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Rational Functions

Practice exam-style IB Math AA questions for Rational Functions, aligned with the syllabus and grouped by topic.

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Question 1
SL • Paper 1
Easy
Non Calculator
SL • Paper 1
Easy
Non Calculator

The function ff is defined by f(x)=ax+bx−2f(x)=\dfrac{ax+b}{x-2}, for x≠2x\neq 2. The graph of y=f(x)y=f(x) has horizontal asymptote y=4y=4 and xx-intercept (−1,0)(-1,0).

A

the values of aa and bb.

[3]
B

the yy-intercept of the graph.

[1]
Question 2
SL • Paper 2
Easy
Calculator Permitted
SL • Paper 2
Easy
Calculator Permitted

Consider g(x)=kx+1x−4g(x)=\dfrac{kx+1}{x-4}, where x≠4x\ne 4. The graph of y=g(x)y=g(x) has horizontal asymptote y=3y=3.

A

the value of kk.

[1]
B

the coordinates of the intercepts of the graph with the coordinate axes.

[2]
C

g(x)=5.5g(x)=5.5.

[2]
Question 3
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

The function ff is defined by f(x)=3x−2x+4f(x)=\dfrac{3x-2}{x+4}, for x≠−4x\neq -4.

A

the equations of the vertical and horizontal asymptotes of the graph of y=f(x)y=f(x).

[2]
B

the coordinates of the intercepts of the graph with the axes.

[2]
C

f(x)=1f(x)=1.

[2]
Question 4
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

Let f(x)=a+bx−cf(x)=a+\dfrac{b}{x-c}, for x≠cx\neq c. The graph of y=f(x)y=f(x) has asymptotes x=3x=3 and y=−2y=-2, and passes through the point P(1,5)P(1,5).

A

the values of aa and cc.

[2]
B

the value of bb.

[2]
C

the xx-intercept of the graph of y=f(x)y=f(x).

[1]

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Question 5
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

The function ff is defined by f(x)=2x+6x−1f(x)=\dfrac{2x+6}{x-1}, for x≠1x\neq 1.

A

f(x)=2+8x−1f(x)=2+\dfrac{8}{x-1}.

[2]
B

fully the transformations that map the graph of y=1xy=\dfrac{1}{x} to the graph of y=f(x)y=f(x).

[2]
C

the domain and range of ff.

[2]
Question 6
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

Let f(x)=kx+32x−kf(x)=\dfrac{kx+3}{2x-k}, where kk is a constant. The graph of y=f(x)y=f(x) has vertical asymptote x=2x=2.

A

the value of kk.

[2]
B

the equation of the horizontal asymptote.

[1]
C

the coordinates of the intercepts of the graph with the axes.

[2]
Question 7
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Consider the rational expression 7x+1(x−2)(x+1)\dfrac{7x+1}{(x-2)(x+1)}.

A

constants AA and BB such that 7x+1(x−2)(x+1)≡Ax−2+Bx+1\dfrac{7x+1}{(x-2)(x+1)}\equiv \dfrac{A}{x-2}+\dfrac{B}{x+1}.

[3]
B

7x+1(x−2)(x+1)=3\dfrac{7x+1}{(x-2)(x+1)}=3.

[3]
Question 8
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The function ff is defined by f(x)=x2+3x+5x+1f(x)=\dfrac{x^2+3x+5}{x+1}, for x≠−1x\neq -1.

A

the domain of ff and the equation of the vertical asymptote.

[2]
B

the equation of the oblique asymptote.

[2]
C

the yy-intercept and why the graph has no xx-intercepts.

[2]

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Question 9
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The function ff is defined by f(x)=2x−1x2−x−6f(x)=\dfrac{2x-1}{x^2-x-6}.

A

the equations of all vertical asymptotes of the graph of y=f(x)y=f(x).

[2]
B

the equation of the horizontal asymptote.

[1]
C

the coordinates of the intercepts of the graph with the axes.

[2]
Question 10
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

Let f(x)=3x−72x+5f(x)=\dfrac{3x-7}{2x+5}, for x≠−52x\ne -\dfrac{5}{2}.

A

the equations of the vertical and horizontal asymptotes of the graph of y=f(x)y=f(x).

[2]
B

the coordinates of the intercepts of the graph with the coordinate axes.

[2]
C

the coordinates of the points of intersection of y=f(x)y=f(x) and y=−xy=-x.

[2]
Question 11
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

A function ff has the form f(x)=ax−h+kf(x)=\dfrac{a}{x-h}+k, where aa, hh and kk are constants. The graph of y=f(x)y=f(x) has asymptotes x=3x=3 and y=−2y=-2, and passes through the point (5,4)(5,4).

A

the values of aa, hh and kk.

[2]
B

the xx-intercept of the graph of y=f(x)y=f(x).

[1]
C

the coordinates of the points where the graph of y=f(x)y=f(x) intersects the line y=xy=x.

[2]
Question 12
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

The resistance RR (in ohms) of a component at time tt (in seconds) is modelled by

R(t)=at+bt+c,t≥0R(t)=\frac{at+b}{t+c}, \quad t\ge 0

where aa, bb and cc are constants. The rational function, considered beyond the physical domain t≥0t\ge 0, has vertical asymptote t=−2 st=-2\ \text{s}, horizontal asymptote R=12 ΩR=12\ \Omega, and R(0)=5 ΩR(0)=5\ \Omega.

A

the values of aa, bb and cc.

[3]
B

the value of tt for which R(t)=9R(t)=9.

[2]
C

whether the value of tt found in part (b) is valid for this model.

[1]

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Question 13
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

Let f(x)=x+1x−2f(x)=\dfrac{x+1}{x-2}, for x≠2x\ne 2.

A

the equations of the asymptotes of the graph of y=f(x)y=f(x).

[2]
B

the coordinates of the intercepts of the graph with the coordinate axes.

[2]
C

the graph of y=f(x)y=f(x), clearly showing the asymptotes and intercepts.

[2]
Question 14
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

The function ff is defined by f(x)=ax+bx+df(x)=\dfrac{ax+b}{x+d}, where x≠−dx\ne -d. The graph of y=f(x)y=f(x) has vertical asymptote x=−3x=-3, horizontal asymptote y=2y=2, and xx-intercept (32,0)\left(\dfrac{3}{2},0\right).

A

the values of aa, bb and dd.

[3]
B

Write f(x)f(x) using the values found in part (a).

[1]
C

the yy-intercept of the graph of y=f(x)y=f(x).

[1]
Question 15
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Let f(x)=2x+1x2−5x+6f(x)=\dfrac{2x+1}{x^2-5x+6}.

A

the domain of ff and the equations of any vertical asymptotes.

[2]
B

the horizontal asymptote and the xx-intercept of the graph of y=f(x)y=f(x).

[2]
C

Using a GDC, the coordinates of the points where y=f(x)y=f(x) intersects the line y=0.7y=0.7.

[2]
Question 16
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Let

h(x)=4x−1(x−1)(x+2),x≠1,−2h(x)=\frac{4x-1}{(x-1)(x+2)}, \quad x\ne 1,-2
A

Express h(x)h(x) in partial fractions.

[3]
B

Using a GDC, h(x)=1.2h(x)=1.2.

[2]

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Question 17
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

The function hh is defined by h(x)=1x−2+3h(x)=\dfrac{1}{x-2}+3, for x≠2x\neq 2.

A

the domain and range of hh.

[2]
B

the coordinates of the intercepts of the graph of y=h(x)y=h(x) with the axes.

[2]
C

h(x)=xh(x)=x.

[2]
Question 18
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

Let nn be a positive integer.

A

1(r+1)(r+3)≡12(1r+1−1r+3)\dfrac{1}{(r+1)(r+3)}\equiv \dfrac12\left(\dfrac{1}{r+1}-\dfrac{1}{r+3}\right).

[2]
B

∑r=1n1(r+1)(r+3)\displaystyle \sum_{r=1}^{n}\dfrac{1}{(r+1)(r+3)} in terms of nn.

[3]
Question 19
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The function ff is defined by f(x)=x+ax2+bx+4f(x)=\dfrac{x+a}{x^2+bx+4}. The graph of y=f(x)y=f(x) has vertical asymptotes x=1x=1 and x=4x=4, and passes through the point (0,−12)(0,-\dfrac12).

A

the value of bb.

[2]
B

the value of aa.

[2]
C

the domain of ff and the xx-intercept of the graph.

[2]
Question 20
HL • Paper 1
Medium
Non Calculator
HL • Paper 1
Medium
Non Calculator

The function ff is defined by f(x)=2x2+px+qx−1f(x)=\dfrac{2x^2+px+q}{x-1}, for x≠1x\neq 1. The graph of y=f(x)y=f(x) has oblique asymptote y=2x+3y=2x+3 and xx-intercept (2,0)(2,0).

A

the value of pp.

[2]
B

the value of qq.

[2]
C

the equation of the vertical asymptote and the yy-intercept of the graph.

[2]

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Question 21
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

For positive integers nn, define

Sn=∑r=1n10(r+1)(r+3)S_n=\sum_{r=1}^{n}\frac{10}{(r+1)(r+3)}
A

Express 10(r+1)(r+3)\dfrac{10}{(r+1)(r+3)} in partial fractions.

[2]
B

Sn=256−5n+2−5n+3S_n=\dfrac{25}{6}-\dfrac{5}{n+2}-\dfrac{5}{n+3}.

[2]
C

the least value of nn for which Sn>4S_n>4.

[2]
Question 22
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Consider the rational function

f(x)=x2−4x+1x−2,x≠2f(x)=\frac{x^2-4x+1}{x-2}, \quad x\ne 2
A

f(x)=x−2−3x−2f(x)=x-2-\dfrac{3}{x-2}.

[2]
B

the equations of the vertical and oblique asymptotes of the graph of y=f(x)y=f(x).

[2]
C

the xx-intercepts of the graph of y=f(x)y=f(x).

[1]
D

the coordinates of the points where the graph of y=f(x)y=f(x) intersects the line y=4y=4.

[2]
Question 23
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

For k∈Rk\in\mathbb{R}, let

fk(x)=x+kx2−2kx+9f_k(x)=\frac{x+k}{x^2-2kx+9}
A

the equation of the horizontal asymptote of the graph of y=fk(x)y=f_k(x).

[1]
B

the set of values of kk for which the graph of y=fk(x)y=f_k(x) has no vertical asymptotes.

[3]
C

For k=4k=4, the equations of the vertical asymptotes of the graph of y=fk(x)y=f_k(x).

[2]
Question 24
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Let f(x)=x2+px+qx−1f(x)=\dfrac{x^2+px+q}{x-1}, where pp and qq are constants. The graph of y=f(x)y=f(x) has oblique asymptote y=x+3y=x+3 and yy-intercept (0,4)(0,4).

A

the values of pp and qq.

[2]
B

write f(x)f(x) in the form x+3+Ax−1x+3+\dfrac{A}{x-1}.

[2]
C

the xx-intercepts of the graph of y=f(x)y=f(x).

[2]

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Question 25
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

Let f(x)=4x−5x+2f(x)=\dfrac{4x-5}{x+2}, where x≠−2x\neq -2.

A
I.

f(x)=4−13x+2f(x)=4-\dfrac{13}{x+2}.

[2]
II.

the equations of the asymptotes of the graph of y=f(x)y=f(x).

[2]
B

the coordinates of the intercepts of the graph of y=f(x)y=f(x) with the coordinate axes.

[3]
C

the coordinates of the points of intersection of the graph of y=f(x)y=f(x) and the line y=−x+4y=-x+4.

[2]
D

f(x)>−x+4f(x)>-x+4.

[3]
Question 26
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

A function has the form f(x)=a+bx−hf(x)=a+\dfrac{b}{x-h}, where aa, bb and hh are constants. The graph of y=f(x)y=f(x) has asymptotes x=−2x=-2 and y=3y=3, and passes through the point (0,1)(0,1).

A
I.

the values of aa and hh.

[2]
II.

the value of bb.

[2]
B

the domain and range of ff, and the xx-intercept of the graph.

[4]
C
I.

the coordinates of the points where the graph of y=f(x)y=f(x) intersects the line y=xy=x.

[3]
II.

the exact distance between these two points.

[1]
Question 27
SL • Paper 1
Medium
Non Calculator
SL • Paper 1
Medium
Non Calculator

The concentration CC of a solution, in grams per litre, is modelled by

C(t)=8−At+b,t≥0C(t)=8-\frac{A}{t+b}, \quad t\geq 0

where tt is the time in minutes and AA and bb are positive constants. It is given that C(0)=2C(0)=2 and C(4)=5C(4)=5.

A
I.

Use C(0)=2C(0)=2 to form an equation involving AA and bb.

[2]
II.

the values of AA and bb.

[3]
B

the time at which C(t)=6C(t)=6.

[2]
C

the range of values of C(t)C(t) for this model, justifying your answer.

[3]
Question 28
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

The function ff is defined by

f(x)=5x−1x+2,x≠−2f(x)=\frac{5x-1}{x+2}, \quad x\ne -2
A
I.

the equations of the vertical and horizontal asymptotes of the graph of y=f(x)y=f(x).

[2]
II.

the coordinates of the intercepts of the graph of y=f(x)y=f(x) with the coordinate axes.

[2]
B

The graph of y=f(x)y=f(x) intersects the line y=xy=x at two points AA and BB. the coordinates of AA and BB.

[3]
C

the equation of the perpendicular bisector of ABAB.

[3]

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Question 29
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

A sensor reading RR is modelled by

R(t)=at−h+k,t>1R(t)=\frac{a}{t-h}+k, \quad t>1

where tt is the time in seconds and aa, hh and kk are constants. The graph of RR has vertical asymptote t=1t=1 and horizontal asymptote R=20R=20. It is known that R(3)=50R(3)=50 and R(6)=32R(6)=32.

A
I.

the values of hh and kk.

[2]
II.

the value of aa.

[2]
B

the time at which the sensor reading is 4040.

[2]
C

Using the model, the least integer value of tt for which R(t)<25R(t)<25.

[3]
Question 30
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

A function has the form

f(x)=k+ax−2,x≠2f(x)=k+\frac{a}{x-2}, \quad x\ne 2

The graph of y=f(x)y=f(x) passes through the points (4,7)(4,7) and (8,4)(8,4).

A
I.

Use the two given points to form two equations in aa and kk.

[2]
II.

the values of aa and kk.

[2]
B

the coordinates of the xx-intercept of the graph of y=f(x)y=f(x).

[2]
C

the coordinates of the points where the graph of y=f(x)y=f(x) intersects the line y=x2y=\frac{x}{2}.

[3]
D

the equations of the asymptotes of the graph of y=f(x)y=f(x).

[1]
Question 31
SL • Paper 1
Hard
Non Calculator
SL • Paper 1
Hard
Non Calculator

Let f(x)=2+9x−2f(x)=2+\dfrac{9}{x-2}, where x≠2x\neq 2.

A
I.

the equations of the asymptotes of the graph of y=f(x)y=f(x).

[2]
II.

the coordinates of the intercepts with the coordinate axes.

[2]
B

ff is a self-inverse function.

[3]
C

the points where the graph of y=f(x)y=f(x) intersects the line y=xy=x.

[2]
D

the graph of y=f(x)y=f(x), showing the asymptotes and the points found in part (c).

[2]
Question 32
SL • Paper 1
Hard
Non Calculator
SL • Paper 1
Hard
Non Calculator

Let f(x)=ax+b2x−1f(x)=\dfrac{ax+b}{2x-1}, where x≠12x\neq \dfrac{1}{2}. The graph of y=f(x)y=f(x) has horizontal asymptote y=−3y=-3 and xx-intercept (4,0)(4,0).

A
I.

the value of aa.

[2]
II.

the value of bb.

[2]
B

the yy-intercept and the vertical asymptote of the graph.

[2]
C

f(x)>0f(x)>0.

[3]
D

the value of kk for which the equation f(x)=kf(x)=k has no solution.

[1]

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Question 33
SL • Paper 1
Hard
Non Calculator
SL • Paper 1
Hard
Non Calculator

Let f(x)=2+6x−1f(x)=2+\dfrac{6}{x-1}, where x≠1x\neq 1. A second function gg is defined by g(x)=f(−x)g(x)=f(-x).

A
I.

an expression for g(x)g(x).

[2]
II.

the transformation that maps the graph of y=f(x)y=f(x) to the graph of y=g(x)y=g(x).

[1]
B

the vertical asymptotes of the graphs of y=f(x)y=f(x) and y=g(x)y=g(x), and their common horizontal asymptote.

[3]
C

the coordinates of the point of intersection of the graphs of y=f(x)y=f(x) and y=g(x)y=g(x).

[2]
D

f(x)>g(x)f(x)>g(x).

[3]
Question 34
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

For a positive integer nn, define

Sn=∑r=1n3(r+2)(r+5)S_n=\sum_{r=1}^{n}\frac{3}{(r+2)(r+5)}
A
I.

constants AA and BB such that 3(r+2)(r+5)≡Ar+2+Br+5\dfrac{3}{(r+2)(r+5)}\equiv\dfrac{A}{r+2}+\dfrac{B}{r+5}.

[3]
B

Sn=4760−1n+3−1n+4−1n+5S_n=\frac{47}{60}-\frac{1}{n+3}-\frac{1}{n+4}-\frac{1}{n+5}
[4]
C

lim⁡n→∞Sn\displaystyle\lim_{n\to\infty}S_n.

[2]
D

2222 is the least value of nn for which Sn>23S_n>\dfrac{2}{3}.

[3]
Question 35
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Let

f(x)=2x+3x2−4x+3f(x)=\frac{2x+3}{x^2-4x+3}
A
I.

the domain of ff and the equations of the vertical asymptotes.

[2]
II.

the equation of the horizontal asymptote.

[1]
B

the coordinates of the intercepts with the coordinate axes.

[3]
C

Express f(x)f(x) in partial fractions.

[3]
D

f(x)≥1f(x)\geq 1.

[4]
Question 36
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Let

f(x)=x2−3x+5x−2,x≠2f(x)=\frac{x^2-3x+5}{x-2}, \quad x\neq 2
A
I.

f(x)=x−1+3x−2f(x)=x-1+\dfrac{3}{x-2}.

[2]
II.

the equations of the asymptotes of the graph of y=f(x)y=f(x).

[2]
B

the yy-intercept and the graph has no xx-intercepts.

[3]
C

the coordinates of the point where the graph of y=f(x)y=f(x) intersects the line y=x+2y=x+2.

[2]
D

the values of the constant kk for which the line y=x+ky=x+k does not intersect the graph of y=f(x)y=f(x).

[3]

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Question 37
SL • Paper 2
Hard
Calculator Permitted
SL • Paper 2
Hard
Calculator Permitted

Let

f(x)=2x+7x−3,x≠3f(x)=\frac{2x+7}{x-3}, \quad x\ne 3
A
I.

the equations of the asymptotes of the graph of y=f(x)y=f(x).

[2]
II.

the range of ff.

[1]
B

f−1(x)f^{-1}(x) and its domain.

[3]
C

The graphs of y=f(x)y=f(x) and y=xy=x intersect at two points. their coordinates, giving your answers to three significant figures.

[3]
D

why the points found in part (c) are intersection points of the graphs of y=f(x)y=f(x) and y=f−1(x)y=f^{-1}(x).

[3]
Question 38
SL • Paper 2
Hard
Calculator Permitted
SL • Paper 2
Hard
Calculator Permitted

Consider the function

g(x)=4−3x+1,x≠−1g(x)=4-\frac{3}{x+1}, \quad x\ne -1
A
I.

the equations of the asymptotes of the graph of y=g(x)y=g(x).

[2]
II.

the transformations that map the graph of y=1xy=\frac{1}{x} to the graph of y=g(x)y=g(x).

[1]
B

the coordinates of the intercepts of the graph of y=g(x)y=g(x) with the coordinate axes.

[2]
C

g(x)>xg(x)>x. Give exact values for any boundary points.

[4]
Question 39
SL • Paper 2
Hard
Calculator Permitted
SL • Paper 2
Hard
Calculator Permitted

The function ff is defined by

f(x)=x+42x−1,x≠12f(x)=\frac{x+4}{2x-1}, \quad x\ne \frac12
A
I.

f(f(x))f(f(x)).

[2]
II.

what this implies about f−1(x)f^{-1}(x).

[1]
B

the two fixed points of ff.

[3]
C

the equation of the perpendicular bisector of the line segment joining the two fixed points.

[3]
Question 40
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

For n∈Z+n\in\mathbb{Z}^+ with n≥4n\ge4, define

Sn=∑r=1n4(r+2)(r+4)S_n=\sum_{r=1}^{n}\frac{4}{(r+2)(r+4)}
A
I.

Express 4(r+2)(r+4)\frac{4}{(r+2)(r+4)} in partial fractions.

[2]
II.

Write out the first four terms of SnS_n using your result from part (a)(i).

[1]
B

Sn=76−2n+3−2n+4S_n=\frac76-\frac{2}{n+3}-\frac{2}{n+4}
[4]
C

the least value of nn for which Sn>1.1S_n>1.1.

[3]

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Question 41
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Consider the rational function

f(x)=x2+2x+5x−1,x≠1f(x)=\frac{x^2+2x+5}{x-1}, \quad x\ne 1
A
I.

f(x)=x+3+8x−1f(x)=x+3+\frac{8}{x-1}.

[2]
II.

the equations of the vertical and oblique asymptotes.

[1]
B

the yy-intercept and why the graph has no xx-intercepts.

[3]
C

the coordinates of the points where the graph of y=f(x)y=f(x) intersects the line y=2xy=2x.

[3]
D

the area between the graph of y=f(x)y=f(x) and its oblique asymptote for 2≤x≤62\le x\le 6.

[3]
Question 42
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Let

h(x)=5x+1(x+1)(x+4),x≠−1,−4h(x)=\frac{5x+1}{(x+1)(x+4)}, \quad x\ne -1,-4
A
I.

Express h(x)h(x) in partial fractions.

[2]
II.

the equation of the horizontal asymptote of y=h(x)y=h(x).

[1]
B

the equations of the vertical asymptotes and the coordinates of the intercepts with the axes.

[3]
C

the graph of y=h(x)y=h(x) does not intersect the line y=1y=1.

[2]
D

the area between the graph of y=h(x)y=h(x), the xx-axis, and the lines x=0x=0 and x=3x=3.

[3]
Question 43
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

This question investigates a finite sum whose terms are rational functions. For n∈Z+n\in\mathbb{Z}^+, define

Sn=∑r=1n3(r+2)(r+5)S_n=\sum_{r=1}^{n}\frac{3}{(r+2)(r+5)}
A
I.

3(r+2)(r+5)≡1r+2−1r+5\frac{3}{(r+2)(r+5)}\equiv \frac{1}{r+2}-\frac{1}{r+5}
[2]
II.

SnS_n in terms of nn.

[2]
B
I.

lim⁡n→∞Sn\displaystyle \lim_{n\to\infty}S_n.

[1]
II.

the least value of nn for which SnS_n is within 0.0010.001 of its limiting value.

[3]
III.

why SnS_n is increasing.

[2]
Question 44
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

The graph of

f(x)=5x+1x2−x−6f(x)=\frac{5x+1}{x^2-x-6}

is shown for an interval not containing its vertical asymptotes.

A
I.

Express f(x)f(x) in partial fractions.

[3]
II.

the equations of the asymptotes of the graph of y=f(x)y=f(x).

[1]
B
I.

the exact area between the graph of y=f(x)y=f(x) and the xx-axis for 0≤x≤10\leq x\leq 1.

[3]
II.

the value of aa, 0<a<10<a<1, for which the area between the graph of y=f(x)y=f(x) and the xx-axis for 0≤x≤a0\leq x\leq a is 0.40.4.

[3]

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Question 45
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

For a∈Ra\in\mathbb{R}, consider the rational function

ga(x)=x2+ax+4x−2,x≠2g_a(x)=\frac{x^2+ax+4}{x-2},\quad x\neq 2
A
I.

ga(x)=x+a+2+2a+8x−2g_a(x)=x+a+2+\frac{2a+8}{x-2}
[2]
II.

the equations of the asymptotes of the graph of y=ga(x)y=g_a(x), for a≠−4a\neq -4.

[2]
B

For the rest of this question, take a=−1a=-1.

I.

the coordinates of the stationary points of the graph of y=g−1(x)y=g_{-1}(x).

[3]
II.

Use algebra to the intercepts shown on the graph of y=g−1(x)y=g_{-1}(x).

[2]
III.

Use the supplied graph and the expression g−1(x)=x+1+6x−2g_{-1}(x)=x+1+\frac{6}{x-2} to why the left and right branches lie on opposite sides of the oblique asymptote.

[1]
Question 46
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

For k∈Rk\in\mathbb{R}, define

fk(x)=x+kx2−2kx+5f_k(x)=\frac{x+k}{x^2-2kx+5}

This question considers how changing kk affects the vertical asymptotes and an area under the curve.

A
I.

the set of values of kk for which the graph of y=fk(x)y=f_k(x) has no vertical asymptote.

[2]
II.

the equation of the horizontal asymptote of the graph of y=fk(x)y=f_k(x).

[1]
III.

For k=3k=3, write f3(x)f_3(x) in partial fractions.

[2]
B

Use f3(x)f_3(x) from part (a).

I.

f3(x)<0f_3(x)<0 for 2≤x≤42\leq x\leq 4.

[2]
II.

the exact area between the graph of y=f3(x)y=f_3(x) and the xx-axis for 2≤x≤42\leq x\leq 4.

[3]
Question 47
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A rational function has the form

h(x)=ax2+bx+cx−3,x≠3h(x)=\frac{ax^2+bx+c}{x-3},\quad x\neq 3

Its oblique asymptote is y=2x−1y=2x-1 and its yy-intercept is (0,−2)(0,-2).

A
I.

aa, bb and cc.

[3]
II.

Write h(x)h(x) in the form 2x−1+Rx−32x-1+\dfrac{R}{x-3}.

[2]
B

Use the form found in part (a).

I.

the graph of y=h(x)y=h(x) does not intersect the line y=xy=x.

[2]
II.

the set of values of xx for which the vertical distance between the graph of y=h(x)y=h(x) and its oblique asymptote is less than 0.10.1.

[3]
Question 48
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

In a model, a signed magnification MM depends on a position xx according to

M(x)=ax+bx2−5x+4,x≠1,4M(x)=\frac{ax+b}{x^2-5x+4},\quad x\neq 1,4

It is known that M(0)=12M(0)=\frac12 and M(2)=−3M(2)=-3.

A
I.

the values of aa and bb.

[2]
II.

the xx-intercept of the graph of y=M(x)y=M(x).

[1]
III.

Express M(x)M(x) in partial fractions.

[2]
B

Use the model from part (a).

I.

the exact value of ∫58M(x) dx\displaystyle \int_5^8 M(x)\,\text{d}x.

[3]
II.

the value of x>4x>4 for which M(x)=1M(x)=1.

[2]

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Question 49
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Let

f(x)=x2+px+qx+1,x≠−1f(x)=\frac{x^2+px+q}{x+1}, \quad x\neq -1

where pp and qq are constants. The graph of y=f(x)y=f(x) has oblique asymptote y=x+2y=x+2 and passes through the point (1,4)(1,4).

A
I.

the value of pp.

[2]
II.

the value of qq.

[3]
B

f(x)=x+2+2x+1f(x)=x+2+\dfrac{2}{x+1}.

[2]
C

the graph of y=f(x)y=f(x) has no xx-intercepts.

[2]
D

the coordinates of the points where the graph of y=f(x)y=f(x) intersects the line y=2x+1y=2x+1.

[4]
Question 50
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

Let

f(x)=4xx2+4f(x)=\frac{4x}{x^2+4}
A
I.

the domain of ff and the equation of the horizontal asymptote.

[2]
II.

the intercept with the coordinate axes.

[1]
B

f′(x)=4(4−x2)(x2+4)2f'(x)=\frac{4(4-x^2)}{(x^2+4)^2}
[3]
C

the coordinates and nature of the stationary points of the graph of y=f(x)y=f(x).

[4]
D

f(x)=12f(x)=\dfrac12.

[2]
E

the range of ff.

[2]
Question 51
HL • Paper 1
Hard
Non Calculator
HL • Paper 1
Hard
Non Calculator

For k∈Rk\in\mathbb{R}, define

fk(x)=x+1x2−4x+kf_k(x)=\frac{x+1}{x^2-4x+k}
A
I.

the equation of the horizontal asymptote of the graph of y=fk(x)y=f_k(x).

[1]
II.

the yy-intercept in terms of kk, where it exists.

[2]
B

the values of kk for which the graph of y=fk(x)y=f_k(x) has no vertical asymptotes.

[3]
C

For k=3k=3, express f3(x)f_3(x) in partial fractions.

[3]
D

For k=3k=3, the equations of the vertical asymptotes and the xx-intercept of the graph of y=f3(x)y=f_3(x).

[3]
E

For k=3k=3, f3(x)>0f_3(x)>0.

[1]
Question 52
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Let

f(x)=2x−3x2−4x+3,x≠1,3f(x)=\frac{2x-3}{x^2-4x+3}, \quad x\ne 1,3
A
I.

the equations of all asymptotes of the graph of y=f(x)y=f(x).

[3]
II.

the xx-intercept of the graph.

[1]
B

Express f(x)f(x) in partial fractions.

[3]
C

∫48f(x) dx\int_4^8 f(x)\,dx
[3]
D

Using a GDC, the coordinates of the points where the graph of y=f(x)y=f(x) intersects the line y=0.4y=0.4.

[3]

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Question 53
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

For a∈Ra\in\mathbb{R}, define

fa(x)=x+ax2−2ax+9f_a(x)=\frac{x+a}{x^2-2ax+9}
A
I.

the discriminant of the denominator, in terms of aa.

[1]
II.

the set of values of aa for which the graph of y=fa(x)y=f_a(x) has no vertical asymptotes.

[2]
B

For the remainder of the question, let a=5a=5. the equations of the vertical and horizontal asymptotes of the graph of y=f5(x)y=f_5(x), and its xx-intercept.

[3]
C

the coordinates of the stationary points of the graph of y=f5(x)y=f_5(x).

[4]
D

Classify each stationary point as a local maximum or a local minimum.

[2]
Question 54
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

For k∈Rk\in\mathbb{R}, define

fk(x)=x2+kx+4x+2,x≠−2f_k(x)=\frac{x^2+kx+4}{x+2}, \quad x\ne -2
A
I.

fk(x)=x+k−2+8−2kx+2f_k(x)=x+k-2+\frac{8-2k}{x+2}
[2]
II.

the equation of the oblique asymptote of the graph of y=fk(x)y=f_k(x).

[1]
B

Let k=6k=6. the equations of the asymptotes of the graph of y=f6(x)y=f_6(x) and the coordinates of its intercepts with the axes.

[4]
C

For k=6k=6, the coordinates of the points where the graph of y=f6(x)y=f_6(x) intersects the line y=3y=3.

[2]
D

the value of kk for which the graph of y=fk(x)y=f_k(x) has no vertical asymptote. what happens at x=−2x=-2 for this value of kk.

[3]
Question 55
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

For a∈Ra\in\mathbb{R}, define

fa(x)=ax+1x−a,x≠af_a(x)=\frac{ax+1}{x-a},\quad x\neq a

This question investigates a family of linear rational functions related to the reciprocal function.

A
I.

the equations of the vertical and horizontal asymptotes of the graph of y=fa(x)y=f_a(x).

[2]
II.

faf_a is self-inverse on its domain.

[2]
B

Let a=2a=2.

I.

the fixed points of f2f_2, where f2(x)=xf_2(x)=x.

[3]
II.

the intercepts of the graph of y=f2(x)y=f_2(x) with the coordinate axes.

[2]
III.

the graph of y=f2(x)y=f_2(x), showing the asymptotes and fixed points.

[1]
Question 56
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

A variable xx changes with time tt according to

dxdt=(x−1)(x+3)x+1,x(0)=2\frac{\text{d}x}{\text{d}t}=\frac{(x-1)(x+3)}{x+1},\quad x(0)=2

This question uses partial fractions to the differential equation.

A
I.

x+1(x−1)(x+3)≡12(1x−1+1x+3)\frac{x+1}{(x-1)(x+3)}\equiv \frac12\left(\frac{1}{x-1}+\frac{1}{x+3}\right)
[2]
II.

t=12ln⁡((x−1)(x+3)5)t=\frac12\ln\left(\frac{(x-1)(x+3)}{5}\right)
[2]
B

If you did not obtain the result in part (a)(ii), use it for this part.

I.

Express xx as a function of tt.

[3]
II.

the time when x=10x=10.

[2]
III.

lim⁡t→∞x(t)\displaystyle \lim_{t\to\infty}x(t) and your result.

[1]

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Question 57
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

For a∈Ra\in\mathbb{R}, define

pa(x)=x−ax2+ax+a2+1p_a(x)=\frac{x-a}{x^2+ax+a^2+1}
A
I.

the graph of y=pa(x)y=p_a(x) has no vertical asymptotes for any real value of aa.

[2]
II.

the xx-intercept and the horizontal asymptote of the graph of y=pa(x)y=p_a(x).

[2]
B

Let a=1a=1.

I.

the stationary points of y=p1(x)y=p_1(x).

[3]
II.

the range of p1p_1.

[2]
III.

y=p1(x)y=p_1(x), showing the intercepts, horizontal asymptote and stationary points.

[1]
Question 58
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

Consider

q(x)=x2+px+qx+1,x≠−1q(x)=\frac{x^2+px+q}{x+1},\quad x\neq -1

The graph of y=q(x)y=q(x) has oblique asymptote y=x+2y=x+2 and has a stationary point on the xx-axis.

A
I.

the values of pp and qq.

[3]
II.

Write the resulting function in the form x+2+Rx+1x+2+\dfrac{R}{x+1}.

[2]
B

Use the function found in part (a).

I.

the coordinates of both stationary points.

[3]
II.

the vertical distance between the graph and its oblique asymptote when x=4x=4.

[1]
III.

the graph, showing both asymptotes and both stationary points.

[1]
Question 59
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

For constants aa, bb and cc, let

F(x)=x2+bx+cx−a,x≠aF(x)=\frac{x^2+bx+c}{x-a},\quad x\neq a

This question investigates the relationship between the remainder after division and the stationary points of FF.

A
AI.

F(x)=x+a+b+a2+ab+cx−aF(x)=x+a+b+\frac{a^2+ab+c}{x-a}
[2]
AII.

Let R=a2+ab+cR=a^2+ab+c. FF has two stationary points if and only if R>0R>0.

[2]
B

Assume that R>0R>0.

BI.

the coordinates of the stationary points in terms of aa, bb and RR.

[3]
BII.

that the midpoint of the two stationary points lies on the vertical asymptote.

[2]
BIII.

For a=2a=2, b=−3b=-3 and c=8c=8, the stationary points of FF.

[1]
Question 60
HL • Paper 3
Hard
Calculator Permitted
HL • Paper 3
Hard
Calculator Permitted

For A>0A>0, consider the family of rational functions

HA(x)=x+1+Ax−2,x≠2H_A(x)=x+1+\frac{A}{x-2},\quad x\neq 2

The graphs all have the same vertical and oblique asymptotes.

A
I.

Write HA(x)H_A(x) as a single rational expression of the form x2+bx+cx−2\dfrac{x^2+bx+c}{x-2}.

[2]
II.

the stationary points of HAH_A occur at x=2±Ax=2\pm\sqrt A.

[2]
B

If you did not obtain the result in part (a)(ii), use it for this part.

I.

For A=9A=9, the coordinates of the stationary points.

[2]
II.

For A=9A=9, HA(x)=10H_A(x)=10.

[2]
III.

the value of AA for which the minimum value of HA(x)H_A(x) on the interval x>2x>2 is 88.

[2]

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Quadratics

Transformations