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R1.4 Entropy and spontaneity (AHL)

Practice exam-style IB Chemistry questions for Entropy and spontaneity (AHL), aligned with the syllabus and grouped by topic.

Question 1
HL • Paper 1A
Easy
Non Calculator

The standard molar entropy of one mole of a substance is greatest for which state under the same conditions?

A.

Liquid

B.

Aqueous precipitate

C.

Perfect crystalline solid

D.

Gas

Question 2
HL • Paper 1A
Easy
Non Calculator

At constant temperature and pressure, what does ΔG < 0 indicate for the forward reaction?

A.

It must be rapid

B.

It is thermodynamically spontaneous

C.

It is at equilibrium

D.

It is non-spontaneous

Question 3
HL • Paper 1A
Easy
Non Calculator

For the reaction

2SO₂

A.

Negative, because all species are gases

B.

Negative, because the number of moles of gas decreases

C.

Positive, because three moles of gas form two moles of gas

D.

Positive, because the reaction forms a compound

Question 4
HL • Paper 1A
Easy
Non Calculator

For A

A.

−350 J K⁻¹ mol⁻¹

B.

−140 J K⁻¹ mol⁻¹

C.

+850 J K⁻¹ mol⁻¹

D.

+350 J K⁻¹ mol⁻¹

Question 5
HL • Paper 1A
Easy
Non Calculator

In a graph of ΔG⦵ against temperature for a reaction, what does the gradient represent?

A.

TΔS⦵

B.

ΔH⦵

C.

−TΔH⦵

D.

−ΔS⦵

Question 6
HL • Paper 1A
Easy
Non Calculator

A reaction has ΔH⦵ < 0 and ΔS⦵ < 0. Under standard conditions, when is it most likely to be spontaneous?

A.

At no temperature

B.

At high temperature only

C.

At low temperature only

D.

At all temperatures

Question 7
HL • Paper 1A
Easy
Non Calculator

If ΔG⦵ is positive for a reaction at a given temperature, what is true about K?

A.

K = 1; neither side is favoured

B.

K < 0; the reaction cannot occur

C.

K > 1; products are favoured

D.

K < 1; reactants are favoured

Question 8
HL • Paper 2
Easy
Calculator
1.

State the unit of standard molar entropy.

[1]
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2.

Explain why Br₂

[1]
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3.

has a higher entropy than Br₂

[1]
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4.

under the same conditions.

[2]
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Question 9
HL • Paper 2
Easy
Calculator
1.

Define a perfect crystal.

[1]
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2.

State why the entropy of a perfect crystal at 0 K is predicted to be zero.

[1]
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Question 10
HL • Paper 2
Easy
Calculator
1.

Distinguish between Q and K.

[1]
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2.

State the value of ΔG when Q = K.

[1]
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Question 11
HL • Paper 1A
Medium
Non Calculator

For a reaction, ΔH⦵ = +48.0 kJ mol⁻¹ and ΔS⦵ = +120 J K⁻¹ mol⁻¹. What is ΔG⦵ at 298 K?

A.

−12.2 kJ mol⁻¹

B.

+12.2 kJ mol⁻¹

C.

+47.9 kJ mol⁻¹

D.

−35.8 kJ mol⁻¹

Question 12
HL • Paper 1A
Medium
Non Calculator

For a reaction, ΔH⦵ = +72.0 kJ mol⁻¹ and ΔS⦵ = +240 J K⁻¹ mol⁻¹. Above what temperature is the reaction spontaneous under standard conditions?

A.

1.73 × 10⁴ K

B.

0.00333 K

C.

Above no temperature

D.

300 K

Question 13
HL • Paper 1A
Medium
Non Calculator

A reaction is thermodynamically spontaneous at 298 K but is not observed to occur over several days. What is the best explanation?

A.

The entropy change must be zero

B.

The activation energy may be large

C.

The reaction must be at equilibrium

D.

ΔG must be positive at 298 K

Question 14
HL • Paper 1A
Medium
Non Calculator

For an electrochemical cell reaction, n = 2 and E⦵cell = +0.54 V. What is the sign of ΔG⦵ and the spontaneity of the reaction as written?

A.

ΔG⦵ is negative; spontaneous

B.

ΔG⦵ is positive; spontaneous

C.

ΔG⦵ is negative; non-spontaneous

D.

ΔG⦵ is positive; non-spontaneous

Question 15
HL • Paper 1A
Medium
Non Calculator

For a reversible reaction at a fixed temperature, Q < K. What is the sign of ΔG for the forward reaction?

A.

Equal to ΔG⦵

B.

Negative

C.

Zero

D.

Positive

Question 16
HL • Paper 1A
Medium
Non Calculator

For N₂O₄

A.

[NO₂]/[N₂O₄]

B.

[NO₂]²/[N₂O₄]

C.

[N₂O₄]²/[NO₂]

D.

[N₂O₄]/[NO₂]²

Question 17
HL • Paper 1A
Medium
Non Calculator

At 298 K, ΔG⦵ = −12.0 kJ mol⁻¹ and Q = 0.050. What is the sign of ΔG?

A.

Negative

B.

Zero

C.

Positive

D.

Cannot be determined without K

Question 18
HL • Paper 2
Medium
Calculator

For each change, predict the sign of ΔS for the system and give a reason.

1.

H₂O

[1]
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2.

→ H₂O

[1]
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3.
[1]
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4.

2NH₃

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5.

→ N₂

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6.
  • 3H₂
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7.
[2]
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Question 19
HL • Paper 2
Medium
Calculator

Methanol can be formed by

CO

SubstanceS° / J K⁻¹ mol⁻¹
CO(g)198
H₂(g)131
CH₃OH(l)127
1.
  • 2H₂
[1]
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2.

→ CH₃OH

[1]
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3.

The standard molar entropies are: CO

[1]
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4.

= 198 J K⁻¹ mol⁻¹, H₂

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5.

= 131 J K⁻¹ mol⁻¹, CH₃OH

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6.

= 127 J K⁻¹ mol⁻¹.

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7.

Calculate ΔS⦵ for the reaction.

[2]
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8.

State why the sign is expected.

[1]
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Question 20
HL • Paper 2
Medium
Calculator

For a reaction at 350 K, ΔH⦵ = −25.0 kJ mol⁻¹ and ΔS⦵ = −60.0 J K⁻¹ mol⁻¹.

1.

Calculate ΔG⦵.

[1]
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2.

State whether the reaction is spontaneous under standard conditions at 350 K.

[1]
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Question 21
HL • Paper 2
Medium
Calculator

A reaction has ΔH⦵ = +95 kJ mol⁻¹ and ΔS⦵ = +250 J K⁻¹ mol⁻¹.

1.

Determine the temperature at which ΔG⦵ = 0.

[1]
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2.

State whether the reaction is spontaneous above or below this temperature.

[1]
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Question 22
HL • Paper 2
Medium
Calculator

A dissolving process is endothermic but occurs spontaneously at room temperature.

1.

State the sign of ΔH for the process.

[1]
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2.

Explain how the process can still be spontaneous.

[1]
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Question 23
HL • Paper 2
Medium
Calculator

For the reaction X(aq) ⇌ Y(aq), K = 25.0 at 310 K.

1.

Calculate ΔG⦵ in kJ mol⁻¹. Use R = 8.31 J K⁻¹ mol⁻¹.

[1]
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2.

State what the value suggests about the equilibrium mixture.

[1]
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Question 24
HL • Paper 2
Medium
Calculator

A straight-line plot of ΔG⦵ against temperature for a reaction has a positive vertical intercept and a negative gradient.

Straight-line relationship between standard Gibbs free energy change and temperature.
1.

State the sign of ΔH⦵.

[1]
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2.

State the sign of ΔS⦵.

[1]
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3.

Predict whether increasing temperature makes the reaction more or less spontaneous.

[1]
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Question 25
HL • Paper 2
Medium
Calculator

The combustion of a hydrocarbon is exothermic and spontaneous at 298 K.

1.

State the effect of heat released on the entropy of the surroundings.

[1]
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2.

Explain why ΔG can be negative even if the entropy of the chemical system decreases.

[1]
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Question 26
HL • Paper 1B
Medium
Non Calculator

The graph shows ΔG⦵ against temperature for reaction I.

Standard Gibbs energy change for reaction I as a function of temperature.
1.

Determine the temperature at which reaction I changes from non-spontaneous to spontaneous under standard conditions.

[1]
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2.

State the sign of ΔH⦵ for reaction I.

[1]
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3.

Explain how the sign of ΔS⦵ can be obtained from the graph.

[1]
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4.

Predict whether reaction I is spontaneous at temperatures above the intercept with the temperature axis.

[1]
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Question 27
HL • Paper 1B
Medium
Non Calculator

The table gives standard molar entropies for substances involved in the reaction:

CaCO₃

SubstanceS⦵ / J K⁻¹ mol⁻¹
CaCO₃(s)92.9
CaO(s)39.8
CO₂(g)213.7
1.

→ CaO

[1]
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2.
  • CO₂
[1]
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3.

Calculate ΔS⦵ for the reaction using the table.

[1]
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4.

Explain why the sign of ΔS⦵ is expected from the equation.

[1]
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5.

Suggest why the physical states must be included when using entropy data.

[1]
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Question 28
HL • Paper 1B
Medium
Non Calculator

The diagram shows a heating curve for a pure substance with labelled solid, liquid and gas regions.

A heating curve with temperature on the vertical axis and heat added on the horizontal axis. Label solid, melting plateau, liquid, boiling plateau and gas regions.
1.

Identify the region with the highest entropy.

[1]
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2.

State whether entropy increases or decreases during freezing.

[1]
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3.

Explain the entropy change during vaporization in terms of matter and energy dispersal.

[1]
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Question 29
HL • Paper 1A
Medium
Non Calculator

At 298 K, a reaction has ΔG⦵ = +5.71 kJ mol⁻¹. What is K? Use R = 8.31 J K⁻¹ mol⁻¹.

A.

10.0

B.

2.30

C.

0.100

D.

0.0100

Question 30
HL • Paper 1A
Medium
Non Calculator

For A(aq) ⇌ B(aq), ΔG⦵ = +8.0 kJ mol⁻¹ at 298 K. In a mixture where Q is very small, the forward reaction can be spontaneous because

A.

ΔG⦵ becomes negative at equilibrium

B.

K becomes equal to zero

C.

the entropy term is omitted outside standard conditions

D.

RT ln Q can be sufficiently negative

Question 31
HL • Paper 2
Medium
Calculator

For a reaction at 298 K, ΔG⦵ = −18.5 kJ mol⁻¹ and ΔS⦵ = +75.0 J K⁻¹ mol⁻¹.

1.

Rearrange the Gibbs equation to make ΔH⦵ the subject.

[1]
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2.

Calculate ΔH⦵.

[1]
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Question 32
HL • Paper 2
Medium
Calculator

At 298 K an electrochemical reaction transfers 3 mol of electrons per mole of reaction and has E⦵cell = +0.42 V. Use F = 9.65 × 10⁴ C mol⁻¹.

1.

Calculate ΔG⦵ in kJ mol⁻¹.

[1]
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2.

State whether the reaction is spontaneous as written.

[1]
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Question 33
HL • Paper 2
Medium
Calculator

For A

1.

⇌ B(g), ΔG⦵ = +4.00 kJ mol⁻¹ at 298 K. In a mixture, Q = 0.100. Use R = 8.31 J K⁻¹ mol⁻¹.

[1]
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2.

Calculate ΔG in kJ mol⁻¹.

[1]
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3.

Predict the direction in which the reaction will proceed.

[1]
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Question 34
HL • Paper 2
Medium
Calculator

For PCl₅

1.

⇌ PCl₃

[1]
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2.
  • Cl₂(g), Kc = 0.80 at a certain temperature. A mixture has [PCl₅] = 0.20 mol dm⁻³, [PCl₃] = 0.10 mol dm⁻³ and [Cl₂] = 0.40 mol dm⁻³.
[1]
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3.

Calculate Q.

[1]
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4.

State the direction in which the reaction will proceed to reach equilibrium.

[1]
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Question 35
HL • Paper 2
Medium
Calculator

For a reaction at 298 K, ΔG⦵ = +16.0 kJ mol⁻¹.

1.

Calculate K. Use R = 8.31 J K⁻¹ mol⁻¹.

[1]
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2.

Comment on the claim: “A positive ΔG⦵ means no products will form.”

[1]
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Question 36
HL • Paper 1B
Medium
Non Calculator

A graph shows ΔG⦵ for four reactions at 298 K, labelled A–D, with their ΔH⦵ and ΔS⦵ sign combinations indicated.

ReactionΔH° signΔS° signAs T increases, ΔG°
A+Decreases
B+Increases
C++Decreases
DIncreases
1.

Identify the reaction that is spontaneous at all temperatures.

[1]
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2.

Identify the reaction that is non-spontaneous at all temperatures.

[1]
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3.

For the reaction with ΔH⦵ > 0 and ΔS⦵ > 0, state whether it is favoured at high or low temperature.

[1]
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4.

Explain your answer to

[1]
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5.

using ΔG⦵ = ΔH⦵ − TΔS⦵.

[1]
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Question 37
HL • Paper 1B
Medium
Non Calculator

The graph shows ΔG against ln Q for a reaction at a fixed temperature.

Linear relationship between Gibbs free energy change and reaction quotient.
1.

State the relationship between the gradient of the graph and temperature.

[1]
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2.

Determine ΔG⦵ from the graph.

[1]
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3.

Identify the point on the graph corresponding to equilibrium.

[1]
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4.

Explain how the graph shows that ΔG becomes less negative as the reaction approaches equilibrium from a reactant-rich mixture.

[1]
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Question 38
HL • Paper 1B
Medium
Non Calculator

The table shows concentrations for three mixtures of the equilibrium:

H₂

Mixture[H₂] / mol dm⁻³[I₂] / mol dm⁻³[HI] / mol dm⁻³Kc
A0.04000.02000.20050.0
B0.03000.03000.15050.0
C0.05000.02000.30050.0
1.
  • I₂
[1]
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2.

⇌ 2HI

[1]
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3.

at the same temperature. The equilibrium constant Kc is given.

[1]
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4.

Write the expression for Qc.

[1]
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5.

Use the table to determine which mixture is at equilibrium.

[1]
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6.

For a mixture with Qc < Kc, state the sign of ΔG for the forward reaction.

[1]
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7.

Explain why pure solids, if present in an equilibrium expression, would be omitted from Q.

[1]
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Question 39
HL • Paper 1B
Medium
Non Calculator

The table gives ΔG⦵ values for three reactions at 298 K.

ReactionΔG⦵ / kJ mol⁻¹
1−8.6
2+0.4
3+14.2
1.

For reaction 1, calculate K using ΔG⦵ = −RT ln K.

[1]
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2.

Identify which reaction has the most product-favoured equilibrium.

[1]
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3.

Explain the relationship between the sign of ΔG⦵ and the magnitude of K.

[1]
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Question 40
HL • Paper 1B
Hard
Non Calculator

A student investigates a reaction and plots ΔG⦵ against temperature. The best-fit line and uncertainty range are shown.

Best-fit relationship between standard Gibbs free energy change and temperature, with uncertainty limits.
1.

Determine whether ΔH⦵ is endothermic or exothermic from the graph.

[1]
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2.

Determine whether ΔS⦵ is positive or negative from the graph.

[1]
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3.

Estimate the temperature at which the reaction becomes spontaneous.

[1]
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4.

Evaluate one limitation of using this straight-line extrapolation to predict spontaneity at much higher temperatures.

[1]
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Question 41
HL • Paper 1B
Hard
Non Calculator

A table gives ΔH⦵ and ΔS⦵ for four proposed industrial reactions.

ReactionΔH⦵ / kJ mol⁻¹ΔS⦵ / J K⁻¹ mol⁻¹
A−84+118
B−42−180
C+96+220
D+58−140
1.

Identify the reaction that is spontaneous at 298 K by calculating or comparing ΔG⦵ values.

[1]
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2.

Identify any reaction whose spontaneity changes with temperature.

[1]
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3.

For one reaction that changes spontaneity with temperature, determine whether increasing temperature favours products or reactants.

[1]
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4.

Explain why the conclusion is thermodynamic and does not predict reaction rate.

[1]
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Question 42
HL • Paper 2
Hard
Calculator

A reaction has ΔH⦵ = +110 kJ mol⁻¹ and ΔS⦵ = +220 J K⁻¹ mol⁻¹.

1.

Calculate the temperature at which ΔG⦵ = 0.

[1]
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2.

Discuss the spontaneity of the reaction below and above this temperature, and explain why an endothermic reaction can be spontaneous.

[1]
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Question 43
HL • Paper 2
Hard
Calculator

Two processes are considered:

I. NH₄NO₃

1.

→ NH₄⁺(aq) + NO₃⁻(aq)

II. 2NO₂

[1]
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2.

→ N₂O₄

[1]
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3.

Predict the sign of ΔS for each process.

[1]
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4.

Compare and contrast the entropy changes in the two processes in terms of dispersal of matter and energy, and discuss how entropy contributes to spontaneity.

[1]
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Question 44
HL • Paper 2
Hard
Calculator

Entropy values for substances in their standard states are absolute values, unlike standard enthalpies of formation.

1.

State the third-law prediction for a perfect crystal at 0 K and define a perfect crystal.

[1]
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2.

Explain how entropy data can be used to calculate standard entropy changes and why balanced coefficients and physical states are essential.

[1]
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Question 45
HL • Paper 1B
Hard
Non Calculator

The graph shows Gibbs energy of a reacting mixture as a function of reaction progress for a reversible reaction at constant temperature and pressure.

Gibbs energy of a reacting mixture at constant temperature and pressure as reaction progress changes.
1.

Identify the point corresponding to equilibrium.

[1]
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2.

State the sign of ΔG for the forward reaction at a point to the left of equilibrium.

[1]
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3.

State the sign of ΔG for the forward reaction at a point to the right of equilibrium.

[1]
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4.

Explain why ΔG⦵ for the reaction need not be zero even though ΔG is zero at equilibrium.

[1]
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Question 46
HL • Paper 2
Hard
Calculator

For the equilibrium

A

1.

⇌ B

[1]
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2.

ΔG⦵ = +6.50 kJ mol⁻¹ at 298 K.

[1]
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3.

Calculate K at 298 K. Use R = 8.31 J K⁻¹ mol⁻¹.

[1]
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4.

Evaluate how the direction of spontaneous change depends on the composition of the mixture, referring to Q, K and ΔG.

[1]
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Question 47
HL • Paper 2
Hard
Calculator

The reaction

C₂H₄

SpeciesS⦵ / J K⁻¹ mol⁻¹
C₂H₄(g)220
H₂(g)131
C₂H₆(g)230
1.
  • H₂
[1]
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2.

→ C₂H₆

[1]
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3.

has ΔH⦵ = −137 kJ mol⁻¹. Standard molar entropy data are provided: C₂H₄

[1]
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4.

= 220 J K⁻¹ mol⁻¹, H₂

[1]
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5.

= 131 J K⁻¹ mol⁻¹, C₂H₆

[1]
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6.

= 230 J K⁻¹ mol⁻¹.

[1]
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7.

Calculate ΔS⦵ for the reaction.

[1]
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8.

Evaluate the effect of increasing temperature on the spontaneity of the reaction under standard conditions.

[1]
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Question 48
HL • Paper 2
Hard
Calculator

A process has ΔH = −40 kJ mol⁻¹ and ΔSsystem = −80 J K⁻¹ mol⁻¹ at 298 K.

1.

Calculate ΔG at 298 K.

[1]
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2.

Discuss the relationship between ΔG, total entropy change, system entropy and surroundings entropy for this process.

[1]
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Question 49
HL • Paper 2
Hard
Calculator

For the reaction

2A

1.

⇌ B

[1]
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2.

at 350 K, ΔG⦵ = −9.50 kJ mol⁻¹. A mixture contains A and B such that Q = 18.0.

[1]
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3.

Calculate ΔG for the mixture. Use R = 8.31 J K⁻¹ mol⁻¹.

[1]
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4.

Evaluate whether the mixture is at equilibrium and predict how its composition will change.

[1]
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Question 50
HL • Paper 2
Hard
Calculator

Two reactions have the following thermodynamic data at 298 K.

Reaction X: ΔH⦵ = −60 kJ mol⁻¹, ΔS⦵ = −150 J K⁻¹ mol⁻¹

Reaction Y: ΔH⦵ = +60 kJ mol⁻¹, ΔS⦵ = +150 J K⁻¹ mol⁻¹

1.

Calculate ΔG⦵ for both reactions at 298 K.

[1]
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2.

Compare and contrast the temperature dependence of spontaneity for X and Y.

[1]
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R1.3 Energy from fuels