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R2.2 How fast? The rate of chemical change

Practice exam-style IB Chemistry questions for How fast? The rate of chemical change, aligned with the syllabus and grouped by topic.

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Question 1
SL • Paper 1A
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SL • Paper 1A
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A clock reaction is repeated using different reactant concentrations. In each trial, the time is measured for the same fixed amount of product to form. What quantity is most directly proportional to the initial rate?

A.

tt

B.

t2t^2

C.

ln⁡t\ln t

D.

1/t1/t

Question 2
SL • Paper 1A
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SL • Paper 1A
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The temperature of a reacting gas mixture is increased from 300 K300\ \text{K} to 330 K330\ \text{K}. What is the main reason for the increase in reaction rate according to collision theory?

A.

A larger fraction of particles has energy at least equal to EaE_a.

B.

The activation energy of the uncatalysed reaction decreases.

C.

The enthalpy change of the reaction becomes more negative.

D.

All collisions occur with the correct collision geometry.

Question 3
SL • Paper 1A
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SL • Paper 1A
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For the reaction 2NO(g)+O2(g)→2NO2(g)2\text{NO(g)} + \text{O}_2\text{(g)} \to 2\text{NO}_2\text{(g)}, the concentration of NO\text{NO} decreases from 0.240 mol dm−30.240\ \text{mol dm}^{-3} to 0.160 mol dm−30.160\ \text{mol dm}^{-3} in 50.0 s50.0\ \text{s}. What is the average rate of reaction over this time interval?

A.

8.00×10−4 mol dm−3 s−18.00\times 10^{-4}\ \text{mol dm}^{-3}\ \text{s}^{-1}

B.

4.00×10−4 mol dm−3 s−14.00\times 10^{-4}\ \text{mol dm}^{-3}\ \text{s}^{-1}

C.

3.20×10−3 mol dm−3 s−13.20\times 10^{-3}\ \text{mol dm}^{-3}\ \text{s}^{-1}

D.

1.60×10−3 mol dm−3 s−11.60\times 10^{-3}\ \text{mol dm}^{-3}\ \text{s}^{-1}

Question 4
SL • Paper 1A
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SL • Paper 1A
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Hydrogen gas is produced when magnesium reacts with excess dilute hydrochloric acid. The gas is to be collected and its volume measured continuously. What apparatus is most suitable?

A.

Gas syringe connected to the reaction flask

B.

Thermometer placed above the reaction flask

C.

pH probe placed in the reaction mixture

D.

Colorimeter and cuvette containing the reaction mixture

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Question 5
SL • Paper 1A
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SL • Paper 1A
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In repeated trials measuring the volume of gas produced in a reaction, all final gas volumes are lower than the expected stoichiometric volume by a similar amount. What is the most likely type of error?

A.

Random error from variation in reaction temperature

B.

Systematic error from gas leaking from the apparatus

C.

Random error from using a smaller measuring cylinder

D.

Systematic error from repeating the experiment several times

Question 6
HL • Paper 1A
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HL • Paper 1A
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The elementary step NO2(g)+CO(g)→NO(g)+CO2(g)\text{NO}_2\text{(g)} + \text{CO(g)} \to \text{NO(g)} + \text{CO}_2\text{(g)} occurs in a proposed mechanism. What is the molecularity of this elementary step?

A.

Unimolecular

B.

Zeromolecular

C.

Termolecular

D.

Bimolecular

Question 7
SL • Paper 2
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SL • Paper 2
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A student investigates the rate of reaction between zinc granules and hydrochloric acid by measuring the hydrogen gas produced.

A

one suitable piece of apparatus for measuring the volume of hydrogen continuously.

[1]
B

two variables, other than acid concentration, that should be controlled when investigating the effect of acid concentration on the rate.

[2]
Question 8
SL • Paper 1A
Medium
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SL • Paper 1A
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An exothermic reaction is carried out with and without a catalyst. The catalyst changes only the activation energy. The correct energy profile is shown by which diagram?

A.
B.
C.
D.

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Question 9
HL • Paper 1A
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HL • Paper 1A
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Initial-rate data for a reaction are shown.

Experiment[A]/mol dm−3[A]/\text{mol dm}^{-3}[B]/mol dm−3[B]/\text{mol dm}^{-3}Initial rate/mol dm−3 s−1\text{mol dm}^{-3}\ \text{s}^{-1}
10.1000.1000.1000.1002.00×10−42.00\times 10^{-4}
20.2000.2000.1000.1008.00×10−48.00\times 10^{-4}
30.1000.1000.3000.3006.00×10−46.00\times 10^{-4}

What is the rate equation?

A.

r=k[A]2[B]2r=k[A]^2[B]^2

B.

r=k[A]2[B]r=k[A]^2[B]

C.

r=k[A][B]2r=k[A][B]^2

D.

r=k[A][B]r=k[A][B]

Question 10
HL • Paper 1A
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HL • Paper 1A
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A proposed mechanism is shown.

Step 1: A+B→IA + B \to I slow

Step 2: I+C→DI + C \to D fast

What are the intermediate and the rate equation predicted by the rate-determining step?

A.

Intermediate DD; r=k[D]r=k[D]

B.

Intermediate II; r=k[A][B]r=k[A][B]

C.

Intermediate CC; r=k[I][C]r=k[I][C]

D.

Intermediate BB; r=k[A][B][C]r=k[A][B][C]

Question 11
HL • Paper 1A
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HL • Paper 1A
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For a reaction with rate equation r=k[A][B]2r=k[A][B]^2, rate is measured in mol dm−3 s−1\text{mol dm}^{-3}\ \text{s}^{-1} and concentration in mol dm−3\text{mol dm}^{-3}. What are the units of kk?

A.

s−1\text{s}^{-1}

B.

dm3 mol−1 s−1\text{dm}^3\ \text{mol}^{-1}\ \text{s}^{-1}

C.

mol dm−3 s−1\text{mol dm}^{-3}\ \text{s}^{-1}

D.

dm6 mol−2 s−1\text{dm}^6\ \text{mol}^{-2}\ \text{s}^{-1}

Question 12
HL • Paper 1A
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HL • Paper 1A
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For an Arrhenius plot of ln⁡k\ln k against 1/T1/T, what are the gradient and vertical intercept?

A.

Gradient Ea/RE_a/R; intercept AA

B.

Gradient ln⁡A\ln A; intercept −Ea/R-E_a/R

C.

Gradient −Ea/R-E_a/R; intercept ln⁡A\ln A

D.

Gradient −R/Ea-R/E_a; intercept ln⁡A\ln A

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Question 13
SL • Paper 2
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SL • Paper 2
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The concentration of bromine was monitored during its reaction with methanoic acid at constant temperature.

Time / s[Br2][\text{Br}_2] / mol dm−3\text{mol dm}^{-3}
00.01000.0100
200.006400.00640
400.004400.00440
A

the average rate of disappearance of bromine between 2020 s and 4040 s.

[2]
B

how the instantaneous rate at 2020 s would be obtained from a concentration-time graph.

[1]
Question 14
SL • Paper 2
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SL • Paper 2
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The rate of reaction between iodide ions and peroxodisulfate ions increases when the temperature is raised from 298 K298\ \text{K} to 318 K318\ \text{K}.

A

Define activation energy.

[1]
B

why increasing the temperature increases the rate of reaction, using collision theory.

[2]
Question 15
SL • Paper 2
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SL • Paper 2
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Magnesium reacts with excess dilute hydrochloric acid. In one experiment a single strip of magnesium is used. In a second experiment the same mass of magnesium is cut into many small pieces.

A

the effect on the initial rate in the second experiment.

[1]
B

your prediction in terms of collisions.

[2]
C

why changing the pressure would have little direct effect on this reaction mixture.

[1]
Question 16
HL • Paper 2
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HL • Paper 2
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The energy profile for a multistep reaction is shown.

A

the number of elementary steps and the number of intermediates shown.

[2]
B

Identify the rate-determining step and justify your answer.

[2]

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Question 17
SL • Paper 1B
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SL • Paper 1B
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Magnesium ribbon was reacted with excess dilute hydrochloric acid. The volume of hydrogen gas was collected in a gas syringe and recorded over time.

A

the total volume of hydrogen gas produced.

[1]
B

the average rate of production of hydrogen gas between 20 s20\ \text{s} and 60 s60\ \text{s}.

[2]
C

why the rate decreases during the reaction.

[2]
Question 18
SL • Paper 1B
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SL • Paper 1B
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A clock reaction was carried out between sodium thiosulfate solution and hydrochloric acid. The time taken for a fixed amount of sulfur precipitate to obscure a mark was recorded at different sodium thiosulfate concentrations. Temperature and total volume were kept constant.

Na2S2O3\text{Na}_2\text{S}_2\text{O}_3 concentration / mol dm−3\text{mol dm}^{-3}

Time / s

0.0250

160

0.0500

80

0.100

40

A

why 1/t1/t can be used as a measure of rate in this experiment.

[1]
B

Use the data to the rate when the sodium thiosulfate concentration is doubled from 0.0500 mol dm−30.0500\ \text{mol dm}^{-3} to 0.100 mol dm−30.100\ \text{mol dm}^{-3}.

[2]
C

the effect of increasing the sodium thiosulfate concentration using collision theory.

[2]
Question 19
SL • Paper 1B
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SL • Paper 1B
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Equal masses of calcium carbonate were reacted separately with excess hydrochloric acid. In experiment 1, large chips were used. In experiment 2, powdered calcium carbonate was used. The volume of carbon dioxide was recorded over time.

A

the initial rates and final volumes of carbon dioxide for the two experiments.

[2]
B

the difference in rate between the two experiments.

[2]
Question 20
HL • Paper 1A
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HL • Paper 1A
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A two-step reaction is exothermic. The second step is rate-determining and there is one intermediate. The correct energy profile is shown by which diagram?

A.
B.
C.
D.

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Question 21
SL • Paper 2
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SL • Paper 2
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A Maxwell-Boltzmann distribution can be used to show the effect of temperature on the proportion of particles able to react.

A

Maxwell-Boltzmann energy distribution curves for the same sample at two temperatures, T1T_1 and T2T_2, where T2>T1T_2 > T_1. Label the activation energy, EaE_a, and show the relative number of particles with energy greater than EaE_a at each temperature.

[3]
Question 22
SL • Paper 2
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SL • Paper 2
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Hydrogen peroxide decomposes exothermically. Manganese(IV) oxide acts as a catalyst for the decomposition.

A

an energy profile for the reaction with and without the catalyst.

[3]
B

the effect of the catalyst on the enthalpy change of the reaction.

[1]
Question 23
HL • Paper 2
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HL • Paper 2
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The following mechanism is proposed for the reaction 2NO(g)+Cl2(g)→2NOCl(g)2\text{NO}(g) + \text{Cl}_2(g) \to 2\text{NOCl}(g).

Step 1: NO(g)+Cl2(g)→NOCl2(g)\text{NO}(g) + \text{Cl}_2(g) \to \text{NOCl}_2(g) slow

Step 2: NOCl2(g)+NO(g)→2NOCl(g)\text{NOCl}_2(g) + \text{NO}(g) \to 2\text{NOCl}(g) fast

A

Identify the intermediate in the mechanism.

[1]
B

the molecularity of the slow step.

[1]
C

The experimentally determined rate equation is r=k[NO][Cl2]r = k[\text{NO}][\text{Cl}_2]. whether the mechanism is consistent with the kinetic and stoichiometric data.

[2]
Question 24
HL • Paper 2
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HL • Paper 2
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Initial-rate data were obtained for the reaction A+B→products\text{A} + \text{B} \to \text{products} at constant temperature.

Experiment[A][\text{A}] / mol dm−3\text{mol dm}^{-3}[B][\text{B}] / mol dm−3\text{mol dm}^{-3}Initial rate / mol dm−3 s−1\text{mol dm}^{-3}\ \text{s}^{-1}
10.1000.1000.1000.1002.00×10−52.00 \times 10^{-5}
20.2000.2000.1000.1008.00×10−58.00 \times 10^{-5}
30.1000.1000.2000.2002.00×10−52.00 \times 10^{-5}
A

the order of reaction with respect to A and with respect to B.

[2]
B

Write the rate equation and the overall order.

[2]

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Question 25
HL • Paper 2
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HL • Paper 2
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For a reaction at 298 K298\ \text{K}, the rate equation is r=k[P][Q]2r = k[\text{P}][\text{Q}]^2. When [P]=0.120 mol dm−3[\text{P}] = 0.120\ \text{mol dm}^{-3} and [Q]=0.200 mol dm−3[\text{Q}] = 0.200\ \text{mol dm}^{-3}, the initial rate is 5.76×10−5 mol dm−3 s−15.76 \times 10^{-5}\ \text{mol dm}^{-3}\ \text{s}^{-1}.

A

the value of the rate constant, kk, including its units.

[3]
Question 26
HL • Paper 2
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HL • Paper 2
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The decomposition of X was followed at constant temperature. Three plots were tested using the same concentration-time data. Only the plot of ln⁡[X]\ln[\text{X}] against time was linear, with gradient −1.80×10−2 s−1-1.80 \times 10^{-2}\ \text{s}^{-1}.

Time / s

[X][\text{X}] / mol dm−3^{-3}

0

0.100

20

0.0698

40

0.0487

60

0.0340

80

0.0237

100

0.0165

120

0.0115

A

the order of reaction with respect to X.

[1]
B

the value and units of the rate constant, kk.

[2]
Question 27
SL • Paper 1B
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SL • Paper 1B
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The diagram shows Maxwell-Boltzmann energy distributions for the same reacting gas mixture at two different temperatures. The activation energy, EaE_a, for the reaction is also shown.

A

what the area under each distribution curve represents.

[1]
B

two differences between the distribution at higher temperature and the distribution at lower temperature.

[2]
C

why the rate is greater at the higher temperature.

[2]
Question 28
SL • Paper 1B
Medium
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SL • Paper 1B
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An energy profile is shown for an exothermic reaction, with and without a catalyst.

A

Identify which pathway has the lower activation energy.

[1]
B

the effect of the catalyst on the overall enthalpy change of the reaction.

[1]
C

how the catalyst increases the rate of reaction.

[2]

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Question 29
HL • Paper 1B
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HL • Paper 1B
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A proposed mechanism for a reaction is shown. The experimentally determined rate equation is also given.

Item

Details

Step 1 (slow)

NO2+Cl2→NO2Cl+Cl\text{NO}_2 + \text{Cl}_2 \to \text{NO}_2\text{Cl} + \text{Cl}

Step 2 (fast)

Cl+NO2→NO2Cl\text{Cl} + \text{NO}_2 \to \text{NO}_2\text{Cl}

Experimental rate law

r=k[NO2][Cl2]r = k[\text{NO}_2][\text{Cl}_2]

A

Identify the intermediate in the mechanism.

[1]
B

the overall equation by adding the elementary steps.

[1]
C

whether the mechanism is consistent with the experimental rate equation.

[2]
Question 30
HL • Paper 1B
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HL • Paper 1B
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The concentration of reactant A was monitored during a reaction at constant temperature. Three possible linearized plots were produced from the same concentration-time data.

Time / s

[A][A] / mol dm−3^{-3}

ln⁡([A])\ln([A])

1/[A]1/[A] / dm3^{3} mol−1^{-1}

0

1.000

0.000

1.000

25

0.3679

-1.000

2.719

50

0.1353

-2.000

7.390

75

0.04979

-3.000

20.09

100

0.01832

-4.000

54.60

125

0.006738

-5.000

148.4

A

Identify the order of reaction with respect to A.

[1]
B

the rate constant, including its units.

[2]
C

how the value of kk would be affected by increasing the temperature, assuming no other change is made.

[1]
Question 31
HL • Paper 2
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HL • Paper 2
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For a first-order decomposition, an Arrhenius plot of ln⁡k\ln k against 1/T1/T is linear. The gradient of the best-fit line is −9.20×103 K-9.20 \times 10^3\ \text{K} and the intercept is 27.527.5. Use R=8.31 J mol−1 K−1R = 8.31\ \text{J mol}^{-1}\ \text{K}^{-1}.

A

the activation energy, EaE_a, in kJ mol−1\text{kJ mol}^{-1}.

[2]
B

the Arrhenius factor, AA, including units.

[2]
Question 32
SL • Paper 1B
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SL • Paper 1B
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A student investigated the effect of hydrochloric acid concentration on the initial rate of reaction with magnesium ribbon. The initial rate was determined from the gradient of a tangent to the volume-time curve for each trial. Several repeats were carried out at each acid concentration.

A

Use the graph to whether the initial rate is directly proportional to the hydrochloric acid concentration over the range investigated.

[2]
B

on the reliability of the data, referring to random error and the anomalous point.

[2]
C

one variable, other than acid concentration, that should be controlled in this investigation.

[1]

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Question 33
HL • Paper 1B
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HL • Paper 1B
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Initial-rate data were obtained for the reaction between reactants A and B at constant temperature.

Experiment

[A] / mol dm−3^{-3}

[B] / mol dm−3^{-3}

Initial rate / mol dm−3^{-3} s−1^{-1}

1

0.100

0.100

2.00×10−42.00 \times 10^{-4}

2

0.200

0.100

4.00×10−44.00 \times 10^{-4}

3

0.100

0.200

8.00×10−48.00 \times 10^{-4}

4

0.200

0.200

1.60×10−31.60 \times 10^{-3}

A

the order of reaction with respect to A and with respect to B.

[2]
B

Write the rate equation for the reaction.

[1]
C

the rate constant, including its units, using the first experiment.

[2]
Question 34
HL • Paper 1B
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HL • Paper 1B
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An energy profile is shown for a reaction that occurs in three elementary steps.

A

the number of transition states and intermediates shown.

[2]
B

Identify the rate-determining step and justify your answer.

[1]
C

the overall enthalpy change for the reaction.

[1]
D

why changing the concentration of a reactant involved only in step 1 may have little effect on the overall rate under these conditions.

[1]
Question 35
SL • Paper 2
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SL • Paper 2
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A student investigates the reaction between marble chips, CaCO3(s)CaCO_3(s), and excess hydrochloric acid.

CaCO3(s)+2HCl(aq)→CaCl2(aq)+H2O(l)+CO2(g)CaCO_3(s) + 2HCl(aq) \to CaCl_2(aq) + H_2O(l) + CO_2(g)

The volume of carbon dioxide is recorded using a gas syringe.

A

The tangent at 30 s30\ \text{s} passes through (10 s,14.0 cm3)(10\ \text{s}, 14.0\ \text{cm}^3) and (50 s,42.0 cm3)(50\ \text{s}, 42.0\ \text{cm}^3).

I.

the instantaneous rate of formation of carbon dioxide at 30 s30\ \text{s} in cm3 s−1\text{cm}^3\ \text{s}^{-1}.

[2]
II.

why the rate calculated from a tangent is an instantaneous rate rather than an average rate.

[1]
B

The experiment is repeated using the same mass of powdered calcium carbonate instead of marble chips. the expected change in the initial rate and the final volume of carbon dioxide.

[2]
C

one improvement to the apparatus if the graph showed a lower final gas volume than expected. how this improvement would affect the data.

[2]
Question 36
SL • Paper 2
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SL • Paper 2
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The reaction between iodide ions and peroxodisulfate ions is followed using a clock method. A fixed amount of thiosulfate ion and starch indicator is added. The time taken for a blue-black colour to appear is measured for different initial concentrations.

S2O82−(aq)+2I−(aq)→2SO42−(aq)+I2(aq)S_2O_8^{2-}(aq) + 2I^-(aq) \to 2SO_4^{2-}(aq) + I_2(aq)

A

The clock endpoint corresponds to the formation of the same small amount of iodine in every trial.

I.

why 1t\frac{1}{t} can be used as a measure proportional to the initial rate in this experiment.

[2]
II.

, using collision theory, why increasing the concentration of iodide ions is expected to decrease the time to the endpoint.

[2]
B

two variables, other than the concentration being investigated, that must be controlled to make the comparison of rates valid.

[2]

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Question 37
SL • Paper 2
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SL • Paper 2
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A student investigates the reaction between sodium thiosulfate solution and hydrochloric acid by timing how long it takes for a cross under the flask to disappear.

S2O32−(aq)+2H+(aq)→SO2(aq)+S(s)+H2O(l)S_2O_3^{2-}(aq) + 2H^+(aq) \to SO_2(aq) + S(s) + H_2O(l)

A

The time for the cross to disappear in one trial is 48.0 s48.0\ \text{s}.

I.

the relative rate, using 1t\frac{1}{t}, in s−1\text{s}^{-1}.

[1]
II.

why the disappearance of the cross is a fixed endpoint for comparing rates.

[1]
B

Design a fair comparison to investigate the effect of thiosulfate concentration on the rate.

[3]
C

Use the graph to distinguish between random error and systematic error in this investigation.

[2]
Question 38
HL • Paper 1B
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HL • Paper 1B
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Rate constants were measured for a first-order reaction at several temperatures. The data were used to construct an Arrhenius plot of ln⁡k\ln k against 1/T1/T.

A

the activation energy, EaE_a, from the gradient of the Arrhenius plot.

[2]
B

the Arrhenius factor, AA, including units.

[2]
C

why temperature must be expressed in kelvin in the Arrhenius equation.

[1]
Question 39
HL • Paper 1B
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HL • Paper 1B
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Two mechanisms have been proposed for the reaction 2NO+Br2→2NOBr2\text{NO}+\text{Br}_2\to 2\text{NOBr}. The experimentally determined rate equation is r=k[NO]2[Br2]r=k[\text{NO}]^2[\text{Br}_2].

Mechanism

Step 1

Step 2

A

NO+Br2→NOBr2\text{NO} + \text{Br}_2 \to \text{NOBr}_2 slow

NOBr2+NO→2NOBr\text{NOBr}_2 + \text{NO} \to 2\text{NOBr} fast

B

NO+Br2⇌NOBr2\text{NO} + \text{Br}_2 \rightleftharpoons \text{NOBr}_2 fast

NOBr2+NO→2NOBr\text{NOBr}_2 + \text{NO} \to 2\text{NOBr} slow

A

the molecularity of the slow step in mechanism B.

[1]
B

Show that mechanism B gives the correct overall equation.

[1]
C

which mechanism is more consistent with the experimental rate equation.

[2]
D

why a mechanism that matches the rate equation is still described as a possible mechanism.

[1]
Question 40
SL • Paper 2
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SL • Paper 2
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The rate of a gas-phase reaction increases when the temperature is raised from T1T_1 to T2T_2, where T2>T1T_2>T_1.

A

Use the axes provided.

I.

Maxwell-Boltzmann energy distribution curves for T1T_1 and T2T_2.

[2]
II.

why the increase in temperature causes a large increase in rate.

[2]
B

A catalyst is added at constant temperature. how the Maxwell-Boltzmann diagram can be used to show the effect of the catalyst on the rate.

[3]

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Question 41
SL • Paper 2
Hard
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SL • Paper 2
Hard
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An uncatalysed exothermic reaction is represented by an energy profile. The same reaction can also occur by a catalysed pathway.

A

Refer to the energy profile shown.

I.

Identify the activation energy and the transition on the diagram.

[2]
II.

how the diagram shows that the reaction is exothermic.

[1]
B

the catalysed pathway on the same diagram and the effect of the catalyst on the rate.

[3]
C

the statement: "A catalyst increases the yield of product because it makes the products more stable."

[2]
Question 42
SL • Paper 2
Hard
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SL • Paper 2
Hard
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Hydrogen peroxide decomposes slowly at room temperature but much faster in the presence of catalase, an enzyme found in potato tissue.

2H2O2(aq)→2H2O(l)+O2(g)2H_2O_2(aq) \to 2H_2O(l) + O_2(g)

A

The volume of oxygen collected is used to the reaction rate.

I.

why using a gas syringe is suitable for following the rate continuously.

[2]
II.

At one instant oxygen is forming at 1.20×10−4 mol dm−3 s−11.20\times10^{-4}\ \text{mol dm}^{-3}\ \text{s}^{-1}. the rate of disappearance of hydrogen peroxide at this instant.

[2]
B

the roles of sufficient energy and proper orientation in the decomposition of hydrogen peroxide.

[2]
C

the effect of catalase with the effect of finely divided manganese(IV) oxide, MnO2MnO_2, on this reaction.

[2]
Question 43
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The initial rate of a reaction involving aqueous reactants AA, BB and CC is measured at constant temperature. The balanced equation is not sufficient to the rate equation.

Experiment

[A] / mol dm−3^{-3}

[B] / mol dm−3^{-3}

[C] / mol dm−3^{-3}

Initial rate / mol dm−3^{-3} s−1^{-1}

1

0.100

0.100

0.100

2.00×10−42.00 \times 10^{-4}

2

0.200

0.100

0.100

8.00×10−48.00 \times 10^{-4}

3

0.100

0.200

0.100

4.00×10−44.00 \times 10^{-4}

4

0.100

0.100

0.300

2.00×10−42.00 \times 10^{-4}

A

Use the initial-rate data.

I.

the order of reaction with respect to AA, BB and CC.

[3]
II.

Write the rate equation and the overall order.

[2]
B

In one experiment, [A]=0.100 mol dm−3[A]=0.100\ \text{mol dm}^{-3}, [B]=0.100 mol dm−3[B]=0.100\ \text{mol dm}^{-3} and the initial rate is 2.00×10−4 mol dm−3 s−12.00\times10^{-4}\ \text{mol dm}^{-3}\ \text{s}^{-1}. kk and give its units.

[2]
C

why the orders in the rate equation cannot be deduced from the coefficients in the overall balanced equation.

[1]
Question 44
HL • Paper 2
Hard
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HL • Paper 2
Hard
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A possible mechanism for a reaction is shown.

Step 1: A→IfastStep 2: I+B→PslowStep 3: P+B→C+Dfast\begin{aligned} \text{Step 1: }& A \to I &&\text{fast}\\ \text{Step 2: }& I+B \to P &&\text{slow}\\ \text{Step 3: }& P+B \to C+D &&\text{fast} \end{aligned}

A

Consider the proposed sequence of elementary steps.

I.

Show that the steps give the overall equation and identify the intermediates.

[3]
II.

the molecularity of step 2 and why termolecular elementary steps are uncommon.

[2]
B

Use the energy profile.

I.

Identify the rate-determining step and the transition for this step.

[2]
II.

why the expression r=k[I][B]r=k[I][B] is not normally written as the experimental rate equation for the overall reaction.

[1]

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Question 45
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The decomposition of a compound XX is monitored at constant temperature. The data are processed using three possible linear plots.

A

The gradient of the straight-line plot is −4.62×10−2 s−1-4.62\times10^{-2}\ \text{s}^{-1}.

I.

the order of reaction with respect to XX.

[1]
II.

the rate constant, including units.

[2]
III.

the half-life of XX.

[2]
B

the instantaneous rate when [X]=0.0800 mol dm−3[X]=0.0800\ \text{mol dm}^{-3}.

[1]
C

why identifying a first-order graph does not prove a unique reaction mechanism.

[1]
Question 46
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The hydrolysis of a tertiary halogenoalkane, RBrRBr, in aqueous alkali is investigated.

RBr(aq)+OH−(aq)→ROH(aq)+Br−(aq)RBr(aq)+OH^-(aq) \to ROH(aq)+Br^-(aq)

Initial-rate data show that doubling [RBr][RBr] doubles the rate, but doubling [OH−][OH^-] has no effect on the rate.

A

Use the kinetic information.

I.

the rate equation.

[2]
II.

the units of kk.

[1]
B

Two possible mechanisms are proposed.

Mechanism 1:

Step 1: RBr→R++Br−slowStep 2: R++OH−→ROHfast\begin{aligned} \text{Step 1: }&RBr \to R^+ + Br^- &&\text{slow}\\ \text{Step 2: }&R^+ + OH^- \to ROH &&\text{fast} \end{aligned}

Mechanism 2:

RBr+OH−→ROH+Br−slowRBr+OH^- \to ROH+Br^- \quad \text{slow}

[3]
C

whether the kinetic data prove mechanism 1.

[2]
Question 47
HL • Paper 2
Hard
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HL • Paper 2
Hard
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The rate constant for a first-order reaction is measured at different temperatures. An Arrhenius plot of ln⁡k\ln k against 1/T1/T is obtained.

A

The gradient of the line is −7.20×103 K-7.20\times10^3\ \text{K} and the intercept is 18.418.4.

I.

the activation energy, EaE_a, in kJ mol−1\text{kJ mol}^{-1}.

[2]
II.

the Arrhenius factor, AA, including units.

[2]
B

kk at 310 K310\ \text{K} using the line equation.

[2]
C

the physical significance of the temperature scale and the Arrhenius factor in this analysis.

[2]
Question 48
HL • Paper 2
Hard
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HL • Paper 2
Hard
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A clock reaction is studied at two temperatures using identical initial concentrations and the same fixed visible endpoint. The reciprocal of the time to the endpoint is used as a value proportional to kk.

At 298 K298\ \text{K}, k=1.25×10−2 s−1k=1.25\times10^{-2}\ \text{s}^{-1}. At 318 K318\ \text{K}, k=1.00×10−1 s−1k=1.00\times10^{-1}\ \text{s}^{-1}.

A

Analyse the temperature-dependence data.

I.

why 1t\frac{1}{t} can be used as a value proportional to kk only under the stated experimental conditions.

[2]
II.

the activation energy using the two values of kk.

[3]
B

Use the value Ea=81.9 kJ mol−1E_a=81.9\ \text{kJ mol}^{-1} to the Arrhenius factor, AA, from the data at 298 K298\ \text{K}.

[2]
C

one major experimental limitation when using a clock reaction to Arrhenius parameters.

[1]

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R2.1 How much? The amount of chemical change

R2.3 How far? The extent of chemical change