Clastify logo
Clastify logo
Subjects
Features
Review
HOT
Tutoring

S2.1 The ionic model

Practice exam-style IB Chemistry questions for The ionic model, aligned with the syllabus and grouped by topic.

Verified by Dennis M.
Verified by Dennis M.
Paper
Difficulty
Status
Level
Question 1
SL • Paper 1A
Easy
Calculator Permitted
SL • Paper 1A
Easy
Calculator Permitted

A neutral atom has 13 protons and the electron arrangement 2,8,3. What are the numbers of protons and electrons in the ion it commonly forms?

A.

13 protons and 16 electrons

B.

10 protons and 13 electrons

C.

13 protons and 10 electrons

D.

16 protons and 10 electrons

Question 2
SL • Paper 1A
Easy
Calculator Permitted
SL • Paper 1A
Easy
Calculator Permitted

An atom has the electron arrangement 2,8,7. What charge is predicted for its most common ion?

A.

7+7+

B.

22-

C.

1+1+

D.

11-

Question 3
SL • Paper 1A
Easy
Calculator Permitted
SL • Paper 1A
Easy
Calculator Permitted

What is an ionic bond?

A.

The attraction between a shared electron pair and two nuclei

B.

The repulsion between ions of equal charge in a lattice

C.

The electrostatic attraction between oppositely charged ions

D.

The attraction between positive ions and delocalized electrons

Question 4
SL • Paper 1A
Easy
Calculator Permitted
SL • Paper 1A
Easy
Calculator Permitted

The formula of aluminium sulfate is based on Al3+\text{Al}^{3+} and SO42\text{SO}_4^{2-} ions. What is the correct formula?

A.

Al2SO4\text{Al}_2\text{SO}_4

B.

AlSO4\text{AlSO}_4

C.

Al2(SO4)3\text{Al}_2(\text{SO}_4)_3

D.

Al(SO4)3\text{Al}(\text{SO}_4)_3

Question 5
SL • Paper 1A
Easy
Calculator Permitted
SL • Paper 1A
Easy
Calculator Permitted

What is the formula of barium hydrogencarbonate?

A.

BaHCO3\text{BaHCO}_3

B.

Ba2(HCO3)2\text{Ba}_2(\text{HCO}_3)_2

C.

Ba(HCO3)2\text{Ba}(\text{HCO}_3)_2

D.

Ba2HCO3\text{Ba}_2\text{HCO}_3

Question 6
SL • Paper 1A
Easy
Calculator Permitted
SL • Paper 1A
Easy
Calculator Permitted

Solid potassium bromide does not conduct electricity, but molten potassium bromide does. What is the best explanation?

A.

The ions become neutral atoms when the solid melts.

B.

Ions are fixed in the solid but mobile in the molten state.

C.

Electrons are delocalized only in the molten state.

D.

Covalent bonds form between ions in the molten state.

Question 7
HL • Paper 1A
Easy
Calculator Permitted
HL • Paper 1A
Easy
Calculator Permitted

An iron atom has the electron configuration [Ar]4s23d6[\text{Ar}]4s^23d^6. What is the electron configuration of Fe3+\text{Fe}^{3+}?

A.

[Ar]4s23d3[\text{Ar}]4s^23d^3

B.

[Ar]4s13d4[\text{Ar}]4s^13d^4

C.

[Ar]3d3[\text{Ar}]3d^3

D.

[Ar]3d5[\text{Ar}]3d^5

Question 8
HL • Paper 1A
Easy
Calculator Permitted
HL • Paper 1A
Easy
Calculator Permitted

For two acids HA\text{HA} and HB\text{HB}, Ka(HA)K_a(\text{HA}) is larger than Ka(HB)K_a(\text{HB}). What does this imply about their conjugate bases?

A.

A\text{A}^- is more stable than B\text{B}^- because dissociation of HA\text{HA} is more favourable.

B.

A\text{A}^- and B\text{B}^- must have the same stability because both are anions.

C.

A\text{A}^- is less stable than B\text{B}^- because dissociation of HA\text{HA} is more favourable.

D.

B\text{B}^- is more stable than A\text{A}^- because HB\text{HB} has the smaller KaK_a.

Question 9
SL • Paper 2
Easy
Calculator Permitted
SL • Paper 2
Easy
Calculator Permitted

A chlorine atom has the electron configuration 1s22s22p63s23p51s^{2}2s^{2}2p^{6}3s^{2}3p^{5}.

A

Deduce the charge of the ion most commonly formed by chlorine.

[1]
B

Explain how the ion in (a) is formed, referring to its electron configuration.

[2]
Question 10
HL • Paper 1A
Medium
Calculator Permitted
HL • Paper 1A
Medium
Calculator Permitted

The successive ionization energies of a transition element increase gradually for the first two electrons removed, followed by a much larger increase for the third electron. What common ion charge is best supported by this pattern?

A.

3+3+

B.

1+1+

C.

2+2+

D.

4+4+

Question 11
HL • Paper 1A
Medium
Calculator Permitted
HL • Paper 1A
Medium
Calculator Permitted

What best explains why first-row transition elements often form cations with different charges?

A.

Their 4s4s and 3d3d subshells are close in energy.

B.

Their proton number changes during ionic bonding.

C.

Their outer shell must always reach a noble gas configuration.

D.

Their ions usually gain electrons into the 4p4p subshell.

Question 12
HL • Paper 1A
Medium
Calculator Permitted
HL • Paper 1A
Medium
Calculator Permitted

A Lewis representation of sulfate with two S=O\text{S}=\text{O} bonds and two SO\text{S}-\text{O} bonds is often preferred to a representation with four single SO\text{S}-\text{O} bonds. What is the formal-charge basis for this preference?

A.

It removes the need for any oxygen lone pairs.

B.

It makes the total charge on sulfate equal to zero.

C.

It places all negative formal charge on sulfur.

D.

It reduces the number and magnitude of non-zero formal charges.

Question 13
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

Ionic compounds are represented by formulas that show the simplest whole-number ratio of ions.

A

Deduce the formula of aluminium nitrate.

[2]
B

Deduce the name of Fe2O3Fe_2O_3.

[2]
Question 14
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

Solid sodium chloride is commonly represented by the formula NaClNaCl.

A

Outline why NaClNaCl does not represent a separate molecule in the solid state.

[2]
B

State what is meant by ionic bonding being non-directional.

[1]
Question 15
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

A student tests the electrical conductivity of potassium bromide in two physical states.

A simple black-and-white apparatus diagram showing two conductivity circuits side by side. One beaker contains solid crystals labelled potassium bromide with fixed ions indicated in a regular lattice. The other beaker contains molten potassium bromide with separated ions shown moving randomly. Each circuit includes two inert electrodes, wires, a power supply and a conductivity indicator. No results are shown on the indicators.
A

Predict the relative electrical conductivity of solid and molten potassium bromide.

[1]
B

Explain the prediction in (a) using the ionic model.

[2]
Question 16
SL • Paper 1B
Medium
Calculator Permitted
SL • Paper 1B
Medium
Calculator Permitted

A spreadsheet was used to compare atoms and their most common monatomic ions for four main-group elements.

Species

Protons / count

Electrons / count

Sodium atom

11

11

Sodium ion

11

10

Magnesium atom

12

12

Magnesium ion

12

10

Oxygen atom

8

8

Oxide ion

8

10

Chlorine atom

17

17

Chloride ion

17

18

A

Identify the two species in the table that are anions.

[1]
B

Deduce the charge of the magnesium ion using the electron and proton data.

[1]
C

Explain why the formation of the chloride ion is described as reduction.

[2]
Question 17
SL • Paper 1B
Medium
Calculator Permitted
SL • Paper 1B
Medium
Calculator Permitted

A student prepared a table of selected ions to practise writing formulas of ionic compounds.

Ion

Formula

Charge

aluminium ion

Al3+\text{Al}^{3+}

3+3+

nitrate ion

NO3\text{NO}_3^-

11-

barium ion

Ba2+\text{Ba}^{2+}

2+2+

phosphate ion

PO43\text{PO}_4^{3-}

33-

ammonium ion

NH4+\text{NH}_4^+

1+1+

carbonate ion

CO32\text{CO}_3^{2-}

22-

A

Deduce the formula of aluminium nitrate.

[1]
B

Deduce the formula of barium phosphate.

[1]
C

Explain why brackets are needed in the formula of ammonium carbonate.

[2]
Question 18
HL • Paper 1A
Medium
Calculator Permitted
HL • Paper 1A
Medium
Calculator Permitted

In a Lewis representation of SO42\text{SO}_4^{2-} with four single SO\text{S}-\text{O} bonds, what formal charge is assigned to the sulfur atom?

A.

4+4+

B.

00

C.

2+2+

D.

22-

Question 19
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

Lattice enthalpy can be used as a measure of the strength of bonding in ionic compounds.

A

State whether NaFNaF or KFKF has the larger lattice enthalpy of dissociation.

[1]
B

Explain the answer to (a).

[2]
C

State why MgOMgO has a much larger lattice enthalpy than NaFNaF.

[1]
Question 20
SL • Paper 2
Medium
Calculator Permitted
SL • Paper 2
Medium
Calculator Permitted

When aqueous silver nitrate is mixed with aqueous sodium chloride, a white precipitate forms.

A

Explain how water molecules can separate ions from an ionic lattice when a salt dissolves.

[2]
B

Write the ionic equation for the formation of the precipitate.

[1]
C

State what the formation of the precipitate indicates about silver chloride.

[1]
Question 21
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Iron is a first-row transition element. The electron configuration of an iron atom may be written as [Ar]4s23d6[Ar]4s^{2}3d^{6}.

A

Write the electron configuration of Fe2+Fe^{2+}.

[1]
B

Write the electron configuration of Fe3+Fe^{3+}.

[1]
C

Explain why transition elements such as iron can form cations with different charges.

[2]
Question 22
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Nitric acid has a much larger acid dissociation constant, KaK_a, than carbonic acid for its first dissociation. The conjugate bases formed are nitrate, NO3NO_3^-, and hydrogencarbonate, HCO3HCO_3^-.

A

State which conjugate base is more stable.

[1]
B

Explain the relationship between conjugate base stability and KaK_a of the conjugate acid.

[2]
Question 23
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Hydrogensulfate, HSO4HSO_4^-, and dihydrogenphosphate, H2PO4H_2PO_4^-, can each act as acids to form polyatomic anions. The KaK_a value for HSO4HSO_4^- is larger than that for H2PO4H_2PO_4^-.

A

Identify the conjugate bases formed when HSO4HSO_4^- and H2PO4H_2PO_4^- each donate one proton.

[2]
B

Discuss what the larger KaK_a value for HSO4HSO_4^- suggests about the relative stability of the two conjugate bases.

[2]
Question 24
SL • Paper 1B
Medium
Calculator Permitted
SL • Paper 1B
Medium
Calculator Permitted

Electronegativity values were used to estimate the ionic character of several binary compounds. A value of Δχ greater than about 1.8 was taken as a guideline for mainly ionic bonding.

Compound

Element 1

χ1\chi_1

Element 2

χ2\chi_2

AlCl3

Al

1.61

Cl

3.16

MgCl2

Mg

1.31

Cl

3.16

MgO

Mg

1.31

O

3.44

SiO2

Si

1.90

O

3.44

A

Calculate Δχ for magnesium oxide from the values in the table.

[1]
B

Identify the compound in the table with the greatest ionic character.

[1]
C

Explain why electronegativity difference is a model rather than a complete classification of bonding.

[3]
Question 25
SL • Paper 1B
Medium
Calculator Permitted
SL • Paper 1B
Medium
Calculator Permitted

The electrical conductivity of an ionic compound was measured as a solid, as a molten liquid and as an aqueous solution.

Conductivity of four samples.
A

Describe the change in conductivity when sodium chloride is melted.

[1]
B

Explain the difference in conductivity between solid sodium chloride and molten sodium chloride.

[2]
C

Suggest why pure water has a much lower conductivity than aqueous sodium chloride.

[1]
Question 26
SL • Paper 1B
Medium
Calculator Permitted
SL • Paper 1B
Medium
Calculator Permitted

A student mixed pairs of aqueous ionic solutions and recorded whether a precipitate formed.

cation / anion

Cl(aq)\text{Cl}^-(\text{aq})

NO3(aq)\text{NO}_3^-(\text{aq})

CO32(aq)\text{CO}_3^{2-}(\text{aq})

SO42(aq)\text{SO}_4^{2-}(\text{aq})

Ag+(aq)\text{Ag}^+(\text{aq})

precipitate

no precipitate

precipitate

precipitate

Ca2+(aq)\text{Ca}^{2+}(\text{aq})

no precipitate

no precipitate

precipitate

precipitate

Na+(aq)\text{Na}^+(\text{aq})

no precipitate

no precipitate

no precipitate

no precipitate

K+(aq)\text{K}^+(\text{aq})

no precipitate

no precipitate

no precipitate

no precipitate

A

Identify one pair of ions from the grid that forms a precipitate.

[1]
B

Deduce the formula and name of the precipitate formed when Ca2+(aq)Ca^{2+}(aq) is mixed with CO32(aq)CO_3^{2-}(aq).

[2]
C

Explain why the formation of a precipitate is evidence for an ionic compound with low solubility in water.

[2]
Question 27
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The table shows successive ionization energies for a first-row transition element.

Ionization number

Ionization energy / kJ mol1^{-1}

1st

650

2nd

1410

3rd

2830

4th

4510

5th

6300

6th

12360

A

State what a much larger jump in successive ionization energy indicates.

[1]
B

Explain how successive ionization energy data support variable oxidation states in transition elements.

[2]
Question 28
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

Two possible Lewis representations of the sulfate ion are shown.

Two labelled Lewis structures for the sulfate ion placed side by side. Structure A shows central sulfur bonded by four single bonds to four oxygen atoms, with lone pairs shown on oxygen atoms. Structure B shows central sulfur bonded to four oxygen atoms, with three sulfur-oxygen double bonds and one sulfur-oxygen single bond, with lone pairs shown. The overall ion charge is shown outside brackets for each structure. No formal charges are printed on atoms.
A

Determine the formal charge on sulfur and on each oxygen atom in Structure A.

[2]
B

Identify the preferred representation and justify the choice using formal charge.

[2]
Question 29
HL • Paper 2
Medium
Calculator Permitted
HL • Paper 2
Medium
Calculator Permitted

The melting points of three period 3 chlorides are compared.

Bar chart of the melting points of three period 3 chlorides.
A

Describe the pattern shown by the melting point data.

[1]
B

Explain why the melting point of aluminium chloride is not predicted well by a purely ionic model.

[3]
Question 30
SL • Paper 1B
Hard
Calculator Permitted
SL • Paper 1B
Hard
Calculator Permitted

Lattice enthalpies and cation radii were compared for the group 1 chlorides.

Scatter plot of lattice enthalpy against cation radius for selected group 1 chlorides.
A

Describe the relationship shown by the graph.

[1]
B

Explain the trend using the ionic model.

[2]
C

Predict, with a reason, whether rubidium chloride or lithium chloride has the higher melting point.

[2]
Question 31
HL • Paper 1B
Hard
Calculator Permitted
HL • Paper 1B
Hard
Calculator Permitted

Successive ionization energies were measured for a first-row transition element, X. The element forms common ions X2+X^{2+} and X3+X^{3+}.

Successive ionization energies of element X.
A

Describe the pattern in the first three ionization energies shown on the graph.

[1]
B

Explain why the gradual increase supports the formation of more than one cation by this transition element.

[2]
C

Explain why the 4s4s electrons are removed before the 3d3d electrons when a first-row transition metal forms a cation.

[2]
Question 32
HL • Paper 1B
Hard
Calculator Permitted
HL • Paper 1B
Hard
Calculator Permitted

The electron configurations of a transition element atom and two of its ions were obtained from spectroscopic data.

Species

Proton number

Electron configuration

Neutral atom

26

[Ar]3d64s2[\text{Ar}]3d^{6}4s^{2}

Ion 1

26

[Ar]3d6[\text{Ar}]3d^{6}

Ion 2

26

[Ar]3d5[\text{Ar}]3d^{5}

A

Identify the element from the proton number and electron configuration.

[1]
B

Deduce the charges of the two ions shown in the table.

[2]
C

Explain why this element is classified as a transition element.

[2]
Question 33
HL • Paper 1B
Hard
Calculator Permitted
HL • Paper 1B
Hard
Calculator Permitted

Polyatomic anions can be considered as conjugate bases of acids. Data for several acids and their conjugate bases are shown.

Acid

Conjugate base

pKa

Nitric acid

Nitrate ion

-1.4

Phosphoric acid

Dihydrogen phosphate ion

2.15

Ethanoic acid

Ethanoate ion

4.76

Carbonic acid

Hydrogencarbonate ion

6.35

A

Identify the conjugate base of nitric acid from the table.

[1]
B

Using the data, state which conjugate base is most stable.

[1]
C

Explain the relationship between conjugate base stability and the value of KaK_a for the conjugate acid.

[3]
Question 34
SL • Paper 2
Hard
Calculator Permitted
SL • Paper 2
Hard
Calculator Permitted

Magnesium reacts with nitrogen to form solid magnesium nitride. The reaction can be interpreted using electron transfer and the ionic model.

A
I.

Deduce the ion formed by a magnesium atom and give its electron configuration.

[2]
II.

Deduce the ion formed by a nitrogen atom and give its electron configuration.

[2]
B
I.

Deduce the empirical formula of magnesium nitride and write the balanced equation for its formation from the elements.

[2]
II.

Explain why the formation of magnesium nitride from its elements is a redox reaction.

[2]
Question 35
SL • Paper 2
Hard
Calculator Permitted
SL • Paper 2
Hard
Calculator Permitted

Polyatomic ions are present in many fertilizer salts. Ammonium phosphate and calcium nitrate both contain ions that must be treated as charged units when formulas are written.

A
I.

Deduce the formula of ammonium phosphate from NH4+NH_4^+ and PO43PO_4^{3-}, explaining the charge balance.

[2]
II.

Deduce the formula of calcium nitrate from Ca2+Ca^{2+} and NO3NO_3^-, explaining why brackets are used.

[2]
B

Compare the bonding within and between the ions in ammonium phosphate.

[2]
C

Explain why solid ammonium phosphate does not conduct electricity but an aqueous solution of ammonium phosphate does.

[2]
Question 36
SL • Paper 2
Hard
Calculator Permitted
SL • Paper 2
Hard
Calculator Permitted

A student compares sodium chloride and silver chloride using solubility and conductivity tests. The observations are shown in Table 2.

Observation

Sodium chloride

Silver chloride

Appearance of solid

white crystalline solid

white precipitate

Conductivity of solid / mS cm1^{-1}

0.0

0.0

After water is added

dissolves completely; clear colourless solution forms

only a small amount dissolves; cloudy suspension remains

Conductivity after water is added / mS cm1^{-1}

12.0

0.2

A
I.

Deduce one observation that supports the conclusion that sodium chloride is not molecular.

[1]
II.

Explain why neither solid sodium chloride nor solid silver chloride conducts electricity.

[2]
B

Explain why an aqueous sodium chloride solution conducts electricity but a suspension containing solid silver chloride has much lower conductivity.

[2]
C

Evaluate the statement: "All ionic compounds dissolve in water."

[2]
Question 37
SL • Paper 2
Hard
Calculator Permitted
SL • Paper 2
Hard
Calculator Permitted

The ions O2O^{2-}, FF^-, Na+Na^+ and Mg2+Mg^{2+} are isoelectronic with neon.

A
I.

State the electron configuration common to these four ions.

[1]
II.

Explain why isoelectronic species are not the same chemical species.

[2]
B

Compare the ionic radii of this isoelectronic series, in terms of nuclear charge.

[2]
C

Use the ionic model to explain why magnesium oxide has a higher lattice enthalpy than sodium fluoride.

[2]
Question 38
HL • Paper 1B
Hard
Calculator Permitted
HL • Paper 1B
Hard
Calculator Permitted

Two possible Lewis representations of the sulfate ion were analysed using formal charge.

An annotated stimulus showing two Lewis representations of $SO_4^{2-}$ with formal charges indicated.
A

State the total charge on the sulfate ion in each representation.

[1]
B

Compare the distribution of formal charges in the two representations.

[2]
C

Evaluate which representation is preferred by the formal-charge model.

[2]
Question 39
HL • Paper 1B
Hard
Calculator Permitted
HL • Paper 1B
Hard
Calculator Permitted

Melting points and bonding indicators were compared for period 3 metal chlorides.

Chloride

Cation charge / ee

Cation radius / pm

Δ\DeltaEN (Pauling)

Melting point / C^\circ\text{C}

NaClNaCl

+1

102

2.2

801

MgCl2MgCl_2

+2

72

1.8

714

AlCl3AlCl_3

+3

54

1.5

192

A

Describe the trend in melting point from NaClNaCl to AlCl3AlCl_3 shown by the data.

[1]
B

Explain why charge alone does not account for the melting point of AlCl3AlCl_3 in the data.

[2]
C

Discuss how lattice enthalpy and the bonding continuum together explain the data.

[2]
Question 40
HL • Paper 1B
Hard
Calculator Permitted
HL • Paper 1B
Hard
Calculator Permitted

Successive ionization energy data for calcium and a first-row transition element were plotted on the same axes.

Successive ionization energies for two elements.
A

Identify which curve is calcium.

[1]
B

Explain the large jump for calcium after removal of two electrons.

[2]
C

Evaluate how the data support the idea that transition elements can form ions with different charges.

[2]
Question 41
SL • Paper 2
Hard
Calculator Permitted
SL • Paper 2
Hard
Calculator Permitted

Lattice enthalpy data for some ionic compounds are shown in Table 1.

Compound

Lattice enthalpy / kJ mol1^{-1}

LiCl

853

NaCl

787

KCl

715

LiF

1036

MgO

3795

A
I.

Using the data, compare the lattice enthalpies of the group 1 chlorides and explain the trend.

[2]
II.

Explain why the group 2 oxide in the table has a much larger lattice enthalpy than the group 1 fluoride.

[2]
B

Predict and explain how the difference in lattice enthalpy between lithium chloride and potassium chloride affects their melting points and volatility.

[2]
C

Explain why molten lithium chloride conducts electricity whereas solid lithium chloride does not.

[2]
Question 42
SL • Paper 2
Hard
Calculator Permitted
SL • Paper 2
Hard
Calculator Permitted

Melting point and electrical conductivity data for three period 3 chlorides are shown in Table 3.

Chloride

Melting point / C^\circ\text{C}

Electrical conductivity when molten / S m1S\ m^{-1}

Volatility / relative

NaCl

801

250

low

MgCl_2

714

200

low

AlCl_3

190

1

high

A
I.

Identify the chloride least well described by a simple ionic lattice model.

[1]
II.

Explain the evidence from the data for your answer to (a)(i).

[2]
B

Compare the expected lattice strength of sodium chloride and magnesium chloride using ionic charge and ionic radius.

[2]
C

Discuss the limitations of classifying bonding as purely ionic or purely covalent using these chlorides as examples.

[3]
Question 43
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Iron forms both Fe2+Fe^{2+} and Fe3+Fe^{3+} ions. A graph compares successive ionization energies for iron with those for sodium.

Successive ionization energies for sodium and iron.
A
I.

Iron has the electron configuration [Ar]4s23d6[Ar]4s^2 3d^6. Deduce the electron configurations of Fe2+Fe^{2+} and Fe3+Fe^{3+}.

[2]
II.

Explain why the 4s4s electrons are removed before the 3d3d electrons when iron forms cations.

[1]
B

Compare the ionization energy patterns to explain why iron can form ions with different charges whereas sodium mainly forms Na+Na^+.

[3]
C

Deduce the formula of iron(III) sulfate and explain the use of brackets in the formula.

[2]
Question 44
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Polyatomic anions are conjugate bases of acids. Table 4 gives acid dissociation constants for selected conjugate acids.

Conjugate acid

Conjugate base

KaK_a

HSO4\text{HSO}_4^-

SO42\text{SO}_4^{2-}

1.2×1021.2 \times 10^{-2}

HNO3\text{HNO}_3

NO3\text{NO}_3^-

2.0×1012.0 \times 10^{1}

H2CO3\text{H}_2\text{CO}_3

HCO3\text{HCO}_3^-

4.3×1074.3 \times 10^{-7}

A
I.

Use the KaK_a data to rank the conjugate bases NO3NO_3^-, HCO3HCO_3^- and SO42SO_4^{2-} in order of increasing stability.

[2]
II.

Explain why a larger KaK_a value indicates a more stable conjugate base.

[2]
B

Deduce the formulas of magnesium hydrogencarbonate and ammonium sulfate.

[2]
C

Compare the bonding in ammonium sulfate with the bonding within the sulfate ion.

[2]
Question 45
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Cobalt forms more than one chloride, including CoCl2CoCl_2 and CoCl3CoCl_3. Cobalt atoms have the electron configuration [Ar]4s23d7[Ar]4s^2 3d^7. Successive ionization energy data for cobalt are shown.

Successive ionization energies of cobalt.
A
I.

Deduce the oxidation state of cobalt in each chloride and give the systematic name of each compound.

[2]
II.

Deduce the electron configurations of Co2+Co^{2+} and Co3+Co^{3+}.

[2]
B

Use the successive ionization energy pattern to explain why cobalt can form both Co2+Co^{2+} and Co3+Co^{3+} ions.

[2]
C

Discuss why the charges of transition metal ions are less easily predicted from group number than the charges of group 1 and group 2 ions.

[2]
Question 46
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Barium ions form low-solubility salts with some polyatomic anions. Solutions of barium nitrate are mixed separately with sodium sulfate and sodium carbonate. Acid dissociation data for the conjugate acids of sulfate and carbonate ions are also provided.

Mixture

Anion present

Conjugate acid

K_a at 25C25^\circ\text{C}

Ba(NO3)2\text{Ba(NO}_3)_2(aq) + Na2SO4\text{Na}_2\text{SO}_4(aq)

SO42\text{SO}_4^{2-}(aq)

HSO4\text{HSO}_4^-(aq)

1.2×1021.2 \times 10^{-2}

Ba(NO3)2\text{Ba(NO}_3)_2(aq) + Na2CO3\text{Na}_2\text{CO}_3(aq)

CO32\text{CO}_3^{2-}(aq)

HCO3\text{HCO}_3^-(aq)

4.7×10114.7 \times 10^{-11}

A
I.

Deduce the net ionic equations for the formation of the barium sulfate and barium carbonate precipitates.

[2]
II.

Use the KaK_a data to compare the stability of SO42SO_4^{2-} and CO32CO_3^{2-} as conjugate bases.

[2]
B

Discuss why both precipitates can have low solubility even if the anions differ in conjugate-base stability.

[2]
C

Evaluate how the electrical conductivity of the mixtures changes after precipitation occurs.

[2]
Question 47
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

The sulfate ion is present in many ionic compounds. Two possible Lewis representations of SO42SO_4^{2-} are shown, with no formal charges displayed.

Two Lewis-style representations of the sulfate ion labelled A and B. In both, sulfur is central with four oxygen atoms arranged tetrahedrally around it. Representation A shows four single $S-O$ bonds. Representation B shows three $S=O$ double bonds and one $S-O$ single bond. Lone pairs are shown on oxygen atoms, but formal charge labels are absent.
A
I.

Calculate the formal charges on sulfur and on each oxygen atom in representation A.

[2]
II.

Calculate the formal charges on sulfur, on a double-bonded oxygen atom and on a single-bonded oxygen atom in representation B.

[2]
B

Evaluate which representation is preferred using formal charge arguments.

[2]
C

Deduce the formula of aluminium sulfate and identify the bonding between aluminium ions and sulfate ions and within the sulfate ion.

[2]
Question 48
HL • Paper 2
Hard
Calculator Permitted
HL • Paper 2
Hard
Calculator Permitted

Sulfate salts contain the polyatomic ion SO42SO_4^{2-}. Table 5 gives cation radius and lattice enthalpy data for selected sulfate salts.

Salt

Cation radius / pm

Lattice enthalpy / kJ mol1^{-1}

Sodium sulfate

102

2510

Magnesium sulfate

72

2890

Aluminium sulfate

53

13800

A
I.

Use charge balance to deduce the formulas of magnesium sulfate and aluminium sulfate.

[2]
II.

Using the data, compare the charge density of Mg2+Mg^{2+} and Na+Na^+ and relate this to their lattice enthalpies.

[2]
B

Explain why cation charge and radius affect lattice enthalpy in sulfate salts.

[2]
C

Evaluate whether formal charge considerations in the sulfate ion alone are sufficient to predict the melting points of sulfate salts.

[2]

S1.5 Ideal gases

S2.2 The covalent model