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Systems of Equations

Practice exam-style IB Math AA questions for Systems of Equations, aligned with the syllabus and grouped by topic.

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Question 1
HL • Paper 1
Easy
Non Calculator
HL • Paper 1
Easy
Non Calculator

Consider the system of equations

x+y+z=22x−y+3z=13x+4y−z=−10.\begin{aligned} x+y+z&=2\\ 2x-y+3z&=13\\ x+4y-z&=-10. \end{aligned}
A

the augmented matrix for the system.

[1]
B

the system.

[4]
Question 2
HL • Paper 1
Easy
Non Calculator
HL • Paper 1
Easy
Non Calculator

The augmented matrix of a system of three linear equations in xx, yy and zz has been reduced to

[12−13014−20000]\left[\begin{array}{ccc|c} 1&2&-1&3\\ 0&1&4&-2\\ 0&0&0&0 \end{array}\right]
A

the solution set of the system, writing your answer using a real parameter.

[3]
B

the geometric meaning of this solution set for the three planes.

[1]
Question 3
HL • Paper 1
Easy
Non Calculator
HL • Paper 1
Easy
Non Calculator

A quadratic function ff is given by f(x)=ax2+bx+cf(x)=ax^2+bx+c. It is known that

f(0)=1,f(1)=0,f(2)=3f(0)=1,\quad f(1)=0,\quad f(2)=3
A

Form a system of three linear equations in aa, bb and cc.

[2]
B

aa, bb and cc.

[2]
Question 4
HL • Paper 2
Easy
Calculator Permitted
HL • Paper 2
Easy
Calculator Permitted

Consider the system of equations

2x−y+3z=14x+4y−2z=−33x+y+z=10.\begin{aligned} 2x-y+3z&=14\\ x+4y-2z&=-3\\ 3x+y+z&=10. \end{aligned}
A

the augmented matrix for this system.

[1]
B

Use your graphic display calculator to row-reduce the augmented matrix.

[2]
C

the solution and the value of 4x−2y+z4x-2y+z.

[2]

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Question 5
HL • Paper 2
Easy
Calculator Permitted
HL • Paper 2
Easy
Calculator Permitted

A system of three linear equations is given by

2.4x−1.5y+0.8z=6.65−1.2x+3.1y+2.5z=4.894.0x+0.6y−1.7z=−1.40.\begin{aligned} 2.4x-1.5y+0.8z&=6.65\\ -1.2x+3.1y+2.5z&=4.89\\ 4.0x+0.6y-1.7z&=-1.40. \end{aligned}
A

the augmented matrix for the system.

[1]
B

Use your graphic display calculator to the system.

[2]
C

5x−2y+z5x-2y+z.

[2]
Question 6
HL • Paper 2
Easy
Calculator Permitted
HL • Paper 2
Easy
Calculator Permitted

The augmented matrix of a system in xx, yy and zz is row-reduced using a graphic display calculator. The result is

[10−24013−10000]\left[\begin{array}{ccc|c} 1&0&-2&4\\ 0&1&3&-1\\ 0&0&0&0 \end{array}\right]
A

the number of solutions of the system. Give a reason.

[1]
B

Write the solution set in terms of a parameter.

[3]
Question 7
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Consider the system, where k∈Rk\in\mathbb{R},

x+2y−z=32x+5y+z=73x+7y+kz=10.\begin{aligned} x+2y-z&=3\\ 2x+5y+z&=7\\ 3x+7y+kz&=10. \end{aligned}
A

Use row reduction to obtain an equation involving only zz and kk.

[2]
B

the value of kk for which the system does not have a unique solution, and the number of solutions in this case.

[2]
Question 8
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Consider the system, where k∈Rk\in\mathbb{R},

x−y+z=22x+y−z=13x+ky+z=5.\begin{aligned} x-y+z&=2\\ 2x+y-z&=1\\ 3x+ky+z&=5. \end{aligned}
A

the value of kk for which the system has no solution.

[3]
B

the system when k=1k=1.

[3]

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Question 9
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Consider the system of two equations in xx and yy, where k∈Rk\in\mathbb{R},

kx+2y=62x+ky=6.\begin{aligned} kx+2y&=6\\ 2x+ky&=6. \end{aligned}
A

the values of kk for which the system does not have a unique solution.

[2]
B

Classify the number of solutions for all real values of kk.

[3]
Question 10
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

A theatre sells adult, child and senior tickets. Let aa, cc and ss be the prices, in dollars, of an adult, child and senior ticket respectively. The ticket sales for three shows are shown below.

1: 8080 adult, 6060 child and 4040 senior tickets, total revenue 17801780 dollars.

2: 100100 adult, 4545 child and 3030 senior tickets, total revenue 18351835 dollars.

3: 6060 adult, 9090 child and 5050 senior tickets, total revenue 18301830 dollars.

A

Form a system of three linear equations in aa, cc and ss.

[2]
B

the price of each type of ticket.

[2]
C

A fourth sells 2525 adult, 4040 child and 2020 senior tickets. its total revenue.

[1]
Question 11
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

A quadratic function has the form f(x)=ax2+bx+cf(x)=ax^2+bx+c. It passes through the points (1,3.45)(1,3.45), (3,4.65)(3,4.65) and (5,11.85)(5,11.85).

A

Form a system of three linear equations in aa, bb and cc.

[2]
B

Use your graphic display calculator to aa, bb and cc.

[2]
C

f(4)f(4).

[1]
Question 12
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

After valid row operations, the augmented matrix of a system in xx, yy and zz is

[12−13014−200h−52h−10]\left[\begin{array}{ccc|c} 1&2&-1&3\\ 0&1&4&-2\\ 0&0&h-5&2h-10 \end{array}\right]

where h∈Rh\in\mathbb{R}.

A

the value of hh for which the system has infinitely many solutions.

[2]
B

For this value of hh, write the solution set in terms of a parameter.

[3]

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Question 13
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

A manufacturer blends three liquid concentrates, AA, BB and CC, to make 120120 kg of a mixture. Concentrate AA contains 10%10\% active ingredient, BB contains 25%25\%, and CC contains 40%40\%. The final mixture must contain 3030 kg of active ingredient. The costs of AA, BB and CC are 88, 55 and 33 dollars per kg respectively, and the total cost is 645645 dollars.

A

Form a system of three linear equations for the masses xx, yy and zz of concentrates AA, BB and CC respectively.

[2]
B

Use your graphic display calculator to xx, yy and zz.

[2]
C

the percentage of the mixture that is concentrate CC.

[1]
Question 14
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The system of equations

x+y+z=42x−y+3z=73x+ay+4z=b\begin{aligned} x+y+z&=4\\ 2x-y+3z&=7\\ 3x+ay+4z&=b \end{aligned}

represents three planes, where a,b∈Ra,b\in\mathbb{R}.

A

the set of values of aa and bb for which the three planes have no common point of intersection.

[5]
Question 15
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

A system of three linear equations has augmented matrix

[1111234534pq]\left[\begin{array}{ccc|c} 1&1&1&1\\ 2&3&4&5\\ 3&4&p&q \end{array}\right]

where p,q∈Rp,q\in\mathbb{R}.

A

the conditions on pp and qq for the system to have a unique solution, no solution, and infinitely many solutions.

[6]
Question 16
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The planes Π1\Pi_1, Π2\Pi_2 and Π3\Pi_3 have equations

Π1:x+y+z=1Π2:2x+3y+z=4Π3:x+2y+λz=μ,\begin{aligned} \Pi_1:\quad x+y+z&=1\\ \Pi_2:\quad 2x+3y+z&=4\\ \Pi_3:\quad x+2y+\lambda z&=\mu, \end{aligned}

where λ,μ∈R\lambda,\mu\in\mathbb{R}.

A

the values of λ\lambda and μ\mu for which the three planes intersect in a line.

[4]
B

For these values of λ\lambda and μ\mu, a parametric form of the line of intersection.

[2]

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Question 17
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Consider the system, where k,m∈Rk,m\in\mathbb{R},

x+2y−z=52x+5y+z=123x+7y+kz=m.\begin{aligned} x+2y-z&=5\\ 2x+5y+z&=12\\ 3x+7y+kz&=m. \end{aligned}
A

the values of kk and mm for which the system has infinitely many solutions.

[4]
B

For these values of kk and mm, write the solution set using a real parameter.

[2]
Question 18
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

At three junctions in a one-way traffic network, the unknown hourly traffic flows xx, yy and zz satisfy

x+y=620y+z=480x−z=140.\begin{aligned} x+y&=620\\ y+z&=480\\ x-z&=140. \end{aligned}
A

the system, giving the solution set in terms of a parameter.

[3]
B

Traffic flows cannot be negative. the possible range of values of zz.

[1]
C

If x=350x=350, yy and zz.

[2]
Question 19
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Consider the system

2x−y+z=1x+3y−2z=45x+y+kz=11,\begin{aligned} 2x-y+z&=1\\ x+3y-2z&=4\\ 5x+y+kz&=11, \end{aligned}

where k∈Rk\in\mathbb{R}.

A

the values of kk for which the system has a unique solution.

[2]
B

Classify the system when k=0k=0.

[2]
C

For k=7k=7, the system.

[2]
Question 20
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The point P(1,−2,3)P(1,-2,3) lies on each of the three planes

mx+2y−z=n3x−y+mz=14x+ny+2z=15,\begin{aligned} mx+2y-z&=n\\ 3x-y+mz&=14\\ x+ny+2z&=15, \end{aligned}

where m,n∈Rm,n\in\mathbb{R}.

A

the values of mm and nn.

[4]
B

For these values of mm and nn, whether the system has a unique solution.

[2]

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Question 21
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

In a small directed network, the unknown flows xx, yy and zz satisfy

x+y−z=82x−y+3z=103x+2z=18.\begin{aligned} x+y-z&=8\\ 2x-y+3z&=10\\ 3x+2z&=18. \end{aligned}

All flows are measured in hundreds of units per hour.

A
I.

the third equation is dependent on the first two equations.

[2]
II.

the general solution of the system in terms of z=tz=t.

[3]
B

Given that no flow can be negative, the possible values of tt.

[2]
C
I.

An additional observation gives y=2xy=2x. tt.

[2]
II.

the three flows.

[1]
Question 22
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The same coefficient matrix is used in two different systems:

x+y+z=22x−y+3z=−3x+2y−z=6andx+y+z=32x−y+3z=5x+2y−z=0.\begin{aligned} x+y+z&=2\\ 2x-y+3z&=-3\\ x+2y-z&=6 \end{aligned} \qquad\text{and}\qquad \begin{aligned} x+y+z&=3\\ 2x-y+3z&=5\\ x+2y-z&=0. \end{aligned}
A
I.

the first system.

[3]
II.

the second system.

[2]
B

Let b1\mathbf{b}_1 and b2\mathbf{b}_2 denote the right-hand side vectors of the first and second systems respectively. Without repeating elimination, the system with the same coefficient matrix and right-hand side vector 2b1−b22\mathbf{b}_1-\mathbf{b}_2.

[2]
C

why the conclusion in part (b) would not necessarily be valid if the coefficient matrix were different in the two original systems.

[2]
Question 23
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

A shop sells three items AA, BB and CC at prices pp, qq and rr dollars respectively. Three bundle prices give the system

2p+q+r=17p+3q+2r=263p+4q+3r=43.\begin{aligned} 2p+q+r&=17\\ p+3q+2r&=26\\ 3p+4q+3r&=43. \end{aligned}
A
I.

the system does not a unique set of prices.

[2]
II.

Let r=tr=t. pp and qq in terms of tt.

[3]
B

Assuming that all prices are non-negative, the possible values of tt.

[2]
C
I.

If items AA and BB have the same price, tt.

[2]
II.

the three prices.

[1]
Question 24
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Consider the system

x+y−z=22x+3y+z=7−x+py+qz=r,\begin{aligned} x+y-z&=2\\ 2x+3y+z&=7\\ -x+py+qz&=r, \end{aligned}

where p,q,r∈Rp,q,r\in\mathbb{R}.

A

the conditions on pp, qq and rr for the system to be inconsistent.

[5]
B

For p=0p=0, q=4q=4 and r=1r=1, the solution set.

[2]

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Question 25
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Consider the symmetric system, where a∈Ra\in\mathbb{R},

x+y+az=2x+ay+z=2ax+y+z=2.\begin{aligned} x+y+az&=2\\ x+ay+z&=2\\ ax+y+z&=2. \end{aligned}
A

the values of aa for which the system does not have a unique solution.

[4]
B

Classify the number of solutions for each of the values found in part (a).

[3]
Question 26
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

An engineer calibrates three sensors, AA, BB and CC. The unknown output contributions, in millivolts, from one unit of each sensor are aa, bb and cc respectively. Three calibration trials are shown in the table.

Trial

Sensor A [units]

Sensor B [units]

Sensor C [units]

Output [mV]

1

1

2

1

18.2

2

3

1

2

34.4

3

2

4

3

47.6

4

4

0

1

25.1

A
AI.

Form an augmented matrix which could be used to aa, bb and cc.

[2]
AII.

Use your graphic display calculator to aa, bb and cc.

[3]
B

The fourth-trial sensor quantities are 44 units of sensor AA, 00 units of sensor BB, and 11 unit of sensor CC.

BI.

the predicted output for the fourth trial.

[2]
BII.

The actual output in the fourth trial is 25.1 mV25.1\ \text{mV}. the percentage error between the predicted and actual outputs, relative to the predicted output.

[3]
Question 27
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The height hh metres of a moving platform at time tt seconds is modelled by

h(t)=at2+bt+ch(t)=at^2+bt+c

Measurements give h(0)=1.80h(0)=1.80, h(2)=5.00h(2)=5.00 and h(5)=0.500h(5)=0.500.

A
I.

a system of three linear equations in aa, bb and cc.

[2]
II.

Use your graphic display calculator to aa, bb and cc.

[3]
B

Use the model found in part (a).

I.

the maximum height of the platform and the time at which it occurs.

[3]
II.

the two times at which the platform is at a height of 3.00 m3.00\ \text{m}.

[2]
Question 28
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

After valid row operations, the augmented matrix of a system of three linear equations in xx, yy and zz is

[102501−1−300k−42k−8]\left[\begin{array}{ccc|c} 1&0&2&5\\ 0&1&-1&-3\\ 0&0&k-4&2k-8 \end{array}\right]

where k∈Rk\in\mathbb{R}.

A
I.

the values of kk for which the system has a unique solution.

[2]
II.

For k≠4k\neq 4, the solution in terms of xx, yy and zz.

[3]
B
I.

Classify the system when k=4k=4.

[2]
II.

For k=4k=4, write the solution set in terms of a real parameter.

[2]

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Question 29
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

A nutritionist prepares a 200200 g mixture using ingredients AA, BB and CC. Let xx, yy and zz be the masses, in grams, of ingredients AA, BB and CC respectively. The mixture must contain 3939 g of protein and have total cost 790790 cents. The following information is available.

Ingredient

Protein per gram / g g−1g\,g^{-1}

Cost / cents g−1g^{-1}

A

0.20

4

B

0.10

3

C

0.30

5

A

(a)

I.

Form a system of three linear equations in xx, yy and zz.

[3]
II.

Use your graphic display calculator to the type of solution and express the solutions parametrically.

[3]
B

A second mixture must still have total mass 200200 g and protein mass 3939 g, but the total cost is not specified.

I.

Write the possible masses in terms of z=tz=t.

[2]
II.

the range of tt for which all masses are non-negative.

[2]
Question 30
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The system

x+2y−z=42x+ay+z=53x+4y+(a−2)z=9\begin{aligned} x+2y-z&=4\\ 2x+ay+z&=5\\ 3x+4y+(a-2)z&=9 \end{aligned}

has parameter a∈Ra\in\mathbb{R}.

A

the values of aa for which the system has a unique solution.

[3]
B

For the remaining values of aa, classify the system and, where appropriate, give the solution set.

[3]
Question 31
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Three planes are represented by

x+y+z=22x−y+3z=53x+ay+5z=b,\begin{aligned} x+y+z&=2\\ 2x-y+3z&=5\\ 3x+ay+5z&=b, \end{aligned}

where a,b∈Ra,b\in\mathbb{R}.

A

the determinant of the coefficient matrix is −a−3-a-3.

[2]
B

the values of aa and bb for which the system has infinitely many solutions.

[3]
C

For these values of aa and bb, write the solution set in terms of a parameter.

[2]
Question 32
HL • Paper 3
Medium
Calculator Permitted
HL • Paper 3
Medium
Calculator Permitted

A row-reduction process is applied to the parameter system

x+2y−z=32x+5y+hz=83x+7y+4z=m,\begin{aligned} x+2y-z&=3\\ 2x+5y+hz&=8\\ 3x+7y+4z&=m, \end{aligned}

where h,m∈Rh,m\in\mathbb{R}.

A
I.

Use the operations R2→R2−2R1R_2\to R_2-2R_1 and R3→R3−3R1R_3\to R_3-3R_1 to obtain two equations in yy and zz.

[2]
II.

an equation involving only zz, hh and mm.

[2]
B

For h=3h=3 and m=15m=15, the system.

[2]
C

Classify the number of solutions when h=5h=5, in terms of mm.

[3]

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Question 33
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Consider the system of equations

x+y+z=32x+3y+z=7x+ay+(a−1)z=b,\begin{aligned} x+y+z&=3\\ 2x+3y+z&=7\\ x+ay+(a-1)z&=b, \end{aligned}

where a,b∈Ra,b\in\mathbb{R}.

A
I.

Use the first two equations to express xx and zz in terms of yy.

[3]
II.

the conditions on aa and bb for which the system has a unique solution, no solution, and infinitely many solutions.

[3]
B

the solution when a=2a=2 and b=5b=5.

[2]
C

In the case where the system has infinitely many solutions, write the solution set in parametric form.

[2]
Question 34
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Consider the system

x+y+kz=12x+(k+1)y+3z=4x+2y+(k+2)z=3,\begin{aligned} x+y+kz&=1\\ 2x+(k+1)y+3z&=4\\ x+2y+(k+2)z&=3, \end{aligned}

where k∈Rk\in\mathbb{R}.

A
I.

the determinant of the coefficient matrix is 4k−54k-5.

[3]
II.

the value of kk for which the system does not have a unique solution.

[2]
B

the number of solutions when k=54k=\dfrac{5}{4}.

[2]
C
I.

the system when k=1k=1.

[2]
II.

For k≠54k\neq\dfrac54, the value of kk for which the solution has z=0z=0.

[1]
Question 35
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Consider the system

x+2y−z=32x+5y+hz=7−x+y+(h−2)z=q,\begin{aligned} x+2y-z&=3\\ 2x+5y+hz&=7\\ -x+y+(h-2)z&=q, \end{aligned}

where h,q∈Rh,q\in\mathbb{R}.

A
I.

Use row operations to the final row may be written in the form 0x+0y+(−2h−9)z=q0x+0y+(-2h-9)z=q.

[3]
II.

classify the system according to the values of hh and qq.

[3]
B

For the values of hh and qq giving infinitely many solutions, the solution set in parametric form.

[3]
Question 36
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

A function has the form

f(x)=ax+bx+cf(x)=\frac{ax+b}{x+c}

where a,b,c∈Ra,b,c\in\mathbb{R} and x≠−cx\neq -c. It is known that

f(0)=2,f(1)=1,f(3)=53f(0)=2,\qquad f(1)=1,\qquad f(3)=\frac53
A
I.

Form a system of three linear equations in aa, bb and cc.

[3]
II.

why these equations are linear in aa, bb and cc.

[1]
B

the system to aa, bb and cc.

[3]
C

the value of xx for which f(x)=0f(x)=0.

[2]

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Question 37
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Consider the symmetric system

x+y+az=1x+ay+z=1ax+y+z=1,\begin{aligned} x+y+az&=1\\ x+ay+z&=1\\ ax+y+z&=1, \end{aligned}

where a∈Ra\in\mathbb{R}.

A
I.

the determinant of the coefficient matrix is −(a−1)2(a+2)-(a-1)^2(a+2).

[3]
II.

the values of aa for which the system does not have a unique solution.

[2]
B

Classify the system for the values of aa found in part (a).

[3]
C

the system when a=0a=0.

[2]
Question 38
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Consider the system

x+2y−z=42x+5y+az=93x+8y+(a+1)z=b,\begin{aligned} x+2y-z&=4\\ 2x+5y+az&=9\\ 3x+8y+(a+1)z&=b, \end{aligned}

where a,b∈Ra,b\in\mathbb{R}.

A
I.

Use row reduction to obtain the final row 0x+0y−az=b−140x+0y-az=b-14.

[3]
II.

classify the system according to aa and bb.

[2]
B

For a=0a=0 and b=14b=14, write the solution set in parametric form.

[3]
C

the system when a=1a=1 and b=9b=9.

[2]
Question 39
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

A plane is written in the form

ax+by+cz=1ax+by+cz=1

It is required to pass through the points P(1,0,1)P(1,0,1), Q(0,1,1)Q(0,1,1) and R(1,1,k)R(1,1,k), where k∈Rk\in\mathbb{R}.

A
I.

Form a system of three linear equations in aa, bb and cc.

[3]
II.

this system reduces to (k−2)c=−1(k-2)c=-1.

[1]
B

the values of kk for which such a plane exists in the form ax+by+cz=1ax+by+cz=1.

[2]
C

the equation of the plane when k=3k=3.

[2]
Question 40
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Consider the system of equations

x+y+z=42x+3y+z=7x+ky+2z=m,\begin{aligned} x+y+z&=4\\ 2x+3y+z&=7\\ x+ky+2z&=m, \end{aligned}

where k,m∈Rk,m\in\mathbb{R}.

A
I.

the determinant of the coefficient matrix is kk.

[3]
II.

the values of kk and mm for which the system has no solution, exactly one solution, or infinitely many solutions.

[4]
B

For the fixed values k=2k=2 and m=8m=8, answer the following.

I.

the system.

[2]
II.

this solution geometrically.

[2]

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Question 41
HL • Paper 2
Hard
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HL • Paper 2
Hard
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Water flows through three pipes with unknown hourly flow rates xx, yy and zz, measured in kilolitres per hour. Conservation of flow at three junctions gives

x+y=120y+z=95x−z=25.\begin{aligned} x+y&=120\\ y+z&=95\\ x-z&=25. \end{aligned}
A

In practice, each flow rate must be non-negative. The hourly pumping cost, measured in dollars per hour, is defined by

C=0.12x+0.08y+0.15zC=0.12x+0.08y+0.15z

Here the coefficients are costs in dollars per kilolitre, and xx, yy and zz are measured in kL h−1\text{kL h}^{-1}.

I.

Use row reduction to the system does not have a unique solution.

[2]
II.

the maximum value of zz if the hourly pumping cost must not exceed $20.00 per hour.

[3]
B

In practice, each flow rate must be non-negative. The hourly pumping cost is

C=0.12x+0.08y+0.15zC=0.12x+0.08y+0.15z
I.

the possible range of values of tt.

[2]
II.

the maximum value of zz if the hourly pumping cost must not exceed 20.0020.00.

[3]
Question 42
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

In an electrical network, the currents I1I_1, I2I_2 and I3I_3, measured in amperes, satisfy

I1+I2−I3=012I1+4I3=188I2−4I3=6.\begin{aligned} I_1+I_2-I_3&=0\\ 12I_1+4I_3&=18\\ 8I_2-4I_3&=6. \end{aligned}
A
I.

the coefficient matrix and constant vector for this system.

[2]
II.

for I1I_1, I2I_2 and I3I_3.

[2]
B

For the following parts, replace 1212 in the second equation by the parameter RR. The system is

I1+I2−I3=0RI1+4I3=188I2−4I3=6.\begin{aligned} I_1+I_2-I_3&=0\\ RI_1+4I_3&=18\\ 8I_2-4I_3&=6. \end{aligned}

The constant vector is unchanged and is (0186)\begin{pmatrix}0\\18\\6\end{pmatrix}.

I.

the determinant of the new coefficient matrix is −4(R+8)-4(R+8).

[3]
II.

the values of RR for which the system has a unique solution.

[1]
III.

Classify the system when R=−8R=-8.

[2]
Question 43
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

A population moves between three regions PP, QQ and RR each year. In the long term, the proportions in the three regions are pp, qq and rr. They satisfy

p=0.7p+0.2q+0.1rq=0.2p+0.6q+0.3rp+q+r=1.\begin{aligned} p&=0.7p+0.2q+0.1r\\ q&=0.2p+0.6q+0.3r\\ p+q+r&=1. \end{aligned}

The total population is expected to remain 60006000 people.

to \ from

P

Q

R

P

0.7

0.2

0.1

Q

0.2

0.6

0.3

R

0.1

0.2

0.6

A
I.

Rewrite the system in standard linear form.

[3]
II.

Use your graphic display calculator to for pp, qq and rr.

[3]
B

The total population is expected to remain 60006000.

I.

the long-term number of people in each region.

[2]
II.

A planning target requires region QQ to contain at least 22502250 people in the long term. whether this target is met.

[2]
Question 44
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Three forces AA, BB and CC, measured in newtons, act on a mechanical joint. Equilibrium conditions lead to

A+B+C=142A−B+3C=28−A+4B+2C=22.\begin{aligned} A+B+C&=14\\ 2A-B+3C&=28\\ -A+4B+2C&=22. \end{aligned}
A
I.

Use your graphic display calculator to the system.

[3]
II.

which force is the greatest.

[1]
B

The final constant 2222 is replaced by a variable load LL, so the new system is

A+B+C=142A−B+3C=28−A+4B+2C=L.\begin{aligned} A+B+C&=14\\ 2A-B+3C&=28\\ -A+4B+2C&=L. \end{aligned}
I.

the new system in terms of LL.

[4]
II.

If the load LL is non-negative, the range of LL for which all three forces are non-negative.

[2]

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Question 45
HL • Paper 2
Hard
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HL • Paper 2
Hard
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A digital filter transforms an original colour vector (R,G,B)(R,G,B) into an observed colour vector. For one pixel, the filter gives

1.2R+0.3G+0.1B=700.2R+1.1G+0.4B=910.1R+0.2G+1.3B=105.\begin{aligned} 1.2R+0.3G+0.1B&=70\\ 0.2R+1.1G+0.4B&=91\\ 0.1R+0.2G+1.3B&=105. \end{aligned}

Filter

Coefficient matrix

Observed vector

Original MM

(1.20.30.10.21.10.40.10.21.3)\begin{pmatrix}1.2&0.3&0.1\\0.2&1.1&0.4\\0.1&0.2&1.3\end{pmatrix}

v=(7091105)\mathbf{v}=\begin{pmatrix}70\\91\\105\end{pmatrix}

Modified MkM_k (1.3→k1.3\to k)

(1.20.30.10.21.10.40.10.2k)\begin{pmatrix}1.2&0.3&0.1\\0.2&1.1&0.4\\0.1&0.2&k\end{pmatrix}

v=(7091105)\mathbf{v}=\begin{pmatrix}70\\91\\105\end{pmatrix}

A
I.

Write the system in matrix form Mx=vM\mathbf{x}=\mathbf{v}.

[2]
II.

Use your graphic display calculator to the original colour vector.

[2]
B

The coefficient 1.31.3 in the third equation is replaced by a parameter kk, so that the new coefficient matrix is

Mk=(1.20.30.10.21.10.40.10.2k)M_k=\begin{pmatrix}1.2&0.3&0.1\\0.2&1.1&0.4\\0.1&0.2&k\end{pmatrix}
I.

the determinant of the new coefficient matrix is 1.26k−0.0911.26k-0.091.

[3]
II.

the value of kk for which the original colour vector cannot be determined uniquely from the observed colour vector.

[2]
III.

why this value of kk causes a problem for reversing the filter.

[1]
Question 46
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

The three planes Π1\Pi_1, Π2\Pi_2 and Π3\Pi_3 are represented by the system

x+y+z=12x+3y+kz=4x+ky+3z=m,\begin{aligned} x+y+z&=1\\ 2x+3y+kz&=4\\ x+ky+3z&=m, \end{aligned}

where k,m∈Rk,m\in\mathbb{R}. This question investigates how the values of kk and mm affect the common intersection of the planes.

A
I.

the determinant of the coefficient matrix is k(3−k)k(3-k).

[3]
II.

the values of kk for which the system has a unique solution.

[2]
B

For the case k=0k=0, the values of mm for which the system is consistent. If it is consistent, write the solution set using a real parameter.

[4]
C

For the case k=3k=3, the values of mm for which the system is consistent. If it is consistent, write the solution set using a real parameter.

[4]
Question 47
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A laboratory calibrates three constants aa, bb and cc in a linear model. Three test readings lead to the system

2a−b+c=5a+3b+2c=144a+b+kc=d,\begin{aligned} 2a-b+c&=5\\ a+3b+2c&=14\\ 4a+b+kc&=d, \end{aligned}

where k,d∈Rk,d\in\mathbb{R}.

Test reading

coefficient of a

coefficient of b

coefficient of c

reading

1

2

-1

1

5

2

1

3

2

14

3

4

1

k

d

A
I.

the determinant of the coefficient matrix.

[3]
II.

the value of kk for which the system does not have a unique solution.

[2]
B

For k=2k=2 and d=17d=17, the system.

[2]
C

When k=237k=\frac{23}{7}, the value of dd for which the system has infinitely many solutions, and write the solution set for this value of dd.

[3]
Question 48
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A company models three unknown daily subscription numbers uu, vv and ww. A parameter pp represents a change in the weighting of two survey questions. The model is

u+v+w=6u+pv+2w=8u+2v+pw=q,\begin{aligned} u+v+w&=6\\ u+pv+2w&=8\\ u+2v+pw&=q, \end{aligned}

where p,q∈Rp,q\in\mathbb{R}.

Equation

uu

vv

ww

RHS

1

1

1

1

6

2

1

p

2

8

3

1

2

p

q

A
I.

the determinant of the coefficient matrix is p(p−2)p(p-2).

[3]
II.

the values of pp for which the system may fail to have a unique solution.

[1]
B

For p=0p=0, the value of qq for which the system has infinitely many solutions. For this value of qq, write the solution set.

[3]
C

For p=2p=2, classify the system for all real values of qq.

[3]

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Question 49
HL • Paper 3
Hard
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HL • Paper 3
Hard
Calculator Permitted

Three pumps XX, YY and ZZ supply water to different parts of an irrigation system. Let xx, yy and zz be the numbers of minutes that the pumps run during a control period. Operational requirements give

x+y+z=1202x+y=150x+2y+3z=d,\begin{aligned} x+y+z&=120\\ 2x+y&=150\\ x+2y+3z&=d, \end{aligned}

where dd is the total weighted delivery index.

A
I.

Use the first two equations to express xx and yy in terms of zz.

[2]
II.

the system is consistent only when d=210d=210.

[2]
B

For d=210d=210, write the solution set and the possible range of zz if no pump can run for a negative time.

[3]
C

The cost, in dollars, of running the pumps is C=5x+4y+6zC=5x+4y+6z. the minimum possible cost.

[4]
Question 50
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A plane surface is modelled by

z=Ax+By+Cz=Ax+By+C

It is required to pass through the points (0,0,2)(0,0,2), (1,2,7)(1,2,7) and (t,1,s)(t,1,s), where t,s∈Rt,s\in\mathbb{R}.

A
I.

Form the system of equations for AA, BB and CC.

[2]
II.

this system has a unique solution unless t=12t=\frac{1}{2}.

[2]
B

AA, BB and CC when t=2t=2 and s=9s=9.

[2]
C

For t=12t=\frac{1}{2}, the value of ss for which there are infinitely many possible planes of the form z=Ax+By+Cz=Ax+By+C.

[3]
Question 51
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A quadratic expression is written in the form

f(r)=x+ry+r2zf(r)=x+ry+r^2z

Values of f(r)f(r) give a system of linear equations for xx, yy and zz. This question investigates when the coefficients are uniquely determined.

Case

rr

f(r)f(r)

general

00

aa

general

11

bb

general

kk

cc

numerical

00

11

numerical

11

44

numerical

33

2222

A
I.

Given f(0)=1f(0)=1, f(1)=4f(1)=4 and f(3)=22f(3)=22, form the system of equations for xx, yy and zz.

[2]
II.

the system.

[2]
B

For the general values f(0)=af(0)=a, f(1)=bf(1)=b and f(k)=cf(k)=c, the determinant of the coefficient matrix is k(k−1)k(k-1).

[3]
C

the values of kk for which xx, yy and zz are not uniquely determined, and this in terms of the input values of rr.

[3]
Question 52
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A simple three- model has long-term proportions pp, qq and rr. At equilibrium,

p=0.6p+0.2q+0.1rq=0.3p+0.5q+0.2rp+q+r=1.\begin{aligned} p&=0.6p+0.2q+0.1r\\ q&=0.3p+0.5q+0.2r\\ p+q+r&=1. \end{aligned}

For a formal coefficient perturbation of this equilibrium system, replace 0.60.6 in the first equation by 1−t1-t, giving the coefficient matrix

(t−0.2−0.1−0.30.5−0.2111)\begin{pmatrix} t&-0.2&-0.1\\ -0.3&0.5&-0.2\\ 1&1&1 \end{pmatrix}
A
I.

Rewrite the first two equilibrium equations as linear equations equal to zero.

[2]
II.

the original equilibrium system.

[2]
B

For the formal coefficient perturbation, the determinant of the coefficient matrix is 0.7t+0.060.7t+0.06.

[3]
C

that the formal perturbed system has a unique solution for all 0≤t≤10\le t\le 1.

[2]

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Question 53
HL • Paper 3
Hard
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HL • Paper 3
Hard
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Three correction values xx, yy and zz are applied to a navigation system. They satisfy

x+y+z=302x−y+z=18x+ay+3z=b,\begin{aligned} x+y+z&=30\\ 2x-y+z&=18\\ x+ay+3z&=b, \end{aligned}

where a,b∈Ra,b\in\mathbb{R}.

Eqn

x

y

z

RHS

1

1

1

1

30

2

2

-1

1

18

3

1

a

3

b

A
I.

the determinant of the coefficient matrix is a−7a-7.

[3]
II.

the condition on aa for a unique solution.

[1]
B

For a=4a=4 and b=100b=100, the system.

[2]
C

For a=7a=7, classify the system for all real values of bb.

[3]
Question 54
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

The planes Π1\Pi_1 and Π2\Pi_2 are given by

Π1:x−y+z=2,Π2:2x+y−z=1\Pi_1:x-y+z=2,\qquad \Pi_2:2x+y-z=1

A third plane is given by

Π3:λx+3y+μz=ν\Pi_3:\lambda x+3y+\mu z=\nu

where λ,μ,ν∈R\lambda,\mu,\nu\in\mathbb{R}.

A
I.

the line of intersection of Π1\Pi_1 and Π2\Pi_2 in parametric form.

[3]
II.

the conditions on λ\lambda, μ\mu and ν\nu for which all three planes intersect in this line.

[2]
B

Suppose λ=2\lambda=2 and ν=0\nu=0. Classify the intersection of the three planes for all real values of μ\mu.

[4]
C

For λ=2\lambda=2, μ=−3\mu=-3 and ν=−1\nu=-1, the common line of intersection.

[2]
Question 55
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Consider the system

kx+y+z=1x+ky+z=1x+y+kz=m,\begin{aligned} kx+y+z&=1\\ x+ky+z&=1\\ x+y+kz&=m, \end{aligned}

where k,m∈Rk,m\in\mathbb{R}.

A
I.

the determinant of the coefficient matrix is (k−1)2(k+2)(k-1)^2(k+2).

[3]
II.

the values of kk for which further investigation is needed.

[1]
B

Classify the system for all values of kk and mm.

[5]
C
I.

For k=1k=1 and m=1m=1, write the solution set.

[1]
II.

For k=−2k=-2 and m=−2m=-2, write the solution set in terms of one parameter.

[2]
Question 56
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Two planes are given by

Π1:x+y+z=6,Π2:2x−y+z=3\Pi_1: x+y+z=6,\qquad \Pi_2: 2x-y+z=3

A third plane is of the form

Π3:x+py+qz=9\Pi_3: x+py+qz=9

where p,q∈Rp,q\in\mathbb{R}.

A
I.

a parametric form of the line of intersection of Π1\Pi_1 and Π2\Pi_2.

[3]
II.

the direction vector of this line.

[1]
B
I.

pp and qq so that Π3\Pi_3 contains the whole line of intersection of Π1\Pi_1 and Π2\Pi_2.

[3]
II.

the number of common points of the three planes for these values of pp and qq.

[1]
C

Instead let p=2p=2 and q=2q=2.

I.

the common point of the three planes.

[2]
II.

why the three planes now have exactly one common point.

[1]

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Question 57
HL • Paper 2
Hard
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HL • Paper 2
Hard
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Consider the system

x+y+z=12x+3y+az=4x+ay+3z=b,\begin{aligned} x+y+z&=1\\ 2x+3y+az&=4\\ x+ay+3z&=b, \end{aligned}

where a,b∈Ra,b\in\mathbb{R}.

A
I.

the determinant of the coefficient matrix is a(3−a)a(3-a).

[3]
II.

the values of aa for which the system may fail to have a unique solution.

[2]
B
I.

Classify the system when a=0a=0, in terms of bb.

[2]
II.

Classify the system when a=3a=3, in terms of bb.

[2]
C
I.

For a=3a=3 and b=5b=5, write the solution set in terms of a real parameter.

[2]
II.

For a≠0,3a\neq 0,3, the number of solutions and your answer.

[1]
Question 58
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

An input-output model for three sectors has total outputs xx, yy and zz. The equations are

0.8x−0.1y=20−0.3x+y−0.2z=30−ky+z=40,\begin{aligned} 0.8x-0.1y&=20\\ -0.3x+y-0.2z&=30\\ -ky+z&=40, \end{aligned}

where kk is a parameter representing the dependence of sector ZZ on sector YY.

A
I.

the determinant of the coefficient matrix in terms of kk.

[2]
II.

why the system has a unique solution for all 0≤k≤10\le k\le 1.

[2]
B

For k=0.5k=0.5, the system, giving each output to three significant figures.

[3]
C

The model is considered realistic only if all outputs are positive. whether the solution in part (b) is realistic, giving a reason.

[2]
Question 59
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A point PP in the plane is represented using weights α\alpha, β\beta and γ\gamma applied to three reference points

A(1,0),B(0,2),C(t,1)A(1,0),\quad B(0,2),\quad C(t,1)

The weights satisfy

αA+βB+γC=P,α+β+γ=1\alpha A+\beta B+\gamma C=P,\qquad \alpha+\beta+\gamma=1
A
I.

For t=3t=3 and P(2,1)P(2,1), form the system for α\alpha, β\beta and γ\gamma.

[2]
II.

the system and the signs of the weights.

[3]
B

the system for the weights has a unique solution unless t=12t=\frac{1}{2}.

[3]
C

For t=12t=\frac{1}{2}, geometrically why some points PP cannot be represented by any weights satisfying α+β+γ=1\alpha+\beta+\gamma=1.

[3]
Question 60
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Consider the family of systems

x+py+z=12x−y+pz=33x+(p−1)y+(p+1)z=λ,\begin{aligned} x+py+z&=1\\ 2x-y+pz&=3\\ 3x+(p-1)y+(p+1)z&=\lambda, \end{aligned}

where p,λ∈Rp,\lambda\in\mathbb{R}. This question investigates a situation in which a third equation may add no new information.

A
I.

the left-hand side of the third equation is the sum of the left-hand sides of the first two equations.

[2]
II.

the value of λ\lambda for which the system is consistent.

[1]
B

For p=2p=2 and λ=4\lambda=4, write the solution set using a real parameter.

[3]
C

that this family of systems never has a unique solution.

[2]

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Sequences & Series