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Differential Equations

Practice exam-style IB Math AI questions for Differential Equations, aligned with the syllabus and grouped by topic.

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Question 1
HL • Paper 1
Easy
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HL • Paper 1
Easy
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The slope field for the differential equation

dydx=y(2−y)\frac{\mathrm{d}y}{\mathrm{d}x}=y(2-y)

is shown for −2≤x≤3-2\leq x\leq 3 and −1≤y≤3-1\leq y\leq 3.

A

the two equilibrium solutions.

[2]
B

whether the gradient is positive or negative in the region 0<y<20<y<2.

[1]
C

On the slope field, the solution curve passing through (0,1)(0,1).

[2]
Question 2
HL • Paper 1
Easy
Calculator Permitted
HL • Paper 1
Easy
Calculator Permitted

The function yy satisfies

dydx=x−y,y(0)=1\frac{\mathrm{d}y}{\mathrm{d}x}=x-y,\qquad y(0)=1

Euler's method with step size h=0.2h=0.2 is used to y(0.6)y(0.6).

A

the Euler recurrence for yn+1y_{n+1} in terms of xnx_n and yny_n.

[1]
B

the Euler estimates for y(0.2)y(0.2) and y(0.4)y(0.4).

[2]
C

y(0.6)y(0.6).

[1]
D

The exact value is y(0.6)=0.698y(0.6)=0.698, correct to three significant figures. whether the Euler is an overestimate or an underestimate.

[1]
Question 3
HL • Paper 1
Medium
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HL • Paper 1
Medium
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A medicine is eliminated from a patient's bloodstream at a rate proportional to the mass QQ of medicine present. Initially, the bloodstream contains 8080 mg of the medicine. After 33 hours, 5050 mg remains.

A

a differential equation that models the mass of medicine, where tt is measured in hours and kk is a positive constant.

[1]
B

kk.

[3]
C

the mass of medicine remaining after 88 hours.

[2]
Question 4
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
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The area GG covered by algae, in square metres, is modelled by

dGdt=kG\frac{\mathrm{d}G}{\mathrm{d}t}=k\sqrt{G}

where tt is the time in days and k>0k>0. Initially, G=4G=4, and after 66 days, G=25G=25.

A

By solving the differential equation, 2G=kt+42\sqrt{G}=kt+4.

[3]
B

kk.

[1]
C

the time at which the area covered by algae first reaches 49 m249\ \text{m}^2.

[2]

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Question 5
HL • Paper 1
Medium
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HL • Paper 1
Medium
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A spherical object expands so that its radius rr, in centimetres, increases at a rate inversely proportional to its radius. Initially, its radius is 44 cm, and after 66 seconds its radius is 88 cm.

A

a differential equation for rr in terms of tt, using a positive constant kk.

[1]
B

the differential equation and kk.

[3]
C

the time at which the radius reaches 1212 cm.

[2]
Question 6
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
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The function yy satisfies

dydx=y(2−y),y(0)=0.5\frac{\mathrm{d}y}{\mathrm{d}x}=y(2-y),\qquad y(0)=0.5

Two Euler approximations for y(0.5)y(0.5) are calculated.

A

Using one step of length 0.50.5, an for y(0.5)y(0.5).

[2]
B

Using two steps of length 0.250.25, another for y(0.5)y(0.5).

[2]
C

The exact value of y(0.5)y(0.5) is 0.9510.951, correct to three significant figures. which Euler approximation is more accurate.

[1]
Question 7
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
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The populations xx and yy, in hundreds, of two interacting species are modelled by

dxdt=0.4x−0.02xy,dydt=−0.3y+0.01xy.\begin{aligned} \frac{\mathrm{d}x}{\mathrm{d}t}&=0.4x-0.02xy,\\ \frac{\mathrm{d}y}{\mathrm{d}t}&=-0.3y+0.01xy. \end{aligned}

Initially, x=20x=20 and y=10y=10. Euler's method is used with step size h=0.5h=0.5.

A

the Euler recurrence relations for xn+1x_{n+1} and yn+1y_{n+1}.

[2]
B

the estimates for xx and yy when t=0.5t=0.5.

[2]
C

xx and yy when t=1t=1.

[2]
Question 8
HL • Paper 2
Medium
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HL • Paper 2
Medium
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An infection is modelled by the coupled system

dSdt=−0.002SI,dIdt=0.002SI−0.4I,dRdt=0.4I,\begin{aligned} \frac{\mathrm{d}S}{\mathrm{d}t}&=-0.002SI,\\ \frac{\mathrm{d}I}{\mathrm{d}t}&=0.002SI-0.4I,\\ \frac{\mathrm{d}R}{\mathrm{d}t}&=0.4I, \end{aligned}

where SS, II and RR are population sizes. Initially, (S,I,R)=(90,10,0)(S,I,R)=(90,10,0). Euler's method is used with h=0.1h=0.1.

A

the Euler estimates for SS, II and RR when t=0.1t=0.1.

[3]
B

the Euler estimates for SS, II and RR when t=0.2t=0.2.

[2]

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Question 9
HL • Paper 1
Medium
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HL • Paper 1
Medium
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A phase portrait is associated with the system

dxdt=3x+y,dydt=x+3y.\begin{aligned} \frac{\mathrm{d}x}{\mathrm{d}t}&=3x+y,\\ \frac{\mathrm{d}y}{\mathrm{d}t}&=x+3y. \end{aligned}
A

the velocity vector at the point (1,0)(1,0).

[1]
B

the eigenvalues and corresponding eigendirections of the system.

[3]
C

the long-term behaviour of a non-equilibrium trajectory.

[1]
Question 10
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
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Consider the system

ddt(xy)=(−1−22−1)(xy)\frac{\mathrm{d}}{\mathrm{d}t} \begin{pmatrix}x\\y\end{pmatrix} = \begin{pmatrix}-1&-2\\2&-1\end{pmatrix} \begin{pmatrix}x\\y\end{pmatrix}
A

the eigenvalues of the coefficient matrix.

[2]
B

the form and stability of trajectories near the origin.

[1]
C

whether the trajectories rotate clockwise or anticlockwise.

[1]
Question 11
HL • Paper 1
Medium
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HL • Paper 1
Medium
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The displacement xx of a particle satisfies

d2xdt2+2dxdt+5x=0\frac{\mathrm{d}^2x}{\mathrm{d}t^2}+2\frac{\mathrm{d}x}{\mathrm{d}t}+5x=0

Initially, x=1x=1 and dxdt=0\dfrac{\mathrm{d}x}{\mathrm{d}t}=0.

A

By defining v=dxdtv=\dfrac{\mathrm{d}x}{\mathrm{d}t}, write the equation as a coupled system of first-order differential equations.

[2]
B

the Euler recurrence relations for xx and vv using step size h=0.1h=0.1.

[2]
C

Use Euler's method to the displacement and velocity when t=0.2t=0.2.

[2]
Question 12
HL • Paper 1
Medium
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HL • Paper 1
Medium
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Solutions of the differential equation

dydx=x2−y\frac{\mathrm{d}y}{\mathrm{d}x}=x^2-y

may have stationary points.

A

the equation of the curve on which all stationary points lie.

[1]
B

whether a stationary point with x<0x<0 is a local maximum or a local minimum.

[2]
C

Classify the stationary point (2,4)(2,4).

[1]

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Question 13
HL • Paper 1
Medium
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HL • Paper 1
Medium
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Consider the linear system

ddt(xy)=(41−21)(xy)\frac{\mathrm{d}}{\mathrm{d}t} \begin{pmatrix}x\\y\end{pmatrix} = \begin{pmatrix}4&1\\-2&1\end{pmatrix} \begin{pmatrix}x\\y\end{pmatrix}
A

the eigenvalues of the coefficient matrix.

[2]
B

an eigenvector corresponding to each eigenvalue.

[2]
C

Classify the equilibrium at the origin and its stability.

[1]
Question 14
HL • Paper 1
Medium
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HL • Paper 1
Medium
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The displacement xx of an object satisfies

d2xdt2−dxdt−6x=0\frac{\mathrm{d}^2x}{\mathrm{d}t^2}-\frac{\mathrm{d}x}{\mathrm{d}t}-6x=0

with x(0)=2x(0)=2 and x′(0)=1x'(0)=1.

A

the roots of the characteristic equation.

[2]
B

the particular solution for x(t)x(t).

[3]
C

the displacement when t=0.5t=0.5.

[2]
Question 15
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
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The displacement xx of a damped system satisfies

d2xdt2+4dxdt+13x=0\frac{\mathrm{d}^2x}{\mathrm{d}t^2}+4\frac{\mathrm{d}x}{\mathrm{d}t}+13x=0

Let v=dxdtv=\dfrac{\mathrm{d}x}{\mathrm{d}t}.

A

Write the corresponding matrix system for (xv)\begin{pmatrix}x\\v\end{pmatrix}.

[2]
B

the eigenvalues of the coefficient matrix.

[1]
C

the phase portrait near the origin, including its direction of rotation.

[2]
Question 16
HL • Paper 1
Medium
Calculator Permitted
HL • Paper 1
Medium
Calculator Permitted

The vector X(t)=(x(t)y(t))\mathbf{X}(t)=\begin{pmatrix}x(t)\\y(t)\end{pmatrix} satisfies

dXdt=(2112)X\frac{\mathrm{d}\mathbf{X}}{\mathrm{d}t}= \begin{pmatrix}2&1\\1&2\end{pmatrix}\mathbf{X}

with X(0)=(31)\mathbf{X}(0)=\begin{pmatrix}3\\1\end{pmatrix}.

A

the two eigenvalues of the coefficient matrix.

[2]
B

an eigenvector corresponding to each eigenvalue.

[2]
C

x(t)x(t) and y(t)y(t).

[3]

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Question 17
HL • Paper 2
Medium
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HL • Paper 2
Medium
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Water leaks from a tank. The volume VV, in litres, decreases at a rate proportional to V\sqrt{V}. Initially the tank contains 900900 litres, and after 44 hours it contains 676676 litres. Let tt be the time in hours and let k>0k>0.

A
I.

a differential equation modelling the volume of water.

[1]
II.

By separating variables, V=30−k2t\sqrt V=30-\dfrac{k}{2}t.

[3]
B
I.

kk.

[2]
II.

when the volume first reaches 400400 litres.

[2]
Question 18
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
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A function yy satisfies

dydx=xe−y,y(0)=0\frac{\mathrm dy}{\mathrm dx}=xe^{-y},\qquad y(0)=0
A
I.

the particular solution in the form y=f(x)y=f(x).

[4]
II.

the exact value of y(2)y(2).

[1]
B

the positive values of xx for which the gradient of the solution curve is 0.50.5.

[3]
Question 19
HL • Paper 2
Medium
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HL • Paper 2
Medium
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The function yy satisfies

dydx=sin⁡x−0.4y2,y(0)=0.5\frac{\mathrm dy}{\mathrm dx}=\sin x-0.4y^2, \qquad y(0)=0.5
A
I.

the Euler recurrence with step size h=0.25h=0.25.

[2]
II.

Use this recurrence to y(1)y(1).

[3]
B

Using Euler's method with h=0.5h=0.5 gives y(1)≈0.649y(1)\approx0.649. the percentage difference between the two Euler estimates, relative to the using h=0.25h=0.25.

[3]
Question 20
HL • Paper 3
Medium
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HL • Paper 3
Medium
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The salt concentration CC, in grams per litre, in a lagoon is modelled by assuming that its rate of increase is proportional to the difference between CC and the limiting concentration 1212. Initially, C=2C=2, and after three days C=7C=7. Time tt is measured in days.

A

Set up the differential-equation model.

I.

the differential equation, using a positive constant kk.

[1]
II.

the units of kk.

[1]
B

By separation of variables, C=12−10e−ktC=12-10e^{-kt}.

[3]
C

Use the model to the first time at which C=10C=10.

[3]

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Question 21
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The population PP of an insect colony is modelled by

dPdt=0.3P(1−P1200)\frac{\mathrm dP}{\mathrm dt}=0.3P\left(1-\frac{P}{1200}\right)

where tt is measured in days. Initially, P=200P=200.

A
I.

the differential equation may be separated in the form

(1P+11200−P) dP=0.3 dt\left(\frac1P+\frac1{1200-P}\right)\,\mathrm dP=0.3\,\mathrm dt
[2]
II.

the particular solution for PP in terms of tt.

[4]
B

the time at which the population reaches 900900, and when it exceeds 900900.

[3]
Question 22
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The slope field shown represents

dydx=(x−1)(y+1)\frac{\mathrm dy}{\mathrm dx}=(x-1)(y+1)
A
I.

the equilibrium solution.

[1]
II.

For a non-equilibrium solution, why a stationary point occurs at x=1x=1 and classify it when y>−1y>-1.

[3]
B

The solution curve passes through (0,0)(0,0). its minimum value.

[4]
Question 23
HL • Paper 2
Hard
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HL • Paper 2
Hard
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Consider the differential equation

dydx=(2−x)(y−1)\frac{\mathrm dy}{\mathrm dx}=(2-x)(y-1)

A solution curve passes through (0,3)(0,3).

A
I.

the equilibrium solution and the vertical line on which all non-equilibrium solutions have stationary points.

[2]
II.

Use the displayed solution-curve graph to classify the stationary point of the specified solution.

[2]
B

the coordinates of this stationary point.

[5]
Question 24
HL • Paper 2
Hard
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HL • Paper 2
Hard
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Two connected tanks contain amounts xx and yy litres of a dissolved substance. The amounts are modelled by

dxdt=−0.3x+0.1y,dydt=0.3x−0.2y\frac{\mathrm dx}{\mathrm dt}=-0.3x+0.1y, \qquad \frac{\mathrm dy}{\mathrm dt}=0.3x-0.2y

Initially, x=40x=40 and y=10y=10, where tt is measured in hours.

A
I.

the simultaneous Euler recurrences for step size h=0.5h=0.5.

[2]
II.

xx and yy when t=1t=1.

[4]
B

Use the model to why the total amount x+yx+y always decreases when y>0y>0.

[3]

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Question 25
HL • Paper 2
Hard
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HL • Paper 2
Hard
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Consider the system

ddt(xy)=(−0.5−22−0.5)(xy)\frac{\mathrm d}{\mathrm dt} \begin{pmatrix}x\\y\end{pmatrix} = \begin{pmatrix}-0.5&-2\\2&-0.5\end{pmatrix} \begin{pmatrix}x\\y\end{pmatrix}

with initial (4,0)(4,0).

A
I.

the eigenvalues. Use the displayed phase-plane trajectory to the stability and form of the phase portrait.

[3]
II.

the direction of rotation.

[1]
B

Use Euler's method with h=0.1h=0.1 to the when t=0.2t=0.2.

[4]
Question 26
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The displacement xx, in metres, of a damped mechanical system satisfies

d2xdt2+5dxdt+6x=0\frac{\mathrm d^2x}{\mathrm dt^2}+5\frac{\mathrm dx}{\mathrm dt}+6x=0

where x(0)=3x(0)=3 and x′(0)=−1x'(0)=-1.

A
I.

By defining v=x′v=x', write the equation as a first-order matrix system and its eigenvalues.

[3]
II.

the particular solution for x(t)x(t).

[3]
B

x(0.5)x(0.5) and the long-term behaviour of the system.

[3]
Question 27
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The vertical displacement xx, in metres, of a ball moving upwards through a resisting medium satisfies

d2xdt2=−0.4dxdt−9.8\frac{\mathrm d^2x}{\mathrm dt^2}=-0.4\frac{\mathrm dx}{\mathrm dt}-9.8

Initially, x=0x=0 and x′=20 m s−1x'=20\ \mathrm{m\,s}^{-1}.

A
I.

Define v=x′v=x' and Euler recurrence relations with step size h=0.2h=0.2.

[2]
II.

Use Euler's method to the displacement and velocity at t=0.6t=0.6.

[4]
B

Without resistance, the displacement after 0.60.6 seconds would be modelled by x=20t−4.9t2x=20t-4.9t^2. this value with the Euler and the difference.

[3]
Question 28
HL • Paper 3
Hard
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HL • Paper 3
Hard
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A block of ice has volume VV cubic centimetres. During melting, its rate of decrease in volume is proportional to V2/3V^{2/3}. Initially, its volume is 1000 cm31000\ \text{cm}^3. After six minutes, its volume is 512 cm3512\ \text{cm}^3.

A

Develop a model for the volume.

I.

a differential equation for VV, using a positive constant kk.

[1]
II.

the differential equation to V=(10−k3t)3V=(10-\frac{k}{3}t)^3 while V>0V>0.

[3]
B

kk and the time predicted for the block to melt completely.

[3]
C

one reason why the predicted melting time may not be reliable.

[1]

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Question 29
HL • Paper 3
Hard
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HL • Paper 3
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A slope field is shown for the differential equation

dydx=(x−1)(y−2)\frac{dy}{dx}=(x-1)(y-2)

y

x=-1

x=0

x=1

x=2

1

2

1

0

-1

2

0

0

0

0

3

-2

-1

0

1

A

the zero-gradient features of the field.

I.

the two lines on which the field has horizontal segments.

[2]
II.

why only one of these lines is an equilibrium solution.

[1]
B

the particular solution passing through (0,3)(0,3).

[3]
C

and classify the stationary point of this solution.

[2]
Question 30
HL • Paper 3
Hard
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HL • Paper 3
Hard
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The number PP of users who have received an emergency alert is modelled by

dPdt=0.6P(1−P5000),P(0)=500\frac{dP}{dt}=0.6P\left(1-\frac{P}{5000}\right),\qquad P(0)=500

where tt is measured in hours.

A

Euler's method is used with step size h=0.5h=0.5 hours.

I.

the Euler recurrence.

[1]
II.

the Euler for P(1)P(1).

[2]
B

By separation of variables, the exact solution can be written as P=50001+Ae−0.6tP=\dfrac{5000}{1+Ae^{-0.6t}}. AA.

[2]
C

the Euler with the exact value at t=1t=1, and on the effect of using a smaller step size.

[3]
Question 31
HL • Paper 3
Hard
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HL • Paper 3
Hard
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Two connected tanks contain amounts xx and yy kilograms of a dissolved mineral. The transfer process is modelled by

dxdt=−0.3x+0.1y,dydt=0.3x−0.1y\frac{dx}{dt}=-0.3x+0.1y, \qquad \frac{dy}{dt}=0.3x-0.1y

where tt is measured in hours. Initially, (x,y)=(20,0)(x,y)=(20,0).

A

conservation in the model.

I.

ddt(x+y)\dfrac{d}{dt}(x+y).

[1]
II.

this result in context.

[1]
B

Use Euler's method with h=1h=1 to (x,y)(x,y) after two hours.

[3]
C

the equilibrium amounts consistent with the initial total amount.

[2]
D

why the Euler values preserve the total amount exactly in this model.

[1]
Question 32
HL • Paper 3
Hard
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HL • Paper 3
Hard
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Deviations xx and yy from the target values of two economic indicators are modelled by

ddt(xy)=(−12−2−1)(xy)\frac{d}{dt}\begin{pmatrix}x\\y\end{pmatrix} = \begin{pmatrix}-1&2\\-2&-1\end{pmatrix} \begin{pmatrix}x\\y\end{pmatrix}
A

Analyse the coefficient matrix.

I.

its eigenvalues.

[2]
II.

Classify the equilibrium at the origin.

[1]
B

the direction of rotation and your answer using the point (1,0)(1,0).

[2]
C

a representative phase portrait, including arrows and the long-term behaviour.

[3]

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Question 33
HL • Paper 3
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HL • Paper 3
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The displacement xx, in metres, of a damped platform satisfies

d2xdt2+5dxdt+6x=0\frac{d^2x}{dt^2}+5\frac{dx}{dt}+6x=0

with x(0)=0.1x(0)=0.1 and x′(0)=0x'(0)=0.

A

an Euler approximation using v=x′v=x'.

I.

Write the coupled first-order system and Euler recurrences for step size h=0.1h=0.1.

[2]
II.

x(0.2)x(0.2) and v(0.2)v(0.2).

[2]
B

the exact displacement x(t)x(t).

[3]
C

the Euler of x(0.2)x(0.2) with the exact value.

[1]
Question 34
HL • Paper 2
Hard
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HL • Paper 2
Hard
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Temperatures xx and yy, in degrees Celsius, in two connected chambers are modelled by

dxdt=0.2(100−x)−0.1(x−y),dydt=0.1(x−y)−0.05y\frac{\mathrm dx}{\mathrm dt}=0.2(100-x)-0.1(x-y), \qquad \frac{\mathrm dy}{\mathrm dt}=0.1(x-y)-0.05y

Initially, (x,y)=(20,0)(x,y)=(20,0) and tt is measured in minutes.

A
I.

Using Euler's method with h=1h=1, the after one minute.

[3]
II.

the temperatures after two minutes.

[3]
B

the equilibrium temperatures predicted by the model.

[4]
Question 35
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The vector X(t)=(x(t)y(t))\mathbf X(t)=\begin{pmatrix}x(t)\\y(t)\end{pmatrix} satisfies

dXdt=(−311−3)X,X(0)=(62)\frac{\mathrm d\mathbf X}{\mathrm dt}= \begin{pmatrix}-3&1\\1&-3\end{pmatrix}\mathbf X, \qquad \mathbf X(0)=\begin{pmatrix}6\\2\end{pmatrix}
A
I.

the eigenvalues and a corresponding eigenvector for each eigenvalue.

[3]
II.

the particular solution.

[3]
B

the time when y=0.9xy=0.9x, and the trajectory as t→∞t\to\infty.

[4]
Question 36
HL • Paper 2
Hard
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HL • Paper 2
Hard
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A coupled system is given by

ddt(xy)=(1221)(xy),(x(0),y(0))=(3,−1)\frac{\mathrm d}{\mathrm dt} \begin{pmatrix}x\\y\end{pmatrix} = \begin{pmatrix}1&2\\2&1\end{pmatrix} \begin{pmatrix}x\\y\end{pmatrix}, \qquad (x(0),y(0))=(3,-1)
A
I.

the eigenvalues and corresponding eigendirections, and classify the origin.

[3]
II.

the particular solution.

[2]
B

when the trajectory first crosses the positive xx-axis, and its asymptote as t→∞t\to\infty.

[4]

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Question 37
HL • Paper 2
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HL • Paper 2
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The system

dxdt=−3y,dydt=12x\frac{\mathrm dx}{\mathrm dt}=-3y, \qquad \frac{\mathrm dy}{\mathrm dt}=12x

has initial condition (x(0),y(0))=(2,0)(x(0),y(0))=(2,0).

A
I.

the eigenvalues and classify the origin.

[2]
II.

4x2+y24x^2+y^2 is constant along every trajectory.

[3]
B

the maximum value of ∣y∣|y|, the direction of rotation and the period of the motion.

[4]
Question 38
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The displacement xx of an unstable system satisfies

d2xdt2+dxdt−6x=0\frac{\mathrm d^2x}{\mathrm dt^2}+\frac{\mathrm dx}{\mathrm dt}-6x=0

with x(0)=1x(0)=1 and x′(0)=0x'(0)=0.

A
I.

Write the equation as a first-order system and classify the equilibrium at the origin.

[3]
II.

expressions for x(t)x(t) and v(t)v(t).

[4]
B

the first time after t=0t=0 when x=5x=5, and the asymptote of the trajectory in the (x,v)(x,v) phase plane as t→∞t\to\infty.

[3]
Question 39
HL • Paper 3
Hard
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HL • Paper 3
Hard
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The density FF of flowering plants and the density BB of pollinating insects are modelled by

dFdt=0.5F(1−F80)−0.04FB,dBdt=0.02FB−0.3B.\begin{aligned} \frac{dF}{dt}&=0.5F\left(1-\frac{F}{80}\right)-0.04FB,\\ \frac{dB}{dt}&=0.02FB-0.3B. \end{aligned}

Both densities are positive and tt is measured in months.

A

the positive equilibrium.

I.

the equilibrium value of FF is 1515.

[2]
II.

the equilibrium value of BB.

[2]
B

Starting from (F,B)=(20,8)(F,B)=(20,8), use one Euler step of length 0.50.5 to the two densities.

[2]
C

A pesticide halves the coefficient 0.020.02 but leaves all other coefficients unchanged. the new positive equilibrium value of FF and the change.

[2]
Question 40
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Two variables satisfy

dXdt=(1221)X,X(0)=(31)\frac{d\mathbf X}{dt}= \begin{pmatrix}1&2\\2&1\end{pmatrix}\mathbf X, \qquad \mathbf X(0)=\begin{pmatrix}3\\1\end{pmatrix}
A

the eigenstructure of the system.

I.

the eigenvalues.

[1]
II.

a corresponding eigenvector for each eigenvalue.

[2]
B

x(t)x(t) and y(t)y(t).

[3]
C

the trajectory as t→∞t\to\infty, including its limiting direction.

[2]

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Question 41
HL • Paper 3
Hard
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HL • Paper 3
Hard
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Temperature deviations xx and yy in two linked chambers satisfy

ddt(xy)=(−311−3)(xy),yqquad(x(0)y(0))=(62)\frac{d}{dt}\begin{pmatrix}x\\y\end{pmatrix} = \begin{pmatrix}-3&1\\1&-3\end{pmatrix} \begin{pmatrix}x\\y\end{pmatrix}, yqquad \begin{pmatrix}x(0)\\y(0)\end{pmatrix}= \begin{pmatrix}6\\2\end{pmatrix}
A

the eigenvalues and corresponding eigendirections.

I.

the eigenvalues.

[1]
II.

a corresponding eigenvector for each eigenvalue.

[2]
B

the particular solution.

[3]
C

Classify the origin and the eigendirection approached by this trajectory.

[2]
Question 42
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
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A conservative system is modelled by

dxdt=−2y,dydt=8x\frac{dx}{dt}=-2y, \qquad \frac{dy}{dt}=8x

with (x(0),y(0))=(1,0)(x(0),y(0))=(1,0).

A

Analyse the phase-plane invariant.

I.

4x2+y24x^2+y^2 is constant along every trajectory.

[2]
II.

the equation of the trajectory through (1,0)(1,0).

[1]
B

x(t)x(t) and y(t)y(t).

[3]
C

the period and direction of motion in the phase plane.

[2]
Question 43
HL • Paper 3
Hard
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HL • Paper 3
Hard
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The vertical displacement xx, in metres, of an object released from rest is measured upwards from its release point. Air resistance is proportional to velocity, giving

d2xdt2=−9.8−2dxdt,x(0)=0,x′(0)=0\frac{d^2x}{dt^2}=-9.8-2\frac{dx}{dt}, \qquad x(0)=0, \qquad x'(0)=0

Here, tt is measured in seconds.

A

Use the forward Euler method with step size h=0.2 sh=0.2\ \text{s}.

I.

Write the coupled Euler recurrences using v=x′v=x'.

[2]
II.

x(0.4)x(0.4) and v(0.4)v(0.4).

[2]
B

the first-order equation for vv and x(t)x(t).

[3]
C

the terminal velocity predicted by the model.

[1]
Question 44
HL • Paper 3
Hard
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HL • Paper 3
Hard
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The angular displacement θ\theta of a pendulum is modelled by

d2θdt2=−4sin⁡θ\frac{d^2\theta}{dt^2}=-4\sin\theta

with θ(0)=0.8\theta(0)=0.8 and θ′(0)=0\theta'(0)=0. Angles are measured in radians.

A

Let ω=θ′\omega=\theta'.

I.

Write the coupled Euler recurrences for step size h=0.1h=0.1.

[2]
II.

θ(0.2)\theta(0.2) and ω(0.2)\omega(0.2).

[2]
B

E=12ω2+4(1−cos⁡θ)E=\dfrac12\omega^2+4(1-\cos\theta) is constant for an exact solution.

[3]
C

why Euler values may not preserve EE exactly.

[1]

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Question 45
HL • Paper 3
Hard
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HL • Paper 3
Hard
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A control-system displacement satisfies

d2xdt2−dxdt−2x=0\frac{d^2x}{dt^2}-\frac{dx}{dt}-2x=0

Let v=x′v=x'.

A

Analyse the corresponding first-order system.

I.

Write the matrix system and its eigenvalues.

[2]
II.

a corresponding eigenvector for each eigenvalue and classify the origin.

[2]
B

Given x(0)=3x(0)=3 and v(0)=0v(0)=0, x(t)x(t).

[3]
C

the condition relating x(0)x(0) and v(0)v(0) for a non-zero solution to approach the origin as t→∞t\to\infty.

[1]
Question 46
HL • Paper 3
Hard
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HL • Paper 3
Hard
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The temperature TT, in degrees Celsius, inside a greenhouse is modelled by

dTdt=−0.25[T−(18+6sin⁡(πt12))],T(0)=30\frac{dT}{dt}=-0.25\left[T-\left(18+6\sin\left(\frac{\pi t}{12}\right)\right)\right], \qquad T(0)=30

where tt is measured in hours.

A

the rate equation.

I.

the curve in the (t,T)(t,T) plane on which dT/dt=0dT/dt=0.

[1]
II.

when the greenhouse is warming and when it is cooling.

[2]
B

Use Euler's method with step size h=3h=3 to T(6)T(6).

[3]
C

A numerical solver using a much smaller step gives T(24)≈15.0T(24)\approx15.0. why the greenhouse is warming at t=24t=24 despite being cooler than it was initially.

[2]
Question 47
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The angular displacement θ\theta, in radians, of a damped pendulum is modelled by

d2θdt2=−0.6dθdt−4sin⁡θ\frac{\mathrm d^2\theta}{\mathrm dt^2}=-0.6\frac{\mathrm d\theta}{\mathrm dt}-4\sin\theta

Initially, θ=0.5\theta=0.5 and θ′=0\theta'=0.

A
I.

Define ω=θ′\omega=\theta' and Euler recurrence relations with step size h=0.1h=0.1.

[2]
II.

Use Euler's method to θ\theta and ω\omega at t=0.3t=0.3.

[4]
B

For small θ\theta, use sin⁡θ≈θ\sin\theta\approx\theta to analyse the equilibrium at the origin in the (θ,ω)(\theta,\omega) phase plane.

[4]
Question 48
HL • Paper 3
Hard
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HL • Paper 3
Hard
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A fish population PP is subject to constant harvesting. It is modelled by

dPdt=0.4P(1−P1000)−H\frac{dP}{dt}=0.4P\left(1-\frac{P}{1000}\right)-H

where HH is the number of fish harvested per year.

A

Suppose that H=64H=64.

I.

the two positive equilibrium populations.

[2]
II.

the stability of each equilibrium.

[2]
B

the equilibrium populations in terms of HH.

[2]
C

the greatest harvesting rate for which an equilibrium population exists, and the corresponding population.

[2]

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Differentiation