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S1.2 The atom

Practice exam-style IB Chemistry questions for The atom, aligned with the syllabus and grouped by topic.

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Question 1
SL • Paper 1A
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SL • Paper 1A
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A subatomic particle has relative charge −1-1, negligible relative mass and occupies the space outside the nucleus. What is the particle?

A.

Electron

B.

Proton

C.

Nucleon

D.

Neutron

Question 2
SL • Paper 1A
Easy
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SL • Paper 1A
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In Rutherford's gold foil experiment, most alpha particles passed through the foil without deflection. What does this observation support?

A.

Atoms are mostly empty space.

B.

Electrons are located in the nucleus.

C.

Protons are spread throughout the atom.

D.

The nucleus has a negative charge.

Question 3
SL • Paper 1A
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SL • Paper 1A
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The nuclear symbol for an ion is 2656Fe3+{}^{56}_{26}\text{Fe}^{3+}. What are the numbers of protons, neutrons and electrons in this ion?

A.

26 protons, 30 neutrons, 29 electrons

B.

30 protons, 26 neutrons, 23 electrons

C.

56 protons, 26 neutrons, 53 electrons

D.

26 protons, 30 neutrons, 23 electrons

Question 4
SL • Paper 1A
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SL • Paper 1A
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An atom has a diameter of approximately 1.0×10−10 m1.0 \times 10^{-10}\ \text{m} and its nucleus has a diameter of approximately 1.0×10−15 m1.0 \times 10^{-15}\ \text{m}. The diameter of the atom is how many times greater than the diameter of the nucleus?

A.

1.0×1051.0 \times 10^5

B.

1.0×10251.0 \times 10^{25}

C.

1.0×10−51.0 \times 10^{-5}

D.

1.0×10−251.0 \times 10^{-25}

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Question 5
SL • Paper 1A
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SL • Paper 1A
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Which pair is best described as isotopes of the same element?

A.

1737X{}^{37}_{17}X and 1837Y{}^{37}_{18}Y

B.

1736X{}^{36}_{17}X and 1836Y{}^{36}_{18}Y

C.

1735X{}^{35}_{17}X and 1835Y{}^{35}_{18}Y

D.

1735X{}^{35}_{17}X and 1737X{}^{37}_{17}X

Question 6
HL • Paper 1A
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HL • Paper 1A
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A mass spectrum of an element plots relative abundance on the vertical axis. What is plotted on the horizontal axis?

A.

Mass-to-charge ratio, m/zm/z

B.

Percentage abundance, pp

C.

Atomic number, ZZ

D.

Neutron number, NN

Question 7
SL • Paper 2
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SL • Paper 2
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A selenium ion contains 34 protons, 45 neutrons and 36 electrons.

A

the mass number of this ion.

[1]
B

Write the nuclear symbol for this ion.

[2]
C

which subatomic particle determines the identity of the element.

[1]
Question 8
SL • Paper 1A
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SL • Paper 1A
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An element has two naturally occurring isotopes with mass numbers 63 and 65. Their percentage abundances are 69.2%69.2\% and 30.8%30.8\%, respectively. What is the relative atomic mass of the element, using these mass numbers?

A.

64.0

B.

64.4

C.

63.6

D.

65.0

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Question 9
HL • Paper 1A
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HL • Paper 1A
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The mass spectrum of an element shows two singly charged isotope peaks at m/z=69m/z = 69 and m/z=71m/z = 71 with relative abundances 60.1%60.1\% and 39.9%39.9\%, respectively. What is the relative atomic mass of the element?

A.

71.00

B.

70.00

C.

70.20

D.

69.80

Question 10
HL • Paper 1A
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HL • Paper 1A
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A doubly charged isotope ion produces a peak at m/z=32m/z = 32 in a mass spectrum. What is the relative mass of the ion?

A.

16

B.

32

C.

34

D.

64

Question 11
HL • Paper 1A
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HL • Paper 1A
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The mass spectrum of an element has two singly charged isotope peaks at m/z=35m/z = 35 and m/z=37m/z = 37. The relative intensities are in the ratio 3:13:1, respectively. What conclusion follows from the spectrum?

A.

The isotope with mass 37 is about three times more abundant than the isotope with mass 35.

B.

The element has a relative atomic mass of exactly 36.0.

C.

The isotope with mass 35 is about three times more abundant than the isotope with mass 37.

D.

The two isotopes have equal natural abundance.

Question 12
SL • Paper 2
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SL • Paper 2
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In an alpha-particle scattering experiment, alpha particles were directed at a thin metal foil. Most alpha particles passed straight through the foil, but a very small proportion were deflected through angles greater than 90∘90^\circ.

A

what is implied by most alpha particles passing straight through the foil.

[1]
B

what is implied by a very small proportion of alpha particles being deflected through angles greater than 90∘90^\circ.

[2]

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Question 13
SL • Paper 2
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SL • Paper 2
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A particular atom has a diameter of 2.0×10−10 m2.0 \times 10^{-10}\ \text{m}. Its nucleus has a diameter of 2.0×10−15 m2.0 \times 10^{-15}\ \text{m}.

A

the ratio of the diameter of the atom to the diameter of the nucleus.

[1]
B

why a diagram showing a visible nucleus inside an atom is not to scale.

[1]
C

where most of the mass of an atom is found.

[1]
Question 14
SL • Paper 2
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SL • Paper 2
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Two neutral atoms of copper are represented by 2963Cu{}^{63}_{29}\text{Cu} and 2965Cu{}^{65}_{29}\text{Cu}.

A

why these atoms are isotopes of copper.

[1]
B

the number of neutrons in each atom.

[1]
C

why these isotopes have very similar chemical properties but may have slightly different physical properties.

[2]
Question 15
SL • Paper 2
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SL • Paper 2
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Naturally occurring element Y contains two isotopes. The isotope with mass number 10 has an abundance of 20.0%20.0\% and the isotope with mass number 11 has an abundance of 80.0%80.0\%.

A

the relative atomic mass, ArA_r, of element Y using these data.

[2]
B

why the relative atomic mass is not a whole number.

[1]
Question 16
HL • Paper 2
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HL • Paper 2
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The mass spectrum of a sample of magnesium is shown. Assume all ions shown have a charge number of +1+1.

A

why the m/zm/z values correspond to the mass numbers of the magnesium isotopes.

[1]
B

The peaks occur at m/zm/z values 24, 25 and 26 with relative abundances 78.6%78.6\%, 10.1%10.1\% and 11.3%11.3\%, respectively. the relative atomic mass of magnesium.

[2]
C

Identify the most abundant isotope in the sample.

[1]

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Question 17
HL • Paper 2
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HL • Paper 2
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The mass spectrum of bromine contains two main peaks. Assume the ions are singly charged.

A

what is represented by the height or area of each peak in an elemental mass spectrum.

[1]
B

The two peaks are at m/z=79m/z = 79 and m/z=81m/z = 81, with relative abundances 50.5%50.5\% and 49.5%49.5\%, respectively. the relative atomic mass of bromine.

[2]
C

what the two similar peak heights indicate about naturally occurring bromine.

[1]
Question 18
SL • Paper 1B
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SL • Paper 1B
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A simulation of Rutherford's alpha-particle scattering experiment was carried out using a very thin metal foil. The outcomes for a large number of alpha particles are shown.

Outcome

Number of alpha particles

Percentage / %

Pass straight through

9700

97.0

Small-angle deflection

250

2.5

Large-angle deflection

40

0.4

Backward scattering

10

0.1

Total

10000

100.0

A

the most common outcome for the alpha particles.

[1]
B

how the data support the nuclear model of the atom.

[2]
C

why increasing the foil thickness would increase the number of deflected alpha particles.

[1]
Question 19
SL • Paper 1B
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SL • Paper 1B
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The table shows nuclear symbols for some atoms and ions.

Item

Given data

1

2965Cu2+^{65}_{29}\text{Cu}^{2+}

2

17 protons, 20 neutrons, 18 electrons

A

the number of protons, neutrons and electrons in 2965Cu2+{}^{65}_{29}\text{Cu}^{2+}.

[2]
B

the nuclear symbol for the species with 17 protons, 20 neutrons and 18 electrons.

[2]
Question 20
SL • Paper 1B
Medium
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SL • Paper 1B
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A student prepared a scale drawing of an atom and its nucleus. The table compares the real diameters with the diameters used in the drawing.

Object

Real diameter / m

Diameter in drawing / mm

Atom

2.0×10−102.0 \times 10^{-10}

100

Nucleus

2.0×10−152.0 \times 10^{-15}

1

A

Convert the atomic diameter of 2.0×10−10 m2.0\times 10^{-10}\ \text{m} into picometres.

[1]
B

the ratio of the atomic diameter to the nuclear diameter, using 2.0×10−15 m2.0\times 10^{-15}\ \text{m} for the nuclear diameter.

[1]
C

why the student's drawing is not to scale and what this implies about atomic structure.

[2]

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Question 21
HL • Paper 1A
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HL • Paper 1A
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A mass spectrum has peaks at m/z=203m/z = 203 and m/z=205m/z = 205 with relative intensities 10.0 and 9.0, respectively. The ions are singly charged. What is the relative atomic mass calculated from these data?

A.

203.00

B.

203.95

C.

204.00

D.

204.90

Question 22
HL • Paper 1A
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HL • Paper 1A
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A student calculates a relative atomic mass from a printed mass spectrum and obtains a value slightly different from the data booklet value. The calculation method is correct. What is the most likely explanation?

A.

The operational details of the mass spectrometer must be included in the calculation.

B.

Peak heights were estimated from the graph or rounded isotope masses were used.

C.

Mass spectra cannot be used to determine relative atomic masses.

D.

The vertical axis gives atomic number rather than abundance.

Question 23
SL • Paper 2
Medium
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SL • Paper 2
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Element Q has two naturally occurring isotopes with mass numbers 69 and 71. Its relative atomic mass is 69.72.

A

Let xx be the percentage abundance of the isotope with mass number 69. Write an expression for the relative atomic mass in terms of xx.

[1]
B

the percentage abundance of each isotope.

[2]
C

which isotope is more abundant and justify your answer.

[1]
Question 24
HL • Paper 2
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HL • Paper 2
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A mass spectrum of an unknown element contains two isotope peaks. The data booklet gives ArA_r values of 35.45 for chlorine, 39.95 for argon and 32.06 for sulfur.

A

The peaks are at m/z=35m/z = 35 and m/z=37m/z = 37 with relative abundances 75.8%75.8\% and 24.2%24.2\%, respectively. the relative atomic mass of the unknown element.

[2]
B

Identify the unknown element using the data booklet values given.

[1]
C

why the relative atomic mass is closer to 35 than to 37.

[1]

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Question 25
HL • Paper 2
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HL • Paper 2
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A mass spectrum of silicon gives three peaks with intensities in arbitrary units rather than percentages. The peaks at m/z=28m/z = 28, 29 and 30 have intensities 100.0, 5.1 and 3.4, respectively. Assume all ions are singly charged.

A

why the intensities must be normalised before calculating the relative atomic mass.

[1]
B

the relative atomic mass of silicon from these data.

[3]
Question 26
HL • Paper 2
Medium
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HL • Paper 2
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The mass spectrum of a compound containing carbon and hydrogen has a molecular ion peak at m/z=44m/z = 44 and fragment ion peaks at m/z=15m/z = 15 and m/z=29m/z = 29. Assume the ions are singly charged.

A

Define the term fragment ion.

[1]
B

the formula of the fragment ion at m/z=15m/z = 15.

[1]
C

how fragment ion peaks can help the structure of a compound.

[2]
Question 27
SL • Paper 1B
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SL • Paper 1B
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A naturally occurring sample of element M contains four isotopes. The relative isotopic masses and percentage abundances are shown.

Relative isotopic mass

Percentage abundance / %

84

0.56

86

9.86

87

7.00

88

82.58

A

the relative atomic mass, ArA_r, of element M using the data.

[3]
B

why the value of ArA_r is closest to 88.

[1]
C

why the calculated value may differ slightly from a value in a data booklet.

[1]
Question 28
SL • Paper 1B
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SL • Paper 1B
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An isotope tracer experiment was used to follow the oxygen atom in the reaction shown. The oxygen atom in P−OHP-OH was labelled with the isotope 18O^{18}\text{O}.

A

Identify the product that contains most of the 18O^{18}\text{O} label.

[1]
B

what the tracer result shows about the fate of the oxygen atom originally in P−OHP-OH.

[1]
C

why an oxygen isotope can be used as a tracer in this experiment.

[2]

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Question 29
SL • Paper 1B
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SL • Paper 1B
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The graph shows the relative rate of diffusion of gaseous molecules containing different isotopes of the same element under the same conditions.

A

the relationship shown in the graph.

[1]
B

the percentage decrease in relative rate from the lightest to the heaviest isotopic molecule.

[1]
C

why isotopic molecules can have different physical properties but very similar chemical properties.

[2]
Question 30
HL • Paper 1B
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HL • Paper 1B
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The mass spectrum of a naturally occurring sample of element X is shown. The ions are singly charged.

A

what each peak in the spectrum represents.

[1]
B

the relative atomic mass of X from peaks at m/z=79m/z=79 and m/z=81m/z=81 with relative abundances of 50.5%50.5\% and 49.5%49.5\%, respectively.

[2]
C

why the peak positions can be treated as isotope mass numbers in this calculation.

[1]
Question 31
HL • Paper 1B
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HL • Paper 1B
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The mass spectrum of a naturally occurring element is shown along with a small extract from a data table of relative atomic masses.

Source

m/z

Relative abundance / %

Element

Relative atomic mass

Mass spectrum

28

92.2

—

—

Mass spectrum

29

4.7

—

—

Mass spectrum

30

3.1

—

—

Data table extract

—

—

Aluminium

26.98

Data table extract

—

—

Silicon

28.09

Data table extract

—

—

Phosphorus

30.97

A

the relative atomic mass from peaks at m/z=28m/z=28, 29 and 30 with percentage abundances 92.2%92.2\%, 4.7%4.7\% and 3.1%3.1\%, respectively.

[2]
B

Identify the element if the data table lists aluminium, silicon and phosphorus with approximate ArA_r values 26.98, 28.09 and 30.97.

[1]
C

why there are three peaks in the elemental mass spectrum.

[1]
Question 32
HL • Paper 2
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HL • Paper 2
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A geological sample contains an element with two isotopes. Its mass spectrum shows two singly charged isotope peaks with an intensity ratio of 1.00:4.001.00:4.00 for the lower and higher m/zm/z peaks, respectively.

A

The lower and higher peaks occur at m/z=10m/z = 10 and m/z=11m/z = 11, respectively. the percentage abundance of each isotope.

[1]
B

the relative atomic mass of the element in this sample.

[2]
C

one reason why this value may differ slightly from a data booklet value for the same element.

[1]

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Question 33
HL • Paper 1B
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HL • Paper 1B
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A mass spectrum of element Y gives peak intensities that are not percentages. The ions are singly charged.

A

Convert the relative intensity of the peak at m/z=24m/z=24 to a percentage abundance.

[1]
B

the relative atomic mass of Y using peaks at m/z=24m/z=24, 25 and 26 with relative intensities 315, 40 and 45.

[3]
C

why the most intense peak does not by itself give the relative atomic mass.

[1]
Question 34
HL • Paper 1B
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HL • Paper 1B
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Mass spectra were recorded for chlorine from two different samples. The spectra show the same two isotope peaks but different relative abundances.

A

ArA_r for sample A, which contains 75.0%75.0\% 35Cl^{35}\text{Cl} and 25.0%25.0\% 37Cl^{37}\text{Cl}.

[2]
B

ArA_r for sample B, which contains 60.0%60.0\% 35Cl^{35}\text{Cl} and 40.0%40.0\% 37Cl^{37}\text{Cl}.

[2]
C

the isotope composition of the two samples using the spectra.

[1]
Question 35
SL • Paper 2
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SL • Paper 2
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A computer simulation represents the scattering of alpha particles by a thin metal foil. The diameter of a typical atom is taken as 1.0×10−10 m1.0 \times 10^{-10}\ \text{m} and the diameter of its nucleus as 1.0×10−15 m1.0 \times 10^{-15}\ \text{m}.

A

The simulation is based on Rutherford's gold foil experiment.

I.

how one observation supports the conclusion that atoms are mostly empty space.

[1]
II.

how the observations support the existence of a small, dense, positively charged nucleus.

[2]
B

Consider the scale of the atom and the nucleus.

I.

the ratio of the diameter of the atom to the diameter of the nucleus.

[1]
II.

the diameter of an atom on a model in which the nucleus has a diameter of 2.0 cm2.0\ \text{cm}.

[2]
C

why the mass number of an atom is determined by the nucleus rather than by the electrons.

[1]
Question 36
SL • Paper 2
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SL • Paper 2
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Strontium bromide is used in some specialist materials. One ion in a sample is represented by the nuclear symbol 3888Sr2+{}^{88}_{38}\text{Sr}^{2+}. A bromide ion in the same sample contains 44 neutrons.

A

Use the nuclear symbols and charges of the ions.

I.

the number of protons, neutrons and electrons in 3888Sr2+{}^{88}_{38}\text{Sr}^{2+}.

[2]
II.

Write the full nuclear symbol, including charge, for the bromide ion.

[1]
B

the roles of protons, neutrons and electrons in determining the identity and charge of these particles.

[2]
C

why 86Sr2+{}^{86}\text{Sr}^{2+} and 88Sr2+{}^{88}\text{Sr}^{2+} have very similar chemical properties.

[1]

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Question 37
SL • Paper 2
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SL • Paper 2
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Silicon atoms are used to make very small electronic devices. A typical silicon atom has a radius of 111 pm111\ \text{pm} and its nucleus has a radius of about 3.6 fm3.6\ \text{fm}.

A

the size of the atom and its nucleus.

I.

Convert both radii to metres and how many times larger the radius of the atom is than the radius of the nucleus.

[3]
II.

On a model, the atom is drawn with a radius of 5.0 cm5.0\ \text{cm}. the radius of the nucleus on the same scale.

[1]
B

why the nucleus contains almost all the mass of a silicon atom but occupies only a tiny fraction of the atom's volume.

[2]
Question 38
HL • Paper 1B
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HL • Paper 1B
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A spectrum of element Z was recorded using ions with charge number z=2z=2. The table gives the observed m/zm/z values and relative abundances.

m/z

Relative abundance / %

32.0

69.1

33.0

30.9

A

the mass numbers of the two isotopes if the observed peaks are at m/z=32.0m/z=32.0 and m/z=33.0m/z=33.0.

[1]
B

the relative atomic mass of Z if the relative abundances of the two peaks are 69.1%69.1\% and 30.9%30.9\%, respectively.

[2]
C

the error in calculating ArA_r directly from the observed m/zm/z values.

[1]
Question 39
HL • Paper 1B
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HL • Paper 1B
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A low-resolution mass spectrum of an element has two broad isotope peaks. A student estimated the isotope abundances from peak heights, but the analyst reported that peak areas should be used.

Isotope mass / u

Peak height / a.u.

Integrated area / a.u.

10

40

40

11

30

60

A

ArA_r using the peak areas for isotopes with masses 10 and 11. The integrated areas are 40 and 60, respectively.

[2]
B

The student used peak heights of 40 and 30 for the same two isotopes. the value of ArA_r the student would obtain.

[1]
C

the student's method for this spectrum.

[2]
Question 40
SL • Paper 2
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SL • Paper 2
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A purified sample of an element, X, contains three naturally occurring isotopes. Their mass numbers and percentage abundances are shown in the table.

Mass number

Percentage abundance / %

50

4.35

52

83.79

53

11.86

A

Consider the meaning of isotope notation.

I.

Define the term isotope.

[1]
II.

why all isotopes of X occupy the same position in the periodic table.

[1]
B

the relative atomic mass, ArA_r, of X using the data in the table.

[3]
C

Another sample contains only 50X{}^{50}\text{X} and 52X{}^{52}\text{X} and has Ar=51.70A_r = 51.70. the percentage abundance of 50X{}^{50}\text{X} in this sample.

[2]
D

why a sample enriched in 53X{}^{53}\text{X} could have a slightly different density from a natural sample of X.

[1]

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Question 41
SL • Paper 2
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SL • Paper 2
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A tracer experiment investigates the source of the oxygen gas produced during a reaction involving water and carbon dioxide in green plant cells. In one experiment the water contains 18O{}^{18}\text{O} atoms; in another the carbon dioxide contains 18O{}^{18}\text{O} atoms. The isotope composition of the oxygen gas is then analysed.

A

Consider the isotope 18O{}^{18}\text{O}.

I.

how 18O{}^{18}\text{O} differs from 16O{}^{16}\text{O}.

[1]
II.

the numbers of protons, neutrons and electrons in a neutral 18O{}^{18}\text{O} atom.

[2]
B

why 18O{}^{18}\text{O}-labelled water can be used as a tracer in this experiment.

[2]
C

the conclusion that the oxygen atoms in the oxygen gas product come from water rather than carbon dioxide.

[2]
Question 42
SL • Paper 2
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SL • Paper 2
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A sample of chlorine from an industrial process contains only 35Cl{}^{35}\text{Cl} and 37Cl{}^{37}\text{Cl}. The relative atomic mass of chlorine in this sample is 35.62.

A

Use the isotope composition of the chlorine sample.

I.

the percentage abundance of each chlorine isotope in this sample.

[2]
II.

the average relative molecular mass of Cl2\text{Cl}_2 molecules in this sample.

[1]
B

why the relative atomic mass of chlorine is not a whole number and why a value calculated using mass numbers may differ slightly from a data booklet value.

[2]
C

whether 35Cl{}^{35}\text{Cl} and 37Cl{}^{37}\text{Cl} have identical chemical and physical properties.

[3]
Question 43
HL • Paper 2
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HL • Paper 2
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The mass spectrum of a naturally occurring sample of an element has two main peaks. The peak heights have been calibrated so that they are proportional to isotope abundance.

A

Interpret the mass spectrum.

I.

what the m/zm/z value of an ion represents and why the peak positions can be used to identify isotopes in this spectrum.

[2]
II.

the relative atomic mass of the element using peaks at m/z=69m/z=69 and m/z=71m/z=71 with relative abundances of 60.1%60.1\% and 39.9%39.9\%, respectively.

[2]
B

Identify the element using the calculated relative atomic mass and the isotope pattern.

[1]
C

three limitations or assumptions involved in using this mass spectrum to a data booklet value of ArA_r.

[3]
Question 44
HL • Paper 2
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HL • Paper 2
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Two mineral samples contain boron. Their mass spectra each show peaks due to 10B+{}^{10}\text{B}^{+} and 11B+{}^{11}\text{B}^{+}. The relative intensities for sample A are 23 and 100, respectively.

A

Use the spectrum for sample A.

I.

Convert the relative intensities for sample A into percentage abundances.

[2]
II.

the relative atomic mass of boron in sample A.

[2]
B

the spectra of samples A and B and whether the samples have the same isotopic composition.

[2]
C

why the two boron samples can have different mass spectra but very similar chemical reactions.

[1]

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Question 45
HL • Paper 2
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HL • Paper 2
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The mass spectrum of a compound containing carbon, hydrogen and bromine has two molecular ion peaks of approximately equal height at m/z=94m/z=94 and m/z=96m/z=96. Other important peaks occur as a pair near the bromine isotope masses and as a peak at m/z=15m/z=15.

A

Interpret the molecular ion region of the spectrum.

I.

why two molecular ion peaks separated by two m/zm/z units and of approximately equal height the presence of one bromine atom.

[2]
II.

the formula of the lower-mass molecular ion if it contains 12C{}^{12}\text{C}, three 1H{}^{1}\text{H} atoms and 79Br{}^{79}\text{Br}.

[1]
B

the average relative molecular mass of CH3Br\text{CH}_3\text{Br} using Ar(C)=12.01A_r(\text{C})=12.01, Ar(H)=1.01A_r(\text{H})=1.01 and Ar(Br)=79.90A_r(\text{Br})=79.90.

[2]
C

how the fragment ion peaks support the proposed composition of the compound.

[2]
Question 46
HL • Paper 2
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HL • Paper 2
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A copper sample gives two singly charged isotope peaks in a mass spectrum. The relative intensities of the peaks due to 63Cu+{}^{63}\text{Cu}^{+} and 65Cu+{}^{65}\text{Cu}^{+} are 100 and 45, respectively. The precise isotopic masses are 62.93 and 64.93.

A

Use the two isotope peaks for the copper sample.

I.

Convert the relative intensities into percentage abundances.

[2]
II.

the relative atomic mass of copper in this sample using the precise isotopic masses.

[2]
B

why the calculated ArA_r is not exactly equal to the m/zm/z value of either peak.

[1]
C

A second copper sample has a higher calculated ArA_r than this sample. one change in isotopic composition that could this.

[1]
Question 47
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The mass spectrum of a neon sample contains peaks from singly charged and doubly charged ions. The singly charged isotope peaks occur at m/z=20m/z=20, 2121 and 2222, with relative abundances of 90.5%90.5\%, 0.3%0.3\% and 9.2%9.2\%, respectively.

A

Consider the peaks due to doubly charged ions.

I.

the charge number, zz, of an ion from 20Ne{}^{20}\text{Ne} that gives a peak at m/z=10m/z=10.

[1]
II.

why the peak at m/z=10m/z=10 should not be interpreted as evidence for a neon isotope with mass number 10.

[2]
B

the relative atomic mass of neon from the singly charged isotope peaks.

[3]
C

the effect on the calculated ArA_r if the smaller doubly charged peaks were incorrectly treated as additional singly charged isotope peaks.

[2]
Question 48
HL • Paper 2
Hard
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HL • Paper 2
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A mineral sample is converted into gaseous atoms and analysed by mass spectrometry. The main singly charged peaks occur at m/z=24m/z=24, 2525 and 2626 with relative intensities 79.079.0, 10.010.0 and 11.011.0, respectively.

A

Use the three main peaks in the mass spectrum.

I.

the relative atomic mass of the element represented by these peaks.

[3]
II.

Identify the element using the isotope pattern and calculated ArA_r.

[1]
B

why the atomic number of the element cannot be read directly from this mass spectrum.

[2]
C

A very small additional peak is observed at m/z=23m/z=23. whether it should be included in the calculation of the relative atomic mass for the element.

[2]

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S1.1 Introduction to the particulate nature of matter

S1.3 Electron configurations