−x)+3g(x)=f(-x)+3
A

the images of the local minimum and the specified x-intercept at (12,0)\left(\dfrac12,0\right) under the transformation.

[2]
B

On a coordinate grid, the graph of gg, clearly indicating its endpoints and local minimum.

[3]
Question 10
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

Let f(x)=exf(x)=e^x. The graph of ff is translated by the vector

(ab)\begin{pmatrix}a\\b\end{pmatrix}

to form the graph of gg. The graph of gg passes through (0,3)(0,3) and (ln⁡4,9)(\ln 4,9).

A

an expression for g(x)g(x) in terms of aa and bb.

[1]
B

the value of aa and the value of bb.

[4]
Question 11
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

Let

f(x)=1x−2+3f(x)=\frac{1}{x-2}+3

A new function is defined by

g(x)=−2f(12(x+4))+1g(x)=-2f\left(\frac12(x+4)\right)+1
A

Express g(x)g(x) in the form ax−h+k\dfrac{a}{x-h}+k.

[2]
B

the equations of the asymptotes of the graph of gg.

[2]
C

the domain and range of gg.

[2]
Question 12
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

A function ff has domain [−2,5][-2,5] and range [−1,7][-1,7]. A function gg is defined by

g(x)=12f(4−2x)−3g(x)=\frac12f(4-2x)-3

It is also known that f(1)=6f(1)=6.

A

the domain of gg.

[2]
B

the range of gg.

[2]
C

the point on the graph of gg corresponding to the point (1,6)(1,6) on the graph of ff.

[2]

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Question 13
HL • Paper 1
Medium
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HL • Paper 1
Medium
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Let f(x)=x2f(x)=x^2. A transformed function has the form

g(x)=pf(q(x−a))+bg(x)=p f(q(x-a))+b

where p>0p>0 and q>0q>0. The graph of gg has vertex (3,−2)(3,-2), is obtained using a horizontal stretch with scale factor 22, and passes through (5,6)(5,6).

A

the values of aa and bb.

[2]
B

the value of qq.

[1]
C

the value of pp and g(x)g(x).

[3]
Question 14
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

The graph of y=f(x)y=f(x) is transformed to the graph of

g(x)=−4f(x+63)+2g(x)=-4f\left(\frac{x+6}{3}\right)+2
A

a sequence of transformations that maps the graph of ff onto the graph of gg.

[3]
B

The point (2,−1)(2,-1) lies on the graph of ff. its image on the graph of gg.

[2]
C

The point (9,−10)(9,-10) lies on the graph of gg. the corresponding point on the graph of ff.

[2]
Question 15
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

Let f(x)=1xf(x)=\dfrac1x. A transformed function is defined by

g(x)=af(b(x−c))+dg(x)=a f(b(x-c))+d

where a>0a>0 and b>0b>0. The graph of gg has vertical asymptote x=2x=2, horizontal asymptote y=−1y=-1, and is obtained using a horizontal stretch with scale factor 22. It also passes through (3,1)(3,1).

A

the values of cc, dd and bb.

[3]
B

the value of aa and g(x)g(x) in simplified form.

[3]
Question 16
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

Let TT denote a translation 33 units to the right and let SS denote a horizontal stretch with scale factor 22. These transformations are applied to the graph of y=f(x)y=f(x) in different orders.

A

the function obtained when TT is applied first and SS second.

[2]
B

the function obtained when SS is applied first and TT second.

[2]
C

A point on the original graph has xx-coordinate rr. its final xx-coordinates under the two sequences.

[2]

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Question 17
HL • Paper 2
Medium
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HL • Paper 2
Medium
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Let

f(x)=1x+1f(x)=\frac{1}{x+1}

and define

g(x)=−2f(x−42)+3g(x)=-2f\left(\frac{x-4}{2}\right)+3
A
I.

a sequence of transformations that maps the graph of ff onto the graph of gg.

[2]
II.

Express g(x)g(x) in the form ax−h+k\dfrac{a}{x-h}+k.

[2]
B

the equations of the asymptotes of the graph of gg.

[2]
C

The line y=1y=1 intersects the graph of gg at PP. the coordinates of PP and the corresponding point on the graph of ff.

[2]
Question 18
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Let f(x)=∣x∣f(x)=|x| and define

g(x)=−2f(x+32)+6g(x)=-2f\left(\frac{x+3}{2}\right)+6
A
I.

the transformations that map the graph of ff onto the graph of gg.

[2]
II.

Write g(x)g(x) in simplified form and the coordinates of its vertex.

[2]
B

the xx-intercepts of the graph of gg.

[2]
C

the coordinates of the intersections of gg with the line y=0.5x+2y=0.5x+2.

[2]
Question 19
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
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The vertical displacement of a test platform is modelled by

f(t)=te−t,t≥0f(t)=te^{-t},\qquad t\geq 0

where tt is measured in seconds. A second sensor produces the transformed signal

g(t)=−3f(2(t−0.4))+0.2,t≥0.4g(t)=-3f(2(t-0.4))+0.2,\qquad t\geq 0.4

The graph of ff has a maximum point at (1,e−1)(1,e^{-1}).

A
I.

the transformations that map the graph of ff onto the graph of gg.

[3]
II.

the image of the maximum point of ff, giving coordinates to three significant figures, and its nature on the graph of gg.

[2]
B

the two values of tt for which g(t)=−0.5g(t)=-0.5.

[2]
C

why the maximum displacement of ff becomes a minimum displacement of gg.

[1]
Question 20
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The depth of water above a reference level at a harbour is modelled by

H(t)=1.8sin⁡(t−22)+3.2H(t)=1.8\sin\left(\frac{t-2}{2}\right)+3.2

where tt is measured in hours and 0≤t≤2+4π0\leq t\leq 2+4\pi.

A
I.

the transformations that map y=sin⁡ty=\sin t onto y=H(t)y=H(t).

[2]
II.

the time and depth of the first maximum value of HH.

[2]
B

the two times during the cycle when H(t)=4H(t)=4.

[2]
C

the length of time during the cycle for which the depth is at least 44 metres.

[2]

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Question 21
HL • Paper 2
Hard
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HL • Paper 2
Hard
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A calibration curve is obtained from the graph of f(x)=ln⁡xf(x)=\ln x using

g(x)=−1.5f(2(8−x))+4g(x)=-1.5f(2(8-x))+4
A
I.

the horizontal transformations that map the graph of ff onto the graph of gg.

[2]
II.

the vertical transformations that map the graph of ff onto the graph of gg.

[2]
B

the domain of gg and the equation of its vertical asymptote.

[2]
C

the value of xx for which g(x)=1g(x)=1.

[2]
Question 22
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
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The temperature of a container is modelled by

C(t)=18+62e−0.12t,t≥0C(t)=18+62e^{-0.12t},\qquad t\geq0

A second container begins cooling after a delay of 55 minutes. It cools 1.41.4 times as slowly, its temperature difference from the original baseline is multiplied by 0.80.8, and its new baseline is 22∘C22^\circ\text{C}.

A
I.

the input of CC that accounts for the delay and slower cooling.

[2]
II.

a model D(t)D(t) for the second container.

[2]
B

the time at which the second container first reaches 30∘C30^\circ\text{C}.

[2]
C

why replacing C(t)C(t) directly by 0.8C(t)0.8C(t) would not model the stated vertical change correctly.

[2]
Question 23
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A retailer models weekly demand by Q=f(P)Q=f(P), where PP is the price in dollars and QQ is the number of units demanded. Two points on the original demand curve are (18,260)(18,260) and (30,140)(30,140). A new market has demand

g(P)=0.75f(1.2(P−10))+40g(P)=0.75f(1.2(P-10))+40
A
I.

the coordinate mapping from a point (P,Q)(P,Q) on the original demand curve to the corresponding point on the new demand curve.

[2]
II.

the images of the two given points.

[2]
B

the weekly revenue represented by each transformed point and which is greater.

[2]
C

The point (20,250)(20,250) lies on the new demand curve. the corresponding point on the original demand curve.

[2]
Question 24
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Let f(x)=xf(x)=\sqrt{x} and define

g(x)=3f(−14(x−8))−2g(x)=3f\left(-\frac14(x-8)\right)-2
A
I.

the horizontal transformations that map the graph of ff onto the graph of gg.

[2]
II.

the vertical transformations that map the graph of ff onto the graph of gg.

[2]
B

the domain and range of gg.

[2]
C

the point on the graph of gg at which y=4y=4.

[2]

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Question 25
HL • Paper 2
Hard
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HL • Paper 2
Hard
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A numerical model is defined by

F(x)=(x−1 000 000)2F(x)=(x-1\,000\,000)^2

Values of xx used in the model are close to 1 000 0001\,000\,000.

A
I.

the transformation that maps y=x2y=x^2 onto y=F(x)y=F(x).

[2]
II.

Introduce the local coordinate u=x−1 000 000u=x-1\,000\,000 and express FF in terms of uu.

[2]
B

F(1 000 000.003)F(1\,000\,000.003).

[2]
C

why storing the local coordinate u=x−1 000 000u=x-1\,000\,000 directly, rather than first rounding x=1 000 000.003x=1\,000\,000.003 to six significant figures, can reduce rounding error.

[2]
Question 26
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The intensity profile of a light pulse is modelled by f(t)=e−t2f(t)=e^{-t^2}. A modified pulse is modelled by

g(t)=4f(1.5(t−2))+0.5g(t)=4f(1.5(t-2))+0.5
A
I.

the transformations that map the graph of ff onto the graph of gg.

[2]
II.

the coordinates of the maximum point and the equation of the horizontal asymptote of gg.

[2]
B

the two values of tt for which g(t)=2.5g(t)=2.5.

[2]
C

the width of the pulse above an intensity of 2.52.5.

[2]
Question 27
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
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A graph-design program transforms y=f(x)y=f(x) into
g(x)=pf(q(x−a))+bg(x)=p f(q(x-a))+b
where p>0p>0 and q>0q>0. The points U(−2,5)U(-2,5) and V(4,−1)V(4,-1) on the original graph are mapped to U′(1,12)U'(1,12) and V′(4,0)V'(4,0) respectively.

A

Consider a general point (u,v)(u,v) on the graph of ff.

I.

For a point (u,v)(u,v) on the graph of y=f(x)y=f(x), its image on the graph of gg has coordinates:

(a+uq, b+pv)\left(a+\frac{u}{q},\,b+pv\right)
[2]
II.

the horizontal and vertical scale factors represented by this mapping.

[2]
B

pp, qq, aa and bb.

[5]
Question 28
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A recorded seismic signal is represented by A=f(t)A=f(t), where tt is measured in seconds and AA in millimetres. A processed signal is defined by
G(t)=−1.5f(2(t−0.8))+0.2G(t)=-1.5f(2(t-0.8))+0.2
The original signal has a local maximum at (1.6,0.9)(1.6,0.9) and crosses the time axis at t=0.4t=0.4 and t=2.8t=2.8.

A

the four transformations mapping the original signal to the processed signal.

[4]
B

Consider the local maximum and the axis crossings of the original signal.

I.

the image of the local maximum and its nature.

[3]
II.

the two times at which G(t)=0.2G(t)=0.2.

[2]

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Question 29
HL • Paper 3
Hard
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HL • Paper 3
Hard
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A graphics filter uses the parent curve
f(x)=2x+1−3f(x)=\frac{2}{x+1}-3
to generate
g(x)=−2f(12(x−4))+5g(x)=-2f\left(\frac12(x-4)\right)+5

A

Analyse the construction of gg.

I.

the transformations mapping the graph of ff to the graph of gg.

[2]
II.

Express g(x)g(x) in the form Ax−h+k\dfrac{A}{x-h}+k.

[2]
B

the equations of the asymptotes and the domain and range of gg.

[3]
C

For a rational function with asymptotes x=rx=r and y=sy=s, the asymptotes after the transformation y=pf(q(x−a))+by=p f(q(x-a))+b, where pq≠0pq\ne0.

[2]
Question 30
HL • Paper 3
Hard
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HL • Paper 3
Hard
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A repeating machine motion is based on the graph of y=f(t)y=f(t). One cycle of ff has a maximum at (1,4)(1,4), a minimum at (3,−2)(3,-2) and the next maximum at (5,4)(5,4). A modified motion is
G(t)=−12f(2(t−3))+1G(t)=-\frac12f(2(t-3))+1

A

Analyse the time transformation.

I.

the period of ff and the period of GG.

[2]
II.

the image of the minimum (3,−2)(3,-2) and its nature.

[2]
B

the maximum and minimum values of GG.

[2]
C

A second modification has the form H(t)=Af(B(t−C))+DH(t)=A f(B(t-C))+D. conditions on AA and BB for HH to have the same period as GG but to preserve the nature of every turning point.

[3]
Question 31
HL • Paper 3
Hard
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HL • Paper 3
Hard
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A digital elevation profile y=f(x)y=f(x) has domain [−5,7][-5,7] and range [−3,9][-3,9]. It begins at (−5,4)(-5,4) and ends at (7,1)(7,1). A transformed profile is defined by
g(x)=3−f(6−x2)g(x)=3-f\left(\frac{6-x}{2}\right)

A

the effect on the coordinates.

I.

a point (u,v)(u,v) is mapped to (6−2u,3−v)(6-2u,3-v).

[2]
II.

the images of the two endpoints.

[2]
B

the domain and range of gg.

[2]
C

why the left endpoint of the transformed profile corresponds to the right endpoint of the original profile.

[2]
Question 32
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
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For a manufacturer, C=f(n)C=f(n) gives the daily operating cost CC, in euros, when nn items are produced. After equipment is replaced, the cost is modelled by
G(n)=0.8f(n−1201.5)+600G(n)=0.8f\left(\frac{n-120}{1.5}\right)+600
The original graph contains the point (300,5400)(300,5400).

A

Analyse the transformations in context.

I.

the horizontal scale factor and horizontal translation, including appropriate units.

[2]
II.

the two vertical transformations.

[3]
B

the transformed operating point corresponding to (300,5400)(300,5400) and its coordinates.

[3]
C

why the value 600600 has units but the values 0.80.8 and 1.51.5 do not.

[1]

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Question 33
HL • Paper 2
Hard
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HL • Paper 2
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Let

f(x)=x3−3xf(x)=x^3-3x

and

g(x)=12f(−2(x−1))−2g(x)=\frac12f(-2(x-1))-2

The graph of ff has a local maximum at (−1,2)(-1,2) and a local minimum at (1,−2)(1,-2).

A
I.

the coordinate mapping from a point (x,y)(x,y) on the graph of ff to its image on the graph of gg.

[2]
II.

the coordinates and nature of both turning points of gg.

[2]
B

the xx-intercept of the graph of gg.

[2]
C

A student claims that the reflection in the yy-axis changes every maximum point into a minimum point. why this claim is incorrect.

[2]
Question 34
HL • Paper 2
Hard
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HL • Paper 2
Hard
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An animation is described by y=f(t)y=f(t) for 0≤t≤120\leq t\leq12. Let TT be a translation 33 seconds to the right and let SS be a horizontal stretch with scale factor 1.51.5.

A
I.

the function and domain obtained when TT is applied first and SS second.

[2]
II.

the function and domain obtained when SS is applied first and TT second.

[2]
B

An event occurs at time t=rt=r in the original animation. its final time under each sequence.

[2]
C

why the order of these transformations changes the animation.

[2]
Question 35
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The graph of y=f(x)y=f(x) is subjected to a vertical translation by bb units and a vertical stretch with scale factor pp, where p>0p>0.

A
I.

the function obtained when the translation is applied before the stretch.

[2]
II.

the function obtained when the stretch is applied before the translation.

[2]
B

all conditions on pp and bb for which the two sequences produce the same graph.

[2]
C

For p=2.5p=2.5 and b=−4b=-4, the vertical distance between the two resulting graphs and why it is constant.

[2]
Question 36
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
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A path profile is modelled by

f(x)={x+2,−2≤x<1,4−x,1≤x≤4.f(x)= \begin{cases} x+2, & -2\leq x<1,\\ 4-x, & 1\leq x\leq4. \end{cases}

A transformed profile is defined by

g(x)=−2f(3−x)+1g(x)=-2f(3-x)+1
A
I.

the transformed domain and the transformed location of the joining point.

[2]
II.

a piecewise expression for g(x)g(x).

[2]
B

the range of gg.

[2]
C

gg is continuous at its joining point.

[2]

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Question 37
HL • Paper 2
Hard
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HL • Paper 2
Hard
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A cyclic environmental index is modelled by

g(t)=acos⁡(b(t−c))+dg(t)=a\cos(b(t-c))+d

where a>0a>0, b>0b>0 and 0≤c<100\leq c<10. The index has a maximum value of 77, a minimum value of 11, a period of 1010 days and a maximum at t=2t=2.

A
I.

aa and dd.

[2]
II.

bb and cc, and the model.

[2]
B

the first time after t=2t=2 at which the index is 55.

[2]
C

the total time during one period for which the index is greater than 55.

[2]
Question 38
HL • Paper 3
Hard
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HL • Paper 3
Hard
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Let ThT_h denote a translation hh units to the right, where h>0h>0, and let HsH_s denote a horizontal stretch with scale factor ss, where s>1s>1. These transformations are applied to the graph of y=f(x)y=f(x).

Step

ThT_h then HsH_s

HsH_s then ThT_h

Starting graph

y=f(x)y=f(x)

y=f(x)y=f(x)

Point to track

(u,v)(u,v)

(u,v)(u,v)

1st transformation

ThT_h

HsH_s

2nd transformation

HsH_s

ThT_h

A

A point on the original graph has coordinates (u,v)(u,v).

I.

its final coordinates when ThT_h is applied before HsH_s.

[2]
II.

its final coordinates when HsH_s is applied before ThT_h.

[2]
B

the horizontal separation between the two final images of the point.

[2]
C

the condition under which the two transformation sequences produce the same graph for every function ff (equivalently, when the transformation operators commute), and this result for h>0h>0 and s>1s>1.

[3]
Question 39
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A sensor response has the shape of the parent function f(x)=ln⁡xf(x)=\ln x. Its calibrated response is
g(x)=pln⁡(q(x−a))+bg(x)=p\ln(q(x-a))+b
where p>0p>0 and q>0q>0. The calibrated graph has vertical asymptote x=4x=4 and contains the points (5,2)(5,2) and (7,8)(7,8).

A

Use the asymptote and the two calibration points.

I.

aa.

[1]
II.

pln⁡3=6p\ln 3=6.

[2]
III.

The horizontal scale factor is known to be 22. pp, qq and bb, giving non-exact answers to three significant figures.

[3]
B

the image on the calibrated graph of the parent point (e2,2)(e^2,2).

[2]
C

why the same calibrated graph can be represented using different pairs of values for qq and bb if the horizontal scale factor is not specified.

[2]
Question 40
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
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A two-dimensional image-registration algorithm maps coordinates according to
X=a+xq,Y=b+pyX=a+\frac{x}{q},\qquad Y=b+py
where pq≠0pq\ne0. Three landmarks on the original image are A(−3,2)A(-3,2), B(1,6)B(1,6) and C(5,−1)C(5,-1). Their registered images include A′(8,−2)A'(8,-2) and B′(6,10)B'(6,10).

A

the transformation parameters.

I.

qq and aa.

[3]
II.

pp and bb.

[3]
B

the coordinates of C′C'.

[2]
C

the reflections present in the registration and your answer.

[2]

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Question 41
HL • Paper 3
Hard
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HL • Paper 3
Hard
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A satellite's measured displacement is modelled near the large time value t0=108t_0=10^8 seconds by
D(t)=0.000003(t−t0)2−0.04(t−t0)+7D(t)=0.000003(t-t_0)^2-0.04(t-t_0)+7
A technician introduces the translated variable u=t−t0u=t-t_0 and defines F(u)=D(u+t0)F(u)=D(u+t_0).

u [s]

t [s]

Displacement

-8000

99992000

519

-4000

99996000

215

0

100000000

7

4000

100004000

-105

6000

100006000

-125

8000

100008000

-121

10000

100010000

-93

16000

100016000

135

A

Work with the translated coordinate.

I.

F(u)=0.000003u2−0.04u+7F(u)=0.000003u^2-0.04u+7.

[2]
II.

the translation mapping the graph of DD to the graph of FF when both are drawn using their stated horizontal variables.

[2]
B

the value of uu at the turning point and the corresponding value of tt.

[3]
C

one numerical advantage of calculating with F(u)F(u) rather than expanding D(t)D(t) as a polynomial in tt.

[2]
Question 42
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

The cross-section of a custom ramp is represented by an unfamiliar function y=f(x)y=f(x) on 0≤x≤100\le x\le10. It contains joins at (2,1)(2,1) and (7,4)(7,4) and has maximum point (5,6)(5,6). A second ramp is modelled by
g(x)=1.2f(−x−182)−0.5g(x)=1.2f\left(-\frac{x-18}{2}\right)-0.5

A

Analyse the transformation of key features.

I.

the horizontal transformations.

[2]
II.

the images of the two joins.

[2]
III.

the image of the maximum point.

[2]
B

the domain of gg.

[2]
C

why the order of the two joins is reversed on the second ramp but their shape type is unchanged.

[2]
Question 43
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

The graph of a function ff with domain DD, where D=−DD=-D (for example, D=RD=\mathbb{R}), is transformed in two ways on this common domain:
g(x)=−f(−x),h(x)=f(x)g(x)=-f(-x),\qquad h(x)=f(x)
The accompanying diagram is illustrative only and is not data to be used in part (c).

A designer wants the graphs of gg and hh to coincide.

A

the transformation producing gg.

I.

the two reflections mapping ff to gg.

[2]
II.

the equivalent single geometric transformation.

[2]
B

the graphs coincide if and only if ff is an odd function.

[3]
C

what can be deduced about the graph if it contains the point (4,−7)(4,-7) and the two graphs coincide.

[2]
Question 44
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A curve is transformed by
T:(x,y)↦(5−x3,2y−4)T:(x,y)\mapsto\left(5-\frac{x}{3},2y-4\right)
A software system must later restore every point to its original position.

A

Relate the coordinate mapping to a graph equation.

I.

If the original graph is y=f(x)y=f(x), its image has equation
g(X)=2f(15−3X)−4g(X)=2f(15-3X)-4

[3]
II.

the horizontal reflection and horizontal scale factor used by TT.

[1]
B

the restoring coordinate transformation T−1T^{-1}.

[3]
C

that applying T−1T^{-1} after TT returns a general point (x,y)(x,y) to itself.

[3]

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Question 45
HL • Paper 3
Hard
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HL • Paper 3
Hard
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A transformation maps every point according to
T(x,y)=(2x−3,12y+4)T(x,y)=(2x-3,\tfrac12y+4)
A point is called invariant if it is unchanged by the transformation.

A

the invariant point.

I.

for the invariant xx-coordinate.

[2]
II.

for the invariant yy-coordinate and the invariant point.

[2]
B

after applying TT nn times, the coordinates are
xn=3+2n(x0−3),yn=8+2−n(y0−8)x_n=3+2^n(x_0-3),\qquad y_n=8+2^{-n}(y_0-8)

[3]
C

the long-term behaviour of the image of a point with x0≠3x_0\ne3 as n→∞n\to\infty.

[2]
Question 46
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
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A non-symmetric function ff has endpoints (0,1)(0,1) and (6,−1)(6,-1) and a local maximum at (2,5)(2,5). It is transformed according to

g(x)=pf(q(x−a))+bg(x)=pf(q(x-a))+b

where q>0q>0. The corresponding features of gg are endpoints (1,0)(1,0) and (13,4)(13,4) and a local minimum at (5,−8)(5,-8).

A
I.

Use the horizontal coordinates of the corresponding endpoints to qq and aa.

[2]
II.

Use the vertical coordinates of the endpoints to pp and bb.

[2]
B

that the local maximum of ff maps to the stated local minimum of gg.

[2]
C

Given that g(7)=−2g(7)=-2, f(3)f(3).

[2]
Question 47
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

For f(x)=exf(x)=e^x, consider the family of transformed functions
g(x)=pf(q(x−a))+bg(x)=p f(q(x-a))+b
where p>0p>0 and q>0q>0. A curve-fitting program reports p=6p=6, q=0.4q=0.4, a=3a=3 and b=−2b=-2.

A

Simplify and key features.

I.

Write g(x)g(x) in the form Ce0.4x−2Ce^{0.4x}-2 and CC to three significant figures.

[2]
II.

the range of gg and the image of the parent point (1,e)(1,e).

[2]
B

The program fixes q=0.4q=0.4 and b=−2b=-2 but allows pp and aa to vary. infinitely many pairs (p,a)(p,a) produce exactly the same curve.

[4]
C

the value of pp that gives the same curve when a=0a=0, and why interpreting pp and aa separately would be unreliable.

[2]
Question 48
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Two vertical transformations act on a graph. Transformation SpS_p is a vertical stretch with non-zero scale multiplier pp, and transformation TbT_b is a vertical translation by bb units. A general point on the graph is (x,y)(x,y).

A

the two possible orders.

I.

the final vertical coordinate when SpS_p is applied before TbT_b.

[2]
II.

the final vertical coordinate when TbT_b is applied before SpS_p.

[2]
B

the condition on pp and bb for SpS_p and TbT_b to commute.

[3]
C

A vertical transformation is written V(y)=py+bV(y)=py+b. It is to be performed in the reverse order, translation first and then stretch, without changing the final graph.

I.

To obtain the same final result as applying SpS_p followed by TbT_b, the translation by cc that must be applied before SpS_p, for p≠0p\ne0.

[2]
II.

rewrite the transformation y↦−3y+12y\mapsto-3y+12 as a translation followed by a vertical stretch and reflection.

[2]

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Properties of Functions