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Integration

Master IB Math AI Integration with notes created by examiners and strictly aligned with the syllabus.

IB Syllabus Requirements for Integration

5.5

Antidifferentiation, definite integrals and area

5.8

The trapezoidal rule

5.11

Further integration techniques

HL

5.12

Areas and volumes of revolution

HL

5.5

ANTIDIFFERENTIATION, DEFINITE INTEGRALS AND AREA

Integration as reverse differentiation

An antiderivative is a function that has the given function as its derivative. So, if

F(x)=f(x)F'(x)=f(x)

An indefinite integral gives the whole family of antiderivatives of a function. For an integer power other than 1-1,

axndx=an+1xn+1+C,nZ, n1\int ax^n\,dx=\frac{a}{n+1}x^{n+1}+C,\qquad n\in\mathbb Z,\ n\ne-1

The constant is needed because differentiation removes constants. For example,

(6x24x+3)dx=2x32x2+3x+C\int(6x^2-4x+3)\,dx=2x^3-2x^2+3x+C

Changing CC shifts the antiderivative curve vertically. Each curve still has the same derivative.

Using a boundary condition

A boundary condition is a known input-output pair used to choose one function from the family of antiderivatives. If

f(x)=6x24x+3f(x)=6x^2-4x+3

and F(2)=9F(2)=9, integrate first, then substitute the known point:

9=2(2)32(2)2+3(2)+C9=2(2)^3-2(2)^2+3(2)+C

This gives C=5C=-5, so

F(x)=2x32x2+3x5F(x)=2x^3-2x^2+3x-5

Don’t remove CC before using the condition. It is the unknown that the condition determines.

Definite integrals and area

A definite integral represents an accumulated signed quantity between two fixed limits. If F(x)=f(x)F'(x)=f(x), then

pqf(x)dx=F(q)F(p)\int_p^q f(x)\,dx=F(q)-F(p)

An indefinite integral gives a family of functions, but a definite integral gives a value, so there is no final +C+C.

If the curve y=f(x)y=f(x) stays above the xx-axis between the limits, the enclosed area is

A=pqf(x)dxA=\int_p^q f(x)\,dx

A definite integral can also be viewed as the limiting total of many narrow strips. This links the antiderivative and the numerical value of the integral to the geometric area beneath a positive curve.

Image

When using technology, enter the full definite-integral expression before evaluating it. For example, write

15(2x3+7)dx\int_1^5(2x^3+7)\,dx

before using the numerical integration command. A graphing application can shade the region and help check that the curve remains positive across the stated interval.

Connections and interpretation

On a velocity-time graph, the integral of velocity over a time interval gives signed displacement. This area idea also connects calculus with velocity-time and acceleration-time graphs in physics, sport and exercise science. The units support the interpretation: velocity multiplied by time has units of displacement.

There is a modelling issue as well. Integration can describe a feature of the world that accumulates, but the choice of variables, interval and assumptions turns the situation into a mathematical model. Mathematics does not reproduce reality untouched. Instead, it selects features and expresses them in a form that can be calculated.

5.8

THE TRAPEZOIDAL RULE

Approximating an integral

The trapezoidal rule estimates an integral numerically. It joins consecutive sections of a curve with straight-line segments, then adds the areas of the trapezia formed. This works particularly well when the values come from a table and there is no convenient function to use.

For NN intervals of equal width,

T=h[y0+yN2+i=1N1yi]T=h\left[\frac{y_0+y_N}{2}+\sum_{i=1}^{N-1}y_i\right]

The same result can be found by calculating each trapezium separately and adding the areas:

T=h2[(y0+y1)+(y1+y2)++(yN1+yN)]T=\frac{h}{2}\big[(y_0+y_1)+(y_1+y_2)+\cdots+(y_{N-1}+y_N)\big]

This version shows the geometry clearly, though the compact form is usually quicker.

Image

Working from data or a function

When using a table, begin by checking that the horizontal values are equally spaced. The interval width is the difference between consecutive horizontal values—not the number of intervals. There should be one more data point than there are intervals.

For a function, choose equally spaced inputs and calculate the corresponding outputs before applying the same rule. Dynamic graphing software can show the trapezia and calculate the approximation. It can also help with interpreting what the resulting area represents in context.

The shape of the curve affects the estimate. When the joining chords sit above the curve, the trapezoidal rule gives an overestimate; when they sit below it, the result is an underestimate. Using more equal intervals usually improves the approximation, since each straight segment follows the curve more closely. This links numerical integration to upper and lower bounds. However, without information about the curve, a trapezoidal estimate is not automatically one particular type of bound.

Applications and wider methods

The rule can estimate irregular areas that a single formula cannot describe conveniently. One example is the area of a natural reserve, found from widths measured along equally spaced survey lines. In kinematics, the same method can estimate displacement from tabulated velocity-time data.

There are other numerical integration methods. Simpson's rule, for instance, models sections using quadratic curves instead of straight lines. Comparing its result with a trapezoidal estimate provides a useful extension. The central skill here is choosing equal-width intervals, setting out the trapezoidal calculation correctly and interpreting the answer with suitable units.

5.11

FURTHER INTEGRATION TECHNIQUES

HL

Standard integrals

The power rule also works for rational exponents:

xndx=xn+1n+1+C,nQ, n1\int x^n\,dx=\frac{x^{n+1}}{n+1}+C,\qquad n\in\mathbb Q,\ n\ne-1

Here, Q\mathbb Q denotes the rational numbers. The excluded case uses a separate result:

x1dx=1xdx=lnx+C\int x^{-1}\,dx=\int\frac{1}{x}\,dx=\ln|x|+C

The natural logarithm is the logarithmic function with base ee, where ee is the dimensionless mathematical constant used as the base of natural exponential growth. We need the absolute-value signs because the derivative of lnx\ln|x| is 1/x1/x on any interval that does not cross zero.

With trigonometric inputs measured in radians, the other standard results are

sinxdx=cosx+C,cosxdx=sinx+C,1cos2xdx=tanx+C,exdx=ex+C.\begin{aligned} \int\sin x\,dx&=-\cos x+C,\\ \int\cos x\,dx&=\sin x+C,\\ \int\frac{1}{\cos^2x}\,dx&=\tan x+C,\\ \int e^x\,dx&=e^x+C. \end{aligned}

These results work for indefinite and definite integration. For a definite integral, find an antiderivative, then evaluate it at the upper and lower limits. Don’t attach +C+C to the final numerical value.

Integration by inspection

Integration by inspection means spotting that an integrand is the derivative of a familiar composite expression. It reverses the chain rule, so you may need to introduce a constant multiplier.

For example,

sin(3x4)dx=13cos(3x4)+C\int\sin(3x-4)\,dx=-\frac13\cos(3x-4)+C

because differentiating the inner expression gives a factor of 33. Likewise,

15x7dx=15ln5x7+C\int\frac{1}{5x-7}\,dx=\frac15\ln|5x-7|+C

That outside factor is essential. It compensates for the derivative of the linear inner function.

Substitution

Substitution changes the variable, replacing an inner function and its derivative with a simpler variable. Look for the pattern

f(g(x))g(x)dx\int f(g(x))g'(x)\,dx

Let

u=g(x),du=g(x)dxu=g(x),\qquad du=g'(x)\,dx

The integral then becomes

f(u)du\int f(u)\,du

Once you have integrated, substitute back to xx unless you have already converted definite limits into values of uu.

Common reverse-chain-rule patterns include

10xsin(5x2+2)dx=cos(5x2+2)+C\int 10x\sin(5x^2+2)\,dx=-\cos(5x^2+2)+C

and

2sinxcosxdx=2lncosx+C\int\frac{2\sin x}{\cos x}\,dx=-2\ln|\cos x|+C

In each case, mentally underline the likely inner function and check for its derivative. If the derivative appears only up to a constant factor, adjust that factor outside the integral.

Historical connection

Practical ideas about integration appeared long before systematic symbolic notation. Ancient Egyptian mathematics included a successful procedure for finding the volume of a truncated pyramid, recorded in the Moscow Mathematical Papyrus. Sophisticated accumulation arguments could therefore exist before modern calculus notation and formal substitution methods.

5.12

AREAS AND VOLUMES OF REVOLUTION

HL

Signed integrals and geometric area

A definite integral is signed. Regions above the xx-axis make a positive contribution, while those below it make a negative one. Geometric area can’t be negative, so for a region between y=f(x)y=f(x) and the xx-axis,

A=pqf(x)dxA=\int_p^q|f(x)|\,dx

First find any intercepts inside the interval. Split the integral at those points, then change the sign of each negative part. A calculator may correctly give a negative value for the integral; when interpreting that value as an area, the result must be non-negative.

For a region bounded by the yy-axis and a curve written as x=ϕ(y)x=\phi(y),

A=pqϕ(y)dyA=\int_p^q|\phi(y)|\,dy

where ϕ(y)\phi(y) is the horizontal coordinate of the curve, measured in the same length unit as xx. The limits here are values on the yy-axis. A useful rule: strips perpendicular to the xx-axis have thickness dxdx; strips perpendicular to the yy-axis have thickness dydy.

Image

Sketch first if the interval crosses an axis intercept. The sketch shows which parts of the integral are positive or negative. It also helps you decide whether integrating with respect to xx or yy gives the cleaner description.

Volumes of revolution

A volume of revolution is the three-dimensional volume created when a plane region rotates around an axis. Rotating about the xx-axis gives circular cross-sections with radius y|y|, so

V=πpqy2dxV=\pi\int_p^q y^2\,dx

where VV is volume measured in m3\text{m}^3 when the coordinates are measured in metres and π\pi is the dimensionless circle constant. The limits are xx-coordinates, and yy must be written as a function of xx.

For rotation about the yy-axis,

V=πpqx2dyV=\pi\int_p^q x^2\,dy

This time, the limits are yy-coordinates and xx must be written as a function of yy. Squaring the radius keeps the cross-sectional area non-negative, even if the original coordinate is negative.

Image

These formulas come from adding thin circular discs. Each disc has cross-sectional area πy2\pi y^2 or πx2\pi x^2, and integration adds those areas across a small thickness. Choose the axis of rotation first; then identify the correct radius and differential.

Context and historical development

Volumes of revolution are used in industrial design and architecture. Curved profiles can be rotated to model containers, components or structural forms. This approach assumes that the object is rotationally symmetric, so the actual design must be checked against that assumption.

Methods for calculating curved areas and volumes emerged across several cultures. In China, Liu Hui’s work included accurate reasoning about the volume of a cylinder. Greek geometers used limiting ideas resembling infinitesimals, while Ibn al-Haytham integrated powers in work leading to the volume of a paraboloid. Alongside earlier Egyptian work on truncated pyramids, these contributions show that integral thinking developed through several mathematical traditions rather than appearing in one step.

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differentiation Differentiation

kinematics Kinematics