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S2.4 From models to materials

Practice exam-style IB Chemistry questions for From models to materials, aligned with the syllabus and grouped by topic.

Verified by Dennis M.
Verified by Dennis M.
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Question 1
SL • Paper 1A
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SL • Paper 1A
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Steel is usually harder than pure iron. What structural feature of an alloy best explains this?

A.

Different-sized atoms distort the lattice and hinder layer sliding

B.

Covalent bonds replace all metallic bonds in the lattice

C.

The metal ions become fixed by strong ionic bonds

D.

Electrons are removed so the lattice has no attraction

Question 2
SL • Paper 1A
Easy
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SL • Paper 1A
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Addition polymerization of an alkene has 100%100\% atom economy for the polymer product. What is the reason?

A.

All atoms from the monomer are incorporated into the polymer

B.

The polymer contains fewer atoms than the monomers

C.

Only the atoms in the double bond enter the polymer

D.

Water is the only product formed in the reaction

Question 3
HL • Paper 1A
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HL • Paper 1A
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A dicarboxylic acid reacts with a diol in a condensation polymerization. What polymer type and small molecule are formed?

A.

Addition polymer and water

B.

Polyamide and water

C.

Polyester and hydrogen chloride

D.

Polyester and water

Question 4
SL • Paper 1A
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SL • Paper 1A
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A solid is lustrous, brittle and has electrical conductivity between that of a metal and an insulator. What bonding description best accounts for these properties?

A.

A simple molecular solid with only weak intermolecular forces

B.

A covalent network with some metallic character

C.

A metallic lattice with layers that slide easily

D.

An ionic lattice with mobile ions in the solid

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Question 5
SL • Paper 1A
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SL • Paper 1A
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The electronegativities of atoms X and Y in a binary compound are 0.8 and 2.8. What coordinates should be used to place the X-Y bond on a bonding triangle, using Δχ\Delta \chi and χˉ\bar{\chi}?

A.

Δχ=1.8\Delta \chi = 1.8, χˉ=2.0\bar{\chi} = 2.0

B.

Δχ=3.6\Delta \chi = 3.6, χˉ=2.0\bar{\chi} = 2.0

C.

Δχ=2.0\Delta \chi = 2.0, χˉ=3.6\bar{\chi} = 3.6

D.

Δχ=2.0\Delta \chi = 2.0, χˉ=1.8\bar{\chi} = 1.8

Question 6
SL • Paper 1A
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SL • Paper 1A
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Most plastics are poor electrical conductors. What structural reason best explains this property?

A.

They have strong ionic attractions between polymer chains

B.

They have covalent chains but no mobile charged particles

C.

They contain small molecules with mobile ions

D.

They contain electrons fixed in a metallic lattice

Question 7
HL • Paper 1A
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HL • Paper 1A
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The characteristic linkage in a polyamide formed from a dicarboxylic acid and a diamine is:

A.

−COO−-\text{COO}-

B.

−OCOO−-\text{OCOO}-

C.

−C=C−-\text{C=C}-

D.

−CONH−-\text{CONH}-

Question 8
HL • Paper 1A
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HL • Paper 1A
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Proteins break down at peptide bonds during digestion. What type of reaction occurs, and what is the role of water?

A.

Condensation; water is a product of linkage formation

B.

Oxidation; water removes electrons from the linkage

C.

Addition; water opens a carbon-carbon double bond

D.

Hydrolysis; water is a reactant that breaks the linkage

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Question 9
HL • Paper 1A
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HL • Paper 1A
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A diacyl chloride reacts with a diamine to form a condensation polymer. What polymer type and small molecule are formed?

A.

Polyalkene and hydrogen chloride

B.

Polyamide and water

C.

Polyester and hydrogen chloride

D.

Polyamide and hydrogen chloride

Question 10
SL • Paper 1A
Medium
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SL • Paper 1A
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The repeating unit formed by addition polymerization of bromoethene, CH2=CHBr\text{CH}_2=\text{CHBr}, is:

A.

[−CH2−CH2Br−]n[-\text{CH}_2-\text{CH}_2\text{Br}-]_n

B.

[−CH2−CHBr−]n[-\text{CH}_2-\text{CHBr}-]_n

C.

[−CHBr−CHBr−]n[-\text{CHBr}-\text{CHBr}-]_n

D.

[−CH=CHBr−]n[-\text{CH}=\text{CHBr}-]_n

Question 11
HL • Paper 1A
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HL • Paper 1A
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A monomer contains both an amino group, −NH2-\text{NH}_2, and a carboxyl group, −COOH-\text{COOH}. What polymerization behaviour is expected?

A.

It can form a polyamide-like chain by condensation with release of water

B.

It can form an addition polymer by opening a carbon-carbon double bond

C.

It can form a polyester by eliminating hydrogen chloride

D.

It cannot polymerize because both functional groups are on one molecule

Question 12
SL • Paper 2
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SL • Paper 2
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Magnesium oxide and silicon may be compared using a bonding triangle.

Electronegativity values: χ(Mg)=1.3\chi(\text{Mg}) = 1.3, χ(O)=3.4\chi(\text{O}) = 3.4, χ(Si)=1.9\chi(\text{Si}) = 1.9.

A

Δχ\Delta \chi and χˉ\bar{\chi} for the Mg-O bond in magnesium oxide.

[2]
B

the value of Δχ\Delta \chi for a Si-Si bond and the bonding region in which silicon is expected to lie.

[1]
C

one physical property of magnesium oxide from its position near the ionic region of the bonding triangle.

[1]

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Question 13
SL • Paper 2
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SL • Paper 2
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A solid has a high melting point, is brittle, does not conduct electricity as a solid, but conducts when molten.

A

the bonding model that best accounts for these properties.

[1]
B

why this solid is brittle but conducts electricity when molten.

[2]
Question 14
SL • Paper 2
Medium
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SL • Paper 2
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Reinforced concrete contains concrete surrounding steel bars. It is used in buildings and bridges.

A

what is meant by a composite material.

[1]
B

why reinforced concrete has properties that are more useful than concrete alone.

[2]
Question 15
HL • Paper 2
Medium
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HL • Paper 2
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A polyester can be prepared from a diol and a diacyl chloride instead of from a diol and a dicarboxylic acid.

A

the small molecule eliminated when an acyl chloride group reacts with a hydroxyl group.

[1]
B

the type of linkage formed in the polymer.

[1]
C

the polymer formed using a diacyl chloride with that formed using the corresponding dicarboxylic acid.

[1]
Question 16
SL • Paper 1B
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SL • Paper 1B
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Samples of iron-carbon alloys were tested for Vickers hardness and electrical resistivity.

Carbon content / wt%

Vickers hardness / HV

Resistivity / 10−8Ω m10^{-8}\\ \Omega\ \text{m}

0.00

92

9.7

0.25

128

10.6

0.50

162

11.4

0.75

198

12.3

1.00

236

13.2

A

the effect of increasing carbon content on the hardness of the alloy.

[1]
B

the change in hardness in terms of metallic bonding and structure.

[2]
C

why the electrical conductivity of the alloy is lower than that of pure iron.

[1]

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Question 17
HL • Paper 1A
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HL • Paper 1A
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Ethane-1,2-diol, HOCH2CH2OH\text{HOCH}_2\text{CH}_2\text{OH}, reacts with butanedioic acid, HOOCCH2CH2COOH\text{HOOCCH}_2\text{CH}_2\text{COOH}, to form a condensation polymer. The repeating unit is:

A.

[−OCH2CH2OCOCH2CH2CO−]n[-\text{OCH}_2\text{CH}_2\text{OCOCH}_2\text{CH}_2\text{CO}-]_n

B.

[−OCH2CH2OHCOCH2CH2COOH−]n[-\text{OCH}_2\text{CH}_2\text{OHCOCH}_2\text{CH}_2\text{COOH}-]_n

C.

[−CH2CH2CH2CH2COO−]n[-\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_2\text{COO}-]_n

D.

[−NHCH2CH2NHCOCH2CH2CO−]n[-\text{NHCH}_2\text{CH}_2\text{NHCOCH}_2\text{CH}_2\text{CO}-]_n

Question 18
SL • Paper 2
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SL • Paper 2
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The hardness of samples of carbon steel was measured as the percentage of carbon was varied.

A

why steel is described as a mixture rather than as a compound.

[1]
B

the trend in hardness using the metallic bonding model.

[2]
Question 19
SL • Paper 2
Medium
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SL • Paper 2
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Polyethene and poly(chloroethene) are synthetic polymers used as plastics.

A

Define the term monomer.

[1]
B

why most plastics are electrical insulators.

[1]
C

Poly(chloroethene) has a higher softening temperature than polyethene of similar chain length. this difference.

[2]
Question 20
SL • Paper 2
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SL • Paper 2
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2-Methylpropene undergoes addition polymerization.

A

the repeating unit of the addition polymer formed from 2-methylpropene.

[2]
B

the change in bonding that occurs in the monomer during addition polymerization.

[1]
C

the atom economy for this addition polymerization.

[1]

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Question 21
HL • Paper 2
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HL • Paper 2
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Ethane-1,2-diol reacts with butanedioic acid to form a polyester.

A

the repeating unit of the polyester.

[2]
B

the small molecule released during the polymerization.

[1]
C

Identify the linkage formed in the polymer backbone.

[1]
Question 22
HL • Paper 2
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HL • Paper 2
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Glycine, NH2CH2COOHNH_2CH_2COOH, can form a biological macromolecule by condensation reactions.

A

the type of polymer and the type of linkage formed when many glycine molecules join.

[2]
B

Formulate an equation for the condensation of two glycine molecules to form a dipeptide.

[1]
C

the role of water in hydrolysis of the polypeptide.

[1]
Question 23
HL • Paper 2
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HL • Paper 2
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Lactic acid, CH3CH(OH)COOHCH_3CH(OH)COOH, can polymerize with itself to form poly(lactic acid), PLA.

A

Identify the two functional groups in lactic acid that allow it to undergo condensation polymerization.

[2]
B

the repeating unit of PLA.

[2]
Question 24
SL • Paper 1B
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SL • Paper 1B
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The table shows selected properties of some period 3 oxides. The oxides are labelled A to D.

Oxide

Melting point / ∘C^\circ\text{C}

Bonding character

Acid-base behaviour

A

1130

predominantly ionic

alkaline

B

950

ionic with some covalent character

basic

C

680

mixed ionic and covalent

amphoteric

D

340

simple molecular covalent

acidic

A

Identify the oxide with the greatest ionic character.

[1]
B

the trend in bonding character shown by the oxides from A to D.

[2]
C

why oxide D has a much lower melting point than oxide A.

[2]

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Question 25
SL • Paper 1B
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SL • Paper 1B
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The electronegativities of selected elements and a bonding triangle are provided. A student is asked to place several binary substances on the triangle.

Element

Electronegativity / Pauling scale

Al

1.61

Cl

3.16

Ba

0.89

I

2.66

A

Δχ\Delta \chi and χˉ\bar{\chi} for the Al--Cl bond.

[2]
B

Use the values for Al--Cl to why aluminium chloride does not behave like a typical high-melting ionic chloride.

[2]
Question 26
SL • Paper 1B
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SL • Paper 1B
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The structures of three alkene monomers and selected properties of their polymers are shown.

A

the structural feature in each monomer that allows addition polymerization.

[1]
B

Write the condensed repeating unit formed from chloroethene, CH2=CHClCH_2=CHCl.

[2]
C

why the polymer from chloroethene has a higher softening temperature than polyethene.

[2]
Question 27
HL • Paper 1B
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HL • Paper 1B
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A polyester is made from benzene-1,4-dicarboxylic acid and ethane-1,2-diol. The monomer structures and a section of the polymer chain are shown.

A

Identify the two functional groups that react to form the polyester.

[1]
B

Write a condensed repeating unit for the polyester.

[3]
C

the small molecule released when each ester linkage forms from these monomers.

[1]
Question 28
HL • Paper 1B
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HL • Paper 1B
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A protein sample was hydrolysed at different temperatures. The graph shows the concentration of free amino acids formed over time.

A

the trend shown for the concentration of free amino acids at higher temperature.

[1]
B

Identify the type of linkage broken during hydrolysis of the protein.

[1]
C

why hydrolysis is described as the reverse of condensation polymerization for proteins.

[2]

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Question 29
HL • Paper 2
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HL • Paper 2
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Hexane-1,6-diamine reacts with hexanedioic acid to form nylon-6,6, a polyamide.

A

the repeating unit of nylon-6,6.

[2]
B

why both monomers must be bifunctional for a long-chain polymer to form.

[1]
C

the products formed by complete hydrolysis of nylon-6,6 under suitable conditions.

[1]
Question 30
HL • Paper 2
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HL • Paper 2
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The repeating unit of PET, a polyester, is shown.

A

the two monomers used to form PET from this repeating unit.

[2]
B

why formation of PET is classified as condensation polymerization rather than addition polymerization.

[2]
Question 31
SL • Paper 1B
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SL • Paper 1B
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Four plastics used for packaging were compared. Each polymer differs in side groups, chain length and the presence or absence of hydrolysable groups.

Plastic

Side groups / main structural feature

Relative chain length

Hydrolysable groups?

Softening temperature / ∘C^\circ\text{C}

Tensile strength / MPa

Mass loss in biodegradation test / %

A

small alkyl side groups

long

no

90

14

4

B

branched alkyl side groups

long

no

115

22

7

C

bulky aromatic side groups

long

no

150

18

3

D

polar side groups

short

yes (ester linkages)

70

6

38

A

Identify the plastic most likely to be suitable for a hot-drink lid, using the data.

[1]
B

why the plastics are electrical insulators.

[2]
C

two structural reasons why plastic D loses the greatest percentage mass in the biodegradation test.

[2]
Question 32
SL • Paper 1B
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SL • Paper 1B
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Reinforced concrete consists of concrete surrounding steel bars. Mechanical test data for concrete, steel and reinforced concrete are shown.

Material

Tensile strength / MPa

Strain at break / %

Concrete

2

0.1

Steel

500

20

Reinforced concrete

20

1.0

A

the performance of concrete and reinforced concrete under tension.

[1]
B

why steel improves the performance of reinforced concrete.

[2]
C

the statement: "The properties of reinforced concrete can be predicted by classifying it as one bonding type."

[2]

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Question 33
HL • Paper 1B
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HL • Paper 1B
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Two routes to a polyamide are compared. Route 1 uses a dicarboxylic acid and a diamine. Route 2 uses a diacyl chloride and the same diamine. Observations during polymer formation are shown.

Feature

Route 1

Route 2

acid/chloride monomer

HOOC−(CH2)4−COOHHOOC-(CH_2)_4-COOH

ClCO−(CH2)4−COCl\text{ClCO}-(\text{CH}_2)_4-\text{COCl}

amine monomer

H2N−(CH2)6−NH2H_2N-(CH_2)_6-NH_2

H2N−(CH2)6−NH2H_2N-(CH_2)_6-NH_2

polymer-forming reaction

condensation

condensation

small molecule formed

H2OH_2O

HCl(g)HCl(g)

observable during formation

polymer forms on heating

rapid polymer formation with steamy acidic fumes

polyamide fragment

…−NH−(CH2)6−NH−CO−(CH2)4−CO−…\ldots-NH-(CH_2)_6-NH-CO-(CH_2)_4-CO-\ldots

…−NH−(CH2)6−NH−CO−(CH2)4−CO−…\ldots-NH-(CH_2)_6-NH-CO-(CH_2)_4-CO-\ldots

A

Identify the linkage in the polyamide chain.

[1]
B

the small molecule produced in route 2.

[1]
C

why both monomers in route 1 must be bifunctional for a long-chain polyamide to form.

[2]
Question 34
HL • Paper 1B
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HL • Paper 1B
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Two monomers, X and Y, each contain two functional groups. Their structures and possible polymer products are shown.

A

which monomer forms a polyester when it polymerizes with itself.

[1]
B

which monomer forms a polyamide-like chain when it polymerizes with itself.

[1]
C

A chain fragment is formed from four molecules of monomer X in a linear condensation reaction. the number of water molecules released.

[2]
Question 35
SL • Paper 2
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SL • Paper 2
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A manufacturer is choosing between pure copper and a copper alloy for electrical connectors that must resist deformation during use.

Material

Hardness / HV

Conductivity / % IACS

Pure copper

50

100

Brass

100

28

Bronze

110

15

Phosphor bronze

150

10

A

Use the metallic bonding model to answer the following.

I.

why pure copper is malleable.

[2]
II.

why copper conducts electricity.

[1]
B

why adding a small amount of another element to copper usually increases hardness but decreases electrical conductivity.

[2]
C

whether pure copper or the copper alloy is more suitable for the electrical connectors.

[2]
Question 36
SL • Paper 2
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SL • Paper 2
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Reinforced concrete contains concrete surrounding steel bars. Concrete is strong under compression but weak under tension, while steel is strong under tension and can deform before breaking.

A

Use bonding models to the different mechanical behaviour of the two components.

I.

why steel can deform without the metallic structure immediately breaking apart.

[2]
II.

why concrete is more brittle than steel.

[1]
B

why reinforced concrete is described as a composite material rather than a compound.

[2]
C

why reinforced concrete can be more useful as a building material than either concrete or steel alone.

[2]

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Question 37
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HL • Paper 2
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Lactic acid, CH3CH(OH)COOHCH_3CH(OH)COOH, can polymerize to form poly(lactic acid), PLA, a biodegradable polyester.

A

Lactic acid is an example of a monomer that polymerizes with itself.

I.

why lactic acid can undergo condensation polymerization without a second type of monomer.

[2]
II.

the repeating unit of PLA.

[2]
B

why PLA is more susceptible to biodegradation than polyethene.

[2]
C

one environmental condition that may still slow the biodegradation of PLA in landfill.

[1]
Question 38
HL • Paper 1B
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HL • Paper 1B
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Three experimental biodegradable plastics were incubated in moist soil. Their structures and mass loss after incubation are compared.

Polymer

Simplified structure

Mass loss after 8 weeks in moist soil / %

A

carbon–carbon backbone only

5

B

ester linkages in backbone; linear chains

33

C

ester linkages in backbone; cross-linked network

18

A

Identify the polymer expected to undergo the greatest hydrolysis.

[1]
B

why ester linkages can increase biodegradability compared with a carbon-carbon backbone.

[2]
C

why polymer C loses less mass than polymer B even though both contain ester linkages.

[2]
Question 39
HL • Paper 1B
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HL • Paper 1B
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The table compares an addition polymerization and a condensation polymerization carried out on the same scale. The desired polymer and any small-molecule by-products are listed.

Polymerization

Total mass of reactants / g

Mass of desired polymer / g

Mass of small-molecule by-product / g

Addition polymerization

100.0

100.0

0.0

Condensation polymerization

100.0

82.0

18.0

A

the atom economy for the condensation polymerization using the data.

[2]
B

the atom economy of the addition polymerization with that of the condensation polymerization.

[1]
C

the difference in atom economy in terms of the polymerization mechanisms.

[2]
Question 40
SL • Paper 2
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SL • Paper 2
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Aluminium chloride is often introduced using an ionic model, but its properties are better explained using a bonding continuum. The electronegativity values are: Al = 1.61, Cl = 3.16, Mg = 1.31, O = 3.44, Si = 1.90.

A

Aluminium chloride contains Al--Cl bonds.

I.

Δχ\Delta \chi and χˉ\bar{\chi} for the Al--Cl bond.

[2]
II.

, using these values, why aluminium chloride should not be placed at the purely ionic corner of the bonding triangle.

[1]
B

why solid aluminium chloride has a much lower melting point than magnesium oxide and does not conduct electricity as a solid.

[3]
C

the expected properties of silicon and magnesium oxide in terms of their different positions in the bonding triangle.

[2]

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Question 41
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SL • Paper 2
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The alkene monomer chloroethene, CH2=CHClCH_2=CHCl, is used to make poly(chloroethene), PVC.

A

Consider the addition polymerization of chloroethene.

I.

the repeating unit of poly(chloroethene).

[2]
II.

why this polymerization has 100%100\% atom economy for the polymer product.

[2]
B

why chloroethene is a gas at room temperature but PVC is a solid plastic.

[2]
C

PVC is usually an electrical insulator and is often more rigid than polyethene. these two properties in terms of structure and bonding.

[2]
Question 42
SL • Paper 2
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SL • Paper 2
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The oxides Na2ONa_2O, Al2O3Al_2O_3 and SO3SO_3 illustrate that bonding changes gradually across period 3.

A

Classify the bonding character of these period 3 oxides.

I.

which of Na2ONa_2O, Al2O3Al_2O_3 and SO3SO_3 is expected to have the greatest ionic character and justify your answer.

[2]
II.

why Al2O3Al_2O_3 is described as amphoteric and intermediate in bonding character.

[1]
B

the expected electrical conductivity of solid Na2ONa_2O and liquid SO3SO_3 in terms of their particles.

[2]
C

why assigning each oxide to a single bonding category can be misleading.

[2]
Question 43
SL • Paper 2
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SL • Paper 2
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Three plastics used in packaging have different repeating units: polyethene, poly(chloroethene) and polystyrene.

A

Relate the structures of the plastics to their physical properties.

I.

why these plastics are usually poor electrical conductors.

[1]
II.

why poly(chloroethene) usually has stronger attractions between chains than polyethene.

[1]
III.

why polystyrene is often more brittle than polyethene.

[2]
B

Packaging fragments can become microplastics in the ocean. Distinguish microplastic formation from biodegradation.

[2]
C

two structural features that could make a plastic more biodegradable.

[2]
Question 44
HL • Paper 2
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HL • Paper 2
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A polyester can be made from benzene-1,4-dicarboxylic acid and ethane-1,2-diol.

A

Consider the formation of the polyester.

I.

Identify the two functional groups that react to form each ester linkage.

[1]
II.

the repeating unit of the polyester, showing continuation bonds.

[3]
III.

the small molecule released during formation of each ester linkage.

[1]
B

why the monomers must be bifunctional for chain growth to occur.

[2]
C

the chemical change that occurs when this polyester is hydrolysed.

[1]

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Question 45
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HL • Paper 2
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Nylon-6,6 is a polyamide made from hexane-1,6-diamine, H2N(CH2)6NH2H_2N(CH_2)_6NH_2, and hexanedioic acid, HOOC(CH2)4COOHHOOC(CH_2)_4COOH.

A

Consider the condensation reaction that forms nylon-6,6.

I.

the functional groups in the two monomers that react to form an amide linkage.

[1]
II.

the repeating unit of nylon-6,6.

[3]
III.

the small molecule released when the amide linkage forms from these monomers.

[1]
B

Hexanedioyl dichloride, ClOC(CH2)4COClClOC(CH_2)_4COCl, can be used instead of hexanedioic acid. one change in the condensation reaction.

[1]
C

condensation polymerization of nylon-6,6 with addition polymerization of ethene.

[2]
Question 46
HL • Paper 2
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HL • Paper 2
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Proteins are biological macromolecules formed from amino acid monomers. A general amino acid contains both −NH2-NH_2 and −COOH-COOH groups.

A

Consider the formation of a peptide linkage between two amino acids.

I.

Identify the functional groups that react.

[1]
II.

the type of linkage formed and the small molecule eliminated.

[2]
III.

why amino acids can form long chains rather than only dimers.

[1]
B

how hydrolysis breaks down a protein chain.

[2]
C

why proteins are classified as condensation polymers.

[1]
Question 47
HL • Paper 2
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HL • Paper 2
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A student prepares a polyamide from equimolar amounts of hexane-1,6-diamine, H2N(CH2)6NH2H_2N(CH_2)_6NH_2, and hexanedioic acid, HOOC(CH2)4COOHHOOC(CH_2)_4COOH. The student reacts 0.250 mol0.250\ \text{mol} of each monomer. Assume that, for a very long chain, each repeat unit forms with elimination of two molecules of water.

A

The student reacts 0.250 mol0.250\ \text{mol} of each monomer.

I.

the amount, in mol, of water eliminated.

[2]
II.

the mass of water eliminated.

[1]
III.

why this polymerization does not have 100%100\% atom economy for the polyamide product.

[1]
B

why the polyamide can be hydrolysed, but an addition polymer such as polyethene is much less susceptible to hydrolysis.

[2]
C

one reason why condensation polymers can still be valuable materials despite producing small-molecule by-products during manufacture.

[1]
Question 48
HL • Paper 2
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HL • Paper 2
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A section of a condensation polymer is shown. The polymer has both ester and amide linkages and is being investigated for chemical recycling by hydrolysis.

A

Analyse the linkages in the polymer chain.

I.

Identify one ester linkage and one amide linkage in the polymer section.

[2]
II.

the two types of functional groups that must have been present in monomers used to form the ester linkage.

[1]
III.

the two types of functional groups that must have been present in monomers used to form the amide linkage.

[1]
B

the chemical changes expected during complete hydrolysis of the polymer.

[2]
C

one advantage and one limitation of using hydrolysis for chemical recycling of this polymer.

[2]

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